新高考數(shù)學(xué)一輪復(fù)習(xí)函數(shù)重難點專題03函數(shù)的最值(值域)求法（原卷版）

專題03函數(shù)的最值(值域)求法專項突破一單調(diào)性法1．函數(shù)SKIPIF1<0在SKIPIF1<0的最大值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．已知函數(shù)SKIPIF1<0，若SKIPIF1<0對任意SKIPIF1<0恒成立，則實數(shù)m的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．若函數(shù)SKIPIF1<0的值域是SKIPIF1<0，則函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，SKIPIF1<0，使得SKIPIF1<0，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．函數(shù)SKIPIF1<0，若SKIPIF1<0的最大值和最小值是____．6．函數(shù)SKIPIF1<0的值域為___________.7．已知函數(shù)SKIPIF1<0．(1)試判斷函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的單調(diào)性，并證明；(2)求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的值域.8．檢驗下列函數(shù)的增減性，并說明是否有最大（?。┲担绻?，指出最大（?。┲岛蛯?yīng)的最大（?。┲迭c．(1)SKIPIF1<0；(2)SKIPIF1<0；(3)SKIPIF1<0；(4)SKIPIF1<0．9．已知SKIPIF1<0．(1)求SKIPIF1<0的定義域；(2)討論SKIPIF1<0的單調(diào)性；(3)求SKIPIF1<0在區(qū)間SKIPIF1<0上的值域．10．已知函數(shù)SKIPIF1<0為冪函數(shù)，且為奇函數(shù).(1)求SKIPIF1<0的值，并確定SKIPIF1<0的解析式；(2)令SKIPIF1<0，求SKIPIF1<0在SKIPIF1<0的值域.11．已知函數(shù)SKIPIF1<0．(1)用定義法證明函數(shù)SKIPIF1<0在SKIPIF1<0上為增函數(shù)；(2)若SKIPIF1<0，且當(dāng)SKIPIF1<0時SKIPIF1<0恒成立，求實數(shù)a的取值范圍．專項突破二判別式法1．函數(shù)SKIPIF1<0的最大值與最小值的和是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．求函數(shù)SKIPIF1<0的值域______________．3．求函數(shù)SKIPIF1<0的最小值.4．求下列函數(shù)的值域：（1）SKIPIF1<0；（2）SKIPIF1<05．已知函數(shù)SKIPIF1<0的值域為SKIPIF1<0，求SKIPIF1<0的值.6．求下列函數(shù)的值域：（1）SKIPIF1<0；（2）SKIPIF1<0；（3）SKIPIF1<0；（4）SKIPIF1<0；（5）SKIPIF1<0；（6）SKIPIF1<0.專項突破三分離常數(shù)法1．函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0SKIPIF1<0SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0SKIPIF1<0SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0，x∈[3，+∞）的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．函數(shù)ySKIPIF1<0的值域是（）A．（﹣∞，+∞） B．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞）C．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞） D．（﹣∞，SKIPIF1<0）∪（SKIPIF1<0，+∞）4．函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0的最大值是______．5．函數(shù)SKIPIF1<0在SKIPIF1<0上的值域為___________.6．函數(shù)SKIPIF1<0的值域為_______．7．函數(shù)SKIPIF1<0的值域是______．8．函數(shù)SKIPIF1<0的值域是________________.9．已知函數(shù)SKIPIF1<0為奇函數(shù)(1)求實數(shù)SKIPIF1<0的值及函數(shù)SKIPIF1<0的值域；(2)若不等式SKIPIF1<0對任意SKIPIF1<0都成立，求實數(shù)SKIPIF1<0的取值范圍.專項突破四二次函數(shù)分類討論1．已知函數(shù)SKIPIF1<0.(1)若SKIPIF1<0，求函數(shù)SKIPIF1<0的最小值和最大值；(2)當(dāng)SKIPIF1<0時，求函數(shù)SKIPIF1<0的最小值．2．已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)當(dāng)SKIPIF1<0時，求函數(shù)SKIPIF1<0的最大值和最小值．(2)當(dāng)SKIPIF1<0時，求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值．3．已知SKIPIF1<0是定義在R上的偶函數(shù)SKIPIF1<0，當(dāng)SKIPIF1<0時，SKIPIF1<0．(1)求SKIPIF1<0的解析式；(2)求SKIPIF1<0在區(qū)間SKIPIF1<0上的值域．4．二次函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上有最大值4，最小值0.(1)求函數(shù)SKIPIF1<0的解析式；(2)設(shè)SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0的最小值為SKIPIF1<0，求SKIPIF1<0的值.5．已知一次函數(shù)SKIPIF1<0滿足SKIPIF1<0.(1)求函數(shù)f（x）的解析式；(2)設(shè)函數(shù)SKIPIF1<0SKIPIF1<0，求SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值．6．已知函數(shù)SKIPIF1<0(1)若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，求a的取值范圍：(2)是否存在實數(shù)a，使得函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為SKIPIF1<0?若存在，求出a的值；若不存在，請說明理由.7．已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)當(dāng)SKIPIF1<0，且SKIPIF1<0時，求函數(shù)SKIPIF1<0的值域；(2)若函數(shù)SKIPIF1<0在SKIPIF1<0的最小值為SKIPIF1<0，求實數(shù)SKIPIF1<0的值；8．已知函數(shù)SKIPIF1<0．(1)當(dāng)SKIPIF1<0時，判斷并證明函數(shù)SKIPIF1<0的奇偶性；(2)求函數(shù)SKIPIF1<0在SKIPIF1<0上的最小值．專項突破五基本不等式法1．下列函數(shù)中最小值為8的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．已知圓SKIPIF1<0關(guān)于直線SKIPIF1<0為大于0的常數(shù)SKIPIF1<0對稱，則SKIPIF1<0的最大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．23．已知SKIPIF1<0，則SKIPIF1<0的最小值是（

）A．14 B．SKIPIF1<0 C．8 D．SKIPIF1<04．若SKIPIF1<0在SKIPIF1<0上恒成立，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．下列函數(shù)中，最小值為9的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．已知正實數(shù)a，b滿足SKIPIF1<0，則SKIPIF1<0的最大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．27．已知函數(shù)SKIPIF1<0則函數(shù)SKIPIF1<0的值域為（

）A．R B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．函數(shù)SKIPIF1<0的值域是______．9．已知x>1，那么SKIPIF1<0的最小值為________.10．函數(shù)SKIPIF1<0在SKIPIF1<0上的值域為________．11．函數(shù)SKIPIF1<0的值域是____________．12．已知SKIPIF1<0，則SKIPIF1<0的最小值為___________.13．已知SKIPIF1<0、SKIPIF1<0均為正實數(shù)，且SKIPIF1<0，則SKIPIF1<0的最小值為___________.14．若正實數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的最大值為________.15．已知關(guān)于SKIPIF1<0的一元二次不等式SKIPIF1<0在實數(shù)集上恒成立，且SKIPIF1<0，則SKIPIF1<0的最小值為________16．若SKIPIF1<0，則函數(shù)SKIPIF1<0的值域為__________.17．若函數(shù)SKIPIF1<0的值域為SKIPIF1<0，則實數(shù)SKIPIF1<0的取值范圍是____.專項突破六指、對數(shù)復(fù)合型1．函數(shù)SKIPIF1<0的值域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．函數(shù)SKIPIF1<0的最小值是（

）．A．10 B．1 C．11 D．SKIPIF1<03．函數(shù)SKIPIF1<0，SKIPIF1<0的值域是(

)A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0的圖象過定點SKIPIF1<0，則SKIPIF1<0在SKIPIF1<0上的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．函數(shù)SKIPIF1<0的值域為______．6．若函數(shù)f(x)＝SKIPIF1<0有最大值3，則a＝________.7．函數(shù)SKIPIF1<0的值域是________．8．求下列函數(shù)的值域:(1)SKI