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專題2-2冪指對三角函數(shù)比大小歸類目錄TOC\o"1-1"\h\u題型01比大小基礎(chǔ):冪指數(shù)函數(shù)性質(zhì) 1題型02比大小基礎(chǔ):對數(shù)函數(shù)性質(zhì) 2題型03比大小基礎(chǔ):三角函數(shù)性質(zhì) 3題型04臨界值型:0與1分界 5題型05臨界值型:中間值 5題型06作差比較法 6題型07作商比較法 7題型08三角函數(shù)與冪指對 7題型09構(gòu)造函數(shù)求導(dǎo):對數(shù)冪型 8題型10構(gòu)造函數(shù)求導(dǎo):指冪型 9題型11構(gòu)造函數(shù)求導(dǎo):對數(shù)線性型 9題型12構(gòu)造函數(shù)求導(dǎo):指數(shù)線性型 10題型13構(gòu)造函數(shù)求導(dǎo):三角函數(shù)線性型 11題型14泰勒展開型比大小 11高考練場 12題型01比大小基礎(chǔ):冪指數(shù)函數(shù)性質(zhì)【解題攻略】冪函數(shù)圖像SKIPIF1<0SKIPIF1<0圖象性質(zhì)定義域SKIPIF1<0值域SKIPIF1<0過定點SKIPIF1<0單調(diào)性在SKIPIF1<0上是增函數(shù)在SKIPIF1<0上是減函數(shù)奇偶性非奇非偶函數(shù)【典例1-1】(2023上·內(nèi)蒙古赤峰·高三??计谥校┰O(shè)SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】.(2023上·河北邢臺·高三邢臺市第二中學(xué)校聯(lián)考階段練習(xí))設(shè)SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023上·河南南陽·高一統(tǒng)考期中)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023上·福建泉州·高三泉州七中??迹┰O(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023上·新疆伊犁·高三校聯(lián)考)已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題型02比大小基礎(chǔ):對數(shù)函數(shù)性質(zhì)【解題攻略】對數(shù)函數(shù)性質(zhì)a>10<a<1圖象性質(zhì)定義域(0,+∞)值域R過定點過定點(1,0),即x=1時,y=0函數(shù)值的變化當(dāng)0<x<1時,y<0;當(dāng)x>1時,y>0當(dāng)0<x<1時,y>0;當(dāng)x>1時,y<0單調(diào)性是(0,+∞)上的增函數(shù)是(0,+∞)上的減函數(shù)【典例1-1】(2023上·四川成都·高三??迹┮阎猘,b是實數(shù),則“SKIPIF1<0”是“SKIPIF1<0”的(
)A.充要條件 B.充分不必要條件C.必要不充分條件 D.既不充分又不必要條件【典例1-2】(2023上·江蘇南京·高三統(tǒng)考)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023上·福建莆田·高三莆田第十中學(xué)校考期中)已知SKIPIF1<0則(
).A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023上·河南周口·高三??茧A段練習(xí))已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023上·山東濰坊·高三統(tǒng)考期中)已知SKIPIF1<0則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題型03比大小基礎(chǔ):三角函數(shù)性質(zhì)【解題攻略】三角函數(shù)圖像性質(zhì)函數(shù)y=sinxy=cosxy=tanx圖象定義域RR{x|x∈R且x≠eq\f(π,2)+kπ,k∈Z}值域[-1,1][-1,1]R單調(diào)性[-eq\f(π,2)+2kπ,eq\f(π,2)+2kπ](k∈Z)上遞增;[eq\f(π,2)+2kπ,eq\f(3π,2)+2kπ](k∈Z)上遞減[-π+2kπ,2kπ](k∈Z)上遞增;[2kπ,π+2kπ](k∈Z)上遞減(-eq\f(π,2)+kπ,eq\f(π,2)+kπ)(k∈Z)上遞增最值x=eq\f(π,2)+2kπ(k∈Z)時,ymax=1;x=-eq\f(π,2)+2kπ(k∈Z)時,ymin=-1x=2kπ(k∈Z)時,ymax=1;x=π+2kπ(k∈Z)時,ymin=-1奇偶性奇函數(shù)偶函數(shù)奇函數(shù)對稱中心(kπ,0)(k∈Z)(eq\f(π,2)+kπ,0)(k∈Z)(eq\f(kπ,2),0)(k∈Z)對稱軸方程x=eq\f(π,2)+kπ(k∈Z)x=kπ(k∈Z)周期2π2ππ【典例1-1】(2021屆黑龍江省哈爾濱六中高三下學(xué)期第四次模擬理科數(shù)學(xué)試卷)若SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0大小關(guān)系為A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(山東省德州市齊河縣第一中學(xué)2020-2021學(xué)年高三上學(xué)數(shù)學(xué)試題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的大小關(guān)系正確的是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(河南省鄭州市第四高級中學(xué)2020-2021學(xué)年高三下學(xué)期5月月考數(shù)學(xué)試題)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小關(guān)系為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題型04臨界值型:0與1分界【解題攻略】解答比較函數(shù)值大小問題,常見的基礎(chǔ)思路之一是判斷各個數(shù)值所在的區(qū)間,這樣的區(qū)間劃分,最基礎(chǔ)的是以正負(fù)劃分,正數(shù)則以1為區(qū)間端點劃分?!镜淅?-1】.(2024上·寧夏銀川·高三銀川一中校考階段練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
).A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023上·吉林長春·高三長春外國語學(xué)校??迹┤鬝KIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023·全國·模擬預(yù)測)已知實數(shù)a,b,c,d滿足SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(廣東省陸豐市林啟恩紀(jì)念中學(xué)2021-2022學(xué)年高三上學(xué)期第2次(12月)數(shù)學(xué)試題)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0三者的大小關(guān)系是()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(重慶市育才中學(xué)2021-2022學(xué)年高三上學(xué)期數(shù)學(xué)試題)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型05臨界值型:中間值【解題攻略】尋找非0、1的中間變量是難點。中間變量的選擇首先要估算要比較大小的兩個值所在的大致區(qū)間。然后可以對區(qū)間使用二分法(或者利用區(qū)間內(nèi)特殊值,或者利用指對互化)尋找合適的中間值。1.估算要比較大小的兩個值所在的大致區(qū)間2.可以對區(qū)間使用二分法(或者利用指對轉(zhuǎn)化)尋找合適的中間值【典例1-1】(2023上·浙江·高三校聯(lián)考)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023上·四川成都·高三??迹┮阎猄KIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023·全國·模擬預(yù)測)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023上·江蘇·高三專題練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則x,y,z的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023上·全國·高三專題練習(xí))已知實數(shù)a,b,c滿足SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型06作差比較法【解題攻略】差比法:作差,變形,判斷正負(fù)。其中難點在于恒等變形的方向和變形的技巧,變形的目的是為了判斷正負(fù),所以可以因式分解,或者計算化簡,或者放縮為具體值,準(zhǔn)確計算找對變形方向是關(guān)鍵?!镜淅?-1】(2023上·江西·高三統(tǒng)考)已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023上·全國·高三專題練習(xí))若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023上·四川成都·高三??迹┮阎猄KIPIF1<0,SKIPIF1<0,SKIPIF1<0則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023·貴州六盤水·統(tǒng)考模擬預(yù)測)若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023下·河南安陽·高二統(tǒng)考期末)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題型07作商比較法【解題攻略】商比法:兩個正數(shù)a,b,如果SKIPIF1<0,運用商比法,要注意兩個數(shù)是正數(shù)還是負(fù)數(shù)?!镜淅?-1】(2023·四川成都·校聯(lián)考模擬預(yù)測)若SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023上·天津南開·高三南開中學(xué)??迹㏒KIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023·云南·校聯(lián)考模擬預(yù)測)已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023·全國·模擬預(yù)測)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023下·四川瀘州·高三瀘縣五中??茧A段練習(xí))設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則()A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型08三角函數(shù)與冪指對【解題攻略】三角函數(shù)與三角函數(shù)值比較大小:1.借助于三角函數(shù)的周期性,對稱性,誘導(dǎo)公式等,轉(zhuǎn)化為一個單調(diào)區(qū)間內(nèi)比大小2.借助一些三角函數(shù)不等式進行放縮轉(zhuǎn)化:如當(dāng)SKIPIF1<0(0,SKIPIF1<0)時,SKIPIF1<03.構(gòu)造含有三角函數(shù)式的函數(shù),求導(dǎo)后借助單調(diào)性比大小【典例1-1】(廣東省深圳外國語學(xué)校高中園2022-2023學(xué)年高三上學(xué)期學(xué)段(三)數(shù)學(xué)試題)已知SKIPIF1<0,則SKIPIF1<0的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(廣西南寧市銀海三雅學(xué)校2022-2023學(xué)年高三上學(xué)期第一次考試數(shù)學(xué)學(xué)科試題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(四川省成都市實驗外國語學(xué)校2022-2023學(xué)年高三上學(xué)期考試數(shù)學(xué)試題)已知SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】已知實數(shù)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則這三個數(shù)的大小關(guān)系正確的是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(河南省濟源市、平頂山市、許昌市2022屆高三文科數(shù)學(xué)試題變式題11-15)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0題型09構(gòu)造函數(shù)求導(dǎo):對數(shù)冪型【解題攻略】構(gòu)造對數(shù)型函數(shù):SKIPIF1<0由對數(shù)性質(zhì)logaMn=nlogaM(n∈R,常見得式子可以同構(gòu)為SKIPIF1<0型【典例1-1】(福建省廈門海滄實驗中學(xué)2021-2022學(xué)年高二下學(xué)期期中考試數(shù)學(xué)試題)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系是A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(廣東省揭陽市2021-2022學(xué)年高三上學(xué)期數(shù)學(xué)試題)已知SKIPIF1<0,則a,b,c的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(北京市鐵路第二中學(xué)2021-2022學(xué)年高三考試數(shù)學(xué)試題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0(SKIPIF1<0),則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(河南省商丘市商丘名校2021-2022學(xué)年高三聯(lián)考數(shù)學(xué)理科試題)已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型10構(gòu)造函數(shù)求導(dǎo):指冪型【解題攻略】指數(shù)冪形式,比較常見的是以e為底的指數(shù)函數(shù)與冪函數(shù)的積或商的形式:SKIPIF1<0【典例1-1】(2023上·重慶·高三重慶一中??茧A段練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則有(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023·陜西商洛·陜西省丹鳳中學(xué)校考模擬預(yù)測)已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2023上·云南昆明·高三??茧A段練習(xí))設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,設(shè)a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2023下·江西上饒·高二統(tǒng)考期末)已知實數(shù):SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2023下·河南商丘·高二統(tǒng)考階段練習(xí))已知SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型11構(gòu)造函數(shù)求導(dǎo):對數(shù)線性型【解題攻略】對數(shù)線性形式,比較常見的是以對數(shù)為整體的線性形式:SKIPIF1<0等【典例1-1】.(2022上·遼寧·高三東北育才學(xué)校??茧A段練習(xí))設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】.(2022上·福建·高三校聯(lián)考階段練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2022下·四川成都·高二校聯(lián)考期中)已知SKIPIF1<0,且SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.c<b<a B.b<c<aC.a(chǎn)<c<b D.a(chǎn)<b<c【變式1-2】(2022上·江蘇徐州·高三期末)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2022上·湖北·高三湖北省紅安縣第一中學(xué)校聯(lián)考階段練習(xí))已知,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型12構(gòu)造函數(shù)求導(dǎo):指數(shù)線性型【解題攻略】指數(shù)線性形式,比較常見的是以指數(shù)為整體的線性形式:SKIPIF1<0等【典例1-1】設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】已知SKIPIF1<0,則a,b,c的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0,SKIPIF1<0,SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2022上·河北唐山·高三開灤第二中學(xué)校考階段練習(xí))已知SKIPIF1<0,則SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2022上·山東淄博·高三校聯(lián)考階段練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則下列關(guān)系式正確的是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型13構(gòu)造函數(shù)求導(dǎo):三角函數(shù)線性型【典例1-1】(2022上·江蘇南通·高三統(tǒng)考階段練習(xí))已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(2023·四川成都·統(tǒng)考一模)設(shè)SKIPIF1<0,則SKIPIF1<0的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2022上·廣東廣州·高三廣州市第十七中學(xué)校考階段練習(xí))設(shè)SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2022上·海南·高三校聯(lián)考階段練習(xí))設(shè)SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-3】(2022上·浙江·高三統(tǒng)考期中)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<0題型14泰勒展開型比大小【解題攻略】泰勒展開式x0=0時得麥克勞林展開式,常常用于放縮法進行比較大小,常用的麥克勞林展開式如下:SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.【典例1-1】已知SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【典例1-2】(江蘇省無錫市江陰市普通高中2022-2023學(xué)年高三上學(xué)期期末數(shù)學(xué)試題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,這三個數(shù)的大小關(guān)系為(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-1】(2022年新高考1卷第7題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0SKIPIF1<0A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0【變式1-2】(2021年全國乙卷理科12題)設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0.則()A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<0高考練場1.(2023上·廣東汕頭·高一金山中學(xué)??计谥校┮阎猄KIPIF1<0,則SKIPIF1<0的大小關(guān)系是(
)A.SKIPIF1<0 B.SKIPIF1<0C.SKIPIF1<0 D.SKIPIF1<02.(2023上·廣東湛江·高三校聯(lián)考階段練習(xí))若SKIPIF1<0,則(
)A.SKIPIF1<0 B.SKIPIF1<0 C.SKIPIF1<0 D.SKIPIF1<03.(安徽省安慶市一中2017-2018學(xué)年高三下學(xué)期數(shù)學(xué)試題)在SKIPIF1<0中,SKIPIF1<0是鈍角,設(shè)SKIPIF1<0,SKIPIF1<0,SKIPIF1<0,則SKIPIF1<0、SKIPIF1<0、SKIPIF1<0的大小關(guān)系是______.4.(福建省三明第一中學(xué)2021-2022學(xué)年高三上學(xué)期學(xué)數(shù)學(xué)試題)設(shè)SKIPIF1<0,SKIPIF1
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