新高考數(shù)學(xué)一輪復(fù)習(xí)講與練第12講 三角函數(shù)恒等變換（練）（原卷版）

第02講三角恒等變換一、單選題1．若SKIPIF1<0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．2 C．SKIPIF1<0 D．SKIPIF1<02．若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．設(shè)SKIPIF1<0，則SKIPIF1<0=（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0．設(shè)SKIPIF1<0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．已知函數(shù)SKIPIF1<0在SKIPIF1<0處取得最大值，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知角SKIPIF1<0的頂點在坐標(biāo)原點，始邊與SKIPIF1<0軸的非負(fù)半軸重合，終邊經(jīng)過點SKIPIF1<0，其中SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0（

）A．2 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．公元前六世紀(jì)，古希臘的畢達(dá)哥拉斯學(xué)派在研究正五邊形和正十邊形的作圖時，發(fā)現(xiàn)了黃金分割約為0.618，這一數(shù)值也可以表示為SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0的值為（

）A．1 B．2 C．-1 D．-2二、填空題9．已知SKIPIF1<0，則SKIPIF1<0___________.10．SKIPIF1<0_____.11．已知SKIPIF1<0，且SKIPIF1<0是第一象限角，則SKIPIF1<0_____________．三、解答題12．已知函數(shù)SKIPIF1<0.(1)若函數(shù)SKIPIF1<0的圖象過點SKIPIF1<0，且SKIPIF1<0，求SKIPIF1<0的值；(2)若SKIPIF1<0，且SKIPIF1<0，求SKIPIF1<0的值.13．已知平面向量SKIPIF1<0，SKIPIF1<0，函數(shù)SKIPIF1<0.(1)求函數(shù)SKIPIF1<0的解析式；(2)求函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的值域.一、單選題1．已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．若SKIPIF1<0，且SKIPIF1<0，則下列結(jié)論正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．函數(shù)SKIPIF1<0的最小正周期是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．已知角SKIPIF1<0的終邊在直線SKIPIF1<0上，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．1 D．SKIPIF1<06．若SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、填空題7．化簡：SKIPIF1<0值是________．8．若函數(shù)SKIPIF1<0的圖像關(guān)于直線SKIPIF1<0對稱，則SKIPIF1<0___________.9．已知SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的最大值為________.三、解答題10．如圖，某圓形小區(qū)有兩塊空余綠化扇形草地SKIPIF1<0（圓心角為SKIPIF1<0）和SKIPIF1<0（圓心角為SKIPIF1<0），SKIPIF1<0為圓的直徑.現(xiàn)分別要設(shè)計出兩塊社區(qū)活動區(qū)域，其中一塊為矩形區(qū)域SKIPIF1<0，一塊為平行四邊形區(qū)域SKIPIF1<0，已知圓的直徑SKIPIF1<0百米，且點SKIPIF1<0在劣弧SKIPIF1<0上（不含端點），點SKIPIF1<0在SKIPIF1<0上?點SKIPIF1<0在SKIPIF1<0上?點SKIPIF1<0和SKIPIF1<0在SKIPIF1<0上?點SKIPIF1<0在SKIPIF1<0上，記SKIPIF1<0.(1)經(jīng)設(shè)計，當(dāng)SKIPIF1<0達(dá)到最大值時，取得最佳觀賞效果，求SKIPIF1<0取何值時，SKIPIF1<0最大，最大值是多少？(2)設(shè)矩形SKIPIF1<0和平行四邊形SKIPIF1<0面積和為SKIPIF1<0，求SKIPIF1<0的最大值及此時SKIPIF1<0的值.一、單選題1．（2022·全國·高考真題）若SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·北京·高考真題）已知函數(shù)SKIPIF1<0，則（

）A．SKIPIF1<0在SKIPIF1<0上單調(diào)遞減 B．SKIPIF1<0在SKIPIF1<0上單調(diào)遞增C．SKIPIF1<0在SKIPIF1<0上單調(diào)遞減 D．SKIPIF1<0在SKIPIF1<0上單調(diào)遞增3．（2022·天津）已知SKIPIF1<0，關(guān)于該函數(shù)有下列四個說法：①SKIPIF1<0的最小正周期為SKIPIF1<0；②SKIPIF1<0在SKIPIF1<0上單調(diào)遞增；③當(dāng)SKIPIF1<0時，SKIPIF1<0的取值范圍為SKIPIF1<0；④SKIPIF1<0的圖象可由SKIPIF1<0的圖象向左平移SKIPIF1<0個單位長度得到．以上四個說法中，正確的個數(shù)為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·浙江）為了得到函數(shù)SKIPIF1<0的圖象，只要把函數(shù)SKIPIF1<0圖象上所有的點（

）A．向左平移SKIPIF1<0個單位長度 B．向右平移SKIPIF1<0個單位長度C．向左平移SKIPIF1<0個單位長度 D．向右平移SKIPIF1<0個單位長度5．（2021·全國（文））函數(shù)SKIPIF1<0的最小正周期和最大值分別是（

）A．SKIPIF1<0和SKIPIF1<0 B．SKIPIF1<0和2 C．SKIPIF1<0和SKIPIF1<0 D．SKIPIF1<0和26．（2021·全國（文））若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2021·全國）若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．S