活期儲蓄賬目管理

1、題目：活期儲蓄帳目管理活期儲蓄處理中，儲戶開戶、銷戶、存入、支出活動頻繁，系統(tǒng)設(shè)計要求：能比較迅速地找到儲戶的帳戶，以實現(xiàn)存款、取款記賬；并能實現(xiàn)排序能比較簡單，迅速地實現(xiàn)插入和刪除，以實現(xiàn)開戶和銷戶的需要。#include#include #include#includeusing namespace std;class consumer;class yhpublic:yh();void set_account();/銀行開戶void del_account();void transfer(int); /轉(zhuǎn)賬void enter_account();void addmoney(int,flo

2、at);void exityh();/ 退出系統(tǒng)void functionshow();/ 功能界面void save();void load();protected: consumer *account20;/賬戶數(shù) static int acnum;int yh:acnum=0;yh:yh()for(int i=0;i20;i+) accounti = null; class consumer:public yhpublic: friend class yh; consumer(int id,string name,string password,float m) id=id;name=n

3、ame;money=m;passwd=password; consumer()id=0;name=0;money=0;passwd=0; int get_id()return id; void savemoney();/ 取錢 string get_passwd() / 取得密碼 return passwd; void display(); void fetchmoney(); /取錢 void change_passwd(); void add_money(float); void dec_money(float); float get_money(); private: int id; /

4、開戶帳號 string passwd; / 用戶密碼 string name; / 用戶姓名 float money;void yh:save()ofstream ofile(bankdat.dat,ios:out);ofstream outfile(bankdat.dat,ios:out);int n=0;outfileacnum ;for(;nacnum;n+)outfileid ;outfilemoney ;outfilename ;outfilepasswd ;outfile.close(); void yh:load()ifstream infile(bankdat.dat,ios:

5、in);if(!infile)cerr讀取錯誤,無資料!acnum;for(;nid;infilem;infilenam;infilepassw;accountn-passwd;consumer * acc = new consumer(id,nam,passw,m); accountn = acc; infile.close();cout讀取資料正常!endl;void yh:transfer(int x)int id; coutid; int flag = 1; int i = 0; while(iget_id() flag = 0; else i+; if(flag) cout帳號不存在

6、!endlendl; return ; float b;coutendlb; while(b=0)cout請輸入正確的數(shù)字!endl;coutb; if(accountx-get_money()b) cout對不起,金額不夠!dec_money(b);accounti-add_money(b);return;void consumer:add_money(float x)money=x+money;void consumer:dec_money(float x)money=money-x;void yh:addmoney(int x,float y)accountx-money=account

7、x-money-y;float consumer:get_money()return money;void yh:functionshow()int n;int z=1;dosystem(cls); couttt*銀行管理系統(tǒng)*endl;/couttt 1.用戶開戶 endl;couttt 2.賬戶登陸 endl;couttt 3.帳戶注銷 endl;couttt 0.退出系統(tǒng) endl;couttt*endl;load();coutendln;if(n3) couttt請輸入正確的操作序號!endl; cout; cinn;switch(n)case 1: set_account() ;br

8、eak;case 2:enter_account() ;break;case 3: del_account() ;break; case 0: exityh();z=0 ;break;cin.get();while(z);void yh:enter_account()int id; coutid; int flag = 1; int i = 0; /while(iget_id() flag = 0; else i+; if(flag) couttt帳號不存在!endlendl; cin.get();return; coutpassw;if(passw!=accounti-get_passwd(

9、) return;accounti-display();cin.get();cin.get();int n;dosystem(cls);couttt請選擇你要進(jìn)行的操作:endltt1)查看信息endltt2)取款endltt3)存款endltt4)修改密碼endltt5)轉(zhuǎn)賬endltt6)返回n;switch(n)case 1: accounti-display();break;case 2: accounti-fetchmoney();save();break;case 3:accounti-savemoney();save();break;case 4:accounti-change_

10、passwd();save();break;case 5:transfer(i);save();break;case 6:return;cin.get();cin.get();while(1);void yh:set_account() int id; string nam; string passw; float m;coutendlid; coutendlnam; coutendlpassw; coutendlm; while(m=0)couttt請輸入正確的數(shù)字!m;consumer * acc = new consumer(id,nam,passw,m); accountacnum =

11、 acc; couttt開戶成功!endlendl; acnum+;save();cin.get();return;void yh:del_account() int id; coutendlid;int flag = 1; int i = 0; while(iget_id()flag = 0;elsei+; if(flag) couttt帳號不存在!endlendl; return; coutpassw;if(passw!=accounti-get_passwd() return;for(int j=i;jacnum;j+) accountj = accountj+1; accountacn

12、um-1=null; acnum-; couttt注銷成功!endlendl; save();cin.get();return; void consumer:change_passwd()string pwd,repwd;coutpwd;coutrepwd;if(pwd!=repwd)couttt你輸入的兩次密碼不一樣,請重新輸入!endl;passwd=pwd;couttt密碼修改成功，請牢記!endl;cin.get(); void consumer:fetchmoney()float m;char ch;docoutendltt你要取多少錢:$m;while(m=0)couttt請輸入正

13、確的數(shù)字!endl;coutm;if(moneym)couttt對不起，你的余額不足!endl;elsemoney=money-m;coutendltt操作成功，請收好錢!endl;couttt是否要繼續(xù)該項操作：(y/n) endl;cout;cinch;while(ch!=n&ch!=n&ch!=y&ch!=y)cout;cinch;while(ch=y|ch=y);void consumer:savemoney() float c; char ch;docoutendltt你要存多少錢:$c;while(c=0)couttt請輸入正確的數(shù)字!endl;coutc;money=money+c;couttt操作已成功!endl;couttt是否要繼續(xù)該項操作：(y/n) endl;cout;cinch;while(ch!=n&ch!=n&ch!=y&ch!=y)cout;cinch;while(ch=y|ch=y); void consumer:display()system(cls