高考物理模擬力學(xué)計算題(四十一)

1、RBB5mAmFBBF（gBBFmhABABgAL2m5mBABmBABd1mgAAAABCDEABCEADEDERBACRAgBAAAn+1mFnn+1nn+11+2+3+n+2+3+nmABhBlABgBABAhAABnLABRBCDEFBFEFmAABBEEFABBABRABCmRRgABCmABAAAhABhBABABgABAB）從BABRBCBCABRBBCAgBmababbLbb2m/sgRLAmBAAABBEgBBDEL2m/sABmABg10m/ABABBRmABBFBChhRABBmBhBBBBCg5m/sBLmAmBAmRABLABmgABBAAFBnnnmmFLAAABA

2、BmABgAABFFABABLABFg）。AmAAIm6m/smm3mmgmFgFdhgml2mEBmAABgABABBBBmglRB2mBAooBmbbgbobbLL8m3m2m/sm3m/sgRmTgLRgLABBAmBRmAABABgmLmqqbbEbgABLAB1m/sm2m/s1m/sBAL4mLgRmFABFAB5m（gBFABCABBCRmFABFgBBF參考答案與試題解析RBB5mAmFBBF（gBBFB解：（CmgmC2m/sBBm/sFFFABABmgF答：（BB2m/sFmhABABgAL解：（hgtlAB3m/sm+M4m/smgsm+M6mmgsL+s答：（3m/sL

3、2m5mBABmBABd1mgAAAAA解：（AmgrFmgFAAB2m+M+2mgLdM+2m+2mgAphmgr+h2m+M+2mg2Lhm答：（AAAmABABCDEABCEADEDERBACRAgBAAABABBDEBACDE解：（BBAmAARBAAAAABAEAEDEeqoac(,E)DEABCDEAAEABAEACDEEAEEE答：（BAAAn+1mFnn+1nn+11+2+3+n+2+3+nnn+1解：（FmaF+ann+1F+s+s+eqoac(,E)eqoac(,E)答：（nn+1mABhBlABgBABAhAABnBBABBBABAnBBMghBABAABm+MABBBh

4、MghABEM+mM+mEBBMghm/s2m/sBAmsBAABm+Mm/sBm1mBAm+Mm/sm/sBAnm/sm/sm/sn答：（BAABnm/sLABRBCDEFBFEFmAABBEEFABBABBEEABBBAEBCDEFBEEEFFFBCDEFBFEFEEFBmgsmgsABBBmgsmgsABBBmgsmgsmgsmgsABBBmgsmgsmgsmgsABBBmgsmgsmgsmgsABBBmgsmgsmgsmgsABBAB+s）（）（）（）（答：（BEABBABRABCmRRgABCE解：（EEF3mgRE答：（3mgmABAAAhABhBABABgABAB）從BABBBA

5、ABBABB解：（BAhh+Beqoac(,E)mgheqoac(,E)mgheqoac(,E)mgheqoac(,E)eqoac(,E)eqoac(,+)EmghABAB）從BABRBCBCABRBBCAgBmABBm解：（mmmg+mmBmababbLbb2m/sgbb解：（RmbFbbFmgmF3mgFmbm+Mbm+MRLAmBAAABBEgBBDELABBBBB解：（ABBAA+mvBB4m/sBFmgmFBFFBBAAAA2mBBmgsBBB8m2LABL5mB4m/sBDELL5m2m/sABmABg10m/ABB解：（mgmag2m/sm1m+t1m2mmg答：（2m/sABA

6、BBRmABBFBChhRABBFA解：（ABBFmgmF3mgAmghmgRh答：（BBF3mgmgRh）。ABBmBhBBBBCg5m/sB）從ABBB5m/s5m/s5m/s解：（ABmghB7m/sBBCCC5m/sBmg5m/sh5m/smghmgshh5m/smgh+mgshBh答：（BhLmAmBAA解：（ABmm+mAB2LABAB9L答：（9Lm解：（M+mRABLABmgABBAAFBnnnBAAAAnnBeqoac(,E)fLeqoac(,E)BBeqoac(,E)ABAAAAABAA+mvBAA+BAAABAAF+mgmAFBnEneqoac(,E)ABBnBneqoa

7、c(,E)m/sn）；AAFBnnnm/sn）。mmFL解：（mm+FkmgFkmgLL答：（FkmgLAAABABmABgAABFFABABLABFABABBF解：（ABFM+mFM+mgtanABFm+MLABFABABFM+mM+mBmmgFABM+mgtanF答：（ABM+mgtanABFM+mgtanFg）。F解：（hFmgt+tFmmmmmm+mm答：（AmAAIAAM+mIM+mM+mIAIm6m/s解：（+Mm/sm+Mm/s答：（mm+meqoac(,P)eqoac(,P)eqoac(,+)eqoac(,|)eqoac(,|)3mmg解：（3mgtgt3mgsm+mvIImI

8、mgt答：（gtmgtmFgFFF解：（+mgmaFmgma2m/s答：（Fmgdhggt解：（gt5m/sdd+rdd+r4m/s4m/s答：（5m/s4m/sml2mEBmAABgABABBBBABBB解：（mAmA+mB4m/sBABmA+mBmA+mB+mCABn1+n答：（AB4m/sABBBBmgl解：（mamg2m/s6m/sTT答：（l2m/sRB2mBAooBmbbgbobbabbbbbbab解：（B2mgabb+mvb+bbbmgmbbBbbbabb答：（bbbLL8m3m2m/s解：（+s答：（m3m/sg解：（mgmgmag答：（RmTg解：（eqoac(,2)Emgheqoac(,E)p答：（LRgLLL，（L2mm/smg+FmFE+mgE答：（L2mABBABC解：（eqoac(,t)2+5+1答：（1mmBRmAABABgAABBBBBA解：（AA5m/sBIBB1m/sAIM+m+m1m/s+QBmB1m/sm1m/smA3mL3m答：（3mmLmqqbbEbgab解：（bFmgbFmgmagmgmagL2Lbbmgmag+a+a+L答：（）物塊從置于絕緣板到第二次與擋板碰撞過程中，電場力所做的功是ABLAB1m/sm2m/s1m/sBAL4mLgB解：（L