模擬電子電路練習(xí)卷4

1、5.7 晶體管abcdevbe(mv) 690690580780820ic(ma)1.0001.0000.13010.1073.95ib(a)507071201050ie(ma)1.0501.0700.13710.2275.000.9520.9350.9490.9880.9862014.2918.5784.1770.43is(a)1.03e-151.03e-15 10.922e-15284.66e-184.208e-165.20110.70.7( )110a ima24 10( )2.52.4125.6 2.52cb imakvv 5.2043( )0,1v0( 10)1100,1mabcbc

2、ivimakii 又6100.7( 10)( )0.9651550,10 150.9654.475cbced imakkiiivkv 5.40/(1)2.41 14/,341.812/1.81.71 (2/34)200.3 ,1.722220 ,62 1.8vcebetvcsaaaacoccecceccevii evvvvvimavarkivvimavimak vv則接近飽和區(qū)時，則時，5.56330.3 ,0.3 ,(5) |5 10| 0.355 100.3,156.67,157.67/,0.005783.351.083cccccevttceocev beccvvtvvvvcececece

3、i rvvavvvvv va vvi raa vaaav vvamvvvvv 輸出波形接近飽和區(qū)，但不進入飽和區(qū)，5.8411111122222( )0, 10,20.7100.71.023100.740.70.71.4 ,4 1025100.2bececcececcaivvvimairvi rvvvvimairvirv ，假設(shè)兩管工作在放大區(qū)假設(shè)成立。5.841111111112122212( )1001210.0091, 10.91 ,0.91,(1)0.922101.6282 ()0.7(1)0.017310()bbbcbebeecbcbebcbcbqqqima vi rviima ii

4、mavi rvqiiririmaviir b1e1b1b，假設(shè)，工作在放大區(qū)對于有：10-(1+ )i r -0.7-i r =0對于：12222221.87230.311.7,(1)1.72410222.56 ,5101.27540.32cbebccvvvvqiima iimavie revvirvvvvq 工作在放大區(qū)又工作在放大區(qū)5.9011,0,13 ,3391,10.1,12/3020.73.712117.67,212.33118,213,1bcerccereccccececerccrbccrebbceiiivvvvvimavvrkrkiiiierrvikrvvvvrrrkrkvrk

5、rkrrk (1)首先假設(shè)則又取則又選擇合適電阻且稍大于理想值，則5.90e90,23.77 ,1|27.55120.72.83,2.8/(1)9103.09,3.052.812 ,0.73.5125.95118,213,1bbccbbbeceebecebeccccccrvvv rrrkrrvima iimarrrima imavv vvvvvi rvrkrkr(2)則電阻為以上取值可見略小于設(shè)計要求，因此減小則910ekr，5.11210.55*7.51.25/20/*7.5150/ceccmctvcimiimavikvgivma vavvgkv v很大，5.130212121593.212

6、7 15/15/279.643.21 0.7/(1)1.29.64/1011.940.99 1.9476.8/0.0251001.3,76.810052.10.99 1.94bbccbbbbeeebcmtmaocrvvvrrrrrkvvirrmaigma vvrkgvrki 5.130si/9.64 /1.31.15/2.11(/)1.1576.8(2.11/ 2)8.13/101.15/()101.158.13()45.2inboutcooioinmoolvsigisigingoolosiginiisigsiginsiglrrrkrrrkvvvrg vrrrgvvvrrvvvivrvrrai

7、vrrvr 3/aa5.137ebc(a)i =i +i =0.5ma0.99*0.50.4952.28ceceebebbiimavi rvi rv注意到( )500(1)30030(2)250300/90/teeoioeiieeoivb rickclvvvikkvvirvvv v 在 點根據(jù)列電流關(guān)系方程，即5.144(1)2.525ttbevvkiiebebe根據(jù)直流通路，可得5-i *3.3k-0.7-i *100k=0又i =(1+ )ii =1mar5.144(1) (3.3 |1 )(1)(3.3 |1 )80.04(1)(3.3 |1 )0.968/(1)(3.3 |1 )0.4

8、3 /77.48/1003.3 |ibbinbboioioinosigsigiinsigiooinliiniloutvi rikkriirkkkvkkv vvrkkvvvrvv vvvvrrviv rvo ra aivi rv rrrk776.31k5.149010020/5100 xcmtmaocrigma vvrkgvrki00015.67(1/)0.620.644.852 ()mcbcdefmjedejedemtccffvvcgpfcccccpfgfghzcc5.15320/2 ()0.547.533.3cmmtttmiggma vfvcccpffrkfmhzg且5.15901212/10|()5.7(|)16.11 /cemttminxoiomsigsigiinmoclinsigxiigma vvvrkgr