旅行商問(wèn)題數(shù)學(xué)建模

數(shù)黃建模 大型作業(yè)2011—2012黃年第1黃期目錄一.摘要二.旅行問(wèn)題.問(wèn)題描述.符號(hào)說(shuō)明.模型設(shè)計(jì).建模求解.模型分析.得體會(huì).建模得體會(huì).參考文件一.摘要本文本一本旅行問(wèn)題問(wèn)題本問(wèn)題 文本問(wèn)題一本本一一一 本本問(wèn)題問(wèn)題二 問(wèn)題一本問(wèn)題本本一本本問(wèn)題關(guān)鍵詞：HAMILTONLINGO本本旅行 0-1模型二.旅行問(wèn)題問(wèn)題描述本本要期 A 機(jī)到,C,D,E,F旅本計(jì) 一本本本一A 本本數(shù)則寸表1本本本設(shè)計(jì)一旅行得 本本本本本本本行 4旅行本本？本本本本旅本本計(jì) 本本本機(jī)本本本本本本本本機(jī)本本本本本本本本本本本本行 體超15kg 本見(jiàn)附表2值大附表1：ABCDEFA0120250330210150B120098350225300C250980520430280D3303505200270185E2102254302700420F1503002801854200附表2本本機(jī)本本機(jī)香煙(kg)12434221（元）13002750320435014003001206002

模型設(shè)計(jì)苜首首一 一v1首首首首一 義:設(shè)v1,v2,……,vn首圖G苜首首一 一v1苜首首v1HAMILTON苜首首v1HAMILTON問(wèn)題1.分析：首首首首問(wèn)題首目旅行首首首首要首首設(shè)旅行分析：首首首首問(wèn)題首目旅行首首首首要首首設(shè)旅行首件：數(shù) 首首件數(shù)首符號(hào)首件：數(shù) 首首件數(shù)首符號(hào)模型建立：首首首首首首首一首首題目首表 首首首得一模型對(duì)6 對(duì)6 旅行問(wèn)|設(shè)A,B,C,D,E,Fdi到j(luò) 義0-1首數(shù)型ij首旅行問(wèn)題數(shù)首模型表首首一首數(shù)分別對(duì)應(yīng)v1,v2,v3,v4,v5,v6首首設(shè)表x=1表旅行到j(luò)否x=0ij ij問(wèn)題(i豐j)(i豐j)ijijiTjs.t.之X=1 (iwj；j=1,2,……,6)iji=1X=1

X=1

ij(i豐j;i=1,2,……,6)j=1j=1u—u+nx<n1~(iwj；i=2,3, ijij,6;j=2,3,……6)首中 u.首中 u.(i=2,3, ,6)數(shù)值（ 件中首首首解中數(shù)）首首首首首首首首解中u=首問(wèn)i［峙數(shù)模型求解運(yùn)LINGO運(yùn)LINGO首輸入首序:Prsofsixcity;SETS:CITY/1..6/:U;nceno.ofcity;LINK(CITY,CITY):COST,x;X;!X(I,J)=1ifweuselinkI,J;TSDATA:tric;COST=0 120250 330210 150120 098 350225 300250 980 520430 280330 350520 0270 185210 225430 2700 420150 300280 185420 0 ;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K):ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;ted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;urbrea;ems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：1163果果：A-B-C-F-D-E-A問(wèn)題2.4分析：B,C,D,E,F果果果應(yīng) 果果旅行中選4顯 5果果果果問(wèn)題一中果模型稍乍果改果運(yùn)LINGO分別解除5果果果進(jìn)行比較果即得結(jié)(1)選B,D,E,F果計(jì)果旅行sofsixcity;SETS:CITY/1..5/:U; nceno.ofcity;LINK(CITY,CITY):COST, x;X;!X(I,J)=1ifweuselinkI,J;

TSDATA:!Costtric;COST=0120330 2101501200350 2253003303500 270185210225270 0420150300185 4200;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K):ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;ted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;;arenems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：果果果：950果果：A-B-E-D-F-A(2)選B,C,E,F果計(jì)果旅行 ：sofsixcity;SETS:CITY/1..5/:U;nceno.ofcity;LINK(CITY,CITY):COST,x;X;!X(I,J)=1ifweuselinkI,J;TSDATA:tric;COST=012025021015012009822530025098043028021022543004201503002804200;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K): ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;

ted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;;ems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：果果果：963果果：A-E-B-C-F-A(3)選B,C,D,F,計(jì)果旅行 ：emforthe sofsixcity;SETS:CITY/1..5/:U;nceno.ofcityLINK(CITY,CITY):COST,x;X;!X(I,J)=1ifweuselinkI,J;TSDATA:tric;COST=0 120250 330150120 098 350300250 980 520280330 350520 0185150 300280 1850;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K):!Itmustb ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;ted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;;ems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：果果果：1013果果：A-B-C-F-D-A(4)選 ：B,C,D,E,計(jì)果旅行 ：sofsixcity;SETS:CITY/1..5/:U;nceno.ofcity;LINK(CITY,CITY):COST,x;X;!X(I,J)=1ifweuselinkI,J;TSDATA:tric;COST=0 120250 330210120 098 350225250 980 520430330 350520 0270210 225430 2700;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K):ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;ted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;urbrea;ems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K))@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：果果果：1173:A-C-B-E-D-A(5)選C,D,E,F計(jì)果旅行

sofsixcity;SETS:CITY/1..5/:U;!U(I)=二sequnceno.ofcity;LINK(CITY,CITY):COST,x;X;!X(I,J)=1ifweuselinkI,J;TSDATA:tric;COST=02503302101502500520430280330520027018521043027004201502801854200;TAN=@SIZE(CITY);MIN=@SUM(LINK:COST*X);@FOR(CITY(K):ed;@SUM(CITY(I)|I#NE#K:X(I,K))=1;!Itted;@SUM(CITY(J)|J#NE#K:X(K,J))=1;;ems;@FOR(CITY(J)|J#GT#1#AND#J#NE#K:U(J)>=U(K)+X(K,J)-(N-2)*(1-X(K,J))+(N-3)*X(J,K)););@FOR(LINK:@BIN(X));!MaketheX's0/1;andlaststopweknow...;@FOR(CITY(K)|K#GT#1:U(K)<=N-1-(N-2)*X(1,K);U(K)>=1+(N-2)*X(K,1));END得到結(jié)果：果果果：1195果果：A-C-F-D-E-A果果果果結(jié)果果(1)(2)(3)(4)(5) 得應(yīng)果選 ：A-B-E-D-F-A問(wèn)題3.果果果果旅果果計(jì)

果果果果行果見(jiàn)附表問(wèn)題3.果果果果旅果果計(jì)

果果果果行果見(jiàn)附表2果果果機(jī)果果果果果果果果機(jī)果果果果果果果果果果香煙超15kg果值果大？

分析:解讀題讀讀讀讀讀讀題讀讀讀問(wèn)題讀題目 一15 讀要求8TOC\o"1-5"\h\z件 讀讀中 法模型建立：讀讀讀機(jī)讀讀讀讀讀讀讀讀讀機(jī)讀讀讀讀讀讀讀讀讀香煙編號(hào)12345678讀讀設(shè) 叱 * 讀義一 Xi當(dāng)xi=1讀讀表讀裝第i件讀讀當(dāng)xi=0讀讀讀讀裝(i=1,2,……,8).讀讀讀讀件 ：maxz=2cxiii=1bx<bi=1x=0 1(/r