復(fù)數(shù)四則運(yùn)算

問題描述：設(shè)計(jì)一個(gè)可進(jìn)行有理數(shù)運(yùn)算的演示程序。基本要求：實(shí)現(xiàn)下列六種基本運(yùn)算：1）由輸入的實(shí)部和虛部生成一個(gè)復(fù)數(shù)；2）兩個(gè)復(fù)數(shù)求和；3）兩個(gè)復(fù)數(shù)求差；4）兩個(gè)復(fù)數(shù)求積；5）從已知復(fù)數(shù)中分離出實(shí)部；6）從已知復(fù)數(shù)中分離出虛部。運(yùn)算結(jié)果發(fā)相應(yīng)的復(fù)數(shù)或褸的表示形式顯示。程序的邏輯框圖窗口初始化窗口初始化輸入數(shù)據(jù)輸入數(shù)據(jù)實(shí)部虛部實(shí)部虛部選擇功能選擇功能voidAddComplex(Complex&sum,Complexc1,Complexc2)//求和運(yùn)算voidAddComplex(Complex&sum,Complexc1,Complexc2)//求和運(yùn)算voidSubtract_C(Complex&Sub,Complexc1,Complexc2)//求差運(yùn)算voidMultiple_C(Complex&product,Complexc1,Complexc2)//求積運(yùn)算voidDivide_C(Complex&product,Complexc1,Complexc2)//求商運(yùn)算調(diào)用判斷功能調(diào)用判斷功能根據(jù)所選功能執(zhí)行相應(yīng)操作根據(jù)所選功能執(zhí)行相應(yīng)操作結(jié)束結(jié)束四、程序源代碼#include<stdio.h>#include<stdlib.h>typedefstructComplex//抽象數(shù)據(jù)類型定義{ floatreal;//數(shù)據(jù)對(duì)象 floatimage;}Complex;voidCreatComplex(Complex&c,floata,floatb)//構(gòu)造二元組{ c.real=a;//實(shí)部 c.image=b;//虛部}voidAddComplex(Complex&sum,Complexc1,Complexc2)//求和運(yùn)算{ sum.real=c1.real+c2.real; sum.image=c1.image+c2.image;}voidSubtract_C(Complex&Sub,Complexc1,Complexc2)//求差運(yùn)算{ Sub.real=c1.real-c2.real; Sub.image=c1.image-c2.image;}voidMultiple_C(Complex&product,Complexc1,Complexc2)//求積運(yùn)算{ product.real=c1.real*c2.real-c1.image*c2.image; product.image=c1.real*c2.image+c1.image*c2.real;}voidDivide_C(Complex&product,Complexc1,Complexc2)//求商運(yùn)算{ product.real=(c1.real*c2.real+c1.image*c2.image)/(c1.image*c1.image+c2.image*c2.image); product.image=(c1.real*c2.real-c1.image*c2.image)/(c1.image*c1.image+c2.image*c2.image);}voidPrint_C(Complexc)//輸出運(yùn)算結(jié)果{ if(c.real==0.0&&c.image==0.0)printf("0\n"); if(c.real==0.0&&c.image!=0.0)printf("i%f\n",c.image); if(c.real!=0.0&&c.image==0.0)printf("%f\n",c.real); if(c.real!=0.0&&c.image!=0.0)printf("%f+i%f\n",c.real,c.image);}voidmain()//主函數(shù){ intchoice; floata,b,c,d; Complexc1,c2,sum,Sub,Prod; printf("*************復(fù)數(shù)四則運(yùn)算***************\n"); printf("*1.兩復(fù)數(shù)求和*\n"); printf("*2.兩復(fù)數(shù)求差*\n"); printf("*3.兩復(fù)數(shù)求積*\n"); printf("*4.兩復(fù)數(shù)求商*\n"); printf("*5.求復(fù)數(shù)實(shí)部*\n"); printf("*6.求復(fù)數(shù)虛部*\n"); printf("*0.退出系統(tǒng)*\n"); printf("****************************************\n"); printf("請(qǐng)分別輸入第一個(gè)復(fù)數(shù)的實(shí)部和虛部:"); scanf("%f%f",&a,&b);CreatComplex(c1,a,b); printf("第一個(gè)復(fù)數(shù)為:");Print_C(c1); printf("請(qǐng)分別輸入第二個(gè)復(fù)數(shù)的實(shí)部和虛部:"); scanf("%f%f",&c,&d);CreatComplex(c2,c,d); printf("第二個(gè)復(fù)數(shù)為:");Print_C(c2); for(;;) { printf("請(qǐng)輸入你選擇的功能:"); scanf("%d",&choice); switch(choice) { case0:exit(0); break; case1:AddComplex(sum,c1,c2); printf("求和后結(jié)果為:"); Print_C(sum); break; case2:Subtract_C(Sub,c1,c2); printf("求差后結(jié)果為:"); Print_C(Sub); break; case3:Multiple_C(Prod,c1,c2); printf("求積后結(jié)果為:"); Print_C(Prod); break; case4:Divide_C(Prod,c1,c2); printf("求商后結(jié)果為:"); Print_C(Prod); break; case5:printf("請(qǐng)輸入復(fù)數(shù)的實(shí)部和虛部:"); scanf("%f%f",&a,&b);p