精品解析2022年人教版九年級化學(xué)下冊第十單元酸和堿定向測評試卷(含答案詳細(xì)解析)

經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁眉頁腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請聯(lián)系刪除，謝謝！人教版九年級化學(xué)下冊第十單元酸和堿定向測評I第I卷（選擇題30分）3222和4D第Ⅱ卷（非選擇題70分）45B5X3223222323232的3O+2HO+4CuCl+2NaCO2CuOHCO+4X=22223232和32223332②2CuOHCl+3HSO3CuSO+CuCl+6HOCuOHCO+2HSO2CuSO+3HO+CO=；=224422232442232AC32232cff若O3222和2233與2與212222取BB和H2424CABCDABC項(xiàng)DABCD3222但CO2HSO2244和444+CaOHO=CaOH＝O3222232232+CaOHO=CaOH22O2232堿222；2點(diǎn)燃2C+O2CO24Al+3O=2AlO223CaO+HO=Ca(OH)22點(diǎn)燃2C+O；2CO24Al+3O=2AlO322CaO+HO=Ca(OH)2。2O3222O2332232O。332x。H）O24242x98x17120g17.1%1.96g20g。100%9.8%y。22HCl+Ba）+2HO22217140g208y171208y為2HSO+2NaOHNaSO+2HO=24242、++SO2-498X800.8gzHSO+2NaOH=NaSO+2HO424214228016g5%z142z8016g5%z1.42g1.42g加100%2.84%10g+16g+24g=。HSO+2NaOHNaSO+2HO24242a點(diǎn)aH、+。+SO2-4HSO+2NaOHNaSO+2HO242429880X16g5%98X800.8g0.98g10g100%9.8%。yyyxHCl+NaOH=NaCl+HO236.540x20g4%36.5x400.8g1B點(diǎn)x。+=+H22x2x2x35.536.57195x設(shè)FeO+6HCl=2FeCl+3HO321603221916gx16016g219xFeO+6HCl=2FeCl+3HO323216016g219xyFeO+6HCl=2FeCl+3HO321603232516gy16016g325yFeO+6HCl=2FeCl+3HO3；23216016g；219x16g100%40%；40g2NaOH+HSO=NaSO+2HO42422；2NaOH+HSO=NaSO+2HO42422x2CuOHCO+2HSO=2CuSO+3HO+CO2324422442222x0.22g222x440.22gx1.11g1.2g-1.11g1.2g3100%7.5%23232232XX為32B23f32f23NaOHHClNaClHO2氫NaOHHClNaClHO2NaOHHClNaClHO。22NaCOCaOH32NaOHCaCO22332水23N