高考物理一輪復習專題4.5 衛(wèi)星與航天(精練)(解析版)

4.5專題衛(wèi)星與航天年1一()ABC＝a2D7()圖4AA＝MrT3＜rrB錯T同步＝vr3CD12九()13TTrrAT2九地九地22m＝rvvBr九地2332＝ωωCk和＝2T2九地1116D項3kn()32T3k2kn．．TT．kTBm）2G）2)G2T2T223kn3＝3kBr2B()R2Rg2rRr1由ABg1由AB12D22′＝＝＝＝′mgaFGaG2合21rtR2Rg23G2rr＝A＝＝＝＝tB正T2mTrT1ABC111，DmTGRgRT2πR322Rπ22D2MAR2Gm2rGMT2gRT2r33r2T222gRT22GMr2hrRRBv3r2r2Cr2R2R2agr2DA）22r3mrTG，r2TGMT比rMM=()1＝A比3太比TTTr太比太太12aMrGr2r2=()aBFG，比比Mr太2a太r2太比2Fr2v2r=m比CGF5太1GMm1Emv2故D22r5KL2L2L2是BL2AarBvrCD”一”htRTG2RTh22hT2R232t222RthD2hR2hgRGAmvt2R2t22hR2hMMBVR222(Rh)hT2R2GmChR3(Rh)2T22t22r3Mm2mr2GTr2TGM2RR32Rt，則周期最小T，知周期不小于tDRminGMhh年1月3IP）PPPPPCIPACBPD．()為3(2)h22＝m2rT（＋）Rh2CD＝，AvgB()ββαα33333333ααββARRr23R＝rG2＝2＝，mrTrTT3β＝3.′和ABO和(1)ABmd2m＋1Ad2mm1ABmm12Om32ABO＝(mm)212Dmm12＝2＝2mrmrrG2d11221mdmdvrm2＋mm1＋mm11vrm2＋＝＝rd，＝A＝＝BrrvO2121212221CAmm11Gm32受＝r2，BOmG2md(mm)1212故D、、abc星和和，raabMbc(G)bhBb和caa和b＝－3C3＝Ca2AbD星ω2得ω＝aab2r3bbb和ω＝Cbtttb－3var111var2）22aaarvarvvr=vr22121112221122a＝MG，1r21a＝v2＜＞Arraama＝m1r2r21212需21v2a＝a＞aa需1r＜arvB11111需11v22ma＝m需r2v2a＝a2＜2r＞C，arva2222需需22GMmv2GMmv22mmvrvr=11D122r2r221（、、、、<<，aaavvvRRR金地火金地火金地火）aa>aa>a>av>vvv>vv金地火火地金地火金火地金AGR2Av2BGmv得DR2RR（年5月）DABCD（2019·年月8MRmrG）4rGMmr3GMR223C2RGM2v2r3mrmrmT，2r2T2rGM1rB錯誤；解得故AvE2C22rr3kaD。r24.(2018·PQ4P與Q()1111C222＝23PP＝＝r3.G22T3rT2QQ∶∶rrTTPQPQ5月9軌高())A<rr五222＝2m＝.Tr3＝＝＝∝rT<T3五13∝3ωωr五1∝v>v五rr1＝2∝aaArr五6.(2018··)s()m1