二次根式的乘除法-鞏固練習(xí)(提高)(最新整理)

1、二次根式的乘除法（提高）5【鞏固練習(xí)】一、 選擇題1. 若 x 0,b 0) 等于（）.1ab1ab a2b1a. b. ab2abc. d . b- 1m4. 把 m根號外的因式移到根號內(nèi)，得（）mm- m- m30.54a. b -c -d25. 設(shè)= a,= b, 用含 a, b 的式子表示，則下列表示正確的是（）.a. 0.3abb. 3abc. 0.1abd. 0.1a2b6. 若ba - b - 2 3+ (a + b - 2 2)2 = 0 ,那么 a 的值是（）.6a1b.-1c. 5 - 2d. 2- 5660二、 填空題7. 計算30 =, 2a 1a =.0.25a228

2、.=.xx2 + 6x + 59. 若-2004與+互為相反數(shù)，則 x=.x200410. 已知 x + 3 =5，則=.11. 計算(-xb ) （- abx )(-2ab x )(x 0) =.baaxa12. 計算： 2bab5 (- 32a3b ) 3=.三、綜合題13. 若 y =+ +，求的值.2x - 33 - 2x4 - xxy(3m + 1)(2 - m)3m + 12 - m9m2 + 6m + 114. 若9 + 13和9- 13的小數(shù)部分分別是a和b,求ab - 4a - 3b -12的值.15. 若=成立，化簡 m - 4 + m - 2 .【答案與解析】一、選擇題1

3、. 【答案】 a【解析】q x 0,所以 a 0, b 0 ，所以(-xb ) （- abx )(-2abx )(x 0) =-x a 2ab xaxab bx x aa= -2a2b bx = -2ab2 x aab12. 【答案】 -a2bbaab5 a3b ab【解析】 2ab5 (- 3a3b ) 3= - 2 3 1 b2b 2 3ab= -a2b三、解答題.13. 【解析】因為 y =32x - 33 - 2x4 - x10+，所以 2x-30,3-2x0，即 x= ，y=2261036則 x =2 =2=15 .y1010513132214. 【解析】因為9 +13和9- 13的

4、小數(shù)部分分別是a和b ，所以 a = 9 +-12 =- 31313b = 9 - 5 = 4 -13所以 ab - 4a - 3b -12 = (- 3)(4 -13) - 4(- 3) - 3(4 -13) -121313= 6- 37 .15【解析】因為=成立(3m + 1)(2 - m)3m + 12 - m所以3m +10, 2 - m01即- m239m2 + 6m + 1則 m - 4 + m - 2(3m +1)2= 4 - m += 6 - 2m + 3m +1=7+ m+ 2 - m“”“”at the end, xiao bian gives you a passage.

5、 minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional clerical and teaching position, i understand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this document is also edited by my studio profes