華南農(nóng)業(yè)大學2015農(nóng)科Java上機實驗

1、印實驗1創(chuàng)建、編譯和運行Java程序仃268計算兩個整數(shù)的和從鍵盤輸入兩個整數(shù)，計算并輸出兩個整數(shù)的和。importjava.util.Sca nner;public class Mai n public static void main( Stri ng args) in ta,b;Scanner in put = new Scann er(System.i n);a=in put. next In t();b=in put. next In t();int c = a + b;System.out.pri ntl n(c);仃269輸出兩個整數(shù)中的較大的值從鍵盤輸入兩個整數(shù)，判斷并輸出兩個

2、整數(shù)中較大的值。importjava.util.Sca nner;public class Mai n public static void main(String args) in ta,b;Scanner in put = new Scann er(System.i n);a=in put. next In t();b=in put. next In t();if(ab)System.out.pri ntl n( a);elseSystem.out.pri ntl n( b);日匚實驗2基本數(shù)據(jù)類型、運算和表達式18135在顯示屏上顯示指定字符要求編寫一個程序，在顯示屏上顯示如下內(nèi)容。注：

3、類名必須為Main(大寫M)C:ABC.TXT is filepublic class Mai n public static void main(String args) System.out.pri nt(C:ABC.TXT is file);18136計算圓的面積由鍵盤輸入圓的半徑，計算并輸出圓的面積，結(jié)果保留2位小數(shù)。注：類名必須為Main(大寫M)importjava.util.Sca nner;importjava.text.DecimalFormat;public class Mai n public static void main( Stri ng args) doublea

4、,b,c;Scanner in put = new Scann er(System.i n);a = in put. nextDouble();b = 3.14159;c = a*a*b;System.out.pri ntl n(new DecimalFormat(#.#).format(c);18138輸出三位整數(shù)的各位數(shù)字從鍵盤輸入一個3位的整數(shù)，要求按照：個位、十位和百位的順序輸出三個數(shù)字。輸出時，每個數(shù)字占單獨的一行。注：類名必須為Main ( M大寫)i mportjava.util.Scanner;public class Mai n public static void main

5、(String args) Scanner in put = new Scann er(System.i n);in tcr = in put. next In t();int b, c, d;b = cr / 100;c = cr /10 %10;d = cr % 10;System.out.pri ntln(+ d);System.out.pri ntln(+ c);System.out.pri ntln(+ b);I目七1實驗3選擇結(jié)構(gòu)程序設(shè)計18139判斷點是否在圓上由鍵盤輸入一個點的坐標，要求編程判斷這個點是否在單位圓上，點在圓上輸出 Y,不在圓上輸出N。使用小數(shù)點后3位精度進行判斷

6、。注：類名必須用Main(大寫M)importjava.util.Sca nner;public class Mai n public static void main(String args) Scanner in put = new Scann er(System.i n);double x = in put. nextDouble();double y = in put. nextDouble();double dista nee = Math.sqrt(x * x + y * y);if (Math.abs(dista nee - 1.0)99999999)place=9;else i

7、f(a9999999)place=8;else if(a999999)place=7;else if(a99999)place=6;else if(a9999)place=5;else if(a999)place=4;else if(a99)place=3;else if(a9)place=2;elseplace=1;System.out.pri ntln( place);18141 數(shù)的排序iFFF-r-F-FFFF-=. FXF 八扌彳-FFFFF-* -F.-F-=*XFXF* 由鍵盤輸入三個整數(shù)a、b、c,按從小到大的順序輸出這三個數(shù)。注：類名必須是Main(M大寫)importjav

8、a.util.Sca nner;public class Mai n public static void main( Stri ng args) in ta,b,c,temp;Scanner in put = new Scann er(System.i n);a = in put. next In t();b = in put. next In t();c = in put. next In t();if(ab)temp = a;a = b;b = temp;if(ac)temp = a;a = c;c = temp;if(bc)temp = b;b = c; c = temp;System

9、.out.pri ntl n(a + , + b + , + c);18142數(shù)的整除由鍵盤輸入5個整數(shù)，逐個判斷它們能否被 27整除，能的輸出“ YES，不能的輸出“ NO (注意，輸出時，一個判斷結(jié)果占一行，5個數(shù)的判斷共占5行)。注：類名必須是 Main(大寫M)importjava.util.Sca nner;public class Mai n public static void main(String args) in ta,b,c,d,e;Scanner in put = new Scann er(System.i n);a = in put. next In t();b =

10、in put. next In t();c = in put. next In t();d = in put. next In t();e = in put. next In t();if(a % 27 = 0)System.out.pri ntln (YES);else System.out.pri ntl n( NO);if(b % 27 = 0)System.out.pri ntln (YES);elseSystem.out.pri ntl n( NO);if(c % 27 = 0)System.out.pri ntln (YES);elseSystem.out.pri ntl n( N

11、O);if(d % 27 = 0)System.out.pri ntln (YES);elseSystem.out.pri ntl n( NO);if(e % 27 = 0)System.out.pri ntln (YES);elseSystem.out.pri ntl n( NO);18143正負奇偶判斷由鍵盤輸入非零整數(shù)x,判斷該數(shù)正負，正數(shù)輸出positive ，負數(shù)輸出negative，接著判斷該數(shù)的奇偶性，奇數(shù)輸出odd，偶數(shù)輸出even。注：類名必須是 Main(大寫importjava.util.Sca nner;public class Mai n public static

12、void main(String args) int x;Scanner in put = new Scann er(System.i n);x = in put. next In t();if(x0)System.out.pri ntl n(positive);else System.out.pri ntln (” negative);if(x % 2 = 0)System.out.pri ntln (eve n);elseSystem.out.pri ntl n( odd);18144簡單四則運算器FFF-Frr-FFFFFrhFFF rXFEFF-XF彳-FF-FF*-F-.八 FEFF

13、-*rF*FF-* *- 下面程序是實現(xiàn)一個簡單的四則運算器(輸出結(jié)果保留2位小數(shù))。輸入時依次輸入：第1個實數(shù)、運算符、第2個實數(shù)，程序根據(jù)運算符進行運算并輸出結(jié)果。在程序中的空白處填寫恰當?shù)拇a，運行通過后在評判系統(tǒng)中提交。import java.util.Sca nner;public class Mai n public static void main( Stri ng args) float a, b, result;char operator;Scanner in put = new Scann er(System.i n);a = in put. nextFloat();ope

14、rator = in put .n ext().charAt(O);b = in put. nextFloat();switch (operator) case +:result=a + b;break;case -: result=a - b;break;case *: result=a * b;break;case /: result=a / b;break;default:System.out.pri ntln (error);return;System.out.pri ntf(%.2fn, result);衍實驗4循環(huán)結(jié)構(gòu)程序設(shè)計iI18145計算階乘輸入正整數(shù)n，計算n!，結(jié)果用長整

15、型數(shù)表示(注 n!=1*2*3*.*n)注：類名必須是 Main(大寫Mimportjava.util.Sca nner;public class Mai n public static void main(String args) Scanner in put= new Sca nn er(System.i n);intnum = 1;int x;x = in put. next In t();for(i nt i = x;i 0;i-) num = num * i;System.out.pri ntln(nu m);肩吵葉彳18146計算數(shù)列和n項和。有數(shù)列1 , 3 , 5, 7, 9,

16、 11 ,，現(xiàn)要求由鍵盤輸入n，計算輸出該數(shù)列的前注：類名必須是 Main(大寫M )importjava.util.Sca nner;public class Mai n public static void main( Stri ng args) Scanner in put= new Sca nn er(System.i n);int sum = 0;int n;n = in put. next In t();for(i nt i = 1;i n)max = m;min = n;elsemin = m;max = n;in tgcd;for(gcd= min; gcd= 1;gcd-)i

17、f(max % gcd = 0 & min % gcd = 0)break;System.out.pri ntl n( gcd);18148 輸出最小值從鍵盤輸入十個整數(shù)，輸出最小值。注：類名必須是 Main(大寫M)importjava.util.Sca nner;public class Mai n public static void main( Stri ng args) Scanner in put = new Scann er(System.i n);in t a = new in t10;for(i nt i = 0;ia .len gth;i+)ai= in put. next

18、 In t();int min = a0;for(i nt i = 0;ia .len gth;i+)if(aimi n)min=ai;System.out.pri nt(min);18149 求素數(shù)輸出2到200之間(包括2、200)的所有素數(shù)。注：要求1行1個素數(shù)，按由小到大的順序輸出。提示：采用雙重循環(huán)，外層循環(huán)產(chǎn)生2到200之間的數(shù)，內(nèi)層循環(huán)對數(shù)進行判斷是否為素數(shù)。注：類名必須是 Main(大寫M)importjava.util.Sca nner;public class Mai n public static void main(String args) Scanner in put

19、= new Sca nn er(System.i n);int n = 0;for (int i = 2;i 200;i+)in tsquareRoot = (int) Math.sqrt(i);int k;for (k = 2;k squareRoot)n+;System.out.pri ntf(%d, i);System.out.pri ntln (); 18150 打印菱形由鍵盤輸入正數(shù)n,要求輸出2*n+1行的菱形圖案。要求菱形頂部無空行，菱形左邊緊靠屏 幕左側(cè)。注：類名必須是 Main(大寫importjava.util.Sca nner;public class Mai n pub

20、lic static void main( Stri ng args) Scanner in put = new Scann er(System.i n);in ti,j,m,k, n;n = in put. next In t();for(i = 1;i=n+1;i+)for(j = 1;j=n _i+1;j+)System.out.pri nt();for(j = 1;j=2*i-1;j+)System.out.pri nt(*);System.out.pri ntl n();for(m = 1;m =n; m+)for(k = 1;k=m;k+)System.out.pri nt();f

21、or(k = 1;k=2*( n-m)+1;k+)System.out.pri nt(*);System.out.pri ntl n();曰臼實驗5數(shù)組與字符串18152數(shù)組的逆序輸出寫一個程序，首先從鍵盤輸入一個正整數(shù)n表示個數(shù)，然后輸入n個整數(shù)，存放到數(shù)組中,最后把這些整數(shù)逆序輸出。輸出時，兩個整數(shù)之間用一個空格隔開。注：類名必須是Main(大寫Mimportjava.util.Sca nner;public class Mai n public static void main( Stri ng args) Scanner in put = new Scann er(System.i n

22、);int n = in put .n ext In t();in t a;a = new in t n;for(i nt i = 0;i=0;i-)System.out.pri nt(ai+);18153 冒泡排序存放到數(shù)組中。輸出時，兩個整編寫一個程序，首先從鍵盤輸入一個正整數(shù)n表示個數(shù)，然后輸入n個整數(shù),使用冒泡排序算法對該數(shù)組進行從大到小的排序，并輸出排序之后的結(jié)果。數(shù)之間用一個空格隔開。注：類名必須是 Main(大寫importjava.util.Sca nner;public class Mai n public static void main(String args) Scan

23、ner in put = new Scann er(System.i n);in t le ngth = in put. next In t();in tarray = new in tle ngth;for(i nt i = 0;iarra y.len gth;i+) arrayi= in put .n ext In t();for(i nt i = 0;iarra y.len gth-1;i+)for(i nt j = 0;jarra y.len gth-1;j+)if (arrayjarrayj + 1)int temp = arrayj;arrayj = arrayj + 1;arra

24、yj + 1 = temp; for (int v :array)System.out.pri nt(v + ); 18154 字符串中數(shù)字字符個數(shù)統(tǒng)計編寫程序，從鍵盤輸入一行字符串，統(tǒng)計其中數(shù)字字符出現(xiàn)的次數(shù)。 說明：數(shù)字字符是指 0-9這10個字符。輸入的字符串可能包含空格。注：類名必須是 Main(大寫importjava.util.Sca nner;肩吵葉彳public class Mai n public static void main( Stri ng args) Scanner in put = new Scann er(System.i n);Stri ng list = n

25、ew Stri ng3;int sum = 0;for(int i = 0;i3;i+)listi=in put. next();for(int i = 0;i3;i+)for(int k = 0;k=O&ch=9)sum = sum+1;System.out.pri nt(sum);18155輸出矩陣n代表二維整M編寫程序，首先從鍵盤輸入兩個正整數(shù)m和n。m表示二維整型數(shù)組的行數(shù)，型數(shù)組的列數(shù)。然后輸入整個二維數(shù)組，并輸出它的轉(zhuǎn)置數(shù)組。注：類名必須是Main(大寫importjava.util.Sca nner;public class Mai n public static void ma

26、in(String args) Scanner in put = new Scann er(System.i n);in tm, n;m = in put. next In t();n = in put. next In t();in tlist;list = new in tm n;for(int i = 0;ilist.length;i+)for(int k = 0;klisti.length;k+)listik = in put. nextI nt();for(int k = 0;kn;k+)for(int i = 0;ilist.length;i+)System.out.pri nt(

27、listik+);System.out.pri ntl n();18156二維數(shù)組的最大值編寫程序，首先從鍵盤輸入兩個正整數(shù)m和n。m表示二維整型數(shù)組的行數(shù)，n代表二維整型數(shù)組的列數(shù)。然后輸入整個二維數(shù)組，然后找出數(shù)組中的最大值，輸出該值及其行下標和列下標。提示：如果最大值有多個，則輸出第1個。importjava.util.Sca nner;public class Mai n public static void main( Stri ng args) Scanner in put = new Scann er(System.i n);in tm, n;m = in put. next I

28、n t(); n = in put. next In t();in tarray = new in tm n;int max = arrayOO;int x = 0,y=0;for (in t i = 0;iarra y.len gth;i+) for (int j = 0; j max) max = arrayij;x = i;y = j; System.out.pri ntl n( array + + x + + + y+ + = +max);18157投票程序現(xiàn)在有三個候選人競選班長，他們的姓名分別是Alan 、“ Mike”和Tom。編寫一個程序。首先輸入一個整數(shù)n代表總票數(shù)，然后輸出

29、 n個姓名，每行輸入一個姓名。程序根據(jù)輸入的姓名為候選人統(tǒng)計得票數(shù)，如果有非候選人姓名的選票，則計為廢票。輸出投票結(jié)果，每行一個候選人。importjava.util.Sca nner;public class Mai n public static void main(String args) Scanner in put = new Scann er(System.i n);int n = in put .n ext In t();int a = 0,b = 0,c = 0,d = 0;Stri ng name1 = Ala n;Stri ng name2 = Mike;String n

30、ame3 = Tom;Strin g list = new Stringn;for(i nt i = 0;ilist.le ngth;i+)listi=in put. next();for(int i = 0;ilist.length;i+)if(lis ti.equals( namel)a = a+1;else if(listi.equals( name2)b = b+1;else if(listi.equals( name3)c = c+1;elsed = d+1;System.out.pri ntl n( Ala n:+a);System.out.pri ntln (Mike:+b);S

31、ystem.out.pri ntln (Tom:+c);System.out.pri ntl n(i nvalid:+d);18158不相同的整數(shù)問題編寫程序，輸入若干個整數(shù)，統(tǒng)計其中互不相同的整數(shù)的個數(shù)。要求如下：首先輸入一個整數(shù) n代表要輸入的整數(shù)個數(shù)；然后輸入n個整數(shù)，統(tǒng)計并輸出這n個整數(shù)中互不相同的整數(shù)的個數(shù)。注：類名必須是 Main(大寫importjava.util.Sca nner;public class Mai n public static void main( Stri ng args) Scanner in put = new Scann er(System.i n);int n = in put .n extI nt();int sum = 0;in t list = new in t n;for(i nt i = 0;ilist.le ngth;i+)listi=in put. next In t();for(int i = 0;ilist.length;i+)int j;for(j = O;j=1;gcd-)if (a % gcd= 0 & b % gcd = 0) break;returngcd; public static void main(String args) Scanne