2021年江西省高考數學教學質量檢測試卷(2021.04)

Rn63nnn1916Rn63nnn19162021年江西省高考學教學質量測試卷（科）（月）一選題每題5分）{24}B{30}ABA{13}B{x2}{x3}D{x1}i

iizA

B

C

DaRa0aaAC

BD{}a4Aln2Abc

BBb

0.1

C2DCcbDc521A

B

C

D{}S0SSnA131224D|

A

B

C

Dlky+10Ox2+21A

kA1B1

D10

1221112211A2B

C2D11

A

BC

D12Cb0PCF2PF42+21eq\o\ac(△,PF)eq\o\ac(△,)FA

B

C

D二填題本共4小題每題5分共20分．13fx22fx[1]14y

zxy2150a10101011

nnn1iiiiiinnn1iiiiii16{}26{}17三解題共分解應出文說、明程演步．～21題必題每試考都須答第2223題為考，生據求答一必題共60分．17ACabc1b5a+6ABC2AsinA18/x

z

x

zz

0.45

0.164

3501yabx+關x21y

31x19PDADPDACABcos1290B20C11C2PBx

PBCAPA21fae+lna1fx2221fx0（）考：10分請生第、23題中選題答．果做則所的

12211221第題分[選修：坐標與數程]22xOyC

15cos0AOAOA|151B2xDDMDN[選修4-5：不等選23ab0a2ab

lCM1xa2abb

RRRn63n63RRRn63n63參考答案一選題共12小題）{24}B{30}ABA{13}B{x2}{x3}D{x1}x

x2A{2x2}x+1xxB{13}A{x2}i

iiz

A

B

C

D1+2izizaRa0aaAC

BDa2a

1a0a0aa0

a{}a4A

BCD{}aa8

nnn1916n91616132513nnn1916n91616132513q2Cln2Abc

Bb

0.1

CcbDc0ln1ln1a11bbD521A

B

C

D5n

211m

621PC

{}S0SSnA131224D{}Sa++0a0SD

25a0n|

AB22

|

C0

D

[0]D

lky+10Ox2+2

kA1B1Ox2+2cos

DD

k10A2B

C2D

1221112211MAC

11

A

BC

Df

ffxyAxf0DBfx12Cb0PCF2PF42+2

eq\o\ac(△,PF)eq\o\ac(△,)FA

B

C

D1ca2+b20

4

11212121112112121211120x22

+y

11

1bc2a

4

P|22

3

|FF4eq\o\ac(△,PF)eq\o\ac(△,)FFPFFC二填題本共4小題每題5分共20分．13fx22fx[1]2

2x0fx2xe]fxx[1e]x[1e]f22

2lnee2

214yx+

BCaaz2+2+2+ay3aBz3323aa

150ak43b1311bi7+18b4343

nnn1n121343565768981011121113nnn1n12134356576898101112111314131514161716nn13671116{}26{}17aaaaa138a19a315614a731aaa14a320a10aaa14{}{}+a++a++a++2306三解題共分解應出文說、明程演步．～21題必題每試考都須答第、題選題考根要作（）考：共60分．17ACabc1b5a+6ABC2AsinA1b2

a

++23acbac6253acsin

iiiiiiiiiiii2cosB0

AC

sinACsin0A

AA

cosAA

A18/x

z

x

zz

0.45

0.164

3501yabx+

關x21y31x

1yc+2yc+

y

y

T

y

x

0.2

1.5x301.545.000.45/45.0019PDADPDACABcos1290BAD2BDPD

3AB3PBBCBD2

PD2

PDABABABC

PABCBPACPABCBPAC2DACEDEACDEBCPEPACdVPAC

20C11C2PBx

PBCAPA12b1

+22PB

111111APAA1PBPB1B1AAA111111APAA1PBPB1B1AAA1AB1ABPAk

2

x

+4k2

kxk

4k30Axx

x

x

PAx

k+kPBkxx+yx+kAB21faexlnx+1fx2221fx01fx

lnx+00xae

f2ae2a

2fx+x0xxae

fae

+

0x1+f1①f10x

0000122111122100001221111221x1f1ae+lnaga+ga+0ga+lnaax0f0

x

a

0x1f0fx1xfaelnaa10xa（）考：10分請生第、23題中選題答．果做則所的第題分[選修：坐標與數程]22xOyC

15cos0AOAOA|151B2xD

l

M||DM|DN1B0A0OA5cosOB515C3032D3l

t

C5cos

2x2+25x