2021年河南省濮陽市高考數(shù)學(xué)一模試卷

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c4BcbcaDcb1{}aa2a+A4B8CD16ysinlnABCD200050

1120002000ABCD102A2B2C

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fxf0xy+30

nn67nnn67n14615ABCD

BCABCABCD與B16S{}n0m

{}三解題共0分解答寫文說，明程演步驟第17-21題為考，個(gè)題生必作第2223題為考，生據(jù)求答（一必題共60分17AcbsinCsinBcsinCAD2AD18

110432

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112112/340//

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200019PABCDPDABCDABCD

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xfxfafg21px0ABAOBO2CE0ll

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CQFMNFPQ（）考：10分請(qǐng)生第，23中選題答果做則所的第題分[選4-4：標(biāo)與數(shù)程]22t0

l

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440}N{y1|1}MNA[0

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{}ttt

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2+2

cosAAIID

c2AD

++2

134+b2

b2+2b06b262a2

18

110432

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BDPDPBDEDAE

ABDEDAEABDEDAEPDABCDBDPDBDPDeq\o\ac(△,Rt)PBDPBBD1eq\o\ac(△,Rt)PCDCD1BDDC

ABCDCDPDPDPDBDAB

AV

ADBCDE

DE2AD

AEDAEhVVhDAE

20falnx+gxxex

xfxfafgf1a+1afxxlnxx

00000000112eq\o\ac(△,S)1100000000112eq\o\ac(△,S)1111201fxx0fx0a1xlnx+Ffxgxlnx++1Fxexx+1x+1exex

0G110x1Gx

xxxxxx0FxFxFFxlnx+x

0

lnxxFx0Fx0fxx21

pBAOBO2CE0ll

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Cl

CQFMNFPQFp2?2y4ll

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xtyaMyyy24ty+4

1112121FMN2FPQFMNFPQ11112121FMN2FPQFMNFPQ116

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|1+talxteq\o\ac(△,2)eq\o\ac(△,)162

at

t2

1|S|

1|t2

0

0eq\o\ac(△,2)eq\o\ac(△,)tatat2a2

2201a11

（）考：10分請(qǐng)生第，23中選題答果做則所的第題分[選4-4：標(biāo)與數(shù)程]22t0l

l

lC

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