用C語言實現(xiàn)矩陣運算

1、精選/任務(wù)二：矩陣的基本運算#include<stdio.h>#include<stdlib.h>#define R1 4/矩陣MA行數(shù)，可以按具體狀況修改#define C1 4/矩陣MA列數(shù)，可以按具體狀況修改#define R2 4/矩陣MB行數(shù)，可以按具體狀況修改#define C2 4/矩陣MB列數(shù)，可以按具體狀況修改 void Scalar(float MAC1);void Transposition(float MAC1);void Add(float MAC1,float MBC2);void Subtraction(float MAC1,float M

2、BC2);void Multiplication(float MAC1,float MBC2);void main()float MAR1C1,MBR2C2;int c;while(1) printf("功能如下：n"); printf("數(shù)乘矩陣 1n"); printf("矩陣轉(zhuǎn)換 2n"); printf("矩陣相加 3n"); printf("矩陣相減 4n"); printf("矩陣乘法 5n"); printf("結(jié)束 0n"); printf

3、("請選定您需要的操作:n"); scanf("%d",&c); switch(c) case 1: Scalar(MA); break; case 2: Transposition(MA); break; case 3: if(R1=R2)&&(C1=C2) Add(MA,MB); else printf("矩陣MA與矩陣MB不能相減!n"); break; case 4: if(R1=R2)&&(C1=C2) Subtraction(MA,MB); else printf("矩陣M

4、A與矩陣MB不能相加!n"); break; case 5: if(C1=R2) Multiplication(MA,MB); else printf("矩陣MA與矩陣MB不能相乘!n"); break; case 0: printf("結(jié)束!n"); exit(0); break; default: printf("對不起，您的輸入不合法!n"); break; void Scalar(float MAC1)/矩陣數(shù)乘函數(shù)int i,j,k;printf("請輸入乘數(shù):n");scanf("%

5、d",&k);printf("請輸入%d*%d矩陣MA(每行以回車結(jié)束):n",R1,C1);for(i=0;i<R1;i+)for(j=0;j<C1;j+)scanf("%f",&MAij);printf("%d乘矩陣MA結(jié)果為:n",k);for(i=0;i<R1;i+)for(j=0;j<C1;j+)printf("%6.2f ",k*MAij);printf("n");void Transposition(float MAC1)/矩陣轉(zhuǎn)置

6、函數(shù)int i,j;float MDC1R1=0;printf("請輸入%d*%d矩陣MA(每行以回車結(jié)束):n",R1,C1);for(i=0;i<R1;i+)for(j=0;j<C1;j+)scanf("%f",&MAij);for(i=0;i<R1;i+)/將矩陣MA的第n行的值賦給矩陣MD的第n列for(j=0;j<C1;j+)MDji=MAij;printf("矩陣MA轉(zhuǎn)置后的結(jié)果為:n");for(i=0;i<C1;i+)for(j=0;j<R1;j+)printf("

7、%6.2f ",MDij);printf("n");void Add(float MAC1,float MBC2)/矩陣加法函數(shù)int i,j;float MER1C1=0;printf("請輸入%d*%d矩陣MA(每行以回車結(jié)束):n",R1,C1);for(i=0;i<R1;i+)for(j=0;j<C1;j+)scanf("%f",&MAij); printf("請輸入%d*%d矩陣MB(每行以回車結(jié)束):n",R2,C2);for(i=0;i<R2;i+)for(j=0;

8、j<C2;j+)scanf("%f",&MBij); for(i=0;i<R1;i+)for(j=0;j<C1;j+)MEij=MAij+MBij;for(i=0;i<R1;i+)for(j=0;j<C1;j+) printf("%6.2f ",MEij);printf("n");void Subtraction(float MAC1,float MBC2)/矩陣減法函數(shù)int i,j;float MFR1C1=0;printf("請輸入%d*%d矩陣MA(每行以回車結(jié)束):n"

9、;,R1,C1);for(i=0;i<R1;i+)for(j=0;j<C1;j+)scanf("%f",&MAij); printf("請輸入%d*%d矩陣MB(每行以回車結(jié)束):n",R2,C2);for(i=0;i<R2;i+)for(j=0;j<C2;j+)scanf("%f",&MBij); for(i=0;i<R1;i+) for(j=0;j<C1;j+) MFij=MAij-MBij;for(i=0;i<R1;i+)for(j=0;j<C1;j+) print

10、f("%6.2f ",MFij);printf("n");void Multiplication(float MAC1,float MBC2)/矩陣相乘函數(shù)int i,j,k;float MGR1C2=0;printf("請輸入%d*%d矩陣MA(每行以回車結(jié)束):n",R1,C1);for(i=0;i<R1;i+)for(j=0;j<C1;j+)scanf("%f",&MAij); printf("請輸入%d*%d矩陣MB(每行以回車結(jié)束):n",R2,C2);for(i=0;i<R2;i+)for(j=0;j<C2;j+)scanf("%f",&MBij); for(i=0;i