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PARTⅠ:ChoiceB
1.Whichofthefollowingservicesdoesnotthetransportlayerprovidefortheapplicationlayer?A.In-orderdeliveryofdatasegmentsbetweenprocessesB.BesteffortdeliveryofdatasegmentsbetweencommunicatinghostsC.MultiplexinganddemultiplexingoftransportlayersegmentsD.CongestioncontrolA
2.WhatarethetwoofthemostimportantprotocolsintheInternet?
A.TCPandIP
B.TCPandUDP
C.TCPandSMTP
D.ARPandDNSC
3.TheInternetprovidestwoservicestoitsdistributedapplications:aconnectionorientedreliableserviceanda(
).
A.connectionorientedunreliableservice
B.connectionlessreliableservice
C.connectionlessunreliableservice
D.InorderdatatransportserviceD
4.Processesontwodifferentendsystemscommunicatewitheachotherbyexchanging(
)acrossthecomputernetwork.
A.packets
B.datagram
C.frames
D.messagesA
5.Thejobofdeliveringthedatainatransport-layersegmenttothecorrectsocketiscalled(
).A.demultiplexing
B.multiplexing
C.TDM
D.FDMC
6.TwoimportantreasonsthattheInternetisorganizedasahierarchyofnetworksforthepurposesofroutingare:A.LeastcostandmaximumfreecircuitavailabilityB.MessagecomplexityandspeedofconvergenceC.ScaleandadministrativeautonomyD.LinkcostchangesandlinkfailureB
7.Whichofcharactersisnotdistance-vectoralgorithm’scharacters?(
)A.iterative
B.global
C.asynchronous
D.distributedD
8.ThelengthofIPV6addressis(
)bits.
A.32
B.48
C.64
D.128C
9.ThehostcomponentofaCIDRaddressoftheforma.b.c.d/25cancontainaddressesfor:A.225hosts(minus“special”hosts)B.512hosts(minus“special”hosts)C.2(32-25)hosts(minus“special”hosts)D.25hosts(minus“special”hosts)C
10.Theprimaryfunctionoftheaddressresolutionprotocol(ARP)thatresidesinInternethostsandroutersis:A.ToprovideLANrouterfunctionsB.TotranslatebetweenLANaddressesandphysicalinterfaceaddressesC.TotranslateIPaddressestoLANaddressesD.TocalculatetheshortestpathbetweentwonodesonaLANA
11.ThePOP3
protocolrunsover____andusesport____.
A.TCP
110
B.UDP
110
C.UDP
25
D.TCP
25D
12.Whenadestinationhosttransportlayerreceivesdatafromthenetworklayer,itunambiguouslyidentifiestheappropriateprocesstopassthedatatobyusingatripletconsistingof:A.Sourceport#,destinationIPaddress,andsourceIPaddressB.Destinationport#,sourceport#,processID#C.Destinationport#,sourceport#,destinationIPaddressD.Destinationport#,sourceport#,sourceIPaddressD
13.Fromthelistbelow,selecttheitemsfoundintheTCPsegmentstructurethatarenotfoundintheUDPsegmentstructure:A.ApplicationGeneratedData
B.DestinationPort#
C.SourcePort#
D.Sequence#A
14.TheRIProutingprotocolisbasedonanalgorithmthatis:A.Basedoninformationreceivedonlyfromlink“neighbors”B.AlinkstatealgorithmC.AnOSPFalgorithmD.AcentralizedroutingalgorithmB
15.Withanexteriorroutingprotocol,whichofthefollowingissuesgenerallydominatestheroutingdecisions?A.GeographicaldistancebetweenAS’sB.PolicyC.NumberofAS’straversedD.CurrentcongestionlevelsintheAS’sA
1.Endsystemareconnectedtogetherby____.A.communicationlinks
B.applicationlayer
C.transportlayer
D.thenetworklayerC
2.Whichapplication’sNOTusingTCP?
A.SMTP
B.HTTP
C.DNS
D.AllofthemB
3.Inthepollingprotocols,themasternodepollseachofthenodesina/an____fashion.
A.random
B.appointed
C.round-robin
D.uncirculated
C
4.TheDNSprotocolrunsover____andusesport____.
A.UDP
36
B.TCP
36
C.UDP
53
D.TCP
53A
5.TCPprovidesa____servicetoitsapplicationstoeliminatethepossibilityofthesenderover-flowingthereceiver’sbuffer.
A.flow-control
B.congestioncontrol
C.reliabilitycontrol
D.dataconnectionD
6.Wecanclassifyjustaboutanymultipleaccessprotocolasbelongingtooneofthreecategories:channelpartitioningprotocols,randomaccessprotocols,and____.
A.addressresolutionprotocols
B.Dynamichostconfigurationprotocols
C.link-controlprotocols
D.taking-turnsprotocols
B
8.Themaximumtransferunit(MTU)inEthernetframestructureis()byte.A.1000
B.1500
C.800
D.2000B
9.ThesocketofUDPisidentifiedby_____and_______.
A.sourceIPaddressandsourceportnumber
B.destinationIPaddressanddestinationportnumber.
C.sourceIPaddressanddestinationportnumber.
D.destinationIPaddressandsourceIPaddress.C
10.Whichisnotplugandplayinthefollowingfouritems?A.DHCP
B.Hubs
C.Routers
D.SwitchesD
11.Whichofroutersisnotdefaultrouters?A.first-hoprouter
B.sourcerouter
C.destinationrouter
D.second-hoprouterB
13.ICMPis_____.
A.theprotocolofApplicationlayer
B.theprotocolofnetworklayerC.theprotocoloftransportlayer
D.notapartofTCP/IPprotocolsB
14.Asgeneral,wehasfollowingchannelpartitioningprotocolsexcept____.
A.TDM
B.CSMA
C.FDM
D.CDMAD
15.____ismostusedforerrorreporting.
A.UDP
B.SMTP
C.FTP
D.ICMPB
16.TheheaderofIPV6is____byte.
A.20
B.40
C.60
D.80B
17.Inthenetworklayertheseservicearehost-to-hostserviceprovidedby____.(B)A.thetransportlayertothenetworklayerB.thenetworklayertothetransportlayerC.thenetworklayertothenetworklayerD.thetransportlayertothetransportlayerA
18.Ifthereisnotenoughmemorytobufferanincomingpacket,apolicythatdropthearrivingpacketcalled____.A.drop-tail
B.packetloss
C.protocol
D.encapsulationC
19.Ineithercase,a____receivesroutingprotocolmessages,whichareusedtoconfigureitsforwardingtable.
A.server
B.host
C.router
D.ModemD
20.WhichofthefollowingfunctionsdoesnotbelongtoPPP___.A.framing
B.link-controlprotocols
C.network-controlprotocols
D.errorcorrectionB
1.WhichofthefollowingservicesdoestheInternetnetworklayerprovidefortheInternettransportlayer?A.In-orderdeliveryofdatasegmentsbetweenprocessesB.BesteffortdeliveryofdatasegmentsbetweencommunicatinghostsC.MultiplexinganddemultiplexingoftransportlayersegmentsD.CongestioncontrolD
2.ThemaintaskoftheInternet’sDomainNameSystem(DNS)isto:A.TranslateportnumberstoIPaddressesB.SpecifythestandardsforInternetdomainnamesC.ProvideanauthorityforregisteringdomainnamesD.Translatemnemonic(記憶的)namestoIPaddressesA
10.TheFTPprotocolrunsover____andusesport____.
A.TCP
21
B.TCP
80
C.UDP
20
D.TCP
110C
3.RDT3.0’sreceiverFSMissameto:a)
RDT1.0
b)RDT2.1
c)RDT2.2
d)RDT2.0B
4.TheTransmissionControlProtocol(TCP)provideswhichofthefollowingservices?a)End-to-endstationaddressingb)Applicationmultiplexingc)Internetworkroutingd)Mediumaccesscontrol(MAC)D
6.Giventhattherequestedinformationisnotavailableatanyintermediatedatabases,anon-iteratedDNSqueryfromarequestinghostwouldfollowthepath:a)Rootnameserver,localnameserver,authoritativenameserverb)Authoritativenameserver,rootnameserver,hostnameserverc)Localnameserver,rootnameserver,localnameserver,authoritativenameservere)Localnameserver,rootnameserver,authoritativenameserverA
8.lectthefouressentialsteps,brieflydescribed,forterminatingaTCPconnectionbetweenaclientandaserver,assumingthattheinitiatinghostistheclient:(1)ClientsendsTCPsegmentwithACK0andfinalsequencenumber(2)ClientsendsTCPsegmentwithFIN=1andgoesintoFIN_WAITstate(3)ServersendsTCPsegmenttoACKtheclient’sFINrequestandentersCLOSE_WAITstate(4)ServersendsTCPsegmentwithFIN=0(5)ServersendsTCPsegmentwithFIN=1(6)ClientsendsTCPsegmentwithtoACKserver’sFINandenterssecondFIN_WAITstate(7)ClientsendsTCPsegmentwithFIN=0a)
2,3,5,6
b)5,1,2,3
c)1,3,5,7
d)
2,3,4,6B
10.Whencompensatingforlinkcostchangesinthedistancevectoralgorithm,itcangenerallybesaidthat:a)Increasedcostsarepropagatedquickly,i.e.,“badnews”travelsfastb)Decreasedcostsarepropagatedrapidly,i.e.,“goodnews”travelsfastc)Decreasedcostsdonotconverged)NoneoftheaboveB
14.AsanIPdatagramtravelsfromitssourcetoitsdestination:a)thesourceIPaddressischangedateachroutertoidentifythesendingrouterb)therouterusesthedestinationIPaddresstoconsultitsroutingtablec)therouterdoesnotusetheIPaddressesinthedatagramd)thedestinationIPaddressischangedateachroutertoreflectthenexthopC
15.Fromthelistbelow,choosethebitpatternwhichcouldbeavalidgeneratorvaluefortheCRCcode(R)11010:a)1110b)011010c)100101d)10011A
16.Considersendinga1300byteIPv4datagramintoalinkthathasanMTUof500bytes:a)Threefragmentsarecreated.b)Fourfragmentsarecreated.c)Threefragmentsarecreatedwithoffsets0,5001000d)Thelastfragmentconsistsofexactly300bytesofdatafromtheoriginaldatagramC
17.SupposeoneIPv6routerwantstosendadatagramtoanotherIPv6router,butthetwoareconnectedtogetherviaaninterveningIPv4router.Ifthetworoutersusetunneling,then:a)ThesendingIPv6routercreatesanIPv4datagramandputsitinthedatafieldofanIPv6datagram.b)ThesendingIPv6routercreatesoneormoreIPv6fragments,noneofwhichislargerthanthemaximumsizeofanIPv4datagram.c)ThesendingIPv6routercreatesanIPv6datagramandputsitinthedatafieldofanIPv4datagram.d)ThesendingIPv6routercreatesanIPv6datagramandinterveningIPv4routerwillrejecttheIPv6datagramD
18.WhichofthefollowingwasanimportantconsiderationinthedesignofIPv6a)fixedlength40-byteheaderandspecifiedoptionstodecreaseprocessingtimeatIPv6nodesb)128-bitaddressestoextendtheaddressspacec)differenttypesofservice(flows)definedd)alloftheaboveD
19.Anetworkbridgetableisusedtoperformthefollowing:a)MappingMACaddressestobridgeportnumbersb)ForwardingframesdirectlytooutboundportsforMACaddressesithandlesc)Filtering(discarding)framesthatarenotdestinedforMACaddressesithandlesd)AlloftheabovePARTⅡ:True/False
(1pointsperquestion–total:20points)1.TheDNSservercanupdatetherecords.
(T)2.TheTCPconnectionisadirectvirtualpipebetweentheclient’ssocketandtheserver’sconnectionsocket.
(T)3.SMTPprotocolconnectthesender’smailserverandreceiver’smailserver
(T)4.Whereasatransport-layerprotocolprovideslogicalcommunicationbetweenprocessesrunningondifferenthosts,anetwork-layerprotocolprovideslogicalcommunicationbetweenhosts.
(T)5.UDPandTCPalsoprovideintegritycheckingbyincludingright-detectionfieldsintheirheaders.
(F)6.IftheapplicationdeveloperchoosesUDPinsteadofTCP,thentheapplicationisnotdirectlytalkingwithIP.
(F)7.Whenwedevelopanewapplication,wemustassigntheapplicationaportnumber.
(T)8.Real-tineapplications,likeInternetphoneandvideoconferencing,reactverypoorlytoTCP’scongestioncontrol.
(T)9.ThesenderknowsthatareceivedACKorNAKpacketwasgeneratedinresponsetoitsmostrecentlytransmitteddatapacket.
(T)10.Tosimplifyterminology,wheninanInternetcontext,werefertothe4-PDUasaunit.
(F)11.DValgorithmisessentiallytheonlyroutingalgorithmusedinpracticetodayintheInternet。(F)12.Everyrouterhasmanyforwardingtables.(F)13.Ineithercase,aserverreceivesroutingprotocolmessages,whichareusedtoconfigureitsforwardingtable.(F)14.AmongtheASs,theyrunthesameinter_ASroutingprotocol.
T15.Routingprotocols’jobistodeterminethepathtakebyadatagrambetweensourceanddestination.
T16.OSPFwasoneof
theearliestintra_ASInternetroutingprotocols.
F17.TheIPV6datagramsaremoresimpler,morestreamlined.
(T)18.Forwardingtablesindatagramnetworkscanbemodifiedatanytime.(T)19.InaVCnetwork,thenetwork’sroutersmustmaintainconnectionstateinformationfortheongoingconnections.(T)20.Theroutersofdatagramnetworksuseforwardingtable,theroutersofvirtual-circuitnetworksdon’tuseforwardingtable.(F)PARTⅡ:Brieflyanswerthefollowingquestions.1.Inthe“10BaseT”,Tstandsfor(
).(twistedpair)2.(
)and(
)aretwoofthemostimportantprotocolsintheinternet.
(TCP)(IP)3.Inaclient-serverarchitecture,thereisanalways-onhost,calledthe(
),whichservicesrequestsfrommanyotherhosts,called(
).
(server)(clients)4.ThebroadcastdestinationIPaddressis(
).
(55)5.Twoofthemoreimportant(
)
protocolsarepollingprotocolsandtoken-passingprotocol.
(taking-turns)6.Transport-layerprotocolsareimplementedinthe(
),butnotinnetworkrouter.(endsystem)7.Theportnumbersranging(
)arecalledwell-knownportnumbers.(0~1023)8.The(
)
algorithmisusedinmanyroutingprotocolsinpractices,includingtheInternet’sRIPandBGP,NovellIPX,andtheoriginalARPAnet.
(DV/distance-vector)9.Internetconsistsofhierarchyofinterconnected(
).
(ISPs)10.InMACaddress,broadcastaddressis(
).
(FF-FF-FF-FF-FF-FF)11.ASisacollectionof(
)underthesameadministrativeandtechnicalcontrol.
(routers)12.(
)andFDMaretwotechniquesthatcanbeusedtopartitionabroadcastchannel’sbandwidthamongallnodessharingthatchannel.
(TDM)13.Asthequeuesgrowlarge,therouter’sbufferspacewilleventuallybeexhaustedand(
)
packetlosswilloccur.
(packetloss)14.Theroleofthenetworklayeristomove(
)fromasendinghosttoareceivinghost.(packets)15.(
)referstotherouter-localactionoftransferringapacketfromaninputlinkinterfacetotheappropriateoutputlinkinterface.
(Forwarding)16.TheInternet’snetworklayerprovidesasingleservice,knownas(
).(best-effortservice)17.Theunitsofdataexchangedbyalink-layerprotocolarecalled(
).
(frames)
18.The(
)-layerprotocoldefinestheformatofthepacketsexchangedbetweenthenodesattheendsofthelink,aswellastheactionstakenbythesenodeswhenthepacketsaresentandreceived.
(link)1.(3points)Whatisthedifferencebetweenahostandendsystem?Listthetypesofendsystems.IsaWebServeranendsystem?答:Thereisnodifference.Throughoutthistext,thewords“host”and“endsystem”areusedinterchangeably.EndsystemsincludePCs,workstations,Webservers,mailservers,Internet-connectedPDAs,WebTVs,etc.1.(1points)WhyisthereaWebcache?答:減少接入網(wǎng)絡(luò)的流量、減小延遲2.(3points)PleasebrieflydescribethefunctionofthefivelayersinTCP/IParchitecture(NOTE:includetheprotocoldataunit)答:1.應(yīng)用層,提供各種網(wǎng)絡(luò)應(yīng)用,運(yùn)行網(wǎng)絡(luò)應(yīng)用程序。Message。2.運(yùn)輸層,提供端到端進(jìn)程之間的數(shù)據(jù)傳輸。Segment。3.網(wǎng)絡(luò)層,主機(jī)到主機(jī)的傳輸。Datagram4.鏈路層,相鄰節(jié)電數(shù)據(jù)傳輸,frame5.物理層,透明傳輸比特流,bitstream.3.(2points)WhataretheservicesofTCP?答:connection-orientedservice;reliable,in-orderbyte-streamdatatransferflowcontrol:congestioncontrol:4.(2points)Pleasebrieflycompare:datagramnetworkversusvirtualcircuit(VC)network.答:數(shù)據(jù)報(bào)網(wǎng)絡(luò)是面向非連接的服務(wù),不可靠的服務(wù),沒(méi)有流量控制和擁塞控制。虛電路網(wǎng)絡(luò)是面向連接的網(wǎng)絡(luò),可以提供可靠的傳輸服務(wù),具有流量控制和擁塞控制。5.(2points)Whatisthedifferencebetweenroutingandforwarding?答:Forwardingisaboutmovingapacketfromarouter’sinputlinktotheappropriateoutputlink.Routingisaboutdeterminingtheend-to-routesbetweensourcesanddestinations.6.(3points)HowbigisMACaddressspace?TheIPv4addressspace?TheIPv6addressspace?答:MAC:248,IPv4:232;IPv6:21287.(4points)Fillintheblank:
1)RIPadvertisementstypicallyannouncethenumberof(
hops
)tovariousdestinations.2)BGPupdatesannouncethe(
ASs
)tovariousdestinations
3)ForSelectiveRepeatprotocol,sequencenumberspace>=(
2
)timeswindowsize.4)TheefficiencyofSlottedALOHA=(
2
)timesbiggerthanPureALOHA.8.(2points)ConsidersendingMpacketsoverapathofNlinks.AssumethateachpackethasLbits.EachlinktransmitsatRbps.Thenetworkislightlyloadedsothattherearenoqueuingdelays.Propagationdelayandnodeprocessingdelayarenegligible.Supposethenetworkisapacket-switcheddatagramnetworkandaconnectionlessserviceisused.Nowsupposeeachpackethas2hbitsofheader.Howlongdoesittaketosendthepacket?(allpacketsgothroughthesamepath)答:(N+M-1)*(L+2h)/R9.(2points)IfallthelinksintheInternetweretoprovidethereliabledeliveryservice,wouldtheTCPreliabledeliveryserviceberedundant?WhyorWhynot?答:AlthougheachlinkguaranteesthatanIPdatagramsentoverthelinkwillbereceivedattheotherendofthelinkwithouterrors,itisnotguaranteedthatIPdatagramswillarriveattheultimatedestinationintheproperorder.WithIP,datagramsinthesameTCPconnectioncantakedifferentroutesinthenetwork,andthereforearriveoutoforder.TCPisstillneededtoprovidethereceivingendoftheapplicationthebytestreaminthecorrectorder.Also,IPcanlosepacketsduetoroutingloopsorequipmentfailures.3.(3points)3.(3points)ConsideraccessingyouremailwithPOP.Supposeyouhaveconfiguredyourpopmailclienttooperateinthedown-load-and-deletemode.Completethefollowingtransaction.C:listS:1498S:2912S:.C:retr1S:blahblah…S:…………blahS:.???答:C:dele1C:retr2S:(blahblah…S:………..blah)S:.C:dele2C:quit4.(3points)Wherecanqueuingoccurinarouter?Brieflyexplaintheconditionsthatleadtosuchqueuing.答:Queuingcanoccuratboththeinputportsandtheoutputportsofarouter.Queuingoccursattheoutputportwhenthearrivingrateofpacketstotheoutgoinglinkexceedsthelinkcapacity.Queueoccursonaninputportwhenthearrivingrateofpacketsexceedstheswitchcapacity;head-of-the-lineblockingcanalsocausequeuingattheinputports.5.(3points)DescribewhyanapplicationdevelopermightchoosetorunanapplicationoverUDPratherthanTCP.答:AnapplicationdevelopermaynotwantitsapplicationtouseTCP’scongestioncontrol,whichcanthrottletheapplication’ssendingrateattimesofcongestion.Often,designersofIPtelephonyandIPvideoconferenceapplicationschoosetoruntheirapplicationsoverUDPbecausetheywanttoavoidTCP’scongestioncontrol.Also,someapplicationsdonotneedthereliabledatatransferprovidedbyTCP.6.(3points)SupposeClientAinitiatesaTelnetsessionwithServerS.Ataboutthesametime,ClientBalsoinitiatesaTelnetsessionwithServerS.Providepossiblesourceanddestinationportnumberfora.ThesegmentssentfromAtoSb.ThesegmentssentfromBtoSc.ThesegmentssentfromStoAd.ThesegmentssentfromStoBe.IfAandBaredifferenthosts,isitpossiblethatthesourceportnumberinthesegmentsfromAtoSisthesameasthatfromBtoS?f.Howaboutiftheyarethesamehost?答:sourceportnumbersdestinationportnumbersa.A→S46723b.B→S51323c.S→A23467d.S→B23513e.yesf.no7.(4points)Fillintheblank:
1)RIPadvertisementstypicallyannouncethenumberof(
hops
)tovariousdestinations.2)BGPupdatesannouncethe(
ASs
)tovariousdestinations
3)ForSelectiveRepeatprotocol,sequencenumberspace>=(
2
)timeswindowsize.4)TheefficiencyofSlottedALOHA=(
2
)timesbiggerthanPureALOHA.8.(3points)ConsidersendingapacketoverapathofNlinks.AssumethateachpackethasLbits.EachlinktransmitsatRbps.Thenetworkislightlyloadedsothattherearenoqueuingdelays.Propagationdelayandnodeprocessingdelayarenegligible.Supposethenetworkisapacket-switcheddatagramnetworkandaconnectionlessserviceisused.Nowsupposeeachpackethas2hbitsofheader.Howlongdoesittaketosendthepacket?答:(L+2h)/R*N9.(3points)IfallthelinksintheInternetweretoprovidethereliabledeliveryservice,wouldtheTCPreliabledeliveryserviceberedundant?WhyorWhynot?答:AlthougheachlinkguaranteesthatanIPdatagramsentoverthelinkwillbereceivedattheotherendofthelinkwithouterrors,itisnotguaranteedthatIPdatagramswillarriveattheultimatedestinationintheproperorder.WithIP,datagramsinthesameTCPconnectioncantakedifferentroutesinthenetwork,andthereforearriveoutoforder.TCPisstillneededtoprovidethereceivingendoftheapplicationthebytestreaminthecorrectorder.Also,IPcanlosepacketsduetoroutingloopsorequipmentfailures.10.(Total4points)CDMASupposethatfournodesusingCDMA(CodeDivisionMultipleAccess)protocoltotransporttheirdata.Thechippingsequencesarelistedrespectivelyasbelow:A:(-1,+1,–1,+1,+1,+1,–1,-1)B:(-1,+1,–1,–1,–1,–1,+1,-1)C:(-1,–1,–1,+1,+1,–1,+1,+1)D:(-1,–1,+1,–1,+1,+1,+1,-1)(Computingprocessisneedless)SupposethataCDMAreceiverhasreceivedanencodeddataas(-1,+1,-3,+1,-1,-3,+1,+1)fromanaggregatesignalchannelinonebit-slottime,whichnode/nodeshas/havesentdata?What’sthecorrespondingdatabiteachofthemsent?(3points)Answer:
Asendnothing,Bsend1,Csends1,Dsends0.11.(2points)Inthefigurebelow,H1remainsinsameIPsubnet,brieflydescribehowtheswitchwouldknowwhichAPisassociatedwithH1whenH1ismovingwithinBSS1andBSS2.答:通過(guò)自學(xué)習(xí)的方法12.(3points)Thisquestionisaboutthe“GSM:handoffwithcommonMSC”.Accordingtothefigurebelow,orderingthe8steps.A.OldBSSinformsMSCofimpendinghandoff,provideslistof1+newBSSsB.OldBSStellsmobile:performhandofftonewBSSC.NewBSSallocatesradiochannelforusebymobileD.NewBSSsignalsMSC,oldBSS:readyE.MSC-oldBSSresourcesreleasedF.MSCsetsuppath(allocatesresources)tonewBSSG.MobilesignalsvianewBSStoMSC:handoffcomplete.
MSCreroutescallH.Mobile,newBSSsignaltoactivatenewchannelAnswer:AFCDBHGE13.(3points)WhyisanARPquerysentwithinabroadcastframe?WhyisanARPresponsesentwithinaframewithaspecificdestinationMACaddress?答:AnARPqueryissentinabroadcastframebecausethequeryinghostdoesnotwhichadapteraddresscorrespondstotheIPaddressinquestion.Fortheresponse,thesendingnodeknowstheadapteraddresstowhichtheresponseshouldbesent,sothereisnoneedtosendabroadcastframe(whichwouldhavetobeprocessedbyalltheothernodesontheLAN).2.Explainthedifferencebetweengo-back-Nandselectiverepeat.(2points)Withgo-back-N,wheneverareceiverdetectsamissingordamagedframek,allframessucceedingkareignoredandthesenderisforcedtostartretransmissionatframek.Withselectiverepeat,itispossibletoretransmitonlyframek;thereceiverbufferssuccessiveframes.3.Wherecanqueuingoccurinarouter?Brieflyexplaintheconditionsthatleadtosuchqueuing.(2points)Queuingcanoccuratboththeinputportsandtheoutputportsofarouter.Queuingoccursattheoutputportwhenthearrivingrateofpacketstotheoutgoinglinkexceedsthelinkcapacity.Queueoccursonaninputportwhenthearrivingrateofpacketsexceedstheswitchcapacity;head-of-the-lineblockingcanalsocausequeuingattheinputports.4.Satellitelinksoftenexhibithighpropagationtimesandlowtransmissionspeed.Whatdoesthismean?(2points)Itmeansthatitcantakealongtimeforthestartofasignalthatrepresentsabittoreachthesender,andthatthenumberofbitsthatcanbetransmittedpertimeunitislow.5.ThedifferencebetweenUDPandIPpacketsisminimal.Whyshouldn’tapplicationsuseIPdirectly?(2points)Itisamatterofseparatingconcerns:thetransportlayershouldofferaninterfacetoapplicationsthathidestheunderlyingnetwork.Forconnectionlessservices,itdoessobymeansofUDP.Furthermore,notethatIPitselfhasnonotionofports.Thistypeofaddressbelongstotheabstractionprovidedbythetransportlayerandofwhichapplicationsmakeheavyuse.Thereis,ingeneral,nowaythatanapplicationcangetanIPpacketsentdirectlytoanapplication.6.Cantwocomputersthathaveadifferentimplementationofthesameprotocolexchangemessages?Explainyouranswer.(2points)Yes,theprotocolprescribestheformatofmessages,andthepreciserulesformessageexchange.Youcaneasilyhavedifferentimplementationsofthesameprotocol.7.Whatarethedifferencesbetweenroutingandforwarding?Brieflyexplaineachofthem.(2points)Forwarding:movepacketsfromrouter’sinputtoappropriaterouteroutput.Routing:determineroutetakenbypacketsfromsourcetodestination.8.Brieflyexplaintheformula“l(fā)astByteSent-lastByteAcked≤min{CongWin,RcvWin}”.Ifnecessary,youcandrawafiguretodescribeyouranswer.(2points)Duetothecongestioncontrolandflowcontrol,TCPlimitstheamountofunacknowledgeddataatasendermaynotexceedtheminimumofcongwinandRcvwin.9.EthernetfollowsaCSMA/CDprotocolscheme.Explainhowthisschemeworks.(2points)CSMA/CDstandsforCarrierSenseMultipleAccesswithCollisionDetection.Thismeansthatwhenanodewantstotransmitdata,it(1)sensesthecarrieruntilnotransmissionsaredetected,(2)startstransmission,and(3)continuestocheckforacollision.Ifacollisionhappens,thenodestopsandwaitsarandomperiodbeforestartingwithstep(1)again.10.Foraslidingwindowprotocol,itisnecessarytohavethewindowsizeatmosthalfoftherangeofsequencenumbers.Why?(2points)Supposeareceiverhasjustreceivedframe#N,anditadvancesitswindowsuchthat(anew)frame#Nisallowedtobetransmitted.Iftheacknowledgementforthereceiptofframe#Nwaslost,thenthesenderwilleventuallyretransmittheoriginalframe,butwhichwillnowbeconsideredasfreshframebythereceiver.1.Explainthedifferencebetweenaconnection-orientedmessagingserviceandaconnectionlessmessagingservice.(2points)Aconnection-orientedservicerequiresthatapeerfirstsetsupaconnectiontothetargetpeerbeforedatacanbeexchanged.Inaconnectionlessservice,messagesaresentdirectlytoapeer,r
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