2023年中考數(shù)學(xué)真題分項(xiàng)匯編專題01 實(shí)數(shù)的有關(guān)概念與計(jì)算（解析版）

專題01實(shí)數(shù)的有關(guān)概念與計(jì)算（53題）一、單選題1．（2023·四川達(dá)州·統(tǒng)考中考真題）SKIPIF1<0的倒數(shù)是（

）A．SKIPIF1<0 B．2023 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【分析】根據(jù)相乘等于1的兩個(gè)數(shù)互為倒數(shù)，即可求解．【詳解】解：SKIPIF1<0的倒數(shù)是SKIPIF1<0，故選：C．【點(diǎn)睛】本題考查了倒數(shù)，掌握倒數(shù)的定義是解題的關(guān)鍵．2．（2023·重慶·統(tǒng)考中考真題）8的相反數(shù)是（

）A．SKIPIF1<0 B．8 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)只有符號(hào)不同的兩個(gè)數(shù)互為相反數(shù)進(jìn)行解答即可得．【詳解】解：8的相反數(shù)是SKIPIF1<0，故選：A．【點(diǎn)睛】本題考查了相反數(shù)的定義，掌握相反數(shù)的定義是解題的關(guān)鍵．3．（2023·四川瀘州·統(tǒng)考中考真題）下列各數(shù)中，最大的是（）A．SKIPIF1<0 B．0 C．2 D．SKIPIF1<0【答案】C【分析】首先化簡(jiǎn)絕對(duì)值，然后把選項(xiàng)中的4個(gè)數(shù)按從小到大排列，即可得出最大的數(shù)．【詳解】∵SKIPIF1<0，∴SKIPIF1<0，∴最大的數(shù)是2．故選：C．【點(diǎn)睛】本題考查了有理數(shù)的大小比較，一般地，正數(shù)大于零，零大于負(fù)數(shù)，兩個(gè)負(fù)數(shù)，絕對(duì)值大的反而小．4．（2023·四川南充·統(tǒng)考中考真題）如果向東走10m記作SKIPIF1<0，那么向西走SKIPIF1<0記作（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【分析】根據(jù)具有相反意義的量即可得．【詳解】解：因?yàn)橄驏|與向西是一對(duì)具有相反意義的量，所以如果向東走10m記作SKIPIF1<0，那么向西走SKIPIF1<0記作SKIPIF1<0，故選：C．【點(diǎn)睛】本題考查了具有相反意義的量，熟練掌握具有相反意義的量是解題關(guān)鍵．5．（2023·四川宜賓·統(tǒng)考中考真題）2的相反數(shù)是（

）A．2 B．－2 C．SKIPIF1<0 D．SKIPIF1<0【答案】B【詳解】2的相反數(shù)是-2.故選：B.6．（2023·浙江·統(tǒng)考中考真題）﹣3的相反數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】D【分析】相反數(shù)的定義是：如果兩個(gè)數(shù)只有符號(hào)不同，我們稱其中一個(gè)數(shù)為另一個(gè)數(shù)的相反數(shù)，特別地，0的相反數(shù)還是0．【詳解】根據(jù)相反數(shù)的定義可得：－3的相反數(shù)是3，故選：D．【點(diǎn)睛】本題考查相反數(shù)，題目簡(jiǎn)單，熟記定義是關(guān)鍵．7．（2023·安徽·統(tǒng)考中考真題）SKIPIF1<0的相反數(shù)是（

）A．5 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)相反數(shù)的定義即可求解．【詳解】解：SKIPIF1<0的相反數(shù)是5，故選：A．【點(diǎn)睛】此題主要考查相反數(shù)，解題的關(guān)鍵是熟知相反數(shù)的定義．8．（2023·浙江嘉興·統(tǒng)考中考真題）﹣8的立方根是（）A．±2 B．2 C．﹣2 D．不存在【答案】C【分析】根據(jù)立方根的定義進(jìn)行解答．【詳解】∵（﹣2）3=﹣8，∴﹣8的立方根是﹣2，故選：C．【點(diǎn)睛】本題主要考查了立方根，解決本題的關(guān)鍵是數(shù)積立方根的定義．9．（2023·浙江金華·統(tǒng)考中考真題）某一天，哈爾濱、北京、杭州、金華四個(gè)城市的最低氣溫分別是SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，其中最低氣溫是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)有理數(shù)的大小比較，即可作出判斷．【詳解】解：SKIPIF1<0，故溫度最低的城市是哈爾濱，故選：A．【點(diǎn)睛】本題考查了有理數(shù)的大小比較的知識(shí)，解答本題的關(guān)鍵是掌握有理數(shù)的大小比較法則．10．（2023·四川遂寧·統(tǒng)考中考真題）已知算式SKIPIF1<0□SKIPIF1<0的值為SKIPIF1<0，則“□”內(nèi)應(yīng)填入的運(yùn)算符號(hào)為（

）A．＋ B．－ C．× D．÷【答案】A【分析】根據(jù)相反數(shù)相加為0判斷即可．【詳解】解：∵SKIPIF1<0，∴“□”內(nèi)應(yīng)填入的運(yùn)算符號(hào)為＋，故選：A．【點(diǎn)睛】題目主要考查有理數(shù)的加法運(yùn)算，熟練掌握運(yùn)算法則是解題關(guān)鍵．11．（2023·江蘇連云港·統(tǒng)考中考真題）實(shí)數(shù)SKIPIF1<0的相反數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．6【答案】D【分析】根據(jù)相反數(shù)的意義，相反數(shù)是只有符號(hào)不同的兩個(gè)數(shù)，改變SKIPIF1<0前面的符號(hào)，即可得SKIPIF1<0的相反數(shù)．【詳解】解：SKIPIF1<0的相反數(shù)是6．故選：D．【點(diǎn)睛】本題考查了相反數(shù)．解題的關(guān)鍵是掌握相反數(shù)的意義，一個(gè)數(shù)的相反數(shù)就是在這個(gè)數(shù)前面添上“?”號(hào)；一個(gè)正數(shù)的相反數(shù)是負(fù)數(shù)，一個(gè)負(fù)數(shù)的相反數(shù)是正數(shù)，0的相反數(shù)是0．12．（2023年安徽省滁州市南片五校中考二模數(shù)學(xué)試卷）SKIPIF1<0的倒數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】B【分析】根據(jù)倒數(shù)的概念，乘積為SKIPIF1<0的兩個(gè)數(shù)互為倒數(shù)，由此即可求解．【詳解】解：SKIPIF1<0的倒數(shù)是SKIPIF1<0，故選：SKIPIF1<0．【點(diǎn)睛】本題主要考查求一個(gè)數(shù)的倒數(shù)，掌握倒數(shù)的概念是解題的關(guān)鍵．13．（2023·浙江寧波·統(tǒng)考中考真題）在SKIPIF1<0這四個(gè)數(shù)中，最小的數(shù)是(

)A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．SKIPIF1<0【答案】A【分析】根據(jù)負(fù)數(shù)小于0小于正數(shù)，負(fù)數(shù)的絕對(duì)值大的反而小，進(jìn)行判斷即可．【詳解】解：∵SKIPIF1<0，∴SKIPIF1<0，∴最小的數(shù)是SKIPIF1<0；故選：A．【點(diǎn)睛】本題考查比較實(shí)數(shù)的大?。炀氄莆肇?fù)數(shù)小于0小于正數(shù)，負(fù)數(shù)的絕對(duì)值大的反而小，是解題的關(guān)鍵．14．（2023·江西·統(tǒng)考中考真題）下列各數(shù)中，正整數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)有理數(shù)的分類即可求解．【詳解】解：SKIPIF1<0是正整數(shù)，SKIPIF1<0是小數(shù)，不是整數(shù)，SKIPIF1<0不是正數(shù)，SKIPIF1<0不是正數(shù)，故選：A．【點(diǎn)睛】本題考查了有理數(shù)的分類，熟練掌握有理數(shù)的分類是解題的關(guān)鍵．15．（2023·新疆·統(tǒng)考中考真題）﹣5的絕對(duì)值是（）A．5 B．﹣5 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)負(fù)數(shù)的絕對(duì)值等于它的相反數(shù)可得答案．【詳解】解：|﹣5|=5．故選：A．16．（2023·甘肅武威·統(tǒng)考中考真題）9的算術(shù)平方根是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．3 D．SKIPIF1<0【答案】C【分析】由SKIPIF1<0，可得9的算術(shù)平方根．【詳解】解：9的算術(shù)平方根是3，故選：C.【點(diǎn)睛】本題考查的是算術(shù)平方根的含義，熟練的求解一個(gè)數(shù)的算術(shù)平方根是解本題的關(guān)鍵．17．（2023·浙江溫州·統(tǒng)考中考真題）如圖，比數(shù)軸上點(diǎn)A表示的數(shù)大3的數(shù)是（

）

A．SKIPIF1<0 B．0 C．1 D．2【答案】D【分析】根據(jù)數(shù)軸及有理數(shù)的加法可進(jìn)行求解．【詳解】解：由數(shù)軸可知點(diǎn)A表示的數(shù)是SKIPIF1<0，所以比SKIPIF1<0大3的數(shù)是SKIPIF1<0；故選：D．【點(diǎn)睛】本題主要考查數(shù)軸及有理數(shù)的加法，熟練掌握數(shù)軸上有理數(shù)的表示及有理數(shù)的加法是解題的關(guān)鍵．18．（2023·四川自貢·統(tǒng)考中考真題）如圖，數(shù)軸上點(diǎn)A表示的數(shù)是2023，SKIPIF1<0，則點(diǎn)B表示的數(shù)是（

）A．2023 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】B【分析】根據(jù)數(shù)軸的定義求解即可．【詳解】解；∵數(shù)軸上點(diǎn)A表示的數(shù)是2023，SKIPIF1<0，∴SKIPIF1<0，∴點(diǎn)B表示的數(shù)是SKIPIF1<0，故選：B．【點(diǎn)睛】本題考查數(shù)軸上點(diǎn)表示有理數(shù)，熟練掌握數(shù)軸上點(diǎn)的特征是解題的關(guān)鍵．19．（2023·浙江紹興·統(tǒng)考中考真題）計(jì)算SKIPIF1<0的結(jié)果是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．3【答案】A【分析】根據(jù)有理數(shù)的減法法則進(jìn)行計(jì)算即可．【詳解】解：SKIPIF1<0，故選：A．【點(diǎn)睛】本題主要考查了有理數(shù)的減法，解題的關(guān)鍵是掌握有理數(shù)的減法計(jì)算法則．減去一個(gè)數(shù)等于加上它的相反數(shù)．20．（2023·江蘇揚(yáng)州·統(tǒng)考中考真題）已知SKIPIF1<0，則a、b、c的大小關(guān)系是(

)A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【分析】由SKIPIF1<0，SKIPIF1<0，進(jìn)行判斷即可．【詳解】解：∵SKIPIF1<0，SKIPIF1<0，∴SKIPIF1<0，故選：C．【點(diǎn)睛】本題考查了實(shí)數(shù)的大小比較，算術(shù)平方根．解題的關(guān)鍵在于對(duì)知識(shí)的熟練掌握．21．（2023·江蘇揚(yáng)州·統(tǒng)考中考真題）SKIPIF1<0的絕對(duì)值是（

）A．3 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)絕對(duì)值的概念，可得SKIPIF1<0的絕對(duì)值就是數(shù)軸上表示SKIPIF1<0的點(diǎn)與原點(diǎn)的距離．進(jìn)而得到答案．【詳解】解：SKIPIF1<0的絕對(duì)值是3，故選：A．【點(diǎn)睛】本題考查絕對(duì)值的定義，正確理解絕對(duì)值的定義是解題的關(guān)鍵．22．（2023·重慶·統(tǒng)考中考真題）4的相反數(shù)是（）A．SKIPIF1<0 B．SKIPIF1<0 C．4 D．SKIPIF1<0【答案】D【分析】只有符號(hào)不同的兩個(gè)數(shù)叫做互為相反數(shù)，由此即可得到答案．【詳解】解：4的相反數(shù)是SKIPIF1<0，故選：D．【點(diǎn)睛】本題考查相反數(shù)的概念，關(guān)鍵是掌握相反數(shù)的定義．23．（2023·四川涼山·統(tǒng)考中考真題）下列各數(shù)中，為有理數(shù)的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)立方根、無理數(shù)與有理數(shù)的概念即可得．【詳解】解：A、SKIPIF1<0，是有理數(shù)，則此項(xiàng)符合題意；B、SKIPIF1<0是無限不循環(huán)小數(shù)，是無理數(shù)，則此項(xiàng)不符合題意；C、SKIPIF1<0是無理數(shù)，則此項(xiàng)不符合題意；D、SKIPIF1<0是無理數(shù)，則此項(xiàng)不符合題意；故選：A．【點(diǎn)睛】本題考查了立方根、無理數(shù)與有理數(shù)，熟記無理數(shù)與有理數(shù)的概念是解題關(guān)鍵．24．（2023·四川成都·統(tǒng)考中考真題）在SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0四個(gè)數(shù)中，最大的數(shù)是（

）A．3 B．SKIPIF1<0 C．0 D．SKIPIF1<0【答案】A【分析】根據(jù)有理數(shù)大小比較的法則：①正數(shù)都大于0；②負(fù)數(shù)都小于0；③正數(shù)大于一切負(fù)數(shù)；④兩個(gè)負(fù)數(shù)，絕對(duì)值大的其值反而小，據(jù)此判斷即可．【詳解】解：根據(jù)有理數(shù)比較大小的方法，可得SKIPIF1<0，∴最大的數(shù)是：3；故選：A．【點(diǎn)睛】此題主要考查了有理數(shù)大小比較的方法，要熟練掌握，解答此題的關(guān)鍵是要明確：①正數(shù)都大于0；②負(fù)數(shù)都小于0；③正數(shù)大于一切負(fù)數(shù)；④兩個(gè)負(fù)數(shù)，絕對(duì)值大的其值反而?。?5．（2023·浙江嘉興·統(tǒng)考中考真題）下面四個(gè)數(shù)中，比1小的正無理數(shù)是（）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】根據(jù)正數(shù)SKIPIF1<0負(fù)數(shù)，即可進(jìn)行解答．【詳解】解：∵SKIPIF1<0∴SKIPIF1<0∴SKIPIF1<0∴比1小的正無理數(shù)是SKIPIF1<0．故選：A．【點(diǎn)睛】本題主要考查了比較實(shí)數(shù)是大小，無理數(shù)的估算，解題的關(guān)鍵是掌握正數(shù)SKIPIF1<0負(fù)數(shù)．26．（2023·四川廣安·統(tǒng)考中考真題）－6的絕對(duì)值是（

）A．-6 B．6 C．-SKIPIF1<0 D．SKIPIF1<0【答案】B【分析】在數(shù)軸上，表示一個(gè)數(shù)的點(diǎn)到原點(diǎn)的距離叫做這個(gè)數(shù)的絕對(duì)值．【詳解】負(fù)數(shù)的絕對(duì)值等于它的相反數(shù)，所以-6的絕對(duì)值是6．故選：B．27．（2023·湖南懷化·統(tǒng)考中考真題）下列四個(gè)實(shí)數(shù)中，最小的數(shù)是（

）A．SKIPIF1<0 B．0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【分析】先根據(jù)實(shí)數(shù)的大小比較法則比較數(shù)的大小，再求出最小的數(shù)即可．【詳解】SKIPIF1<0SKIPIF1<0最小的數(shù)是：SKIPIF1<0故選：A．【點(diǎn)睛】本題考查了實(shí)數(shù)的大小比較，能熟記實(shí)數(shù)的大小比較法則是解此題的關(guān)鍵．28．（2023·浙江臺(tái)州·統(tǒng)考中考真題）下列無理數(shù)中，大小在3與4之間的是（

）．A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【分析】根據(jù)無理數(shù)的估算可得答案．【詳解】解：∵SKIPIF1<0，SKIPIF1<0，而SKIPIF1<0，SKIPIF1<0，∴大小在3與4之間的是SKIPIF1<0，故選：C．【點(diǎn)睛】本題考查了無理數(shù)的估算，熟練掌握基礎(chǔ)知識(shí)是解題的關(guān)鍵．29．（2023·浙江臺(tái)州·統(tǒng)考中考真題）下列各數(shù)中，最小的是（

）．A．2 B．1 C．SKIPIF1<0 D．SKIPIF1<0【答案】D【分析】根據(jù)正數(shù)大于零，零大于負(fù)數(shù)，兩個(gè)負(fù)數(shù)，絕對(duì)值大的反而小判斷即可．【詳解】解：∵2，1是正數(shù)，SKIPIF1<0，SKIPIF1<0是負(fù)數(shù)，∴最小數(shù)的是在SKIPIF1<0，SKIPIF1<0里，又SKIPIF1<0，SKIPIF1<0，且SKIPIF1<0，∴SKIPIF1<0，∴最小數(shù)的是SKIPIF1<0．故選：D．【點(diǎn)睛】本題主要考查了有理數(shù)大小比較，解答此題的關(guān)鍵是掌握有理數(shù)大小比較法則．二、填空題30．（2023·四川自貢·統(tǒng)考中考真題）請(qǐng)寫出一個(gè)比SKIPIF1<0小的整數(shù)________．【答案】SKIPIF1<0（答案不唯一）【分析】根據(jù)算術(shù)平方根的意義求解．【詳解】解：∴由SKIPIF1<0可得：SKIPIF1<0，即SKIPIF1<0，故答案為：SKIPIF1<0（答案不唯一）．【點(diǎn)睛】本題考查算術(shù)平方根和無理數(shù)的估算，熟練掌握基本知識(shí)是解題關(guān)鍵．31．（2023·四川瀘州·統(tǒng)考中考真題）8的立方根為______．【答案】2【分析】根據(jù)立方根的意義即可完成．【詳解】∵SKIPIF1<0∴8的立方根為2故答案為：2.【點(diǎn)睛】本題考查了立方根的意義，掌握立方根的意義是關(guān)鍵．32．（2023·浙江嘉興·統(tǒng)考中考真題）SKIPIF1<0___________．【答案】2023【分析】負(fù)數(shù)的絕對(duì)值是它的相反數(shù)，由此可解．【詳解】解：SKIPIF1<0的相反數(shù)是2023，故SKIPIF1<0，故答案為：2023．【點(diǎn)睛】本題考查求一個(gè)數(shù)的絕對(duì)值，解題的關(guān)鍵是掌握負(fù)數(shù)的絕對(duì)值是它的相反數(shù)．33．（2023·四川廣安·統(tǒng)考中考真題）SKIPIF1<0的平方根是_______．【答案】±2【詳解】解：∵SKIPIF1<0∴SKIPIF1<0的平方根是±2．故答案為：±2．34．（2023·重慶·統(tǒng)考中考真題）計(jì)算SKIPIF1<0_____.【答案】1.5【分析】先根據(jù)負(fù)整數(shù)指數(shù)冪及零指數(shù)冪化簡(jiǎn)，再根據(jù)有理數(shù)的加法計(jì)算.【詳解】SKIPIF1<0SKIPIF1<0.故答案為：1.5.【點(diǎn)睛】本題考查了負(fù)整數(shù)指數(shù)冪及零指數(shù)冪的意義，任何不等于0的數(shù)的負(fù)整數(shù)次冪，等于這個(gè)數(shù)的正整數(shù)次冪的倒數(shù)，非零數(shù)的零次冪等于1.35．（2023·重慶·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0________．【答案】6【分析】根據(jù)絕對(duì)值、零指數(shù)冪法則計(jì)算即可．【詳解】解：SKIPIF1<0．故答案為：6．【點(diǎn)睛】本題考查了實(shí)數(shù)的混合運(yùn)算，熟練掌握相關(guān)運(yùn)算法則是解決本題的關(guān)鍵．36．（2023·四川涼山·統(tǒng)考中考真題）計(jì)算SKIPIF1<0_________．【答案】SKIPIF1<0【分析】根據(jù)零指數(shù)冪、二次根式的性質(zhì)進(jìn)行計(jì)算即可．【詳解】SKIPIF1<0SKIPIF1<0SKIPIF1<0．故答案為：SKIPIF1<0．【點(diǎn)睛】本題考查了實(shí)數(shù)的混合運(yùn)算，二次根式的性質(zhì)等知識(shí)，掌握任何一個(gè)不為零的數(shù)的零次冪都是1是解題的關(guān)鍵．37．（2023·安徽·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0_____________．【答案】SKIPIF1<0【分析】根據(jù)求一個(gè)數(shù)的立方根，有理數(shù)的加法即可求解．【詳解】解：SKIPIF1<0SKIPIF1<0，故答案為：SKIPIF1<0．【點(diǎn)睛】本題考查了求一個(gè)數(shù)的立方根，熟練掌握立方根的定義是解題的關(guān)鍵．38．（2023·江蘇連云港·統(tǒng)考中考真題）如圖，數(shù)軸上的點(diǎn)SKIPIF1<0分別對(duì)應(yīng)實(shí)數(shù)SKIPIF1<0，則SKIPIF1<0__________0.(用“SKIPIF1<0”“SKIPIF1<0”或“SKIPIF1<0”填空)

【答案】SKIPIF1<0【分析】根據(jù)數(shù)軸可得SKIPIF1<0，進(jìn)而即可求解．【詳解】解：由數(shù)軸可得SKIPIF1<0∴SKIPIF1<0SKIPIF1<0故答案為：SKIPIF1<0.【點(diǎn)睛】本題考查了實(shí)數(shù)與數(shù)軸，有理數(shù)加法的運(yùn)算法則，數(shù)形結(jié)合是解題的關(guān)鍵．39．（2023·江蘇連云港·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0__________．【答案】SKIPIF1<0【分析】根據(jù)二次根式的性質(zhì)即可求解．【詳解】解：SKIPIF1<0SKIPIF1<0故答案為：SKIPIF1<0．【點(diǎn)睛】本題考查了二次根式的性質(zhì)，熟練掌握二次根式的性質(zhì)是解題的關(guān)鍵．三、解答題40．（2023·浙江金華·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0．【答案】SKIPIF1<0【分析】根據(jù)零指數(shù)冪、算術(shù)平方根的定義、特殊角的三角函數(shù)值、絕對(duì)值的意義，計(jì)算即可．【詳解】解：原式SKIPIF1<0，SKIPIF1<0，SKIPIF1<0．【點(diǎn)睛】本題考查了零指數(shù)冪、算術(shù)平方根的定義、特殊角的三角函數(shù)值、絕對(duì)值的意義．本題的關(guān)鍵是注意各部分的運(yùn)算法則，細(xì)心計(jì)算．41．（2023·四川自貢·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0．【答案】SKIPIF1<0【分析】先化簡(jiǎn)絕對(duì)值，零指數(shù)冪，有理數(shù)的乘方，再進(jìn)行計(jì)算即可求解．【詳解】解：SKIPIF1<0SKIPIF1<0SKIPIF1<0．【點(diǎn)睛】本題考查了實(shí)數(shù)的混合運(yùn)算，熟練掌握化簡(jiǎn)絕對(duì)值，零指數(shù)冪，有理數(shù)的乘方是解題的關(guān)鍵．42．（2023·四川瀘州·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0．【答案】3【分析】根據(jù)負(fù)整數(shù)指數(shù)冪和零指數(shù)冪運(yùn)算法則，特殊角的三角函數(shù)值，進(jìn)行計(jì)算即可．【詳解】解：SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0．【點(diǎn)睛】本題主要考查了實(shí)數(shù)混合運(yùn)算，解題的關(guān)鍵是熟練掌握負(fù)整數(shù)指數(shù)冪和零指數(shù)冪運(yùn)算法則，特殊角的三角函數(shù)值，準(zhǔn)確計(jì)算．43．（2023·浙江·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0．【答案】2【分析】直接利用負(fù)整數(shù)指數(shù)冪的性質(zhì)以及零指數(shù)冪的性質(zhì)、絕對(duì)值的意義分別化簡(jiǎn)，再利用有理數(shù)的加減運(yùn)算法則計(jì)算得出答案．【詳解】原式SKIPIF1<0．【點(diǎn)睛】此題主要考查了負(fù)整數(shù)指數(shù)冪的性質(zhì)以及零指數(shù)冪的性質(zhì)，絕對(duì)值的意義，掌握這些知識(shí)并正確計(jì)算是解題關(guān)鍵．44．（2023·四川廣安·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0【答案】SKIPIF1<0【分析】先計(jì)算有理數(shù)的乘方、零指數(shù)冪、特殊角的余弦值、化簡(jiǎn)絕對(duì)值，再計(jì)算乘法與加減法即可得．【詳解】解：原式SKIPIF1<0SKIPIF1<0SKIPIF1<0．【點(diǎn)睛】本題考查了零指數(shù)冪、特殊角的余弦值、實(shí)數(shù)的混合運(yùn)算，熟練掌握各運(yùn)算法則是解題關(guān)鍵．45．（2023·江蘇連云港·統(tǒng)考中考真題）計(jì)算SKIPIF1<0．【答案】3【分析】根據(jù)化簡(jiǎn)絕對(duì)值，零指數(shù)冪以及負(fù)整數(shù)指數(shù)冪進(jìn)行計(jì)算即可求解．【詳解】解：原式SKIPIF1<0．【點(diǎn)睛】本題考查了實(shí)數(shù)的混合運(yùn)算，熟練掌握化簡(jiǎn)絕對(duì)值，零指數(shù)冪以及負(fù)整數(shù)指數(shù)冪是解題的關(guān)鍵．46．（2023·四川眉山·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0【答案】6【分析】先計(jì)算零指數(shù)冪，負(fù)整數(shù)指數(shù)冪和特殊角三角函數(shù)值，再根據(jù)實(shí)數(shù)的混合計(jì)算法則求解即可．【詳解】解：原式SKIPIF1<0SKIPIF1<0SKIPIF1<0．【點(diǎn)睛】本題主要考查了實(shí)數(shù)的混合計(jì)算，特殊角三角函數(shù)值，零指數(shù)冪和負(fù)整數(shù)指數(shù)冪，熟知相關(guān)計(jì)算法則是解題的關(guān)鍵．47．（2023·云南·統(tǒng)考中考真題）計(jì)算：SKIPIF1<0．【答案】6【分析】根據(jù)絕對(duì)值的性質(zhì)、零指數(shù)冪的性質(zhì)、負(fù)指數(shù)冪的性質(zhì)和特殊角的三角函數(shù)值分別化簡(jiǎn)計(jì)算即可得出答案．【詳解】解：SKIPIF1<0SKIPIF1<0SKIPIF1<0．【點(diǎn)睛】本題考查了實(shí)數(shù)的運(yùn)算，熟練掌握絕對(duì)值的性質(zhì)、零指數(shù)