中央電大《微積分初步》模擬試題21

經典word整理文檔，僅參考，雙擊此處可刪除頁眉頁腳。本資料屬于網絡整理，如有侵權，請聯(lián)系刪除，謝謝！微積分初步模擬試卷一41f(x)ln(x)1fx3x2)ln(x1x20x2f(x))ln(x223xxy=．x1x1f(x)x在0f(x)x在x00xxf(x)f(x)f(x)000xx0xx0x10f(x)x1(在12kf(x)yf(x)x11()fx，將0代入上式得(0)xf22x1f(x)dxcos2xcf(x)．42x(x)2xc)22x：ffxx()(22)4cos2x()02y34yxxB１/9f(x)xsin(x)xxf(x)yxxxf(x)limf(x)（.2xx01．12Axx1112212xx2x0x0y(x2(2,2)）C2(y0xx121y0yx1x2y0sxx．indedxx．20011dx．x．x11xBsxxindcosxcos1001111122ed2xxe2x22e2001dxx1x011dx2x2x101yy）1x2cyy；yx2c；2ecyce1xxD1yy()()1pxqx(x)ex，ep(x)exp(x)dxxp，e２/9p(x)dxyep(x)dx[q(x)edxc]e(edxc)e(ec)1cexxxxx3x21⒈limx2．x2x13x2(xx2)(xxx2x11limx2limlim解12x2x1x1x13⒉設y解yxlncosx.y231321x21(sin)xx2tanx2cosxexdx5exexd(5ex)dxx25ec解x5ex5exdxx20解xdxxxdxx12220200034m4hShxx2S(x)x4x,22x()2Sxxx2()0令Sxx2，xh1.S(2).３/9微積分初步模擬試卷二4f(xx2xf(x)．2x21f(xx2x(x122f(x)x122xsink,x0(x)x0k．fx在x022lim(xk)0kf(0)20kxx0f(x)x1(在12kf(x)yf(x)x11()fx，將x0代入上式得(0)f22x1⒋152)dx3xx．14此21dx4x41=02()sin02y3y4x1y232xx．x2．Dx1．x2x0且x2x1．且x1232x1yxx20(xxxx４/91f．0(x)xlimf(x)（.xx1．12Csin11limf(x)limxsinlimx11x10xxxxyx4x7(）2Cy24y0x250xyx2xy011x．x．x23x1111dx．x．x11xA1x1.011x2x111323.dxx2323x111.xxx111dx2xx.211）yx；ye；yxyyyBxyxyyy、y的５/96x8x2⒈limx2．x2x16x8x2(x2)(x4)(x2)(x(x4)(x23limx2limlim解x2x1x2x2cos5xln3xy.⒉設y3lnx2(cos5)(ln)sin5)3ln(ln)5sin5解yx3xxx2xxxxsinxdx.xsinxdx=2sindxx2cosxc解xxdx20xdxxsinxsindxx1解2220202200M62.5yxh2xh62.5，hx262.5yx4x4xx222x2x2yxx2令y0x5x5hx5h2.5，52６/9微積分初步期末模擬試卷三41f(x)4x2(2,2)xx24x201xx2f(x)(2,2)。4x24x2k．x024x4x444xkkx02k2。x0f(x)xf(x)．1x2111())()()fxx，fxxxx2sinxdx．cosxc提示：sinxdxcosxc()sinxe3y4xy4yxxBf(x)xsin(x)xxf(x)yxx02xxx0.k=（f(x)kx01．01B７/9lim(x1f(0)kk1。2x0()0fxfx()(x)()daffxx（）-a0f(x)dxB．0f(x)dx．f(x)dx0a2．-a-a01yy）yxC；y12；xCyeCx1；yCe1x2Bp(x)q(x)p(x)dxx,ep(x)p(x)exexep(x)dxyep(x)dx[q(x)edxc]e(edxc)e(ec)ce1xxxxx3x24limx2．x2x23x2(xx2)(x2)(x2)x11limx2limlim解4x24x2x2x2x2sin5xcosxy.y35cos53cos(sin)5cos53解yx2xxxx2xx)2