C0擴充文法編譯器測試報告

1、c0擴充文法編譯器測試報告學號：_37230118_姓名：_羅楊_2010年 1月 16日1測試樣例一（正確）測試樣例int fib(int k)if (k=0)return (1);if (k=1)return (1);return (fib(k-1)+fib(k-2);void main()int n,result;printf(please enter n: );scanf(n);printf(fib(n) is: );result=fib(n);printf(result);return ;程序輸出輸入一個數(shù)字，輸出其斐波那契數(shù)目標代碼.386.model flat,stdcallop

2、tion casemap:noneincludec:radasmmasm32includewindows.incincludec:radasmmasm32includekernel32.incincludec:radasmmasm32includemsvcrt.incincludelib c:radasmmasm32libmsvcrt.libincludelib c:radasmmasm32libkernel32.libincludec:radasmmasm32includemacros.asm.datapiequ40490fcfh.codefibprocpushebpmovebp,espsu

3、besp,100hmoveax,dword ptr ebp+08hcmpeax,0jnelabel0_1movdword ptr ebp-04h,1jmplabel0_2label0_1:movdword ptr ebp-04h,0label0_2:cmpdword ptr ebp-04h,0jzl1moveax,1addesp,100hpopebpret04hl1:moveax,dword ptr ebp+08hcmpeax,1jnelabel1_1movdword ptr ebp-08h,1jmplabel1_2label1_1:movdword ptr ebp-08h,0label1_2

4、:cmpdword ptr ebp-08h,0jzl2moveax,1addesp,100hpopebpret04hl2:moveax,dword ptr ebp+08hsubeax,1movebx,eaxmoveax,ebxpusheaxcallfibmovdword ptr ebp-010h,eaxmoveax,dword ptr ebp+08hsubeax,2movebx,eaxmoveax,ebxpusheaxcallfibmovdword ptr ebp-018h,eaxmoveax,dword ptr ebp-010haddeax,dword ptr ebp-018hmovebx,

5、eaxmoveax,ebxaddesp,100hpopebpret04hfibendpstart:pushebpmovebp,espsubesp,100hinvokecrt_printf,sadd(please enter n: )invokecrt_scanf,sadd(%d),addr dword ptr ebp-04hinvokecrt_printf,sadd(fib(n) is: )moveax,dword ptr ebp-04hpusheaxcallfibmovdword ptr ebp-0ch,eaxmoveax,dword ptr ebp-0chmovdword ptr ebp-

6、08h,eaxinvokecrt_printf,sadd(%d),dword ptr ebp-08haddesp,100hpopebpinvokeexitprocess,nulladdesp,100hpopebpinvokeexitprocess,nullendstart執(zhí)行結果正確2測試樣例二（正確）測試樣例void main()int i,n,sum,sum2,temp;printf(please enter the total count:);scanf(n);sum=0;sum2=0;for ( i=0; i= a * 5)c = c + 2;a = a * 2;d = d - 4;e

7、lsed = d + 5;printf(c);程序輸出屏幕輸出67108918，此為溢出值目標代碼.386.model flat,stdcalloption casemap:noneincludec:radasmmasm32includewindows.incincludec:radasmmasm32includekernel32.incincludec:radasmmasm32includemsvcrt.incincludelibc:radasmmasm32libmsvcrt.libincludelibc:radasmmasm32libkernel32.libincludec:radasmm

8、asm32includemacros.asm.data_adword?_bdword?_cdword?_ddword?.codestart:pushebpmovebp,espsubesp,100hmoveax,20mov_b,eaxmoveax,4mov_a,eaxmoveax,1mov_d,eaxmoveax,0mov_c,eaxl0:moveax,_dcmpeax,0jelabel0_1movdword ptr ebp-04h,1jmplabel0_2label0_1:movdword ptr ebp-04h,0label0_2:cmpdword ptr ebp-04h,0jzl1move

9、ax,10movecx,_dimulecxmovedi,eaxmoveax,ediaddeax,1movesi,eaxmoveax,_amovecx,5imulecxmovebx,eaxmoveax,esicmpeax,ebxjllabel1_1movdword ptr ebp-014h,1jmplabel1_2label1_1:movdword ptr ebp-014h,0label1_2:cmpdword ptr ebp-014h,0jzl5moveax,_caddeax,2movedi,eaxmoveax,edimov_c,eaxmoveax,_amovecx,2imulecxmoves

10、i,eaxmoveax,esimov_a,eaxmoveax,_dsubeax,4movebx,eaxmoveax,ebxmov_d,eaxjmpl8l5:moveax,_daddeax,5movebx,eaxmoveax,ebxmov_d,eaxl8:jmpl0l1:invokecrt_printf,sadd(%d),_caddesp,100hpopebpinvokeexitprocess,nullendstart執(zhí)行結果正確6測試樣例六（錯誤）測試樣例const int a = 1;float b;int c;void main()b = 123.456;c = b / 1.5 + 1;p

11、rintf c;程序輸出出錯，printf缺少括號執(zhí)行結果錯誤7測試樣例七（錯誤）測試樣例void main() int a; scanf(a); a = a+1; printf(a=, a); return程序輸出出錯，return缺少分號執(zhí)行結果錯誤8測試樣例八（錯誤）測試樣例int g(int aa)int a;if(aa=1)a=1;else a=aa*g(aa-1);void main()int i;scanf(i);a=g(i);printf(a);程序輸出出錯，標識符a未定義執(zhí)行結果錯誤9測試樣例九（錯誤）測試樣例void main()int fahr,celsius,lower,step;lower=0;celsius=0;step=20;fahr=lower;printf(/while statementn);while(fahr=upper)celsius=2*(fahr-32);printf(celsius);printf(n);fahr=fahr+step;printf(/while statementn);程序輸出標識符upper未