二級圓柱斜齒輪減速器計(jì)算說明書

1、機(jī)械設(shè)計(jì)課程設(shè)計(jì)設(shè)計(jì)計(jì)算說明書設(shè)計(jì)題目：帶式運(yùn)輸機(jī)傳動裝置班 級：設(shè)計(jì)者：指導(dǎo)教師：完成日期：教育資料目錄課程任務(wù)說明書3、電動機(jī)的選擇 41.1 電動機(jī)類型選擇 41.2 電動機(jī)容量選擇 41.3 確定電動機(jī)的轉(zhuǎn)速41.4 傳動比的分配41.5 計(jì)算傳動裝置的運(yùn)動和動力參數(shù) .4.齒輪設(shè)計(jì)42.1 高速級52.2 低速級1.0三、軸的設(shè)計(jì).43.1 高速軸1.43.2 中速軸 1.63.3 低速軸1.7四、中速軸的校核 1.84.1 齒輪受力分析 184.2 中速軸的各參數(shù) .194.3 繪制受力簡圖1.94.4 水平面H受力分析 .194.5 鉛錘面 V的受力分析 20.4.6 中速軸所受

2、的扭矩圖 214.7 合成彎矩.224.8 按彎扭合成應(yīng)力校核軸的強(qiáng)度 22五、滾動軸承的選擇及其基本額定壽命的計(jì)算 22.5.1 求兩軸承受到的徑向載荷 ?1和？?2225.2 求兩軸承計(jì)算軸向力?1和？?2225.3 求兩軸承的當(dāng)量動載荷 ?1和？235.4 驗(yàn)算軸承的壽命 23六、鍵的選擇和鍵的連接強(qiáng)度計(jì)算 246.1 鍵的選擇246.2 鍵連接強(qiáng)度的校核24七、聯(lián)軸器的選擇247.1高速軸聯(lián)軸器242.1低速軸聯(lián)軸器24八、齒輪及軸承潤滑方法、潤滑劑牌號及裝油量 24.8.1 齒輪潤滑248.2 軸承潤滑.25.九、密封方式的選擇 259.1 減速器的密封259.2 密封類型的選擇 2

3、5十、 密圭寸方式的選擇 2510.1 疾速器的機(jī)體結(jié)構(gòu)尺寸 252710.2 減速器附件 26 參考文獻(xiàn)【機(jī)械設(shè)計(jì)】課程設(shè)計(jì)任務(wù)書設(shè)計(jì)專業(yè):帶式輸送機(jī)傳動裝置設(shè)計(jì)者題目姓名:題目工作機(jī)輸入轉(zhuǎn)速工作機(jī)輸入功率(kW)2.363數(shù)據(jù)(rpm)1 電動機(jī) 2 聯(lián)軸器 3 減速器 4 帶式輸送機(jī)(工作機(jī))工作條件1、連續(xù)單向運(yùn)轉(zhuǎn)；2、載荷較平穩(wěn)；3、兩班制；4、結(jié)構(gòu)緊湊；5、工作壽命5年。設(shè) 計(jì) 內(nèi)容1、減速器裝配圖1張（0號圖）；2、零件圖23張；3、設(shè)計(jì)計(jì)算說明書 1份。設(shè)計(jì)期限答辯日期指導(dǎo)教師設(shè)計(jì)成績（表x.x如表9.1來自參考文獻(xiàn)1、表x-x、式（x-x）、式x-x、圖x-x如表10-1來自

4、 參考文獻(xiàn)2）、電動機(jī)的選擇1.1 電動機(jī)類型選擇:Y系列三廂籠型異步電動機(jī)（全封自扇冷式）1.2 電動機(jī)容量選擇:電動機(jī)所需工作功率？?？ 二?式中？?為工作機(jī)的輸入功率，？?為組成傳動裝置和工作機(jī)的各部分運(yùn)動副或傳動副的效率乘積。設(shè)?1、？?2、？?3分別為聯(lián)軸器、滾動軸承、齒輪傳動的傳動效率。查表9.1得:?1 = 0.99、？2 = 0.99、?3 = 0.97。? = 0.992 X0.993 X 0.972 = 0.895則:?”=?= _2.3_ ? = 2.57?0.895?99 ?選取電動機(jī)額定功率為3kw。1.3確定電動機(jī)轉(zhuǎn)速:? =0.8952.57?工作機(jī)輸入轉(zhuǎn)速為已？

5、?？= 63?/?,展開式減速器的傳動比為840,即電動機(jī)的實(shí)際轉(zhuǎn)速為?= （5042520）?/?。綜合考慮傳動裝置的機(jī)構(gòu)緊湊,選同步轉(zhuǎn)速為750r/min的電動機(jī)。根據(jù)電動機(jī)類型、容量和轉(zhuǎn)速，查表 14.1選定型號為Y132SM- 8。其主要性能如下:電動機(jī)型號額定功率/kw起動轉(zhuǎn)矩最大轉(zhuǎn)矩額定轉(zhuǎn)矩額定轉(zhuǎn)矩滿載轉(zhuǎn)速/(r/min)Y132SM- 837102.02.0i = 11.27?1 = 3.97?2 = 2.84?1 = 710?/?2=178.84?/?3=62.97?/?1 = 2.544?2 = 2.44?3 = 2.34?4 = 2.32?"?=34568.31?

6、. ?1=34222.63?. ?2=130470?.?1.4 傳動比的分配：總傳動比？ = ?= 710= 11.27,考慮潤滑條件、為使兩級大齒輪直徑相近 ?63?1 = 1.4?2。故：？1 = V1.4? = V1.4X 11.27= 3.97?11.27?” = =2 84"2 ?13.971.5 計(jì)算傳動裝置的運(yùn)動和動力參數(shù)：各州轉(zhuǎn)速：1 軸：？1 = ?= 710?/?2軸：？?2=券=397?/?= 17884?/?一?2178.843 軸：？?3=旃=28?/?= 62.97?/?各軸的輸入功率：1 軸：？1 = ? ?1 = 2.57 X0.99?= 2.544?

7、2 軸：？?2 = ?1 ?2?3 = 2.544 X0.99 X0.97?= 2.44?3 軸：？?3 = ?2 ?2 ?3 = 2.44 X0.99 X0.97? = 2.34?卷筒*由：？?4= ?3 ?1 = 2.34 X 0.99? = 2.32?各軸的輸入轉(zhuǎn)矩：電動機(jī)的輸出轉(zhuǎn)矩：? = 9.55 X106 X?= 9.55 X106 X2-57?.? = 34568.31?.? ?7101 軸：?1 = ? ?1 = 34568.31 X0.99?.?= 34222.63?. ?2 軸 :?2 = ?1 ?2 ?3 ?1 = 34222.63 X0.99 X0.97 X3.97?.

8、?=130470?.?3=355824.66N.mm?4 = 352266N. mm3 軸：？3= ?2 ?2 ?3 ?2 = 130470 X0.99 X0.97 X2.84N.mm = 355824.66N.mm卷筒軸：？4= ?3 ?1 = 355824.66 X0.99N.mm = 352266N. mm整理列表軸名功率P/kw轉(zhuǎn)矩 T/(N.mm)轉(zhuǎn)速/(N.mm)傳動比i效率4電機(jī)軸2.573.46 X10471010.991軸2.5443.42 X1047103.970.96032軸2.441.3 X105178.842.840.96033軸2.343.56 X10562.971

9、0.99卷筒*由2.323.52 X10562.97二、齒輪設(shè)計(jì)2. 1高速級：選精度等級、材料及齒數(shù)1）依照傳動方案，本設(shè)計(jì)選用二級斜齒輪傳動。標(biāo)準(zhǔn)結(jié)構(gòu)參數(shù)壓力角? = 20°,齒頂高系數(shù)？?？= 1,頂隙系數(shù)？?？= 0.25。2）運(yùn)輸機(jī)為一般工作機(jī)器，運(yùn)動轉(zhuǎn)速不高，查表16.1選用8級精度。3）由表10-1，小齒輪選用40cr （調(diào)質(zhì)），齒面硬度280HBs大齒輪選用45鋼（調(diào)質(zhì)），齒面硬度240HBs4)初選小齒輪齒數(shù)？?1 = 19,大齒輪？?2= ?1?1= 3.97 X19 = 75.43,??？?2= 76,?1與？?2互質(zhì)。5）初選螺旋角B= 14?1 = 19?2

10、= 76按齒面接觸疲勞強(qiáng)度設(shè)計(jì):1）由式（10-24）試算小齒輪分度圓直徑:?99?3 2?1 /?+ 1 ? ,(?、?)4 2 *B= 14°a.確定公式中的各參數(shù)值:i .試選載荷系數(shù)？?？ = 1.3ii.由圖10-20差得區(qū)域系數(shù)？?？= 2.433,表10-5查得材料彈性影響系數(shù)?=1189.6?1.508,表 10-7 ??？= 1。iii.由式10-21計(jì)算接觸疲勞強(qiáng)度重合系數(shù)？?。? = arctan(?/ ?) = arctan(?20° ?14 ?1 = arccos?1?/( ?1 + 2?|=arccos19 Xcos20.562° /(9

11、 + 2 x 1 Xcos14° )=?2 = arccos?2?/( ?2 + 2?=arccos76 Xcos20.562° /76 + 2X1 Xcos14° )=20.56231.840°24.0790?= ?1 (?1 - ?)+ ?2(?2- ?) / 2? =19(?31.840 - ?20,562 ) + 76(?24.079 °-?20.5620 )2?= 1.611? = 7?1? =1X19 Xtan14 ° ? = 1.508? = 1.3?= 2.4331?= 189.6? ? = 1? = 20.5620?

12、1 = 31.840 04- 1.611?2 = 24.079 0?= 1.611由圖10-25查得小齒輪和大齒輪的接觸疲勞極限分別為?1= 600Mpa,?2= 550Mpa?= 1.508?= 0.729iv.由式(10-23 )可得螺旋角系數(shù)?=儲?？=儲?？14° = 0.985v.計(jì)算接觸疲勞需用應(yīng)力?由式（10-15）計(jì)算應(yīng)力循環(huán)次數(shù):?1 = 60?1? = 60 X710 X1 X(2 X8 X300 X5) = 1.022 X109 ?1?= 0.985?2 =舅=1.022 X 109/( 76/19) = 2.556 X1081%、由圖10-23查取接觸疲勞壽命

13、系數(shù)？?1= 0.90、?2 = 0.93,取失效概率為安全系數(shù)S = 1,由式（10-14）得:? 1?1 ?10.90 X 600?2 =?1?2?20.93 X 550?= 540?= 511.5?1=600Mpa99?2=550Mpa?1 = 1.022 X109?2 = 2.556 X108取?1和?2中的較小者為該齒輪的接觸疲勞強(qiáng)度許用應(yīng)力，即?=?2 = 511.5?b.試算小齒輪分度圓直徑:?1 = 0.90342X1.3 X3.42X10 *76+1%X(19?1 /? + 1 ?(? ,(?2.433X1898X0.729 X0Q85511.5?.?)mm = 36.014

14、mm?殳=0.93?1 = 540?2）調(diào)整小齒輪分度圓直徑a.計(jì)算實(shí)際載荷系數(shù)前的數(shù)據(jù)準(zhǔn)備:i.圓周速度V?2=511.5?ii.齒寬b_ ?1?1V= 60 X1000?X 36.014 X710 m/s= 1.339m/s60 x1000?=511.5?b = ? ?1? = 1X 36.014?= 36.014?b.計(jì)算實(shí)載荷系數(shù)?i.由表10-2查得使用系數(shù)? = 1。10-8查得動載系數(shù)?= 1.07。ii .根據(jù)V = 1.339m/s, 8級精度，由圖dt = 36.014mmiii .齒輪的圓周力？?1 = 2?1/?1? = 2 X3.42 X104/36.014N = 1

15、.899 乂 103?,?1/?= 1 X 1.899 X 103/36.014?/?= 52.736?/? < 100?/ ?,查表10-3得齒間載荷分配系數(shù)？?？= 1.4。iv.由表10-4用插值法查得8級精度、小齒輪相對支承非對稱布置時(shí)，？?？= 1.4445則載荷系數(shù)為? = ? = 1 X 1.07 X 1.4 X 1.445 = 2.16463）由式（10-12）,可得按實(shí)際載荷系數(shù)算得的分度圓直徑?3 2.1646?1 = ?1?3/；7 = 36.014?= 42.686?1？?？1.3及相應(yīng)的齒輪模數(shù)?= ?1?= 42.686 x?14° 19?= 2.1

16、799? ?1按齒根彎曲疲勞強(qiáng)度設(shè)計(jì):1）由式（10-20）試算齒模數(shù)，即QO?3 2?”“？ ？”?”？/? ? I ? ?考?(?a.確定公式中的各參數(shù)值。V= 1.339m/sb = 36.014? = 1?1=1.899 X103?1/?=52.736?/ ? = 1.4i.試選載荷系數(shù)? = 1.3。ii.由式（10-18）,可得計(jì)算彎曲疲勞強(qiáng)度的重合系數(shù)？?。?= 2.1646?= arctan(?) = arctan(tan14 cos20.562 ) = 13.140? = ?/?2? = 1.611/?213.140O = 1.699?= 0.25+ 0.75/?= 025+

17、 0.75/1.699= 0.691iii.由式(10-19 )可得計(jì)算彎曲疲勞強(qiáng)度的螺旋角系數(shù)？?。?1 = 42.686?iv.計(jì)算?99 = 1 - ?99 = 1 - 1 5084- = 0 824 ,?1' ?1200120。由當(dāng)量齒數(shù)？?1=?1/?3?= 19/ ?3140 = 20.799?2= ?2/ ?3? = 76/?3140 = 83.196? = 2.1799?查圖 10-17 ,得齒形系數(shù)？?1= 2.78,?2= 223由圖10-18查得應(yīng)力修正系數(shù)？?1 = 1.55,?2= 1.77由圖10-24c查得小齒輪和大齒輪的齒根彎曲疲勞極限分別為?1 = 5

18、00Mpa,?2= 380Mpa由圖 10-22 查得彎曲疲勞系數(shù)？?1 = 0.84、？?2= 0.90,取彎曲疲勞安全系數(shù)S = 1.4由式（10-14）得?1?1?10.855 X500?14?= 303.57?2?2 ?2 = ?1?1? 1?2?2?20.88 X380 ? = 244.28?1.42.78 X1.55 =0.01419 303.572.23 X1.77 =0.01615 244.28? = 1.3? = 13.140°因?yàn)榇簖X輪的?大于小齒輪,所以? =0.691b.試算齒輪模數(shù)99 ? ?2?2?2=0.016153 2?”？?“？”？2?尸,? 1 ?

19、 ?1?(?=?1 =0.82420.799X1.3 X3.42 X104 X 0.691 X0.824 X?/14°1 X192X 0.01615?= 1.287?97=?2 = oo?183.196 =2.782）調(diào)整齒輪模數(shù)a.計(jì)算實(shí)際載荷系數(shù)前的數(shù)據(jù)準(zhǔn)備。i.圓周速度V?1二?1 =? ?1?1 60 X1000 =1.28719X?14°?= 25204? X 25.204 X710?/ ? = 0.9369?/?60 X1000?2 = 2.23 ?1 = 1.55, ?2 = 1.77 99?1 =500Mpa 99 ?2=380Mpaii .尺寬bb = ?

20、1 = 1 x 25204 mm = 25.204mmiii .齒晨j h及寬圖比b /hh = (2?+ ?)?= (2 X1 + 0.25) X 1.287 = 2.895? b/h = 25204/ 2.895 = 8.7037b.計(jì)算實(shí)際載荷系數(shù)22?。i .根據(jù)V=0.9639m/s,8級精度，由圖10-8查得動載系數(shù)？?？ = 1.02ii . ?1 = 2?1/?1?= 2 X3.42 X104/25.204N = 2.713 X 103?,?1/?= 1 X2.713 X103/25.204?/?= 107.67?/?> 100?/?,查表 10-3 得齒間載荷 分酉己系

21、數(shù)？?？= 1.4。iii .由表 10-4 用插值法得？?？= 1.445，結(jié)合b/h = 8.7037 ,查圖 10-13 ,得？?？ = 1.31。則載荷系數(shù)為? = ? = 1 X 1.02 X 1.4 X 1.31 = 1.871c.由式(10-13),可得按實(shí)際載荷系數(shù)算得的齒輪模數(shù)& ?r3 1.9257? = ?3rr- = 1.287 x，？? = 1.453mm? ?1.3對比計(jì)算結(jié)果，由齒面接觸疲勞強(qiáng)度計(jì)算的法面模數(shù)？?大于齒根彎曲疲勞強(qiáng)度 計(jì)算的法面模數(shù)。從滿足彎曲疲勞強(qiáng)度出發(fā)，從標(biāo)準(zhǔn)中就近取 ?= 1.5?, 為了同時(shí)滿足接觸疲勞強(qiáng)度，需按接觸疲勞強(qiáng)度算得的分

22、度圓宜徑？?1 =42.686?來計(jì)算小齒輪的齒數(shù)，即？?1 = ?1?/?= 42.686 X ?14° 1.5= 27.6。??？?1 = 28,貝U?2 = ?1 = 3.97 X28= 111.16,??？?2 = 111 , ?1 與？?2互為質(zhì) 數(shù)。?1=303.57?2=244.28? ?=0.01615? = 1.287?1 = 25.204?幾何尺寸計(jì)算1）計(jì)算中心矩V = 0.9369?/?b = 25.204mmh = 2.895?b/h = 8.7037arccos(?1 + ?2)?27?arccos(28+ 111) X1.52 X108=15.142

23、6;?1 ?(28 + 111) X1.5?= 1_?_= 2?= 107 44?2?2 X ?14將中心矩圓整為108mm2）按圓整后的中心矩修正螺旋角? = 1.02?=1?2 =4）計(jì)算齒輪寬度?1?2?28 X 1.5?15.142。?= 43.511?111 X1.5 ?= 172.488? ?15142b = ?1 = 1 X 43.511?= 43.511?1=2.713 X102 3?1/ ?=107.67?/? = 1.4453）計(jì)算小、大齒輪的分度圓直徑?= 1.871??？?1 = 50?、?2 = 44?。主要設(shè)計(jì)結(jié)論? = 1.453mm? = 1.5?1 = 28齒數(shù)

24、？1= 28,?2 = 111，模數(shù)m = 1.5?,壓力角 a= 20°,螺旋角 0= 15.142°, 變位系數(shù)？?1= ?2 = 0,中心矩a = 108?,齒寬？?1 = 50?、?2 = 44?。小齒輪 選用40?（調(diào)質(zhì)），大齒輪選用45鋼（調(diào)質(zhì)）。按8級精度設(shè)計(jì)。系數(shù)？?？= 1,頂隙系數(shù)？?？= 0.25。2）運(yùn)輸機(jī)為一般工作機(jī)器，運(yùn)動轉(zhuǎn)速不高，查表16.1選用8級精度。3）由表10-1，小齒輪選用40cr （調(diào)質(zhì)），齒面硬度280HBs大齒輪選用45鋼（調(diào)質(zhì)），齒面硬度240HBS4）初選小齒輪齒數(shù)？?1 = 24,大齒輪？?2 = ?2?1 = 2.84

25、X24 = 68.16,?。?2 = 69,?1與？?2互質(zhì)。5）初選螺旋角B= 14°按齒面接觸疲勞強(qiáng)度設(shè)計(jì):1）由式（10-24）試算小齒輪分度圓直徑:?99?3 2?2 /上 ? ,(?.?)2c.確定公式中的各參數(shù)值:i .試選載荷系數(shù)？?？ = 1.3ii.由圖10-20差得區(qū)域系數(shù)？?？= 2.433,表10-5查得材料彈性影響系數(shù)?=1189.6?2,表 10-7 ??？= 1。iii.由式10-21計(jì)算接觸疲勞強(qiáng)度重合系數(shù)？?。? = arctan(?/? = arctan(?20° ?14 ?1 = arccos?1?/( ?1 + 2?=arccos24

26、Xcos20.562° -4 + 2X1 Xcos14° )=?2 = arccos?2?/( ?2 + 2?=arccos69 Xcos20.562° &9 + 2X1 Xcos14° )=20.56229.974024.4000?2 = 111a= 107.44?B= 15.142°?1 = 43.511?2 = 172.488?b = 43.511?1 = 50?2 = 44?= ?1 (?1 - ?) + ?2(?2- ?) / 2? =24(?29.974 - ?20.562 ) + 69(?24.400 °-?20

27、.5620 )2?= 1.632?= ?1?= 1 X24 Xtan14° ? = 1.905= ?=4 - ?(1- ?) +?4 - 1.632?"?1.905X(1 - 1.905) + 1632= 0.673iv.由式（10-23 ）可得螺旋角系數(shù)?=儲？= 儲？14 = 0.985v.計(jì)算接觸疲勞需用應(yīng)力?由圖10-25查得小齒輪和大齒輪的接觸疲勞極限分別為?1 = 600Mpa, ?2 = 550Mpa（10-15）計(jì)算應(yīng)力循環(huán)次數(shù):?1 = 60?2? = 60 X 178.84 X1 X(2 X8 X300 X 5) = 2.57 X108 ?2 =焉=2.

28、57 X 108/( 69/ 24) = 8.939 X107由圖10-23查取接觸疲勞壽命系數(shù)？?1 = 0.93、?2 = 0.95,取失效概率為1%、?1 = 24?2 = 69安全系數(shù)S = 1,由式（10-14）得:? 1?1 ?10.93 X 600 =? = 558?0= 14°?2 =?1?2?20.95 X550?= 522.2?取?1和?2中的較小者為該齒輪的接觸疲勞強(qiáng)度許用應(yīng)力，即?=?2 = 522.2?d.試算小齒輪分度圓直徑:99 ?1?3 2?2 /? + 1 ? ,(?.?3 /2X1.3 X1052.84+1V X2.84、/ / 2.433X189

29、.8X0.673X0.985、2x(51) mm=53.95mm? = 1.3?= 2.4331?= 189.6?2）調(diào)整小齒輪分度圓直徑? ? = 1? = 20.5620a.計(jì)算實(shí)際載荷系數(shù)前的數(shù)據(jù)準(zhǔn)備:i.圓周速度V?1 = 29.974 0ii.齒寬b?1?2=60 X1000? X 53.95 X 178.8460 X 1000m/s = 0.505m/s?2 = 24.400?= 1.632b = ?1? = 1 X 53.95?= 53.95?b.計(jì)算實(shí)載荷系數(shù)?i.由表10-2查得使用系數(shù)？?？ = 1ii .根據(jù)V = 0.505m/s, 8級精度，由圖10-8查得動載系數(shù)？

30、?？ = 1.03。iii .齒輪的圓周力？?1 = 2?2/?1? = 2 X1.3 X105/53.95N = 4819277?,?1/?= 1 X4819.277/53.95?/?= 89.33?/? < 100?/?,查表 10-3 得齒間載荷分酉己系數(shù)？?？= 1.4。iv.由表10-4用插值法查得8級精度、小齒輪相對支承非對稱布置時(shí)，？?？= 1.4545則載荷系數(shù)為? = ? = 1 X1.03 X 1.4 X1.4545 = 2.0973)由式(10-12),可得按實(shí)際載荷系數(shù)算得的分度圓直徑?1 = ?1?3?= 53.95 XV20|7?= 63.2717? ：?1.

31、3及相應(yīng)的齒輪模數(shù)?= ?1?= 63.2717 x?14° 24?= 2.558? ?1按齒根彎曲疲勞強(qiáng)度設(shè)計(jì)：?= 1.905?= 0.673?= 0.985?1=600Mpa?2=550Mpa?1 = 2.57 X108?2 = 8.939 X107?1 = 0.93?2 = 0.953）由式（10-20）試算齒模數(shù)，即3 2?”？。?»?”？2?”“？”“?1 = 558? ?2?1'(?b.確定公式中的各參數(shù)值。i .試選載荷系數(shù)？?？ = 1.3?2=522.2?ii.由式（10-18）,可得計(jì)算彎曲疲勞強(qiáng)度的重合系數(shù)？?=522.2?= arctan

32、(?) = arctan(tan14 cos20.562 °) = 13.140? = ?/?2? = 1.632/ ?213.140O = 1.733?= 0.25+ 0.75/ ?= 025+ 0.75/1.733= 0.682iii .由式（10-19）可得計(jì)算彎曲疲勞強(qiáng)度的螺旋角系數(shù)?14°?= 1- ?蘇=1 - 1.905 = 0.778.、r y?iv .計(jì)算-7?r-。由當(dāng)量齒數(shù)?1 = ?1/?3? = 24/ ?3140 = 26.27?2 = ?2/ ?3? = 69/?3140 = 75.533查圖10-17,得齒形系數(shù)？?1= 2.62,?2= 2

33、23?1? = 53.95mm由圖10-18查得應(yīng)力修正系數(shù)?i = 1.6, ?2 = 1.77由圖10-24C查得小齒輪和大齒輪的齒根彎曲疲勞極限分別為?1 = 500Mpa, ?2= 380Mpa由圖 10-22 查得彎曲疲勞系數(shù)？?1 = 0.91、?2 = 0.98,取彎曲疲勞安全系數(shù)S=1.4由式(10-14 )得?1?1?1?0.91 X500 ? = 325?1.4V= 0.505m/s?2 =?2?2?1?1?1=?2?2?2因?yàn)榇簖X輪的？?曹?；?大于小齒輪,?:0.98 X380=? = 266?1.42.62 X1.6 =0.0128983252.23 X1.77 =0

34、.014419266所以?2?2_ _一= 0.014419? 2b.試算齒輪模數(shù)99 ?3 2?oooo?o?oo?oo?2? 尸,? 2? ,?1?,(?)b = 53.95? = 1? = 1.03?1 = 4819.277?1?=89.33?/ ? = 1.4?= 1.4545?= 2.097X1.3 X1.3 X105 X0.682 X0.778 x?2141 X242°X 0.014419?= 1.6168?4）調(diào)整齒輪模數(shù)?1 = 63.2717?d.計(jì)算實(shí)際載荷系數(shù)前的數(shù)據(jù)準(zhǔn)備。i.圓周速度V?1?1?1 = 1.6168 X ?24?u ? = 39992?V =

35、?1?1 _ ? X 39.992 X 178.84?/ ? = 0 37448?/ ?60 X 100060 X1000ii.尺寬bb = ?1 = 1 x 39.992 mm = 39.992mmiii.齒高h(yuǎn)及寬高比b / hh = (2?+ ?)?= (2 X1 + 0.25) X 1.6168 = 3.6378?b/h = 39.992/ 3.6378 = 10.993e.計(jì)算實(shí)際載荷系數(shù)？?。i.根據(jù)V=0.9639m/s,8級精度，由圖10-8查得動載系數(shù)？?？ = 1.00ii. ?1 = 2?2/?1?= 2 X1.3 X105/ 39.992N = 6.5013 X 103

36、?,?/?=1 X6.5013 X 103/39.992?/?= 162.565?/?> 100?/?,查表 10-3 得齒間載荷分配系數(shù)？?？= 1.4。iii.由表 10-4 用插表法得?= 1.450，結(jié)合b/h = 10.993,查圖 10-13 ,得？?？ =1.36。則載荷系數(shù)為? = ? = 1 X 1 X 1.4 X 1.36 = 1.904f.由式（10-13 ）,可得按實(shí)際載荷系數(shù)算得的齒輪模數(shù)3 ?r3 1.904? = ?3/ = 1.6168 x V- ? = 1.8361mm?1 .3對比計(jì)算結(jié)果，由齒面接觸疲勞強(qiáng)度計(jì)算的法面模數(shù)？?大于齒根彎曲疲勞強(qiáng)度計(jì)算的

37、法面模數(shù)。從滿足彎曲疲勞強(qiáng)度出發(fā)，從標(biāo)準(zhǔn)中就近取? = 2?,為了同時(shí)滿足接觸疲勞強(qiáng)度，需按接觸疲勞強(qiáng)度算得的分度圓直徑？?163.2717?來計(jì)算小齒輪的齒數(shù)，即 ?1 = ?1 ?/ ? = 63.2717 乂?14° 2= 30.696o?= 2.558? = 1.3? = 13.140°? = 1.733?= 0.682?= 0.778?1 = 26.27?2 = 75.533?1 = 2.62?2 = 2.23?1 = 1.6?2 = 1.7799?1=500Mpa?2=380Mpa?1 = 0.91 ?2 = 0.98取？?1 = 31 ,則？?2 = ?1 =

38、 2.84 X31 = 88.04，?。?2 = 88, ?1 與？?2互為質(zhì)數(shù)。?1 = 325?幾何尺寸計(jì)算1）計(jì)算中心矩?2 = 266?1?1?1”?1?=12?(31 + 88) X2:?=2 X?14122.643?=0.012898?2?2將中心矩圓整為122mm?22）按圓整后的中心矩修正螺旋角=0.014419?arccos(?1 + ?2)?2?(31+ 88)arccos -2 X122X20=12.732=0.0144193）計(jì)算小、大齒輪的分度圓直徑?1?2 =?1 ?2?'31 X 2；?= 63.562? ?12.73288 X2？= 180.436?12

39、.7324）計(jì)算齒輪寬度b = ?11 X 63.562?= 63.562???？?1 = 70?、?2 = 64?。主要設(shè)計(jì)結(jié)論齒數(shù)？1 = 31,?2 = 88,模數(shù)m = 2?,壓力角 a= 20°,螺旋角 0= 12.732°,變位系數(shù)？?1 = ?2 = 0,中心矩a = 122 ?, ?1 = 70?、?2 = 64?。小齒輪選用40?（調(diào)質(zhì)）,大齒輪選用45鋼（調(diào)質(zhì)）。按8級精度設(shè)計(jì)。高速級低速級齒數(shù)z281113188中心距a108122法面模數(shù)mn1.52.0齒輪的主要參數(shù)? = 1.6168?1 = 39.992?V= 0.37448?/ ?螺旋角15.1

40、42°12.732°b = 39.992mmh = 3.6378?b/h = 10.993? = 1.00 ?1 = 2?2/?1? =6.5013 X103N ?i/? =162.565?/? ? = 1.450 ? = 1.36 ?= 1.904?= 1.8361mm?= 2?1 = 30.696?1 = 31?2 = 88.04?2 = 88a= 122?法面壓力角n200200b50447064分度圓直徑d43.511172.48863.562180.436齒頂圓直徑da46.511175.48867.562184.436齒根圓直徑df39.761168.73858

41、.562175.436三、軸的設(shè)計(jì)3.1高速軸(1)材料選擇查表15-1 ,選用45鋼(調(diào)質(zhì))(2)確定最小直徑？?？3 ?1?0 V-?1查表 15-3 , ?0 = 112,由上面結(jié)論?1 = 2.544?,?1 = 710r/min,3 2.544? >112 X AA710-? = 17.138?考慮該軸有一鍵槽，將計(jì)算結(jié)果加5%, ?= 17.138 X(1 + 5%? = 17.65?(3)選擇聯(lián)軸器根據(jù)傳動裝置的工作條件擬選用LH型彈性柱銷聯(lián)軸器。聯(lián)軸器的計(jì)算轉(zhuǎn)矩為? = ?,查表 14-1 取？?？ = 1.5 ,由？?？ = 3.46 X104?.?,得?=1.5 X3.46 X104?. ?= 5.19 X104?.? 根