![VHDL語言設(shè)計(jì)信號(hào)發(fā)生器實(shí)驗(yàn)報(bào)告_第1頁](http://file4.renrendoc.com/view/f3d0d5042271e3817c6aeb1b91910522/f3d0d5042271e3817c6aeb1b919105221.gif)
![VHDL語言設(shè)計(jì)信號(hào)發(fā)生器實(shí)驗(yàn)報(bào)告_第2頁](http://file4.renrendoc.com/view/f3d0d5042271e3817c6aeb1b91910522/f3d0d5042271e3817c6aeb1b919105222.gif)
![VHDL語言設(shè)計(jì)信號(hào)發(fā)生器實(shí)驗(yàn)報(bào)告_第3頁](http://file4.renrendoc.com/view/f3d0d5042271e3817c6aeb1b91910522/f3d0d5042271e3817c6aeb1b919105223.gif)
![VHDL語言設(shè)計(jì)信號(hào)發(fā)生器實(shí)驗(yàn)報(bào)告_第4頁](http://file4.renrendoc.com/view/f3d0d5042271e3817c6aeb1b91910522/f3d0d5042271e3817c6aeb1b919105224.gif)
![VHDL語言設(shè)計(jì)信號(hào)發(fā)生器實(shí)驗(yàn)報(bào)告_第5頁](http://file4.renrendoc.com/view/f3d0d5042271e3817c6aeb1b91910522/f3d0d5042271e3817c6aeb1b919105225.gif)
版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
VHDL語言設(shè)計(jì)信號(hào)發(fā)生器試驗(yàn)報(bào)告VHDL語言設(shè)計(jì)信號(hào)發(fā)生器,波、鋸齒波的變換。VHDL設(shè)計(jì)多功能信號(hào)發(fā)生器一、設(shè)計(jì)任務(wù)VHDL(EDA6000試驗(yàn)箱)設(shè)計(jì)一個(gè)多功能信號(hào)發(fā)生器,要求:輯的特定波形(選作);100Hz~200KHz,且輸出頻率可以調(diào)整;具有顯示輸出波形、頻率的功能。(選作)二、系統(tǒng)頂層框圖弦波的數(shù)字幅度信息,每個(gè)查找表的地址對(duì)應(yīng)正(余)弦波幅度信號(hào),同時(shí)輸出到數(shù)模轉(zhuǎn)換器(DAC)輸入端,DAC輸出的模擬信號(hào)經(jīng)過低通濾波器(LPF),可以得到一個(gè)頻譜純潔的正(余)弦波。二、設(shè)計(jì)步驟用VHDL語言結(jié)合原理圖設(shè)計(jì)實(shí)現(xiàn)一個(gè)函數(shù)信號(hào)發(fā)生器,輸出正方波發(fā)生鄧各個(gè)模塊分別用VHDL語言編程為一個(gè)子程序,并把每一個(gè)模塊轉(zhuǎn)換成圖形文件,然后在原理圖編輯框調(diào)用這些圖形模塊,連接18f〔7...0〕,6、按鍵7、按鍵8掌握dlt、sin、sqr波形選通,最終把八位輸出接DAC0832D/A轉(zhuǎn)換,從示波器上就能看到波形輸出。按下不同的按鍵輸出不同的波形及頻率。三、系統(tǒng)設(shè)計(jì)(1)數(shù)控分頻器模塊DIN,來轉(zhuǎn)變輸出頻率。假設(shè)分頻系數(shù)為N,波形存儲(chǔ)模塊存儲(chǔ)一個(gè)周期的波形,試驗(yàn)里依據(jù)一個(gè)64foutfclk64.N(2).(存儲(chǔ)波形數(shù)據(jù))采樣點(diǎn)。080255;64個(gè)時(shí)鐘周期為一個(gè)三8.鋸齒波的存儲(chǔ)數(shù)據(jù)與三角波類似。0132個(gè)周期的延時(shí)來實(shí)現(xiàn)。正弦波:要通過波形變換實(shí)現(xiàn)把sina變換成(cosa1)*127.5的形式8位二進(jìn)制碼,存儲(chǔ)在波形存儲(chǔ)器里。(3)數(shù)據(jù)選擇器模塊3個(gè)按鍵來掌握波形選擇(4).LED(選作)LED顯示模塊主要是完成頻率掌握字的顯示,由于本次試驗(yàn)承受八位的由鍵盤輸入的頻率掌握字,累計(jì)尋址,讀取8256小,而恰好此時(shí)的頻率掌握字就是系統(tǒng)輸出波形的頻率,所以,LED8位二進(jìn)BCD碼。四、試驗(yàn)內(nèi)容設(shè)計(jì)程序libraryieee;useieee.std_logic_1164.all;useieee.std_logic_unsigned.all;entityVhdl1isport(clk,sel:instd_logic;pout:outintegerrange255downto0);end;architecturedaccofVhdl1issignalq:integerrange63downto0;signalq1:integerrange2downto0;signald:integerrange255downto0;beginprocess(clk)beginifclk”eventandclk=”1”thenifq<63>elseqendif;endif;endprocess;process(sel)beginifsel”eventandsel=”1”thenifq1<3>elseq1<=0;endif;endif;endprocess;process(q,q1)begincaseq1iswhen0=>正弦波caseqiswhen00=>d<=255;>d<=254;>d<=252;>d<=249;>d<=245;>d<=239;>d<=233;>d<=225;>d<=217;>d<=207;>d<=197;>d<=186;>d<=174;>d<=162;>d<=150;>d<=137;>d<=124;>d<=112;>d<=99;>d<=87;>d<=75;>d<=64;>d<=53;>d<=43;>d<=34;>d<=26;>d<=19;>d<=13;>d<=8;>d<=4;>d<=1;>d<=0;when63=>d<=255;>d<=254;>d<=252;>d<=249;>d<=245;>d<=239;>d<=233;>d<=225;>d<=217;>d<=207;>d<=197;>d<=186;>d<=174;>d<=162;>d<=150;>d<=137;>d<=124;>d<=112;>d<=99;>d<=87;>d<=75;>d<=64;>d<=53;>d<=43;>d<=34;>d<=26;>d<=19;>d<=13;>d<=8;>d<=4;>d<=1;>d<=0;>null;endcase;when1=>方波caseqiswhen00=>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=225;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;>d<=255;when63=>d<=0;>d<=0;>d<=0;>d<=0;when59=>d<=0;>d<=0;>d<=0;>d<=0;when55=>d<=0;>d<=0;>d<=0;>d<=0;when51=>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>d<=0;>null;endcase;when2=>三角波caseqiswhen00=>d<=0;>d<=1;>d<=2;>d<=3;when04=>d<=4;>d<=5;>d<=6;>d<=7;when08=>d<=8;>d<=9;>d<=10;>d<=11;>d<=12;>d<=13;>d<=14;>d<=15;>d<=16;>d<=17;>d<=18;>d<=19;>d<=20;>d<=21;>d<=22;>d<=23;>d<=24;>d<=25;>d<=26;>d<=27;>d<=28;>d<=29;>d<=30;>d<=31;when62=>d<=0;>d<=1;>d<=2;when59=>d<=3;>d<=4;>d<=5;>d<=6;>d<=7;>d<=8;>d<=9;>d<=10;>d<=11;>d<=12;>d<=13;>d<=14;>d<=15;>d<=16;>d<=17;>d<=18;>d<=19;>d<=20;>d<=21;>d<=22;>d<=23;>d<=24;>d<=25;>d<=26;>d<=27;>d<=28;>d<=29;>d<=30;>null;endcase;when2=>鋸齒波caseqiswhen00=>d<=0;>d<=3;>d<=6;>d<=9;>d<=12;>d<=15;>d<=18;>d<=21;>d<=24;>d<=27;>d<=30;>d<=33;>d<=36;>d<=39;>d<=42;>d<=45;>d<=44;>d<=43;>d<=42;>d<=41;>d<=40;>d<=39;>d<=38;>d<=37;>d<=36;>d<=35;>d<=34;>d<=33;>d<=32;>d<=31;>d<=30;>d<=29;when62=>d<=28;>d<=27;>d<=26;when59=>d<=25;>d<=24;>d<=23;>d<=22;>d<=21;>d<=20;>d<=19;>d<=18;>d<=17;>d<=16;>d<=15;>d<=14;>d<=13;>d<=12;>d<=11;>d<=
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- 臨床中藥學(xué)模擬練習(xí)題(含答案)
- 電商平臺(tái)的用戶體驗(yàn)設(shè)計(jì)與優(yōu)化技巧
- 知識(shí)產(chǎn)權(quán)教育在人才培養(yǎng)中的重要性
- 環(huán)境科學(xué)教育培養(yǎng)未來環(huán)保領(lǐng)袖
- 文山學(xué)院《機(jī)器人基礎(chǔ)原理》2023-2024學(xué)年第二學(xué)期期末試卷
- 電梯維修中的故障診斷與應(yīng)急處理
- 浙江工商大學(xué)《法理學(xué)專題研究》2023-2024學(xué)年第二學(xué)期期末試卷
- 中國過濾設(shè)備行業(yè)發(fā)展監(jiān)測(cè)及投資方向研究報(bào)告
- 山東工商學(xué)院《油罐及管道強(qiáng)度設(shè)計(jì)》2023-2024學(xué)年第二學(xué)期期末試卷
- 知識(shí)產(chǎn)權(quán)保護(hù)教育領(lǐng)域的發(fā)展與挑戰(zhàn)
- 縣城屠宰場(chǎng)建設(shè)可行性研究報(bào)告
- 25學(xué)年六年級(jí)數(shù)學(xué)寒假作業(yè)《每日一練》
- 2025高考數(shù)學(xué)一輪復(fù)習(xí)-第8章-第3節(jié) 圓的方程【課件】
- DB3301T 1088-2018 杭州龍井茶栽培技術(shù)規(guī)范
- 環(huán)保行業(yè)深度研究報(bào)告
- 工程機(jī)械租賃服務(wù)方案及保障措施 (二)
- 保障性住房補(bǔ)貼委托書范本
- DB36T 1393-2021 生產(chǎn)安全風(fēng)險(xiǎn)分級(jí)管控體系建設(shè)通則
- 公益捐助活動(dòng)影響力評(píng)估方法
- 國家電網(wǎng)安全培訓(xùn)
- 《中醫(yī)養(yǎng)生學(xué)》課件
評(píng)論
0/150
提交評(píng)論