c語言程序代碼

1、精選文檔1. 要求在屏幕上輸出下一行信息。This is a c program.程序:#include<stdio.h>int main()printf(“this is a c program.n”);return 0;2. 求兩個(gè)整數(shù)之和。程序：#include<stdio.h>int main()int a,b,sum;a=122;b=234;sum=a+b;printf(“sum is %dn”,sum);return 0;3. 求兩個(gè)整數(shù)之間的較大者。程序：#include<stdio.h>int main()int max(int x,int

2、y);int a,b,c;scanf("%d,%d",&a,&b);c=max(a,b);printf("max=%dn",c);return 0;int max(int x,int y)int z;if(x>y)z=x;else z=y;return(z);4. 有人用溫度計(jì)測量出華氏發(fā)表示的溫度（如69°F），今要求把她轉(zhuǎn)換成以攝氏法表示的溫度（如20）。公式：c=5（f-32）/9.其中f代表華氏溫度，c代表攝氏溫度。程序：#include<stdio.h>int main()float f,c;f=64

3、.0;c=(5.0/9)*(f-32);printf("f=%fnc=%fn",f,c);return 0;5. 計(jì)算存款利息。有1000元，想存一年。有一下三種方法可選：（1）活期：年利率為r1；（2）一年定期：年利率為r2；（3）存兩次半年定期：年利率為r3。分別計(jì)算一年后按三種方法所得到的本息和。程序：#include<stdio.h>int main()float p0=1000,r1=0.0036,r2=0.0225,r3=0.0198,p1,p2,p3;p1=p0*(1+r1);p2=p0*(1+r2);p3=p0*(1+r3/2)*(1+r3/2)

4、;printf("p1=%fnp2=%fnp3=%fn",p1,p2,p3);return 0;6. 給定一個(gè)大寫字母，要求以小寫字母輸出。程序：#include<stdio.h>int main()char c1,c2;c1=A;c2=c1+32;printf(“%cn”,c2);printf(“%dn”,c2);return 0;7. 給出三角形的三邊長，求三角形的面積。公式：若給定三角形的三邊長，且任意兩邊之長大于第三邊。則：area=ss-as-b(s-c)其中s=(a+b+C)/2.程序：#include<stdio.h>#include&

5、lt;math.h>int main()double a,b,c,area;a=3.67;b=5.43;c=6.21;s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c);printf(“a=%ftb=%ftc=%fn”,a,b,c);printf(“area=%fn”,area);return 0;8. 求ax2+bx+c=0方程的根。a,b,c由鍵盤輸入，設(shè)b2-4ac>0.程序：#include<stdio.h>#include<math.h>int main()double a,b,c,disc,x1,x2,p,q;sc

6、anf(“%lf%lf%lf”,&a,&b,&c);disc=b*b-4*a*c;if(disc<0)printf(“This question has no real rootsn”);elsep=-b/(2.0*a);q=sqrt(disc)/(2.0*a);x1=p+q;x2=p-q;printf(“x1=%7.2fnx2=%7.2fn”,x1,x2);return 0;9. 先后輸出BOY三個(gè)字符。程序：#include<stdio.h>int main()char a=B,b=O,c=Y;putchar(a);putchar(b);putch

7、ar(c);putchar(n);return 0;10. 用三個(gè)getchar函數(shù)先后向計(jì)算機(jī)輸入BOY三個(gè)字符，然后用putchar函數(shù)輸出。程序：#include<stdio.h>int main()char a,b,c;a=getchar();b=getchar();c=getchar();putchar(a);putchar(b);putchar(c);putchar(n);return 0;或#include<stdio.h>int main()putchar(getchar();putchar(getchar();putchar(getchar();put

8、char(n);return 0;11. 用getchar函數(shù)從鍵盤讀入一個(gè)大寫字母，把它轉(zhuǎn)換成小寫字母，然后用getchar函數(shù)輸出對應(yīng)的小寫字母。程序：#include<stdio.h>int main()char c1,c2;c1=getchar();c2=c1+32;putchar(c2);putchar(n);return 0;12. 輸入兩個(gè)實(shí)數(shù)，按代數(shù)值由小到大的順序輸出這兩個(gè)數(shù)。（參照將兩個(gè)杯子中的水互換，必須借助第三個(gè)杯子）。程序：#include<stdio.h>int main()float a,b,t;scanf(“%f,%f”,&a,&

9、amp;b);if(a>b)t=a;a=b;b=t;printf(“%5.2f,%5.2fn”,a,b);return 0;13. 輸入a，b，c三個(gè)數(shù)，要求由小到大的順序輸出。程序：#include<stdio.h>int main()float a,b,c,t;scanf("%f,%f,%f",&a,&b,&c);if(a>b);t=a;a=b;b=t;if(a>c)t=a;a=c;c=t;if(b>c)t=b;b=c;c=t;printf("%5.2f,%5.2f,%5.2fn",a,b,

10、c);return 0;14輸入一個(gè)字符，判斷它是否為大寫字母，如果是，將它轉(zhuǎn)換成小寫字母，如果不是，不轉(zhuǎn)換。然后輸出最后得到的字符。程序：#include<stdio.h>int main()char ch;scanf(“%c”,&ch);ch=(ch>=A&&ch<=Z)?(ch+32):ch;printf(“%cn”,ch);return 0;或#include<stdio.h>int main()char ch;scanf("%c",&ch);if(ch>='A'&&a

11、mp;ch<='Z')printf("%cn",ch+32);elseprintf("%cn",ch);return 0;15.有一個(gè)函數(shù):y=-1 (x<0)0 (x=0) 1 x>0 編一程序。輸入一個(gè)x的值，要求輸出相應(yīng)的y值。程序：#include<stdio.h>int main()int x,y;scanf("%d",&x);if(x<0)y=-1;elseif(x=0)y=0;elsey=1;printf("x=%dny=%dn",x,y);

12、return 0;16.要求按照考試成績的等級輸出百分制分?jǐn)?shù)段，A等為85分以上，B等為70-84分。C等為60-69分，D等為60分以下。成績的等級由鍵盤輸入。程序：#include<stdio.h>int main()char grade;scanf("%c",grade);printf("You score:n");switch(grade)case'A':printf("85100n");break;case'B':printf("7084n");break;ca

13、se'C':printf("6069n");break;case'D':printf("<60n");break;default:printf("enter date errorn");return 0;17.寫一程序，判斷某一年是否為閏年。程序:#include<stdio.h>int main()int leap,year;printf("please enter year:");scanf("%d",&year);if(year%4

14、=0)if(year%100=0)if(year%400=0)leap=1;elseleap=0;else leap=1;else leap=0;if(leap)printf("%d is a leap yearn",year);elseprintf("%d is not a leap yearn",year);return 0;或#include<stdio.h>int main()int leap,year;printf("please enter year:");scanf("%d",&y

15、ear);if(year%4!=0)leap=0;else if(year%100!=0)leap=1;else if(year%400!=0)leap=0;elseleap=1;if(leap=1)printf("%d is a leap yearn",year);elseprintf("%d is not a leap yearn",year);return 0;或#include<stdio.h>int main()int leap,year;printf("please enter year:");scanf(&q

16、uot;%d",&year);if(year%4=0&&year%100!=0)|(year%400=0)leap=1;elseleap=0;if(leap=1)printf("%d is a leap yearn",year);elseprintf("%d is not a leap yearn",year);return 0;18. 求ax2+bx+c=0方程的根。a,b,c由鍵盤輸入。（完整版）程序：#include<stdio.h>#include<math.h>int main()dou

17、ble a,b,c,disc,x1,x2,x3,realpart,imagepart;scanf("%lf,%lf,%lf",&a,&b,&c);printf("The equation");if(fabs(a)<=1e-6)printf("is not a quadratic");elsedisc=b*b-4*a*c;if(fabs(disc)<=1e-6)printf("has two equal roots %8.4fn",-b/2*a);elseif(disc>1e

18、-6)printf("has two distinct real rootsn%8.4f,%8.4f",x1,x2);x1=(-b+sqrt(disc)/2*a;x2=(-b-sqrt(disc)/2*a;elserealpart=-b/2*a;imagepart=sqrt(-disc)/2*a;printf("has two complex roots:n");printf("%8.4f+%8.4fin",realpart,imagepart);printf("%8.4f-%8.4fin",realpart,im

19、agepart);return 0;/注釋：由于b*b-4*a*c（disc）是實(shí)數(shù)，而實(shí)數(shù)在計(jì)算和存儲(chǔ)時(shí)會(huì)有一些微小的誤差，因此不能直接進(jìn)行如下判斷：/“if（disc=0）",因?yàn)檫@樣可能出現(xiàn)本來是零的量，由于上述誤差而判別為不等于零而導(dǎo)致結(jié)果錯(cuò)誤，/所以采取的辦法是判別disc的絕對值（fabs（disc）是否小于一個(gè)很小的數(shù)（例如：1e-6）。如果小于此數(shù)，則認(rèn)為disc=0.19.給出一個(gè)不多出5位的正整數(shù)，要求：（1）：求出它是幾位數(shù);（2）：分別輸出每一位數(shù)字；（3）：按逆序輸出各位數(shù)字，例如原數(shù)為321，輸出123。程序：#include<stdio.h>

20、int main()int num,indiv,ten,hundred,thousand,ten_thousand,place;printf("請輸入一個(gè)正整數(shù)(099999)：");scanf("%d",&num);if(num>9999)place=5;else if(num>999)place=4;else if(num>99)place=3;else if(num>9)place=2;elseplace=1;printf("位數(shù)為:%dn",place);ten_thousand=num/100

21、00;thousand=(num-ten_thousand*10000)/1000;hundred=(num-ten_thousand*10000-thousand*1000)/100;ten=(num-ten_thousand*10000-thousand*1000-hundred*100)/10;indiv=(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);printf("每一個(gè)數(shù)字分別為：");printf("%d,%d,%d,%d,%dn",ten_thousand,thousand,hundred,ten,indiv);switch(place)case 5:printf("