PUCCH結構與配置

1、1. PUCCH概述2. PUCCH結構3. PUCCH網(wǎng)管配置與系統(tǒng)消息參數(shù)4. PUCCH容量計算 ZTE Corporation. All rights reserved.PUCCH概述物理上行控制信道PUCCH承載上行控制信息：ACK/NACK、CQI和SRI（調(diào)度請求），PUCCH和PUSCH是不會同時傳輸?shù)?。PUCCH支持6種格式：bitMPUCCH格式格式調(diào)制方式調(diào)制方式每子幀中包含的每子幀中包含的bitbit數(shù)數(shù)應用場景應用場景1N/AN/A上行調(diào)度請求1aBPSK1單數(shù)據(jù)塊ACK/NACK1bQPSK2雙數(shù)據(jù)塊ACK/NACK2QPSK20CQI2aQPSK+BPSK21CQ

2、I+單數(shù)據(jù)塊ACK/NACK2bQPSK+QPSK22CQI+雙數(shù)據(jù)塊ACK/NACK1. PUCCH概述2. PUCCH結構3. PUCCH網(wǎng)管配置與系統(tǒng)消息參數(shù)4. PUCCH容量計算 ZTE Corporation. All rights reserved.PUCCH結構-Format 1/1a/1b ZTE Corporation. All rights reserved.PUCCH結構-Format 1/1a/1b ZTE Corporation. All rights reserved.PUCCH結構-Format 2/2a/2b ZTE Corporation. All righ

3、ts reserved.PUCCH結構-Format 2/2a/2b ZTE Corporation. All rights reserved.PUCCH結構-混合模式1. PUCCH概述2. PUCCH結構3. PUCCH網(wǎng)管配置與系統(tǒng)消息參數(shù)4. PUCCH容量計算 ZTE Corporation. All rights reserved.PUCCH網(wǎng)管配置 ZTE Corporation. All rights reserved.PUCCH系統(tǒng)消息參數(shù)PUCCH-ConfigCommon :=SEQUENCE deltaPUCCH-ShiftENUMERATED ds1, ds2, ds

4、3,nRB-CQIINTEGER (0.98),nCS-ANINTEGER (0.7),n1PUCCH-ANINTEGER (0.2047)PUCCH-ConfigDedicated :=SEQUENCE ackNackRepetitionCHOICEreleaseNULL,setupSEQUENCE repetitionFactorENUMERATED n2, n4, n6, spare1,n1PUCCH-AN-RepINTEGER (0.2047)1. PUCCH概述2. PUCCH結構3. PUCCH網(wǎng)管配置與系統(tǒng)消息參數(shù)4. PUCCH容量計算 ZTE Corporation. All

5、 rights reserved.PUCCH容量計算上行PUCCH的占用的RB數(shù)計算過程如下。1.PUCCH format 1/1a/1b的循環(huán)偏移量：如果Cycle Shift Number for PUCCH Format 1/1a/1b(byPucchDeltaShf) = 1，每個RB上可復用的最大pucch format1個數(shù)為36；如果Cycle Shift Number for PUCCH Format 1/1a/1b (byPucchDeltaShf) = 2則每個RB上PUCCH format1可復用的pucch format1個數(shù)為 36/2 = 18。2.PUCCH fo

6、rmat 2/2a/2b使用的RB數(shù)：RB Number of PUCCH Format 2/2a/2b (byNumPucchCqiRB) = 23.SR信道個數(shù)：The Number of SR PUCCH (wNPucchSr) = 184.半靜態(tài)分配的PUCCH Format 1的信道個數(shù)：Number of Semi Allocation Format 1 PUCCH(wNPucchSemiAn) = 185.動態(tài)分配的AN信道數(shù)與CCE個數(shù)（Ncce）相關, the Factor of PHICH Group(byNg)取1/2時，CCE個數(shù)如下表Bandwidth1.4MHz(6

7、RB)3MHz(15RB)5MHz(25RB)10MHz(50RB)15MHz（75RB）20MHz(100RB）CFI = 1024101521CFI = 22713264054CFI = 341221436587由于PUCCH在一個子幀的兩個時隙中跳頻，PUCCH占用的RB數(shù)是偶數(shù)，因此PUCCH占用的RB數(shù)由下式計算：CEIL( (byNumPucchCqiRB + CEIL( (Ncce + wNPucchSemiAn + wNPucchSr) / (36 / byPucchDeltaShf) ) )/2 )*2 帶寬15MHz(75RB)：PUCCH占用的RB個數(shù) = CEIL (2+CEIL (40+18+18)/(36/2), 1)/2, 1)*2 = 8 ZTE Corporation. All rights reserved.遺留問題1. Format1使用開關鍵控調(diào)制，但是在1a、1b中SR該如何傳輸？2. 按照我們后臺網(wǎng)管的配置，如何對