新高考數(shù)學(xué)一輪復(fù)習(xí)第3章 第02講 導(dǎo)數(shù)與函數(shù)的單調(diào)性 精講+精練（學(xué)生版）

第02講導(dǎo)數(shù)與函數(shù)的單調(diào)性(精講+精練）目錄第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶第二部分：課前自我評(píng)估測(cè)試第三部分：典型例題剖析高頻考點(diǎn)一：利用導(dǎo)數(shù)求函數(shù)的單調(diào)區(qū)間（不含參）高頻考點(diǎn)二：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)高頻考點(diǎn)三：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間高頻考點(diǎn)四：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)高頻考點(diǎn)五：函數(shù)單調(diào)性的應(yīng)用①導(dǎo)函數(shù)與原函數(shù)圖象的單調(diào)性②比較大?、蹣?gòu)造函數(shù)解不等式高頻考點(diǎn)六：含參問題討論單調(diào)性①導(dǎo)函數(shù)有效部分是一次型（或可化為一次型）②導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且可因式分解型③導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且不可因式分解型第四部分：高考真題感悟第五部分：第02講導(dǎo)數(shù)與函數(shù)的單調(diào)性（精練）第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶第一部分：知識(shí)點(diǎn)精準(zhǔn)記憶1、函數(shù)的單調(diào)性與導(dǎo)數(shù)的關(guān)系（導(dǎo)函數(shù)看正負(fù)，原函數(shù)看增減）條件恒有結(jié)論函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上可導(dǎo)SKIPIF1<0SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞增SKIPIF1<0SKIPIF1<0在SKIPIF1<0內(nèi)單調(diào)遞減SKIPIF1<0SKIPIF1<0在SKIPIF1<0內(nèi)是常數(shù)函數(shù)2、求已知函數(shù)（不含參）的單調(diào)區(qū)間①求SKIPIF1<0的定義域②求SKIPIF1<0③令SKIPIF1<0，解不等式，求單調(diào)增區(qū)間④令SKIPIF1<0，解不等式，求單調(diào)減區(qū)間注：求單調(diào)區(qū)間時(shí)，令SKIPIF1<0（或SKIPIF1<0）不跟等號(hào).3、由函數(shù)SKIPIF1<0的單調(diào)性求參數(shù)的取值范圍的方法（1）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)①已知SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增SKIPIF1<0SKIPIF1<0，SKIPIF1<0恒成立.②已知SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞減SKIPIF1<0SKIPIF1<0，SKIPIF1<0恒成立.注：已知單調(diào)性，等價(jià)條件中的不等式含等號(hào).（2）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間①已知SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)增區(qū)間SKIPIF1<0令SKIPIF1<0，解不等式，求單調(diào)增區(qū)間SKIPIF1<0，則SKIPIF1<0②已知SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)減區(qū)間SKIPIF1<0令SKIPIF1<0，解不等式，求單調(diào)減區(qū)間SKIPIF1<0，則SKIPIF1<0（3）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)SKIPIF1<0SKIPIF1<0，使得SKIPIF1<04、含參問題討論單調(diào)性第一步：求SKIPIF1<0的定義域第二步：求SKIPIF1<0（導(dǎo)函數(shù)中有分母通分）第三步：確定導(dǎo)函數(shù)有效部分，記為SKIPIF1<0對(duì)于SKIPIF1<0進(jìn)行求導(dǎo)得到SKIPIF1<0，對(duì)SKIPIF1<0初步處理（如通分），提出SKIPIF1<0的恒正部分，將該部分省略，留下的部分則為SKIPIF1<0的有效部分（如：SKIPIF1<0，則記SKIPIF1<0為SKIPIF1<0的有效部分）.接下來就只需考慮導(dǎo)函數(shù)有效部分，只有該部分決定SKIPIF1<0的正負(fù).第四步：確定導(dǎo)函數(shù)有效部分SKIPIF1<0的類型：①SKIPIF1<0為一次型（或可化為一次型）②SKIPIF1<0為二次型（或可化為二次型）第五步：通過分析導(dǎo)函數(shù)有效部分，討論SKIPIF1<0的單調(diào)性第二部分：課前自我評(píng)估測(cè)試第二部分：課前自我評(píng)估測(cè)試一、判斷題1．（2021·全國(guó)·高二課前預(yù)習(xí)）函數(shù)f(x)在定義域上都有f′(x)<0，則函數(shù)f(x)在定義域上單調(diào)遞減.()2．（2021·全國(guó)·高二課前預(yù)習(xí)）函數(shù)f(x)在某區(qū)間內(nèi)單調(diào)遞增，則一定有f′(x)>0.()3．（2021·全國(guó)·高二課前預(yù)習(xí)）函數(shù)y＝x3＋x的單調(diào)遞增區(qū)間為(－∞，＋∞).()二、單選題1．（2022·廣東·佛山市南海區(qū)桂城中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的圖象如圖所示，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0的符號(hào)不確定2．（2022·河北·武安市第三中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的單調(diào)遞減區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·江西南昌·高二期末（理））若函數(shù)SKIPIF1<0，則SKIPIF1<0的單調(diào)增區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·湖北·華中師大一附中高一期末）“函數(shù)SKIPIF1<0在SKIPIF1<0上是增函數(shù)”是：“實(shí)數(shù)SKIPIF1<0”的（

）A．充分不必要條件 B．必要不充分條件C．充要條件 D．既不充分也不必要條件第三部分：典型例題剖析第三部分：典型例題剖析高頻考點(diǎn)一：利用導(dǎo)數(shù)求函數(shù)的單調(diào)區(qū)間（不含參）1．（2022·廣東·深圳市南山區(qū)華僑城中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的單調(diào)減區(qū)間是（

）A．（－∞，SKIPIF1<0] B．（0，SKIPIF1<0） C．SKIPIF1<0和（0，SKIPIF1<0） D．SKIPIF1<02．（2022·福建·福鼎市第一中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的減區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·重慶八中高三階段練習(xí)）函數(shù)SKIPIF1<0的遞增區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國(guó)·高二課時(shí)練習(xí)）函數(shù)SKIPIF1<0的減區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·全國(guó)·高三專題練習(xí)）函數(shù)SKIPIF1<0的遞增區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點(diǎn)二：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)1．（2022·黑龍江·鐵人中學(xué)高二開學(xué)考試）已知函數(shù)SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0在SKIPIF1<0單調(diào)遞增，a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國(guó)·高三專題練習(xí)）若函數(shù)f(x)＝x3＋bx2＋cx＋d的單調(diào)遞減區(qū)間為(－1，3)，則b＋c＝（

）A．－12 B．－10 C．8 D．103．（2022·廣西欽州·高二期末（文））函數(shù)SKIPIF1<0在SKIPIF1<0單調(diào)遞增的一個(gè)必要不充分條件是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國(guó)·高二課時(shí)練習(xí)）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞減，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·全國(guó)·高二課時(shí)練習(xí)）若函數(shù)SKIPIF1<0在SKIPIF1<0上是減函數(shù)，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，若SKIPIF1<0在區(qū)間SKIPIF1<0上單調(diào)遞增，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點(diǎn)三：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)區(qū)間1．（2022·河北·武安市第三中學(xué)高二階段練習(xí)）若函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)存在單調(diào)遞減區(qū)間，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上存在單調(diào)遞增區(qū)間，則實(shí)數(shù)b的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·重慶市萬州第二高級(jí)中學(xué)高二階段練習(xí)）已知函數(shù)SKIPIF1<0存在三個(gè)單調(diào)區(qū)間，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國(guó)·高二）若函數(shù)SKIPIF1<0存在遞減區(qū)間，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．（2021·內(nèi)蒙古·赤峰二中高二期末（理））若函數(shù)SKIPIF1<0存在增區(qū)間，則實(shí)數(shù)SKIPIF1<0的取值范圍為A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點(diǎn)四：已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)1．（2022·重慶市青木關(guān)中學(xué)校高二階段練習(xí)）已知函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)不是單調(diào)函數(shù)，則實(shí)數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·河南·高二階段練習(xí)（理））若函數(shù)SKIPIF1<0在定義域內(nèi)的一個(gè)子區(qū)間SKIPIF1<0上不是單調(diào)函數(shù)，則實(shí)數(shù)k的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·安徽·合肥一中高二階段練習(xí)）若函數(shù)SKIPIF1<0在其定義域上不單調(diào)，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·浙江·高二階段練習(xí)）函數(shù)SKIPIF1<0在區(qū)間[-1，2]上不單調(diào)，則實(shí)數(shù)a的取值范圍是（

）A．(-∞，-3] B．(-3，1)C．[1，+∞) D．(-∞，-3]∪[1，+∞)5．（2022·安徽省太和中學(xué)高二開學(xué)考試）已知函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上不單調(diào)，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·江蘇·高二）若函數(shù)SKIPIF1<0在其定義域上不單調(diào)，則實(shí)數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2022·全國(guó)·高二課時(shí)練習(xí)）已知函數(shù)SKIPIF1<0，則SKIPIF1<0在SKIPIF1<0上不單調(diào)的一個(gè)充分不必要條件是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點(diǎn)五：函數(shù)單調(diào)性的應(yīng)用①導(dǎo)函數(shù)與原函數(shù)圖象的單調(diào)性1．（2021·廣西河池·高二階段練習(xí)（理））如果函數(shù)SKIPIF1<0的導(dǎo)函數(shù)SKIPIF1<0的圖象如圖所示，則以下關(guān)于函數(shù)SKIPIF1<0的判斷：①在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞增；②在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞減；③在區(qū)間SKIPIF1<0內(nèi)單調(diào)遞增；④SKIPIF1<0是極小值點(diǎn)；⑤SKIPIF1<0是極大值點(diǎn).其中不正確的是（

）A．③⑤ B．②③ C．①④⑤ D．①②④2．（2021·福建省漳州第一中學(xué)高二階段練習(xí)）SKIPIF1<0是函數(shù)y＝f(x)的導(dǎo)函數(shù)，若y＝SKIPIF1<0的圖象如圖所示，則函數(shù)y＝f(x)的圖象可能是（

）A． B．C． D．3．（2021·海南·三亞華僑學(xué)校高三階段練習(xí)）已知函數(shù)SKIPIF1<0的圖象如圖所示，則SKIPIF1<0的圖象可能是（

）A． B．C． D．4．（2021·全國(guó)·高二課時(shí)練習(xí)）如圖為函數(shù)SKIPIF1<0的導(dǎo)函數(shù)SKIPIF1<0的圖象，那么函數(shù)SKIPIF1<0的圖象可能為（

）A． B．C． D．5．（2021·江西省銅鼓中學(xué)高二階段練習(xí)（理））設(shè)SKIPIF1<0是函數(shù)SKIPIF1<0的導(dǎo)數(shù)，SKIPIF1<0的圖象如圖所示，則SKIPIF1<0的圖像最有可能的是（

）．A． B．C． D．②比較大小1．（2022·云南省昆明市第十中學(xué)高二階段練習(xí)）已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·重慶市清華中學(xué)校高二階段練習(xí)）若函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·河南·民權(quán)縣第一高級(jí)中學(xué)高三階段練習(xí)（理））已知函數(shù)SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·四川·成都外國(guó)語學(xué)校高二階段練習(xí)（理））已知SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0③構(gòu)造函數(shù)解不等式1．（2022·全國(guó)·高二課時(shí)練習(xí)）已知定義在R上的奇函數(shù)f（x），當(dāng)x＞0時(shí),SKIPIF1<0，且f（3）＝0，則不等式f（x）≥0的解集為（

）A．（﹣∞，﹣3]∪[3，+∞） B．[﹣3，3]C．（﹣∞，﹣3]∪[0，3] D．[﹣3，0]∪[3，+∞）2．（2022·河南·高二階段練習(xí)（文））已知函數(shù)SKIPIF1<0對(duì)于任意的SKIPIF1<0滿足SKIPIF1<0，其中SKIPIF1<0是函數(shù)SKIPIF1<0的導(dǎo)函數(shù)，則下列各式正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0D．SKIPIF1<03．（2022·全國(guó)·高三專題練習(xí)（理））設(shè)函數(shù)SKIPIF1<0是偶函數(shù)SKIPIF1<0（SKIPIF1<0）的導(dǎo)函數(shù)，SKIPIF1<0，當(dāng)SKIPIF1<0時(shí)，SKIPIF1<0，則使得SKIPIF1<0成立的x的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0D．SKIPIF1<04．（2022·重慶南開中學(xué)高二期末）已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0滿足：SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·甘肅·永昌縣第一高級(jí)中學(xué)高二階段練習(xí)（理））已知f(x)為R上的可導(dǎo)函數(shù)，其導(dǎo)函數(shù)為SKIPIF1<0，且對(duì)于任意的x∈R，均有SKIPIF1<0，則（

）A．e－2021f(－2021)>f(0)，e2021f(2021)<f(0) B．e－2021f(－2021)<f(0)，e2021f(2021)<f(0)C．e－2021f(－2021)>f(0)，e2021f(2021)>f(0) D．e－2021f(－2021)<f(0)，e2021f(2021)>f(0)高頻考點(diǎn)六：含參問題討論單調(diào)性①導(dǎo)函數(shù)有效部分是一次型（或可化為一次型）1．（2022·廣東·清遠(yuǎn)市博愛學(xué)校高二階段練習(xí)）已知函數(shù)SKIPIF1<0．（1）討論SKIPIF1<0的單調(diào)性；2．（2022·全國(guó)·高三專題練習(xí)（理））設(shè)a為實(shí)數(shù)，函數(shù)f(x)＝SKIPIF1<0－2x＋2a，x∈R．(1)求f(x)的單調(diào)區(qū)間與極值；2．（2022·全國(guó)·高二）已知函數(shù)SKIPIF1<0，討論SKIPIF1<0的單調(diào)性．3．（2022·全國(guó)·高二課時(shí)練習(xí)）已知函數(shù)SKIPIF1<0.討論SKIPIF1<0的單調(diào)性.②導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且可因式分解型1．（2022·江蘇宿遷·高二期末）已知函數(shù)SKIPIF1<0，SKIPIF1<0.(1)討論SKIPIF1<0的單調(diào)性；2．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，討論SKIPIF1<0的單調(diào)性.3．（2022·全國(guó)·高二課時(shí)練習(xí)）已知函數(shù)SKIPIF1<0.（1）當(dāng)SKIPIF1<0時(shí)，求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程；（2）求SKIPIF1<0的單調(diào)區(qū)間.4．（2022·河北邢臺(tái)·高二階段練習(xí)）已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0，求SKIPIF1<0在SKIPIF1<0上的值域；(2)若SKIPIF1<0，討論SKIPIF1<0的單調(diào)性.5．（2022·廣西柳州·三模（理））若SKIPIF1<0.(1)當(dāng)SKIPIF1<0，SKIPIF1<0時(shí)，討論函數(shù)SKIPIF1<0的單調(diào)性；(2)若SKIPIF1<0，且SKIPIF1<0有兩個(gè)極值點(diǎn)SKIPIF1<0，SKIPIF1<0，證明：SKIPIF1<0.6．（2022·遼寧撫順·一模）已知函數(shù)SKIPIF1<0.(1)討論函數(shù)SKIPIF1<0的單調(diào)性；③導(dǎo)函數(shù)有效部分是二次型（或可化為二次型）且不可因式分解型1．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0．（1）討論函數(shù)的單調(diào)性；2．（2022·全國(guó)·高二課時(shí)練習(xí)）設(shè)函數(shù)SKIPIF1<0討論SKIPIF1<0的單調(diào)性.3．（2022·全國(guó)·高三專題練習(xí)）已知函數(shù)SKIPIF1<0(1)若函數(shù)SKIPIF1<0的一個(gè)極值點(diǎn)為SKIPIF1<0，求函數(shù)SKIPIF1<0的極值(2)討論SKIPIF1<0的單調(diào)性.第四部分：高考真題感悟第四部分：高考真題感悟1．（2021·全國(guó)·高考真題）已知函數(shù)SKIPIF1<0．（1）討論SKIPIF1<0的單調(diào)性；2．（2021·北京·高考真題）已知函數(shù)SKIPIF1<0．（1）若SKIPIF1<0，求曲線SKIPIF1<0在點(diǎn)SKIPIF1<0處的切線方程；（2）若SKIPIF1<0在SKIPIF1<0處取得極值，求SKIPIF1<0的單調(diào)區(qū)間，以及其最大值與最小值．3．（2021·浙江·高考真題）設(shè)a，b為實(shí)數(shù)，且SKIPIF1<0，函數(shù)SKIPIF1<0（1）求函數(shù)SKIPIF1<0的單調(diào)區(qū)間；4．（2021·全國(guó)·高考真題（文））設(shè)函數(shù)SKIPIF1<0，其中SKIPIF1<0.（1）討論SKIPIF1<0的單調(diào)性；5．（2021·全國(guó)·高考真題（理））已知SKIPIF1<0且SKIPIF1<0，函數(shù)SKIPIF1<0．（1）當(dāng)SKIPIF1<0時(shí)，求SKIPIF1<0的單調(diào)區(qū)間；6．（2021·全國(guó)·高考真題（文））已知函數(shù)SKIPIF1<0．（1）討論SKIPIF1<0的單調(diào)性；7．（2021·全國(guó)·高考真題）已知函數(shù)SKIPIF1<0.（1）討論SKIPIF1<0的單調(diào)性；第五部分：第02講導(dǎo)數(shù)與函數(shù)的單調(diào)性（精練）第五部分：第02講導(dǎo)數(shù)與函數(shù)的單調(diào)性（精練）一、單選題1．（2022·廣東·高州市長(zhǎng)坡中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的定義域?yàn)镾KIPIF1<0，其導(dǎo)函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)的圖象如圖所示，則函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)極小值點(diǎn)的個(gè)數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·廣東·高州市長(zhǎng)坡中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0是減函數(shù)的區(qū)間為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·江西·贛州市第一中學(xué)高二階段練習(xí)（文））設(shè)函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0，若對(duì)任意SKIPIF1<0都有SKIPIF1<0成立，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0與SKIPIF1<0的大小關(guān)系不能確定4．（2022·北京交通大學(xué)附屬中學(xué)高二階段練習(xí)）若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞增，則實(shí)數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·湖北省羅田縣第一中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的導(dǎo)函數(shù)為SKIPIF1<0，對(duì)SKIPIF1<0，都有SKIPIF1<0成立，若SKIPIF1<0，則不等式SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·四川·雅安中學(xué)高二階段練習(xí)（文））函數(shù)