數(shù)值分析報告 (李慶揚版)

《數(shù)值分析》作業(yè)學院：機械學院專業(yè)：機械工程姓名：趙博學號：2014520024日期：2

第二章作業(yè)P48_2給出的數(shù)值表如下：x0.40.50.60.70.8lnx-0.916291-0.693147-0.510826-0.356675-0.223144問：用線性插值及二次插值計算ln0.54的近似值。答：VB程序如下：OptionExplicitSubczfl(ByRefx()AsSingle,y()AsSingle,nAsInteger,x1AsDouble,fAsDouble)Dimi,jAsIntegerDimpAsSingleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addf=0Fori=0Tonp=1Forj=0TonIfi<>jThenp=p*(x1-x(j))/(x(i)-x(j))EndIfNextjwsmysheet.cells(i+1,1)=Str(p)wsmysheet.cells(i+1,2)=Str(p*y(i))f=f+p*y(i)Nextiwsmysheet.cells(n+1,3)="最終結果"+Str(f)appexcel.Visible=TrueEndSubPrivateSubCommand1_Click(IndexAsInteger)Dimx()AsSingleDimy()AsSingleDimnAsIntegerDimkAsIntegerDimfAsDoublek=0n=Val(Text1.Text)ReDimx(n)ReDimy(n)Open"czfl.txt"ForOutputAs#1Print#1,Text3.TextClose#1Open"czfl.txt"ForInputAs#1DoWhileNotEOF(1)Input#1,x(k),y(k)'Printx(k),y(k)k=k+1LoopClose#1SelectCaseIndexCase0Callczfl(x(),y(),Text1.Text,Text2.Text,f)Case1Callczfnt(x(),y(),Text1.Text,Text2.Text,f)EndSelectEndSubSubczfnt(ByRefx()AsSingle,y()AsSingle,nAsInteger,x1AsDouble,fAsDouble)Dimi,jAsIntegerDimk,lAsIntegerDimsAsDoubleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addf=y(0)s=1Forj=1TonFori=nTojStep-1y(i)=(y(i)-y(i-1))/(x(i)-x(i-j))wsmysheet.cells(i,j)=Str(y(i))NextiNextjFork=1Tons=s*(x1-x(l))f=f+s*y(k)Nextkwsmysheet.cells(n,n+1)="最終結果"+Str(f)appexcel.Visible=TrueEndSub結果：線性插值0.6-0.415890.4-0.20433最終結果-.620218614056672二次插值-0.120.1099550.84-0.582240.28-0.14303最終結果-.615319814966043

第三章作業(yè)P95_16.觀測物體的直線運動，得到一下數(shù)據(jù)：時間t（s）00.91.93.03.95.0距離s（m）010305080110求運動方程。答：vb程序如下：（窗體見工程文件）OptionExplicitOptionBase1Sublufj(nAsInteger,a()AsSingle,b()AsSingle)DimiAsInteger,jAsInteger,kAsIntegerDimsAsSingleFori=2Tona(i,1)=a(i,1)/a(1,1)NextiFori=2TonForj=iTons=0Fork=1Toi-1s=s+a(i,k)*a(k,j)Nextka(i,j)=a(i,j)-sNextjForj=i+1Tons=0Fork=1Toi-1s=s+a(j,k)*a(k,i)Nextka(j,i)=(a(j,i)-s)/a(i,i)NextjNextiFori=1Tons=0Forj=1Toi-1s=s+a(i,j)*b(j)Nextjb(i)=b(i)-sNextiFori=nTo1Step-1s=0Forj=i+1Tons=s+a(i,j)*b(j)Nextjb(i)=(b(i)-s)/a(i,i)NextiEndSubSubdxnh(nAsInteger,mAsInteger,x()AsSingle,y()AsSingle,a()AsSingle,c()AsSingle)DimiAsInteger,jAsInteger,kAsSingleDimsAsSingleFori=1Tom+1Forj=iTom+1s=0Fork=1Tons=s+x(k)^(i+j-2)Nextka(i,j)=sa(j,i)=sNextjNextiFori=1Tom+1s=0Fork=1Tons=s+y(k)*x(k)^(i-1)Nextkc(i)=sNextiFori=1Tom+1a(i,m+2)=c(i)NextiCalllufj(m+1,a(),c())EndSubSubxy(nAsInteger,x()AsSingle,y()AsSingle,z()AsSingle,aAsSingle,bAsSingle)DimsumAsSingle,sumxAsSingle,sumyAsSingleDimsumxyAsSingle,sumxxAsSingleDimxavAsSingle,yavAsSingle,iAsIntegerFori=1Tonsum=sum+z(i)sumx=sumx+x(i)*z(i)sumy=sumy+y(i)*z(i)sumxy=sumxy+x(i)*y(i)*z(i)sumxx=sumxx+x(i)^2*z(i)Nextixav=sumx/sumyav=sumy/sumb=(sum*sumxy-sumx*sumy)/(sum*sumxx-sumx^2)a=yav-b*xavEndSubPrivateSubCombo1_Click()DimIndexAsIntegerIndex=Combo1.ListIndexSelectCase(Index)Case0:Command2.Visible=FalseLabel4.Visible=FalseText3.Visible=FalseLabel1.Caption="請輸入實驗數(shù)據(jù)x(i),y(i),及每組數(shù)據(jù)出現(xiàn)的次數(shù)z(i)：n=1，2，3，4，5...如："Text1.Text="3.2,4,2"&vbCrLf&"3.7,4.5,4"Label3.Visible=TrueText2.Visible=TrueCommand1.Visible=TrueCase1:Command1.Visible=FalseText2.Text="0"Text3.Text="0"Label1.Caption="請輸入實驗數(shù)據(jù)x(i),y(i)：n=1，2，3，4，5...如："Text1.Text="3.2,4"&vbCrLf&"3.7,4.5"Label3.Visible=TrueText2.Visible=TrueLabel4.Visible=TrueText3.Visible=TrueCommand2.Visible=TrueEndSelectEndSubPrivateSubCommand1_Click()Dimx()AsSingle,y()AsSingle,z()AsSingleDimnAsInteger,iAsIntegerDimbAsSingle,aAsSingleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddOpen"shuju.txt"ForOutputAs#1Print#1,Text1.TextClose#1n=Val(Text2.Text)Open"shuju.txt"ForInputAs#1ReDimx(n)ReDimy(n)ReDimz(n)Fori=1TonInput#1,x(i),y(i),z(i)wsmysheet.cells(1,i)=Str(x(i))wsmysheet.cells(2,i)=Str(y(i))wsmysheet.cells(3,i)=Str(z(i))NextiClose#1Callxy(n,x(),y(),z(),a,b)Open"yicijigeuo.txt"ForOutputAs#1Print#1,"所求的一元線性擬合方程為："+"Y=";a;"+";b;"X"Close#1wsmysheet.cells(4,n+1)="最終結果："+"Y="+Str(a)+"+"+Str(b)+"X"appexcel.Visible=TrueEndSubPrivateSubCommand2_Click()Dimx()AsSingle,y()AsSingle,a()AsSingle,c()AsSingleDimiAsInteger,jAsInteger,mAsInteger,nAsInteger,fstrAsStringn=Val(Text2.Text)m=Val(Text3.Text)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddOpen"shuju.txt"ForOutputAs#1Print#1,Text1.TextClose#1Open"shuju.txt"ForInputAs#1ReDimx(n)ReDimy(n)ReDimc(m+1)ReDima(m+1,m+2)Fori=1TonInput#1,x(i),y(i)wsmysheet.cells(1,i)=Str(x(i))wsmysheet.cells(2,i)=Str(y(i))'Printx(i);y(i)'PrintNextiClose#1Calldxnh(n,m,x(),y(),a(),c())fstr="Y="Fori=1Tom+1wsmysheet.cells(3,i)=Str(c(i))Ifi=m+1Thenfstr=fstr+Str(c(i))&"x^"&(i-1)Elsefstr=fstr+Str(c(i))&"x^"&(i-1)&"+"EndIfNextiOpen"duocijigeuo.txt"ForOutputAs#1Print#1,"所求的多次擬合方程為："+fstrClose#1wsmysheet.cells(4,n+1)="最終結果："+fstrappexcel.Visible=TrueEndSubPrivateSubForm_Load()Label1.Caption="下面的文本框為實驗數(shù)據(jù)輸入框"Combo1.AddItem"一次線性擬合",0Combo1.AddItem"多項式擬合",1EndSub結果：一次多項式擬合結果00.91.933.950.610305080110111111最終結果：Y=-7.550592+22.25376X第四章作業(yè)P135_2.(1).分別用梯形公式和辛普森公式計算下列積分答：vb程序如下：OptionExplicitDimindexAsIntegerPrivateSubCombo1_Click()index=Combo1.ListIndexSelectCase(index)Case0:Label3.Visible=TrueText1.Visible=TrueLabel1.Caption="你選擇的是復化梯形求積公式"Case1:Label3.Visible=TrueText1.Visible=TrueLabel1.Caption="你選擇的是復化辛普森積公式"Case2:Label3.Visible=FalseText1.Visible=FalseLabel1.Caption="你選擇的是柯斯特求積公式"EndSelectEndSubPrivateSubCommand1_Click()Dima,bAsIntegerDimfAsDoubleDimnAsIntegera=0b=1n=Val(Text1.Text)SelectCase(index)Case0:Calltx(a,b,f,n)Case1:Callxps(a,b,f,n)Case2:Callkst(a,b,f)EndSelectEndSubSubtx(ByRefa,b,f1AsDouble,nAsInteger)DimiAsIntegerDimc()AsDoubleDimsumAsDoubleDimhAsDoubleReDimc(n-1)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addwsmysheet.cells(1,1)=Str(a)wsmysheet.cells(1,2)=Str(f(a))wsmysheet.cells(n+1,1)=Str(b)wsmysheet.cells(n+1,2)=Str(f(b))h=(b-a)/nFori=1Ton-1c(i)=a+i*hwsmysheet.cells(i+1,1)=Str(c(i))wsmysheet.cells(i+1,2)=Str(f(c(i)))sum=sum+f(c(i))Nextif1=(b-a)*(f(a)+2*sum+f(b))/16wsmysheet.cells(n+1,3)=Str(f1)appexcel.Visible=TrueEndSubSubxps(ByRefa,b,f2AsDouble,nAsInteger)DimiAsIntegerDimx()AsDoubleDimy()AsDoubleDimsumAsDoubleDimsum1AsDoubleDimhAsDoubleReDimx(n)ReDimy(n-1)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addwsmysheet.cells(1,1)=Str(a)wsmysheet.cells(1,2)=Str(f(a))wsmysheet.cells(2*n+1,1)=Str(b)wsmysheet.cells(2*n+1,2)=Str(f(b))h=(b-a)/nFori=0To3x(i)=a+i*h+h/2sum=sum+f(x(i))wsmysheet.cells(2*i+2,1)=Str(x(i))wsmysheet.cells(2*i+2,2)=Str(f(x(i)))NextiFori=1To3y(i)=a+i*hsum1=sum1+f(y(i))wsmysheet.cells(2*i+1,1)=Str(y(i))wsmysheet.cells(2*i+1,2)=Str(f(y(i)))Nextif2=h*(f(a)+4*sum+2*sum1+f(b))/6wsmysheet.cells(2*n+1,3)=Str(f2)appexcel.Visible=TrueEndSubSubkst(ByRefa,b,f3AsDouble)Dimc(4)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddDimiAsIntegerFori=0To4c(i)=a+i*(b-a)/4wsmysheet.cells(i+1,1)=Str(c(i))wsmysheet.cells(i+1,2)=Str(f(c(i)))Nextif3=(b-a)*(7*f(c(0))+32*f(c(1))+12*f(c(2))+32*f(c(3))+7*f(c(4)))/90wsmysheet.cells(5,3)=Str(f3)appexcel.Visible=TrueEndSubPrivateSubForm_Load()Combo1.AddItem"復化梯形求積公式",0Combo1.AddItem"復化辛普森求積公式",1Combo1.AddItem"科特斯求積公式",2EndSub結果：1.梯形公式000.1253.11E-020.256.15E-020.3759.06E-020.50.1176470.6250.1423490.750.1643840.8750.18360710.20.1114022.辛普森公式000.1253.11E-020.256.15E-020.3759.06E-020.50.1176470.6250.1423490.750.1643840.8750.18360710.20.111572

第五章作業(yè)P177_10.用平方根法解方程組，這里用的是高斯主消元法答：vb程序如下：（窗體見工程文件）OptionExplicitOptionBase1SubGS(nAsInteger,a()AsSingle,x()AsSingle)DimiAsInteger,kAsInteger,sAsInteger,jAsIntegerDimyinziAsSingle,maxAsSingle,bAsSingleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddFork=1TonFori=1Ton+1wsmysheet.cells(k,i)=Str(a(k,i))NextiNextkwsmysheet.cells(n+1,1)="消元變換的最終形式："Fork=1Ton-1max=Abs(a(k,k))s=k'選列最大元素Fori=kTonIfAbs(a(i,k))>maxThens=imax=Abs(a(i,k))EndIfNexti'交換兩列Fori=1Ton+1max=a(k,i)a(k,i)=a(s,i)a(s,i)=maxNexti'約化，進行行變換Fori=k+1Tonyinzi=a(i,k)/a(k,k)Forj=kTon+1a(i,j)=a(i,j)-a(k,j)*yinziNextjNextiNextkPrintFori=1TonForj=1Ton+1wsmysheet.cells(n+1+i,j)=Str(Format(a(i,j),"######0.0000"))NextjNextix(n)=a(n,n+1)/a(n,n)wsmysheet.cells(1,n+2)="計算的最終結果："wsmysheet.cells(n,n+3)="x"+"("+Str(n)+")"wsmysheet.cells(n,n+4)=Str(x(n))Fori=n-1To1Step-1b=0Forj=i+1Tonb=b+a(i,j)*x(j)Nextjx(i)=(a(i,n+1)-b)/a(i,i)wsmysheet.cells(i,n+3)="x"+"("+Str(i)+")"wsmysheet.cells(i,n+4)=Str(x(i))Nextiappexcel.Visible=TrueEndSubPrivateSubCommand1_Click()Dima()AsSingle,x()AsSingle,nAsInteger,iAsInteger,jAsIntegern=Val(Text2.Text)Open"shuju.txt"ForOutputAs#1Print#1,Text1.TextClose#1Open"shuju.txt"ForInputAs#1ReDima(n,n+1)ReDimx(n)Fori=1TonForj=1TonInput#1,a(i,j)NextjPrintNextiFori=1TonInput#1,a(i,n+1)NextiClose#1CallGS(n,a(),x())EndSub結果：2-114計算的最終結果：x(1)1.111111-1-235x(2)0.7777781316x(3)2.555556消元變換的最終形式：2-11403.50.54003.85719.8571第六章作業(yè)P209_1.設方程組用雅可比迭代法及高斯—塞德爾迭代法解此方程組，要求當時迭代終止。答：vb程序如下：OptionExplicitOptionBase1DimindexAsIntegerSubykb(nAsInteger,a()AsSingle,x()AsSingle,flatAsDouble)DimiAsInteger,jAsInteger,kAsIntegerDimsum1AsSingle,sum2AsSingleDimmaxAsSingleDimy()AsSingle,z()AsSingleReDimy(n)ReDimz(n)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddFori=1TonForj=1Ton+1wsmysheet.cells(i,j)=Str(a(i,j))NextjNextiwsmysheet.cells(n+1,1)="初始向量為："Fori=1Tonwsmysheet.cells(n+2,i)=Str(x(i))Nextik=0DoFori=1Tonsum1=0sum2=0Forj=1Toi-1sum1=sum1+a(i,j)*x(j)NextjForj=i+1Tonsum2=sum2+a(i,j)*x(j)Nextjy(i)=(a(i,n+1)-sum1-sum2)/a(i,i)NextiFori=1Tonz(i)=Abs(y(i)-x(i))x(i)=y(i)Nextimax=z(1)Fori=1TonIfz(i)>maxThenmax=Abs(z(i))EndIfNextik=k+1LoopUntilmax<flatwsmysheet.cells(1,n+2)="最終結果為："Fori=1Tonwsmysheet.cells(i,n+3)=Str(x(i))Nextiwsmysheet.cells(n+3,1)="迭代次數(shù)："wsmysheet.cells(n+3,2)=Str(k)appexcel.Visible=TrueEndSubSubGS(nAsInteger,a()AsSingle,x()AsSingle,flatAsDouble)DimiAsInteger,jAsInteger,kAsIntegerDimsum1AsSingle,sum2AsSingleDimmaxAsSingleDimy()AsSingle,z()AsSingleReDimy(n)ReDimz(n)DimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddFori=1TonForj=1Ton+1wsmysheet.cells(i,j)=Str(a(i,j))NextjNextiwsmysheet.cells(n+1,1)="初始向量為："Fori=1Tonwsmysheet.cells(n+2,i)=Str(x(i))Nextik=0DoFori=1Tonsum1=0sum2=0Forj=1Toi-1sum1=sum1+a(i,j)*x(j)NextjForj=i+1Tonsum2=sum2+a(i,j)*x(j)Nextjy(i)=(a(i,n+1)-sum1-sum2)/a(i,i)z(i)=Abs(y(i)-x(i))x(i)=y(i)Nextimax=z(1)Fori=1TonIfz(i)>maxThenmax=Abs(z(i))EndIfNextik=k+1LoopUntilmax<flatwsmysheet.cells(1,n+2)="最終結果為："Fori=1Tonwsmysheet.cells(i,n+3)=Str(x(i))Nextiwsmysheet.cells(n+3,1)="迭代次數(shù)："wsmysheet.cells(n+3,2)=Str(k)appexcel.Visible=TrueEndSubPrivateSubCombo1_Click()index=Combo1.ListIndexSelectCase(index)Case0:Command1.Caption="高斯—賽德爾迭代法"Case1:Command1.Caption="雅可比迭代法"EndSelectEndSubPrivateSubCommand1_Click()Dima()AsSingle,x()AsSingle,nAsInteger,iAsInteger,jAsInteger,flatAsDoublen=Val(Text2.Text)flat=Val(Text3.Text)Open"shuju.txt"ForOutputAs#1Print#1,Text1.TextClose#1Open"shuju.txt"ForInputAs#1ReDima(n,n+1)ReDimx(n)'Fori=1TonForj=1TonInput#1,a(i,j)NextjNextiFori=1TonInput#1,a(i,n+1)NextiFori=1TonInput#1,x(i)NextiClose#1SelectCase(index)Case0:CallGS(n,a(),x(),flat)Case1:Callykb(n,a(),x(),flat)EndSelectEndSubPrivateSubForm_Load()Combo1.AddItem"高斯—賽德爾迭代法",0Combo1.AddItem"雅可比迭代法",1EndSub結果：1、高斯-賽德爾迭代法521-12最終結果為：-4.00003-142202.9999832-31032.000001初始向量為：000迭代次數(shù)：82、雅可比迭代法521-12最終結果為：-4-142202.9999742-31032初始向量為：000迭代次數(shù)：18

第七章P238_7.用下列方法求在x0=2附近的根，根的準確值x*=1.87938524···，要求計算結果精確到四位有效數(shù)字。（1）用牛頓法；（2）用弦截法，取x0=2，x1=1.9；答：vb程序如下：DimindexAsIntegerPrivateSubCombo1_Click()index=Combo1.ListIndexSelectCase(index)Case0:Label1.Caption="你選擇的是牛頓法："Label3.Visible=FalseText3.Visible=FalseCase1:Label1.Caption="你選擇的是弦截法："Label3.Visible=TrueText3.Visible=TrueEndSelectEndSubPrivateSubCommand1_Click()DimaAsSingle,bAsSingle,flatAsSingleflat=Val(Text1.Text)SelectCase(index)Case0:a=Val(Text2.Text)Callnd(a,flat)Case1:a=Val(Text2.Text)b=Val(Text3.Text)Callxj(a,b,flat)EndSelectEndSubSubxj(aAsSingle,bAsSingle,flatAsSingle)DimiAsInteger,kAsIntegerDimx(0To20)AsDoubleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addx(0)=ax(1)=bk=0Dok=k+1x(k+1)=x(k)-(x(k)-x(k-1))/(hanshu(x(k))-hanshu(x(k-1)))*hanshu(x(k))LoopUntilAbs(x(k+1)-x(k))/Abs(x(k+1))<flatFori=0Tok+1wsmysheet.cells(i+1,1)=Str(i)wsmysheet.cells(i+1,2)=Str(x(i))Nextiappexcel.Visible=TrueEndSubSubnd(aAsSingle,flatAsSingle)DimiAsIntegerDimx(0To100)AsDoubleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.Addx(0)=a'x(1)=bk=-1Dok=k+1x(k+1)=x(k)-hanshu1(x(k))LoopUntilAbs(x(k+1)-x(k))/Abs(x(k+1))<flatFori=0Tok+1wsmysheet.cells(i+1,1)=Str(i)wsmysheet.cells(i+1,2)=Str(x(i))Nextiappexcel.Visible=TrueEndSubPrivateSubForm_Load()Combo1.AddItem"牛頓法",0Combo1.AddItem"弦截法",1EndSub運行結果：1、牛頓法：0211.88888921.87945231.87938541.8793852、弦截法：0211.921.88109431.87941141.87938551.879385第八章P276_3_(1).用冪法計算下列矩陣的主特征值及對應的特征向量當特征值有3位小數(shù)穩(wěn)定時迭代終止。答：vb程序如下：OptionExplicitOptionBase1DimindexAsIntegerSubcm(ByRefNAsInteger,x()AsSingle,A()AsSingle,z()AsSingle,_epsAsSingle,sAsInteger,v2AsSingle)Dimv1AsSingle,iAsInteger,jAsInteger,sumAsSingle,b()AsSingleReDimb(N)v1=x(1)DoWhileAbs(v2-v1)>=epsv1=v2s=s+1Fori=1ToNsum=0Forj=1ToNsum=sum+A(i,j)*x(j)Nextjz(i)=sumNextiv2=z(1)Fori=1ToNIfAbs(z(i))>Abs(v2)Thenv2=z(i)EndIfb(i)=z(i)NextiIfAbs(v2-v1)<=epsThenExitDoFori=1ToNx(i)=b(i)/v2NextiLoopEndSubPrivateSubCombo1_Click()index=Combo1.ListIndexSelectCase(index)Case0Label1.Caption="你選擇的是求主特征值；請輸入元素A=a(i,j)(i,j=1,2,...n)及初值向量x(i)(i=1,2,...n)"Command1.Caption="求主特征值"Case1Label1.Caption="你選擇的是求最小特征值；請輸入元素A=a(i,j)(i,j=1,2,...n)及初值向量x(i)(i=1,2,...n)"Command1.Caption="求最小特征值"EndSelectEndSubPrivateSubCommand1_Click()DimA()AsSingle,x()AsSingle,z()AsSingleDimNAsInteger,MAsInteger,sAsInteger,iAsInteger,jAsInteger,epsAsSingle,v2AsSingleDimappexcelAsObjectDimwbmybookAsObjectDimwsmysheetAsObjectSetappexcel=CreateObject("excel.application")Setwbmybook=appexcel.workbooks.AddSetwsmysheet=appexcel.worksheets.AddN=Val(Text2.Text)Open"shuju.dat"ForOutputAs#1Print#1,Text1.TextClose#1eps=0.00001Open"shuju.dat"ForInputAs#1M=2*NReDimA(N,M)ReDimx(N)ReDimz(N)Print"矩陣A(i,j)"Fori=1ToNForj=1ToNInput#1,A(i,j)wsmysheet.cells(i,j)=A(i,j)NextjForj=N+1ToMIfi=j-NThenA(i,j)=1ElseA(i,j)=0EndIfNextjPrintNextiwsmysheet.cells(N+1,1)="初值向量："Fori=1ToNInput#1,x(i)wsmysheet.cells(N+2,i+1)=x(i)NextiClose#1PrintSelectCase(index)Case0:Callcm(N,x(),A(),z(),eps,s,v2)wsmysheet.cells(N+3,1)="最大特征值是："wsmysheet.cells(N+3,2)=Format(v2,"#0.######")Case1:CallNJ(N,M,A())'求逆Fori=1ToNForj=N+1ToMA(i,j-N)=A(i,j)NextjNextiCallcm(N,x(),A(),z(),eps,s,v2)wsmysheet.cells(N+3,1)="最大特征值是："wsmysheet.cells(N+3,2)=Format(v2,"#0.######")EndSelectwsmysheet.cells(N+4,1)="對應特征向量分量是："Fori=1ToNwsmysheet.cells(N+5,i+1)=Format(z(i)/v2,"#0.######")Nextiappexcel.Visible=TrueEndSubSubNJ(ByRefNAsInteger,MAsInteger,A()AsSingle)DimiAsInteger,jAsInteger,kAsInteger,bAsSingleFori=1ToNForj=1To2*NIf(j>N)ThenIfi=j-NThenA(i,j)=1ElseA(i,j)=0EndIfEndIfNextjNextiFork=1ToNb=A(k,k)Forj=kToMA(k,j)=A(k,j)/bNextjFori=1ToNIf(i<>k)Thenb=A(i,