冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件

一輪復(fù)習(xí)講義冪函數(shù)

一輪復(fù)習(xí)講義冪函數(shù)1憶一憶知識(shí)要點(diǎn)憶一憶知識(shí)要點(diǎn)2憶一憶知識(shí)要點(diǎn)憶一憶知識(shí)要點(diǎn)3RRRRR奇函數(shù)偶函數(shù)奇函數(shù)奇函數(shù)非奇非偶函數(shù)增增增RRRRR奇函數(shù)偶函數(shù)奇函數(shù)奇函數(shù)非奇非偶函數(shù)增增增4冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件5冪函數(shù)的定義及應(yīng)用

冪函數(shù)的定義及應(yīng)用6冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件7冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件8冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件9冪函數(shù)的圖象及性質(zhì)的簡單應(yīng)用

冪函數(shù)的圖象及性質(zhì)的簡10冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件11冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件12冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件13利用冪函數(shù)的性質(zhì)比較冪值的大小

利用冪函數(shù)的性質(zhì)比較14冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件15冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件16冪函數(shù)的綜合應(yīng)用

冪函數(shù)的綜合應(yīng)用17冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件18冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件19冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件20冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件2105利用轉(zhuǎn)化思想求參數(shù)范圍

05利用轉(zhuǎn)化思想求參數(shù)范圍22冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件23冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件24冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件25冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件26冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件271.冪函數(shù)的圖象特征憶一憶知識(shí)要點(diǎn)1.冪函數(shù)的圖象特征憶一28例1.右圖是冪函數(shù)的示意圖,試求n的值.解：∵函數(shù)圖象不過原點(diǎn),∴n2-2n-3<0.∴-1<n<3.∵n∈Z∴n=0,1,2.當(dāng)n=1時(shí),

n2-2n-3=-4,即f(x)=x–4適合題意.∴n=1.當(dāng)n=0,2時(shí),

n2-2n-3=-3,即f(x)=x–3不合題意.xoy例1.右圖是冪函數(shù)29【1】下列函數(shù)圖象中,表示的是().④④xyoxyoxyoxyo②①③練一練【1】下列函數(shù)圖象中,表示的是()30練一練練一練31【3】指出函數(shù)的單調(diào)區(qū)間,并比較的大小.其圖象可由冪函數(shù)y=x-2的圖象向左平移2個(gè)單位,再向上平移1個(gè)單位得到，該函數(shù)在(-2,+∞)上是減函數(shù),在(-∞,-2)上是增函數(shù),且其圖象關(guān)于直線x=-2對(duì)稱(如圖所示).<練一練【3】指出函數(shù)的單調(diào)區(qū)間,并32【2】(山東文13)

設(shè)函數(shù)則1，3

【2】(山東文13)設(shè)函數(shù)則1，333解題是一種實(shí)踐性技能,就象游泳、滑雪、彈鋼琴一樣，只能通過模仿和實(shí)踐來學(xué)到它！——波利亞解題是一種實(shí)踐性技能,就象游泳、滑雪、彈鋼琴一樣，只34冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件35一輪復(fù)習(xí)講義冪函數(shù)

一輪復(fù)習(xí)講義冪函數(shù)36憶一憶知識(shí)要點(diǎn)憶一憶知識(shí)要點(diǎn)37憶一憶知識(shí)要點(diǎn)憶一憶知識(shí)要點(diǎn)38RRRRR奇函數(shù)偶函數(shù)奇函數(shù)奇函數(shù)非奇非偶函數(shù)增增增RRRRR奇函數(shù)偶函數(shù)奇函數(shù)奇函數(shù)非奇非偶函數(shù)增增增39冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件40冪函數(shù)的定義及應(yīng)用

冪函數(shù)的定義及應(yīng)用41冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件42冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件43冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件44冪函數(shù)的圖象及性質(zhì)的簡單應(yīng)用

冪函數(shù)的圖象及性質(zhì)的簡45冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件46冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件47冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件48利用冪函數(shù)的性質(zhì)比較冪值的大小

利用冪函數(shù)的性質(zhì)比較49冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件50冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件51冪函數(shù)的綜合應(yīng)用

冪函數(shù)的綜合應(yīng)用52冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件53冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件54冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件55冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件5605利用轉(zhuǎn)化思想求參數(shù)范圍

05利用轉(zhuǎn)化思想求參數(shù)范圍57冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件58冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件59冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件60冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件61冪函數(shù)高考數(shù)學(xué)一輪復(fù)習(xí)課件621.冪函數(shù)的圖象特征憶一憶知識(shí)要點(diǎn)1.冪函數(shù)的圖象特征憶一63例1.右圖是冪函數(shù)的示意圖,試求n的值.解：∵函數(shù)圖象不過原點(diǎn),∴n2-2n-3<0.∴-1<n<3.∵n∈Z∴n=0,1,2.當(dāng)n=1時(shí),

n2-2n-3=-4,即f(x)=x–4適合題意.∴n=1.當(dāng)n=0,2時(shí),

n2-2n-3=-3,即f(x)=x–3不合題意.xoy例1.右圖是冪函數(shù)64【1】下列函數(shù)圖象中,表示的是().④④xyoxyoxyoxyo②①③練一練【1】下列函數(shù)圖象中,表示的是()65練一練練一練66【3】指出函數(shù)的單調(diào)區(qū)間,并比較的大小.其圖象可由冪函數(shù)y=x-2的圖象向左平移2個(gè)單位,再向上平移1個(gè)單位得到，該函數(shù)在(-2,+∞)上是減函數(shù),在(-∞,-2)上是增函數(shù),且其圖象關(guān)于直線x=-2對(duì)稱(如圖所示).<練一練【3】指出函數(shù)的單調(diào)區(qū)間,并67【2】(山東文13)

設(shè)函數(shù)則1