微機軟件實驗習題與答案(完整版)

./微機原理軟件實驗實驗1 兩個多位十進制數(shù)相加的實驗實驗容：將兩個多位十進制數(shù)相加,要求加數(shù)和被加數(shù)均以ASCII碼形式各自順序存放以DATA1和DATA2為首的5個存單元中〔低位在前,結(jié)果送回DATA1處。完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB'inputthefirstnumber:','$'STRING2DB13,10,'inputthesecondnumber:','$'STRING3DB13,10,'theoutputis:','$'DATA1DB6DUP<00H>,'$'DATA2DB6DUP<00H>,'$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼LEASI,DATA1LEADI,DATA2L0:LEADX,STRING1;打印字符串STRING1MOVAH,09INT21HINPUT1:;輸入第一個數(shù)MOVAH,01;輸入字符至AL中INT21HCMPAL,'/'JEL1MOV[SI],ALINCSIJMPINPUT1L1:LEADX,STRING2;打印字符串STRING2MOVAH,09INT21HINPUT2:;輸入第二個數(shù)MOVAH,01;輸入字符至ALINT21HCMPAL,'/'JEL2MOV[DI],ALINCDIJMPINPUT2L2:MOVSI,0CLC;清空進位標志位CFMOVCX,6PLUSE:;相加;SUBDATA1[SI],30H;SUBDATA2[SI],30H;這里不能使用這兩條指令,因為如果DATA1[5]=00H,00H-30H需要借位相減,使CF=1MOVAL,DATA1[SI]ADCAL,DATA2[SI]AAA;加法調(diào)整指令,可使兩個ASCII數(shù)直接相加MOVDATA1[SI],AL;和賦給DATA1[SI]INCSILOOPPLUSEL3:LEADX,STRING3;打印字符串STRING3MOVAH,09INT21HMOVCX,6MOVSI,6SHOW:DECSICMPDATA1[SI],00HJESHOWSHOW2:MOVDL,DATA1[SI]ADDDL,30HMOVAH,02INT21HCMPSI,0JEL4DECSIJMPSHOW2L4:MOVAH,4CHINT21HCODESENDSENDSTART運行結(jié)果如下：輸入為低位在前,即輸入1234和99999相加實際上是4321和99999相加〔即：4321+99999=104320實驗2 兩個數(shù)相乘的實驗〔無符號數(shù)相乘實驗容：實現(xiàn)十進制數(shù)的乘法。要求被乘數(shù)和乘數(shù)均以ASCII碼形式各自順序存放在存中,乘積在屏幕上顯示出來。完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB'theoutputis:','$'DATA1DB31H,32H,33HDATA2DB35H,36HDATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼MOVDL,10MOVAL,DATA1[0];AL=31HSUBAL,30H;AL=01HMULDL;乘10;AL=10ADDAL,DATA1[1];AL=10+32HSUBAL,30H;AL=10+32H-30H=12MULDL;AL=120ADDAL,DATA1[2];AL=120+33HSUBAL,30H;AL=120+33H-30H=123MOVBL,AL;BL=AL;MOVAL,DATA2[0];AL=35HSUBAL,30H;AL=5MULDL;乘10;AL=50ADDAL,DATA2[1];AL=50+36HSUBAL,30H;AL=50+36H-30H=56MULBL;AX=123x56=6888SUBDX,DX;DX清零MOVBX,1000DIVBX;<DX,AX>/1000,商6在AX中,余數(shù)888在DX中PUSHDXMOVDL,ALADDDL,30HMOVAH,02;打印最高位6INT21HPOPDXMOVBL,100MOVAX,DX;888賦給AXDIVBL;AX/100,商放在AL中,余數(shù)88放在AH中MOVDL,ALMOVCL,AH;?。?！這里千萬不能把AH直接賦給AL,因為經(jīng)過INT21H指令后AL,AH會改變ADDDL,30HMOVAH,02;打印第二位INT21HMOVBL,10MOVAL,CLSUBAH,AH;清空AHDIVBL;AX/10,商放在AL中,余數(shù)8放在AH中MOVDL,ALMOVCL,AHADDDL,30HMOVAH,02;打印第三位INT21HMOVDL,CLADDDL,30HMOVAH,02;打印第四位INT21HCODESENDSENDSTART運行結(jié)果為：實驗3 字符串匹配實驗實驗容：編寫程序?qū)崿F(xiàn)兩個字符串比較。如果相同,則屏幕顯示"match",否則屏幕顯示"nomatch" ,完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼PRINT1DB'inputthefirststring:','$'PRINT2DB13,10,'inputthesecondstring:','$'PRINT3DB'match','$'PRINT4DB'nomatch','$'PRINT5DB13,10,'output:','$'STRING1DB30DUP<00H>,13,10,'$'STRING2DB30DUP<00H>,13,10,'$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKS,ES:DATASSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼LEADX,PRINT1;打印字符串PRINT1MOVAH,09INT21HLEASI,STRING1;STRING1地址賦給SILEADI,STRING2;STRING2地址賦給DIINPUT1:MOVAH,01;輸入字符至ALINT21HCMPAL,'/';輸入字符串以‘/’結(jié)束,轉(zhuǎn)L0JEL0MOV[SI],ALINCSIJMPINPUT1L0:LEADX,PRINT2;打印字符串PRINT2MOVAH,09INT21HINPUT2:MOVAH,01;輸入字符至ALINT21HCMPAL,'/'JEL1MOV[DI],ALINCDIJMPINPUT2L1:MOVCX,30;CX=30代表比較30次MOVSI,00HCOMPARE:;字符串一個一個比較MOVAL,STRING1[SI];取STRING1存儲單位中的第SI個字符賦給ALCMPAL,STRING2[SI];AL與STRING2存儲單位中的第SI個字符比較JNENOMATCHINCSILOOPCOMPAREJMPMATCHNOMATCH:;打印output:nomatchLEADX,PRINT5MOVAH,09INT21HLEADX,PRINT4MOVAH,09INT21HJMPL2MATCH:;打印output:matchLEADX,PRINT5MOVAH,09INT21HLEADX,PRINT3MOVAH,09INT21HL2:MOVAH,4CHINT21HCODESENDSENDSTART運行結(jié)果：實驗4 從鍵盤輸入數(shù)據(jù)并顯示的實驗實驗容：將鍵盤輸入的2位十六進制數(shù)轉(zhuǎn)換為等值的二進制數(shù),并在屏幕上顯示。列如：鍵入f2,則顯示11110010.完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB'pleaseinputastring:','$'STRING2DB13,10,'theoutputis:','$'STRING3DB13,10,'inputerror',13,10,'$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼L0:LEADX,STRING1;打印字符串STRING1MOVAH,09INT21HMOVAH,01;輸入第一個字符至AL中INT21HCMPAL,'0'JBERROR1CMPAL,'9'JBEENTER1CMPAL,'A'JBERROR1CMPAL,'F'JBEENTER1CMPAL,'a'JBERROR1CMPAL,'f'JBEENTER1ERROR1:LEADX,STRING3;打印字符串STRING3MOVAH,09INT21HJMPL0ENTER1:CALLASC2BCD;把ASCII碼轉(zhuǎn)化成十進制數(shù)BCD碼MOVCL,4ROLAL,CLMOVBL,AL;把高四位放到BL寄存器中;輸入第二個字符MOVAH,01;輸入第二個字符至AL中INT21HCMPAL,'0'JBERROR1CMPAL,'9'JBEENTER2CMPAL,'A'JBERROR1CMPAL,'F'JBEENTER2CMPAL,'a'JBERROR1CMPAL,'f'JBEENTER2ENTER2:CALLASC2BCD;把ASCII碼轉(zhuǎn)化成十進制數(shù)BCD碼ADDBL,ALLEADX,STRING2;打印字符串STRING2MOVAH,09INT21HMOVCX,9CLC;清空標志位SHOW:;顯示BL中的二進制數(shù)DECCXCMPCX,0JENEXT;輸出完八位之后返回DOSROLBL,1;循環(huán)左移一位,若溢出為1,則CF=1JCM1JMPM2M1:MOVDL,'1';若CF=1,轉(zhuǎn)至M1打印‘1’MOVAH,02INT21HJMPSHOWM2:MOVDL,'0';若CF=0,轉(zhuǎn)至M1打印‘0’MOVAH,02INT21HJMPSHOWNEXT:MOVAH,4CHINT21HASC2BCDPROCCMPAL,'9'JBEL1;若AL≤9,轉(zhuǎn)L1SUBAL,07H;若輸入的數(shù)為A~F,或者a~f,則減7,A接在39H后面,A~F=3AH~3FH,a~f=5AH~5FHL1:SUBAL,30H;減30HANDAL,0FH;濾除高位,保留低位,因為a~f恰好比A~F大20H,這樣a~f就和A~F的數(shù)值一樣了RETASC2BCDENDPCODESENDSENDSTART輸出結(jié)果為：〔若輸出不在0~9,A~F,a~f,則重新輸入實驗5 字符和數(shù)據(jù)計算的實驗實驗容：先在屏幕上顯示"inputstring,",輸入字符串;再顯示"result="。如為0~9的數(shù)字,則計數(shù)器加1,如為非數(shù)字,則直接顯示,但不計數(shù)。完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB'inputstring:','$'STRING2DB13,10,'result=','$'STRING3DB13,10,'zifu:','$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼LEADX,STRING1;打印字符串1MOVAH,09INT21HMOVCX,0MOVBX,0INPUT:MOVAH,01;輸入字符至ALINT21HCMPAL,'/';輸入/后轉(zhuǎn)L0JEL0CMPAL,'0';下溢出轉(zhuǎn)RUZHANJBRUZHANCMPAL,'9';上溢出轉(zhuǎn)RUZHANJARUZHANINCCL;若為數(shù)字則計數(shù)器+1JMPINPUTRUZHAN:;非數(shù)字字符入棧PUSHAXADDBL,1;BL代表入棧的字符個數(shù),方便待會輸出JMPINPUTL0:LEADX,STRING3;打印字符串3MOVAH,09INT21HCHUZHAN:POPAXMOVDX,AXMOVAH,02INT21HSUBBL,1CMPBL,0;入了多少個棧,出多少棧JNECHUZHANOUTPUT:;輸出數(shù)字的個數(shù)LEADX,STRING2;打印字符串2MOVAH,09INT21HMOVDL,CLADDDL,30HMOVAH,02INT21HMOVAH,4CHINT21HCODESENDSENDSTART輸出結(jié)果為：〔這里非數(shù)字字符輸出順序與輸入順序相反實驗6改變年月日的實驗實驗容：先在屏幕上顯示"whatisthedate<mm/dd/yy>?"從鍵盤輸入的月日年能把計算機的系統(tǒng)日期改為你鍵入的值。完整代碼如下：DATASSEGMENT S1DB0AH,0DH,"whatisthedate<mm/dd/yy>?:",'$'DATASENDSSTACKSSEGMENTSTACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AXMOVDX,OFFSETS1MOVAH,09H;打印字符串"whatisthedate<mm/dd/yy>?:"INT21HMOVDX,0H;DX=CH=0MOVCH,0;MOVSI,0AHKAISHI:MOVCL,0;用來壓縮移位SHURU:MOVAH,01H;輸入字符存入AL中INT21HMOVAH,0AH;10賦給AHCMPAL,0DH;AL=13則結(jié)束,設(shè)置日期JEGENGGAICMPAL,'/';計算來判斷是年,月,日JEZIZENGANDAL,0FHCMPCH,0;等于0則轉(zhuǎn)月JEYUECMPCH,1;等于1則轉(zhuǎn)日JERICMPCH,2;等于2則轉(zhuǎn)年JENIANZIZENG:INCCHJMPSHURU;無條件轉(zhuǎn)移至SHURUYUE:ADDDH,ALCMPCL,0JNZKAISHIINCCLMOVAL,DHMULAHMOVDH,ALJMPSHURU;無條件轉(zhuǎn)移至SHURURI:ADDDL,ALCMPCL,0JNZKAISHIINCCLMOVAL,DLMULAHMOVDL,ALJMPSHURU;無條件轉(zhuǎn)移至SHURUNIAN:CMPCL,0JNZXIABUADDBL,ALMOVCL,03H;3賦給CLJMPSHURU;無條件轉(zhuǎn)移至SHURUXIABU:MOVAH,0;清空AHMOVSI,BX;SI=BXSHLBX,CL;BX左移三位,乘以8SHLSI,1;SI左移一位,乘以2ADDBX,SI;兩個相加,即乘以10ADDBX,AX;BX加上新輸入的數(shù)字JMPSHURUGENGGAI:MOVCX,BXMOVAH,2BH;設(shè)置日期INT21HMOVAH,4CHINT21HCODESENDSENDSTART輸出結(jié)果為：〔設(shè)置20XX12月3日,注意如果要設(shè)置好系統(tǒng),否則可能計算機的日期改變不了實驗7 將小寫字母轉(zhuǎn)換為大寫字母的實驗實驗容：接收鍵入字符〔以Ctrl-c為結(jié)束,將小寫字母變?yōu)榇髮懽帜?并在屏幕上顯示。完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB13,10,'pleaseinputastring:','$'STRING2DB13,10,'theoutputstringis:','$'DATADB100DUP<00H>,'$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼M:LEASI,DATALEADX,STRING1;打印字符串1MOVAH,09INT21HINPUT:MOVAH,01;輸入字符CINT21HCMPAL,03HJEOUTPUTCMPAL,'a'JBMCMPAL,'z'JAMSUBAL,20H;減20H變小寫MOV[SI],ALINCSIJMPINPUTOUTPUT:LEADX,STRING2;打印字符串2MOVAH,09INT21HLEASI,DATAL1:MOVDL,[SI]CMPDL,00HJEENDINGMOVAH,02INT21HINCSIJMPL1ENDING:MOVAH,4CHINT21HCODESENDSENDSTART運行結(jié)果為：〔如果輸入的不在a~f中,則重新輸入實驗8 排序?qū)嶒?lt;0~9>實驗容：從首地址為1000H開始存放10個數(shù),將這些數(shù)按降序排列.完整代碼如下：DATASSEGMENT;此處輸入數(shù)據(jù)段代碼STRING1DB'pleaseinput10numbers:','$'STRING2DB13,10,'thesortednumbersare:','$'ORG1000HDATADB10DUP<00H>,'$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼LEADX,STRING1;輸入提示語'pleseinput10numbers:'MOVAH,09INT21HMOVCX,10LEASI,DATAINPUT:MOVAH,01;輸入字符至ALINT21HMOV[SI],AL;把AL賦給偏移地址為SI指向的單元INCSILOOPINPUTMOVBL,0L0:MOVCX,9LEASI,DATAL1:;比較第SI個數(shù)和第SI+1個數(shù)的大小MOVAL,[SI]INCSICMPAL,[SI]JBCHANGE;若小于則轉(zhuǎn)CHANGEL2:LOOPL1;小循環(huán)〔CX自動減1,若CX=0則結(jié)束L3:INCBLCMPBL,10JBL0;若大循環(huán)有10次了,則轉(zhuǎn)OUTPUTJMPOUTPUTCHANGE:;交換兩個數(shù)XCHGAL,[SI];交換,MOV[SI-1],AL;賦給SI-1JMPL2OUTPUT:LEADX,STRING2;輸入提示語'thesortednumbersare:'MOVAH,09INT21HMOVCX,10LEASI,DATAL4:;循環(huán)輸出MOVDL,[SI]MOVAH,02INT21HINCSILOOPL4MOVAH,4CHINT21HCODESENDSENDSTART輸出結(jié)果為：實驗8 排序?qū)嶒?lt;多位數(shù)排序>實驗容：從首地址為1000H開始存放10個數(shù),將這些數(shù)按降序排列.完整代碼如下：DATASEGMENT;CHANGE函數(shù)DI,SI為入口函數(shù),交換SI,DI的值,SI,DI值已經(jīng)大變BUFFERDB100DB?DB100DUP<?>DB"$"ORG1000HNEQU10STOREDATADB110DUP<30H>;每個數(shù)最大為10位TEMP1DB12DUP<24H>;中間變量TEMP2DB12DUP<24H>;中間變量TEMP3DB12DUP<24H>;中間變量DATAENDSSTACKSEGMENTPARASTACKDW60HDUP<0>STACKENDSCODESEGMENTASSUMEDS:DATA,CS:CODE,SS:STACKSTART:MOVAX,DATAMOVDS,AX;MOVAX,STACK;MOVSS,AX;可以有可以無,因為其已經(jīng)默認為SS了MOVDX,OFFSETBUFFERMOVAH,0AHINT21HCALLTURNLINELEASI,BUFFERLEADI,STOREDATACALLBUFFERTOSTORECALLTURNLINELEASI,STOREDATACALLCOMPAREGO:MOVSI,OFFSETSTOREDATAMOVCL,110PRINT:MOVDL,[SI]CMPDL,30HJNEPRINT1CMPAL,1JEPRINT1;打印該有的0INCSILOOPPRINTPRINT1:CMPDL,2CHJEPRINT0JIXU:MOVAH,02HINT21HCMPDL,2CHJNEGOON5MOVAL,0JMPGOON6PRINT0:CMPAL,0JNEJIXUMOVDL,30HMOVAH,02HINT21HMOVDL,2CHJMPJIXUGOON5:MOVAL,1GOON6:INCSILOOPPRINTMOVAH,01HINT21HMOVAH,4CHINT21HCOMPAREPROC;以SI為入口傳遞MOVBX,SI;LEADI,TEMP2;GETLAST:;CALLTEMPSAVE;INCDL;CMPDL,N;JEGOON1;LEADI,TEMP2;JMPGETLAST;TEMP2始終指向當前最后一個數(shù);GOON1:MOVCL,NCOMPARE1:MOVSI,BXLEADI,TEMP1CALLTEMPSAVE;TEMP1指向第一個數(shù),錯啦,為什么呢,因為那樣比不會進行變化MOVSI,BXMOVDH,1LEADI,TEMP1PUSHSICOMPARE2:LODSBMOVAH,[DI]CMPAL,2CHJEEQUALCMPAL,AHJBBELOWCMPAL,AHJAABOVEINCDIJMPCOMPARE2BELOW:INCDHPOPSIPUSHSILEADI,TEMP1CALLTEMPSAVE;使TEMP1存入當前最小,因為TEMP1當前元已經(jīng)存在了;不可以再轉(zhuǎn)存,否則出錯POPSIADDSI,NINCSIPUSHSICMPDH,CLJAGOON2LEADI,TEMP1JMPCOMPARE2EQUAL:INCDH;不交換POPSIADDSI,NINCSIPUSHSICMPDH,CLJAGOON2;比較CL次LEADI,TEMP1JMPCOMPARE2ABOVE:;TEMP1始終指向當前最小,若當前值大于時最小時前移;此時TEMP1不便,只需前移就好,交換前后兩個數(shù)的大小INCDHPOPSIPUSHSISUBSI,NSUBSI,1MOVDI,SIPOPSIPUSHSICALLCHANGEPOPSIADDSI,NINCSIPUSHSICMPDH,CLJAGOON2;比較CL次LEADI,TEMP1JMPCOMPARE2GOON2:LOOPCOMPARE1JMPGORETCOMPAREENDP;存儲函數(shù)思路：從最后一位開始存,首位均置零,最高10位BUFFERTOSTOREPROCMOVCL,10ADDSI,2;SUBDI,3STORE:MOVAL,[SI]CMPAL,2CH;直到SI指向,<結(jié)束一個數(shù)>,再進行存儲JESTORE2INCSIJMPSTORESTORE2:MOVBX,SI;存儲SISTOREIN:ADDDI,N;ADDDI,3MOVDX,DI;存儲DISTOREIN1:MOVAL,[SI]MOV[DI],ALDECSIDECDILEAAX,BUFFERADDAX,1;注意邊界要取好,因其也有值CMPSI,AXJEJMP1MOVAL,[SI]CMPAL,2CHJEJMP1JMPSTOREIN1;條件控制循環(huán)JMP1:MOVSI,BXINCSI;進行存儲下個數(shù)INCDX;使DI加1因為前幾位已經(jīng)用了MOVDI,DXLOOPSTORE;MOVAL,"$";INCDI;MOV[DI],ALRETBUFFERTOSTOREENDPCHANGEPROCPUSHDIPUSHSILEADI,TEMP3CALLTEMPSAVE;TEMP3存放SI當前值POPDI;往SI存入值POPSIPUSHSICALLTEMPSAVE;******把DI的值存入SI中POPDILEASI,TEMP3CALLTEMPSAVE;*******把SI的值存入DI中RETCHANGEENDPTEMPSAVEPROC;存儲中間變量的函數(shù),以DI,SI,為入口,以,標志位結(jié)束STEMP:LODSBMOV[DI],ALINCDICMPAL,2CHJENEXTJMPSTEMPNEXT:RETTEMPSAVEENDPTURNLINEPROCMOVDL,0AHMOVAH,02HINT21HRETTURNLINEENDPCODEENDSENDSTART輸出結(jié)果為：實驗9 設(shè)置光標的實驗實驗容：設(shè)置光標,起始位置為第5行第6列,結(jié)束位置為第8行第6列。完整代碼如下:DATASSEGMENT;此處輸入數(shù)據(jù)段代碼DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKSSTART:MOVAX,DATASMOVDS,AX;此處輸入代碼段代碼MOVAH,08;輸入無回顯INT21HMOVDH,5;設(shè)置行MOVDL,6;設(shè)置列MOVBH,0;設(shè)置頁MOVAH,02INT10HMOVAH,08;輸入無回顯INT21HMOVDH,8;設(shè)置行MOVDL,6;設(shè)置列MOVBH,0;設(shè)置頁MOVAH,02INT10HMOVAH,08;輸入無回顯INT21HMOVAH,4CHINT21HCODESENDSENDSTART輸出結(jié)果為：〔任意輸入一個字符,光標跳到5行6列,再任意輸入一個字符,光標跳到8行6列這里光標截圖后是看不到的,所以就不截圖了實驗10 計算N!的實驗實驗容：在鍵盤輸入數(shù)字,結(jié)果顯示在屏幕上。DATASSEGMENT;段定義〔結(jié)構(gòu);此處輸入數(shù)據(jù)段代碼P1DB'inputthenumber<0-6>:','$'p2DB13,10,'theresultis:','$'DATASENDSSTACKSSEGMENT;此處輸入堆棧段代碼ST1DW40HDUP<0>STACKSENDSCODESSEGMENTASSUMECS:CODES,DS:DATAS,SS:STACKS;段分配〔結(jié)構(gòu)START:MOVAX,DATAS;設(shè)置段地址〔結(jié)構(gòu)MOVDS,AXMOVAX,STACKSMOVSS,AX;此處輸入代碼段代碼LEADX,P1;顯示提示字符串'inputthenumber:'MOVAH,09INT21HMOVAH,01;鍵入N到A