




已閱讀5頁,還剩17頁未讀, 繼續(xù)免費(fèi)閱讀
版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡介
Functional safety Engineering - Layers of Protection,Layers of Protection Analysis,Fault Propagation Context Event Tree Method Layers of Protection Definition LOPA Event Tree Initiating Evnents and Failure Rates Example of Layers of Protection,Fault Propagation modelling,Analyze the Chain of events that leads to an accident,Control System Fails,Operator does not respond properly,Mechanical relief failed,Overpressure Event,Initiating event,Layers of Protection Analysis - LOPA,A variant of Event Tree Analysis More structures Like event tree analysis, the initiating event start the chain of events Branches are layers of protection Consider only two outcome Accident No Event,LOPA Version of Event Tree,PL2, fails,PL1, fails,PL3, fails,Accident,Quantify using multiplications; all logical ANDs,Ex, Column Rupture LOPA,Draw the LOPA diagram for following situations Consequence of the accident = fire due to distillation column rupture has a root cause of loss of cooling water Layers of protection Operator respond to alarms and stops the process Process generally designed to withstand loss of cooling water The column has a pressure relief valve Source of ignition are controlled in the process area,Ex: Column rupture LOPA,LOPA Calculations,Proceed as with event tree, but only need to calculate the frequency of accident Resulting accident frequency is initiating event frequency multiplied by PFD of all protection layers Example Cooling water failure frequency is 0,5/year Protection layers Operator response failure PFD = 0,15 Relief valve failure PFD = 0,07 Process design inadequate PFD = 0,01 Ignition source contacted PFD = 0,3,Ex: Column Rupture, LOPA,F=0,5/y * 0,15 * 0,01* 0,07 * 0,3 = 1,58E-5 per year,Failure Rate Quantification,Historical reliability data specific to your installation is best, but often difficult to get Plant maintenance and SIS function test data by equipment type Industry average data grouped by equipment type Some expert judgment is still inevitable,Using Maintenance and Function Test Data,Companies usually keep maintenance logs IEC 61511 requires function testing and documentation of results Function test data used to approximate failure rate: Simple Equation for point estimate of failure rate: = # Failures / Total Unit of Operation = Failure rate,PFD from Failure Rate,PFD depends on failure rate, failure mode and test interval Failure rate is divided into failures that can cause a false trip versus those that failure on demand Most databases list the failure mode for an equipment item An untested devices PFD gets larger as the operational time interval increases For devices subject to periodic inspection and test the average PDF can be used,PDFavg ( t)/2,Typical Protection Layers,BPCS The BPCS and SIS are physically separated devices, including sensors, logic solvers and final elements Failure of the BPCS is not responsible for initiating the unwanted accident BPCS has the proper sensor and actuators available to perform a function similar to the one performed by the SIS,PDF 0,1 (By definition),Typical Protection Layers,Operator Response Operator always Present Operator has indication of Problem Operator has time to Act Operator is Trained in the Proper Response,PDF 0,1, if all condition is met PDF = 1,0, if condition not met,Typical Protection Layers,Use factor (Time at Risk) Hazard is not always present Ex Batch production,Typical Protection Layers,Mechanical Integrity of Vessel Is vessel designed to withstand the pressure and temperature generated as a result of the initiating event? Mechanical Relied Devices Relief Valves Rupture Disk Fusible Plugs PFD calculated based on failure rate statistics found in database,Typical Protection Layers,External Risk Reduction Water Spray Curtains Dual Walled piping Enclosures with Scrubing Only consider LOPA if protection system will COMPLETELY ELIMINATE the CONSEQUENCE,Typical Protection Layers,Ignition Probability Most plants are designed to limit sources of Ignition Function of release size and released material P 0,3 for flammable gases P 0,1 - 0,3 for volatile gases P 0,1 for heavy liquid,Typical Protection Layers,Explosion Probability Probability that explosion will occur given ignition has already occurred Not typically used because flash fire will occur if explosion does not, so consequences not prevented Use with CAUTION ! In most cases explosion probability should be ignored,Typical Protection Layers,Occupancy Fraction of time that effect zone of incident outcome in question is occupied Not typically used because oc
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲空間,僅對用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對自己和他人造成任何形式的傷害或損失。
最新文檔
- 安全護(hù)理試題及答案
- 地?zé)崮芄┡诒狈睫r(nóng)村地區(qū)的應(yīng)用現(xiàn)狀與2025年發(fā)展前景報(bào)告001
- 民間艾灸達(dá)人培訓(xùn)課件
- 乙型腦炎的培訓(xùn)課件
- 員工職業(yè)道德提升課件
- 中國利率市場化課件
- 制取氧氣說課課件
- 江蘇省蘇州市吳中學(xué)、吳江、相城區(qū)2025屆英語七年級第二學(xué)期期末檢測試題含答案
- 年度員工活動計(jì)劃方案
- 山東省德州市德城區(qū)2025年八下英語期末經(jīng)典試題含答案
- 有限空間作業(yè)通風(fēng)時(shí)間專題
- 廣東省廣州市天河外國語學(xué)校2025年七年級英語第二學(xué)期期末綜合測試模擬試題含答案
- 2025年中國氯化聚醚項(xiàng)目投資計(jì)劃書
- 2025年公務(wù)員綜合素質(zhì)能力考試卷及答案
- TSZGFA-信息通信基礎(chǔ)設(shè)施工程規(guī)劃設(shè)計(jì)規(guī)范
- 成都市高新區(qū)2023年七年級《歷史》下冊期末試卷與參考答案
- 化工智能控制技術(shù)-形考任務(wù)4(預(yù)備知識:第十~十三章;分值100分;不需輔導(dǎo)老師評閱)測驗(yàn)-國開-參考資料
- 螞蟻花唄對大學(xué)生消費(fèi)行為的實(shí)證分析
- 儲能專業(yè)知識考試試題及答案
- 中國上市銀行2024年回顧及未來展望-安永-202505
- 抗腫瘤藥卡鉑的介紹與研究
評論
0/150
提交評論