煤礦采區(qū)變電所供電設計

XXXX礦采區(qū)變電所設一三二

實用標準文案---520五采區(qū)現(xiàn)660v，1水平

×

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實用標準文案

21采煤設備負荷統(tǒng)計表

精彩文檔

實用標準文案2掘進設備負荷統(tǒng)計表

3掘進風機負荷統(tǒng)計表

精彩文檔

實用標準文案3水平

1）西變

-3交221.051995m。環(huán)，g精彩文檔

∑∑kg實用標準文案∑∑kgIg

kexUcosηepj

pj∑

P

e

U

e

；pjη—pj1521.10.5760.55Icos6×0.9pjI故所gI===j2.25

mm

J=2.25

A

mm

A

I

tC

fAI

；min(3)—6

av4

=6.3,=MVAsMYJV

-

=avSs

2

2=50MYJV

-

r=0.612Ω/0

x=/km0精彩文檔

s實用標準文案s

w

=x0

Rr==w0

=()+(

+)

=

++0.13)

=1.44+=2.29=ΩI

(3)s

avz

630031.5

2425(I

(2)d1

=

3I=2425=2100()2t=93.4,jA

I

tC

j

=12.98mm

MYJV

×35

ΔU%g

g10

2e

(Rtan

)P

=

x

∑

;∑K

Pe

tan

2

U

e

kV

精彩文檔

e1517.3∑∑Pkexge1517.3∑∑PkexgR

X

實用標準文案；L

()=R760.551.995()0.105×62（+0.0819）==變電所222）采區(qū)-3交221.051200m。環(huán)，gIg

Pkcos

∑

P

e

U

e

；pjη—pj346I==62cosη×6×0.6×epjIg精彩文檔

s實用標準文案sI62=n=28mmj

2

<

35

=2.25

mm

A

I

tC

fAI

min

6

av4

=6.3,=MVAsMYJV

-

6.32av4=S50sMYJV

-

r=0.612Ω/=/0

w

=x1.2=0.07680

Rr=0.6121.2=Ωw

=()2+(X

X)

=(0.7344)

+(0.7938+0.0768)

=0.54+=1.41=ΩI

(3)s1

=

av3

=

630031.19

=A)I

)d1

=

3I(3)=×3057=A)2精彩文檔

e實用標準文案et=93.4,jA

I

(3)1

tC

j

=16.4

MYJV

3

ΔU%=

10U

(R+Xtan

)P

=

x

∑

;∑K

Pe

tan

=

2

UR

e—X—；L

。()U=R+X10U2()+0.78（）符合==0.83%西變電水交22精彩文檔

XeB∑XB∑eB∑P實用標準文案XeB∑XB∑eB∑P11K∑0.5S==81φ0.65jeK

X

K

X

cosφp

j

cosp

j

2K∑S==φpjeK

X

KXcosφp

j

cp

j

3∑S=φp

j

e

=0.6cosφp

j

cosφp

j

2水平S

B

=

K∑Xcosφpj

=

0.40.6

=KVA精彩文檔

實用標準文案

∑

P

e

K

X

KXcosφp

j

cp

j

3132Kw水泵6水1F1.15=2maxe2I××303.6315.5KVA-1）I

ca

B

N

813×0.66

=A）電纜主芯截面（）

長期連續(xù)負荷允許截流量（）精彩文檔

實用標準文案610162535507095

466485113138173215260電長時）變壓

P=，阻抗電N=4%0.73%sr

3.933%

cos

T

=

T

=

II

caT2N

caN10

ca

S

A

S

II

ca

ScaSN

=0.26Δ=K

10T

(

+sin

)100%×(0.73+3.933××+2.71377)100%×3.18827精彩文檔

10XU實用標準文案10XUΔV

T損

=

ΔVV660T2=5.5V100100()ΔU%=R+X0eP

；

K

x

∑

e∑

Pe

Ktan

URL

e0——。ΔU%=Xtan200×)=+2.29×247.115=×+0.23）4.356=×=8.9%ΔU

b

660×8.9%=V=ΔVΔ

b

=+=V

2）I

ca

=

SB

N

=

7330.66

=64A）精彩文檔

10實用標準文案10電長時）變壓

P=，阻抗電N=4%u0.73%sr

u

cos

=

sin

=

II

caN

ScaSN10

caT

AS

A

S

II

ca

ScaSN

=0.24Δ=K

10T

(

+sin

)100%×(0.73+3.933××+2.71377)100%×3.18827ΔV

損

ΔVV0.77=T==V100100()ΔU%=R+X0eP

；

K

x

∑

e∑

Pe

Ktan精彩文檔

XUeXUeUR

實用標準文案e0L

pL()ΔU=R+Xtan00×0.9(=+0.099××239.06=×(0.597+0.23）4.356=×0.827=7.4%ΔU

b

=660=ΔV=ΔVV

b1

=5.1+48.84

3）I

B

N

193

=AI

ca

37A3N））變壓

P=，阻抗電N=4%u0.73%sr

u

cos

=

sin

=

II

caN

ScaSN精彩文檔

UU10

實用標準文案

caT

AS

A

S

1

II

caTN

ScaSN

=0.06Δ

1

=K

10

(cos

+sin

)100%=0.06×(0.730.65+×100%=0.06×+2.71377)=0.06×3.18827=

1

II

ca

ScaTSN

0.12Δ

=K

10

(

+sin

)100%0.12××0.65×0.69)100%=×100%=×=ΔV

=

ΔVV6602==1.25V100100ΔV

損2

ΔVV0.4660=2==100100()ΔU=+eP

；

K

x

∑

e∑

Pe

Ktan

精彩文檔

XUeUeXUeUeUR

實用標準文案e0L

pL)ΔU%=tan0×0.9()=+2.2910×0.669.9=×(0.828+）4.356==ΔU

b

660=pL()ΔU%=+Xtan0×0.4()=0.828+×2.29×28.8=×(0.828+0.244.356=2.02=2.2%Δ

b1

=6602.2%=ΔVΔVΔ

b1

=+14.52=17.16

4水平）I

ca

B

N

12830.66

=112A）電長時）精彩文檔

UX實用標準文案UX變壓

P=，阻抗電N=4%u0.73%sr

u

cos

=

sin

=

=

II

caTN

=

ScaSN10

caT

S

A

S

10-

II

caT

ScaSN

0.4Δ=

10

(cos

+

)=×0.65+×100%=×(0.4745+2.71377)100%=×=ΔV

T損

ΔVV660=T=8.58100100()ΔU%=+0eP

；

K

x

∑

e∑

Pe

Ktan

UR精彩文檔

e0

Ue實用標準文案UeL

pL()ΔU=R+Xtan0077×)=0.305+0.089×2.29×246.2=×(0.305+0.2044.356=×0.509Δ

b1

=660ΔVΔVV

b

=

5）I

ca

B

N

31.14

=A）電長時）K變3300=N

0.66%r

u=3.945%

cos

T

=

T

=

II

caT2N

caN10

caT

AS

A

S精彩文檔

10XU實用標準文案10XU

II

caN

SSN

315.5

=ΔV=

10T

cos+sinTX

)=×(0.66×0.65+×100%0.631×2.72205)0.631×=1.99%ΔV

T損

=

ΔVV1.991140TN=100100

V()ΔU%=R+X0eP

；

K

x

∑

e∑

Pe

Ktan

URL

e0。ΔU%=R+20×0.5()=0.305×2.291.142=×+0.204）12.996×0.509=ΔU

b1

10.3%=67.98VΔV=ΔV+Δ

b1

22.686=

精彩文檔

實用標準文案標級額定電壓

空載

負載

空載

短路阻抗額定容量

聯(lián)結(jié)組高壓

低壓

損耗

損耗

電流

%kVA

標號kV

V

W

W

%Uz

UrUx50

400

600

1.203.816693/40

3100

600

1000

1.003.8730200

950

1700

0.853.90942.5

3.93315

Yy0

130023000.7331

Yd11500

18003300

0.663.9456200/69

2630

21004000

50.635380010001250

230052002700610032007200

5.50.655.4610.615.96961.50.5761200Yy01600

39008800

0.556.4773450Yyn0

6.52000

4500103000.515注：負載損耗值和短路阻抗值為H絕緣材料參考溫度145℃時值。、西變1×6、精彩文檔

實用標準文案單獨掘風PJG-100/6高防開關，高防開；西變14臺高壓隔爆、2及231）（805真空6照開1變壓器精彩文檔

∑實用標準文案∑I

(315)

=

315U

=

≈2五變壓I

(315)

=

315U

=

×

≈3進變壓I

(315)

=

315U

=

≈A4水變壓I

(315)

=

315U

=

×6

≈13A5泵變I

(500)

=