華為校園招聘筆試題合集

1Cstatic4for(；1while(1)相同。5、do……whilewhile……do6＃include<stdio.h>inta,b,c,d;return0;答1inta[2][2]={{1},{2,3}};a[0][1]0。（2、int(*ptr)(),則ptr是一維數(shù)組的名字。 3、指針在任何情況下都可進(jìn)行>,<,>=,<=,==運(yùn)算。 4switch(c)cint,long,char,float,unsignedint 5、#defineprint(x)printf(＂theno,＂#x＂,ischarstr[]=charint voidfunc(char 2、voidsetmemory(char**p,int{*p=(char*)void{char 3intint 101intstrcmp(char*source,char*dest)0，不等返回-1；2、寫一函數(shù)intfun(char*p)1，不是返0，出錯(cuò)返回-1ntint8，87，88，9OSI的七層網(wǎng)絡(luò)結(jié)構(gòu)圖和TCP/IP請你詳細(xì)地解釋一下IP協(xié)議的定義，在哪個(gè)層上面？主要有什么作用？TCPUDP請問C++的類和C里面的struct7．8086Voidcharstring[10]; char*str1="0123456789";strcpy(string,str1);Voidcharstring[10],for(I=0 Istr1[i] Voidtest3(char*charstring[10];strcpy(string,#defineMAX_SRMDSNstaticintSRM_no;intI;SRM_no%=return(NULL_SRM);returnintsum(int

autointc=0;staticintb=3;voidintI;inta=2;printf("%d,",intfunc(intintb;case1:case2:case3:default:returninta[0]=0;a[1]=1;int*p,*q;則a[q- 定義int**a[3][4],則變量占有的內(nèi)存空間為 200412312359592005年1月1日0時(shí)0分0age,age#include"stdio.h"#includestructcharname[20];charsex;intno;intstructstu*structstu*creatlist(intintstructstu*h,*p,*s;h=(structstu*)malloc(sizeof(structstu));h->next=NULL;s=(structstu*)malloc(sizeof(structstu));p->next=s;printf("Pleaseinputtheinformationofthestudent:namesexnoage\n");scanf("%s%c%d%d",s->name,&s->sex,&s->no,&s->age);s->next=NULL;p=printf("Createsuccessful!");voiddeletelist(structstu*s,intstructstu*p;p=s=s-printf("Therecordisnotexist.");p->next=s->next;printf("Deletesuccessful!");voiddisplay(structstus=s->next;printf("%s%c%d%d\n",s->name,s->sex,s->no,s->age);s=s->next;intstructstu*s;intn,age;printf("Pleaseinputthelengthofseqlist:\n");s=creatlist(n);printf("Pleaseinputtheage:\n");return#include"stdio.h"#includevoiduppers(char*s,char*us=*s-*us=*us=intchar*s,*us;charprintf("Pleaseinputastring:\n");s=ss;printf("Theresultis:\n%s\n",us);1Cstatic4for(；1while(1)相同。5、do……whilewhile……do6＃include<stdio.h>intreturn0;答static？（請至少說明兩種在模塊內(nèi)（但在函數(shù)體外），1constructorO(n^2)。floatxifTcp/IpInternetIPARP(AddressResolutionProtocol)（地址解析協(xié)議IPM,N1至NMCswitchABCDa(3inta=(A)a+=(a++);(B)a+=(++a);(C)(a++)+=a;(D)(++a)+=a=答：C(++a)a;9,10,10,1132C++sizeof(5charstr[]=“/”char*p=str;intn=10;sizeof(str)=？（1）sizeof(p)=？（2）sizeof(n)=？（3）voidFoocharstr[100]){sizeof(str)=void*pmalloc(100sizeof(p)=答：（1）17（2）4（3）4（4）4回答下面的問題.(4ifndef/define/endif＃include和＃include“filename.h”C++Cextern“C”C++CexternCC函數(shù)。C++Cextern“C”回答下面的問題(6(1).VoidGetMemory(char**p,int*p=(charvoidTest(void){char*str=GetMemory(&str,100);strcpy(str,"hello");Testvoidchar*str=(char*)malloc(100);strcpy(str,“hello”);if(str!=NULL){strcpy(str,“world”);Testchar*GetMemory(void){charp[]="helloworld";returnp;voidTest(void){char*str=NULL;str=GetMemory();Teststrcat(6已知strcatchar*strcat(char*strDest,constchar*strSrstrDest是目的字符串，strSrcC++/CstrcatVCchar*cdeclstrcat(char*dst,constchar*char*cp=dst;while(*cp)cp++;/*findendofdstwhile(*cp++=*src++);/*Copysrctoendofdst*/return(dst);/*returndst*/strcatstrSrcstrDestchar*MFCCStringC++答：(1)CSingleLockNEWTEXTMETRICC/SCPUCPULinuxDOSI/OWindowsNTOS/2LinuxC++中什么數(shù)據(jù)分配在?；蚨阎?，New堆:程序運(yùn)行時(shí)動(dòng)態(tài)申請，new malloc申請的內(nèi)存就在堆SQLServersizof()inti=10,j=10,k=3;k*=i+j;k答：60，此題考察優(yōu)先級，實(shí)際寫成：k*=(i+j);，TCP/IP建立連接的過程?(3-wayN_SENDSYN（syn=k），SYN+ACKSYN_RECVESTABLISHEDICMP答：Internet（IPDELETESQLSQLwinsockrecv（et()DLLDLLDLL運(yùn)行時(shí)動(dòng)態(tài)鏈接（run-timedynamiclinking），LoadLibraryLoaDLLIPVoidcharchar*strcpy(string,Voidcharstring[10],str1[10];for(I=0;I<10;I++)str1[i]strcpy(string,Voidtest3(char*charstring[10];strcpy(string,#defineMAX_SRMDSNstaticintSRM_no;intI;SRM_no%=return(NULL_SRM);return