VB程序設(shè)計(jì)編程考試題及答案

1、vb程序設(shè)計(jì)編程考試題及答案1. 輸入3個(gè)數(shù)，輸出最大的數(shù)private sub command1_click()dim maxfor i = 1 to 3n = val(inputbox("輸入第" & i & "個(gè)數(shù)")if n > max thenmax = nend ifnextprint "三個(gè)數(shù)中最大的數(shù)是" ; maxend sub2. 有一元二次方程：ax2+bx+c=0，依次輸入a，b，c，判斷此方程是否有實(shí)根private sub command1_click()dim a, b, c, na

2、 = text1b = text2c = text3n = b * b - 4 * a * cif n >= 0 thenlabel4 = "方程有根" else label4 = "方程無(wú)根"end ifend sub3. 輸入一個(gè)百分制的成績(jī)，若大于等于60，則用消息框彈出，顯示“恭喜！成績(jī)通過(guò)！”，若小于60，則彈出消息框，顯示“抱歉！成績(jī)沒(méi)有通過(guò)！private sub form_load()text1 = ""end subprivate sub command1_click()dim nn = text1if n &

3、gt; =60 thenval (msgbox("恭喜！成績(jī)通過(guò)！")elseval (msgbox("抱歉！成績(jī)沒(méi)有通過(guò)！")end ifend sub4. 輸入一年份，判斷它是否為閏年，并顯示有關(guān)信息。（判斷閏年的條件是：年份能被4整除但不能被100整除，或者能被400整除）private sub command1_click()dim y%y = inputbox("請(qǐng)輸入年份")if y mod 4 = 0 and y mod 100 <> 0 or y mod 400 = 0 thenval (msgbox(&q

4、uot;閏年！")elseval (msgbox("平年！")end ifend sub5. 輸入學(xué)生的百分制成績(jī)，轉(zhuǎn)換輸出為五級(jí)制成績(jī)，90100分轉(zhuǎn)換為優(yōu)秀，8089轉(zhuǎn)換為良好，7079轉(zhuǎn)換為中等，6069轉(zhuǎn)換為及格，060轉(zhuǎn)換為不及格。private sub command1_click()a = val(inputbox("請(qǐng)輸入成績(jī)")if a > 100 then print "超出范圍"if a >= 90 and a <= 100 then print "優(yōu)秀"if a

5、>= 80 and a < 90 then print "良好"if a >= 70 and a < 80 then print "中等"if a >= 60 and a < 70 then print "及格"if a < 60 then print "不及格"end sub6. 隨機(jī)產(chǎn)生一個(gè)三位正整數(shù)，然后逆序輸出，產(chǎn)生的數(shù)與逆序數(shù)同時(shí)顯示。例如，產(chǎn)生246，輸出是642。private sub command1_click()dim x%, x1%, x2%, x3%

6、x = text1x1 = x mod 10x2 = (x mod 100) 10x3 = x 100label1 = x1 * 100 + x2 * 10 + x3end sub7. 輸入兩個(gè)整數(shù)，求它們的最大公約數(shù)。private sub command1_click() n1 = inputbox("輸入n") m1 = inputbox("輸入m") if m1 > n1 then m = m1: n = n1 else m = n1: n = m1 end if r = m mod n do while r <> 0 m =

7、n n = r r = m mod n loopprint "m n 的最大公約數(shù)是：" nend sub8. 編程求200-400范圍內(nèi)5的倍數(shù)或7的倍數(shù)之和。(一個(gè)數(shù)如果同時(shí)是7和5的倍數(shù)，則只能加一次。private sub command1_click()for i = 200 to 400if i mod 5 = 0 or i mod 7 = 0 thensum = sum + iend ifnext ifor i = 200 to 400if i mod 5 = 0 and i mod 7 = 0 thensum = sum - iend ifnext ipri

8、nt “倍數(shù)之和=”; sumend sub9. 計(jì)算100300之間所有能被3和7整除的數(shù)之和private sub command1_click()dim isum = 0for i = 100 to 300if i mod 3 = 0 and i mod 7 = 0 thensum = sum + iend ifnext iprint sumend sub10. 分別統(tǒng)計(jì)1-100中，滿足3的倍數(shù)、7的倍數(shù)的數(shù)各有多少。private sub command1_click()dim i, s3, s7s3 = 0s7 = 0for i = 1 to 100if i mod 3 = 0 t

9、hens3 = s3 + 1end ifnext ifor i = 1 to 100if i mod 7 = 0 thens7 = s7 + 1end ifnext iprint "3的倍數(shù)" s3print "7的倍數(shù)" s7end sub11. 某次歌曲大獎(jiǎng)賽，有7個(gè)評(píng)委。如果分別輸入7個(gè)評(píng)委對(duì)某個(gè)參賽者的打分?jǐn)?shù)，按照去掉一個(gè)最高分和一個(gè)最低分的計(jì)算辦法，求出該參賽者的平均得分。private sub command1_click()dim max, a(1 to 7), min, sfor i = 1 to 7a(i) = val(inputbox

10、("輸入第" & i & "個(gè)數(shù)")next imax = a(1)min = a(1)s = a(1)for i = 2 to 7if a(i) > max then max = a(i)if a(i) < min then min = a(i)s = s + a(i)next is = s - min - maxs = s / 5print "平均分" send sub12. 輸入一串字符，統(tǒng)計(jì)其中字母a(不區(qū)分大小寫)出現(xiàn)的次數(shù)。private sub command1_click()dim c as

11、 string, a as integerb = inputbox("請(qǐng)輸入字符")for i = 1 to len(b) c = ucase(mid(b, i, 1) if c = "a" then a = a + 1 end if next i print "a出現(xiàn)的次數(shù)：" aend sub13. 我國(guó)目前有13億人口，按人口年增長(zhǎng)率0.8%計(jì)算，多少年后我國(guó)人口將超過(guò)26億。private sub command1_click()dim a, ia = 13i = 0do while a < 26 a = a * (1.

12、008)i = i + 1loopprint iend sub14. 小猴有桃若干，第一天吃掉一半多一個(gè)；第二天吃剩下桃子的一半多一個(gè)；以后每天都吃尚存桃子的一半多一個(gè)，到第7天只剩一個(gè)，問(wèn)小猴原有桃多少？private sub command1_click()dim a, ia = 1for i = 1 to 6a = 2 * (a + 1)next iprint "小猴原有桃" a;”只”end sub15. 求100以內(nèi)的素?cái)?shù)private sub command1_click()dim i, jfor i = 2 to 100for j = 2 to i - 1if

13、 i mod j = 0 then exit fornext jif j = i then print inext iend sub16. 百元買百雞問(wèn)題。假定小雞每只5角，公雞每只2元，母雞每只3元，編程求解購(gòu)雞方案。private sub command1_click()print "小雞" " " "母雞" " " "公雞"print ""for x = 1 to 100for y = 1 to 100for z = 1 to 100if 0.5 * x + 2 * y

14、 + 3 * z = 100 thenprint "" x; " " y; " " zend ifnext znext ynext xend sub17. 編程求斐波那契數(shù)列前11項(xiàng)。（斐波那契數(shù)列：f(0)=f(1)=1, f(n)=f(n-1)+f(n-2) n>=2 ）private sub command1_click()dim f(11), i as longf(0) = 1f(1) = 1for i = 2 to 10f(i) = f(i - 1) + f(i - 2)next ifor i = 0 to 11pri

15、nt f(i);next iend sub18. 將輸入的字符串以反序顯示。例如：輸入“asdfgt”，顯示“tgfdsa”private sub command1_click()dim a, b, c, d, na = inputbox("輸入字符串")n = len(a)for b = 1 to int(n 2)c = mid(a, b, 1)mid(a, b, 1) = mid(a, n - b + 1, 1) mid(a, n - b + 1, 1) = cnext bprint aend sub19. 隨機(jī)產(chǎn)生10個(gè)30,100內(nèi)的整數(shù)，求最大值及所對(duì)應(yīng)的下標(biāo)pr

16、ivate sub command1_click()dim a(1 to 10), mrandomizefor i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imax = a(1)for i = 2 to 10if a(i) > max then max = a(i): m = inext iprint "max=" maxprint "max的下標(biāo)為" mend sub20. 隨機(jī)產(chǎn)生10個(gè)30,100內(nèi)的整數(shù)，求最大值、最小值和平均值。private sub command1_click(

17、)dim a(1 to 10)for i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imax = a(1)min = a(1)avg = a(1)for i = 2 to 10if a(i) > max then max = a(i)if a(i) < min then min = a(i) avg = avg + a(i)next iavg = avg / 10print "max=" maxprint "min=" minprint "avg=" avgend s

18、ub 21. 隨機(jī)產(chǎn)生10個(gè)30,100內(nèi)的整數(shù)，求最小值及所對(duì)應(yīng)的下標(biāo)。private sub command1_click()dim a(1 to 10), mrandomizefor i = 1 to 10a(i) = int(rnd * 71) + 30print a(i)next imin = a(1)for i = 2 to 10if a(i) < min then min = a(i): m = inext iprint "min=" minprint "min的下標(biāo)為" mend sub22. 隨機(jī)生成一個(gè)整型的二維數(shù)組，范圍在10

19、,20之間，以下三角形式輸出該數(shù)組。private sub command1_click()dim a(1 to 10, 1 to 10), i, j as integerfor i = 1 to 10for j = 1 to 10a(i, j) = int(rnd *11 + 10)nextnextfor i = 1 to 10for j = 1 to iprint spc(3); a(i, j);nextprintnextend sub23. 隨機(jī)產(chǎn)生10個(gè)1100的正整數(shù)放入數(shù)組，顯示產(chǎn)生的數(shù)，求最大值、最小值、平均值。private sub command1_click()dim a(

20、1 to 10)for i = 1 to 10a(i) = int(rnd * 101) + 1print a(i)next imax = a(1)min = a(1)avg = a(1)for i = 2 to 10if a(i) > max then max = a(i)if a(i) < min then min = a(i) avg = avg + a(i)next iavg = avg / 10print "max=" maxprint "min=" minprint "avg=" avgend sub24. 利

21、用隨機(jī)函數(shù)生成一個(gè)4×4的矩陣(即二維矩陣),范圍是20,50內(nèi)的整數(shù),輸出該矩陣所有數(shù)據(jù)之和private sub command1_click()dim a%(4, 5), sumfor i = 1 to 4for j = 1 to 4a(i, j) = int(rnd * 31) + 20print a(i, j);sum = sum + a(i, j)next jprint '換行next iprint "sum=" sumend sub25. 已知有序數(shù)組a()，編程插入x（x的值為14）。數(shù)組a中的元素分別為12，6，4，89，75，63，10

22、0，20，31。private sub command1_click()dim a(), i%, k%, x%, n%a = array(4, 6, 12, 20, 31, 63, 75, 89, 100)n = ubound(a)x = val(inputbox("請(qǐng)輸入所要插入數(shù)")for k = 0 to nif x < a(k) then exit fornext kredim preserve a(n + 1)for i = n to k step -1a(i + 1) = a(i)next ia(k) = xfor i = 0 to n + 1print

23、a(i);next iend sub26. 編寫一函數(shù)，計(jì)算double類型一維數(shù)組所有元素的平均值。27. 編一子過(guò)程procmin,求一維數(shù)組a中的最小值，子過(guò)程的形參自己確定private sub command1_click()dim a(1 to 10), min, i%for i = 1 to 10a(i) = int(rnd * 101)print a(i);next icall procmin(a(), min)printprint "min =" minend sub sub procmin(b(), min)dim i%min = b(lbound(b)for i = lbound(b) + 1 to ubound(b)if b(i