C語言結構體共用體選擇題(新)

1、1、變量a所占的內(nèi)存字節(jié)數(shù)是_。struct stu char name20;long int n;int score4; a ;A 28 B 30C 32 D 36C2、下列程序的輸出結果是A5 B6 C7 D8 struct abcint a,b,c;main(struct abc s2=1,2,3,4,5,6;int t;t=s0.a+s1.b;printf("%dn",t;B3、有如下定義struct person char name9; int age;struct person calss4= "Johu",17,"Paul&quo

2、t;,19,"Mary",18,"Adam",16,;根據(jù)以上定義,能輸出字母M的語句是_。A printf("%cn",;B printf("%cn",1;C printf("%cn",1;D printf("%cn",0;D4、以下程序的輸出是_。struct stint x;int *y; *p;int dt4=10,20,30,40;struct st aa4=50,&dt

3、0,60,&dt0,60,&dt0,60,dt0,; main( p=aa;printf("%dn",+(p->x;A 10 B 11C 51 D 60C5、設有以下定義和語句,則輸出的結果是_(用small模式編譯,指針變量占2個字節(jié)。struct date long *cat;struct date *next;double dog; too;printf("%d",sizeof(too;A 20 B 16C 14 D 12D6、以下程序的輸出結果是_。struct HAR int x,y; struct HAR *p; h2;

4、main( int h0.x=1; h0.y=2;h1.x=3;h1.y=4;h0.p=&h1; h1.p=h;printf("%d%dn",(h0.p->x,(h1.p->y; A 12 B 23C 14 D 32D7、下面程序的輸出是_。main(struct cmplx int x; int y; cnum2=1,3,2,7; printf("%dn",cnum0.y /cnum0.x * cnum1.x; A 0 B 1C 3 D 6D8、設有變量定義struct stuint age;int num;std,*p=&

5、std;能正確引用結構體變量std中成員age的表達式是A std->age B *std->ageD9、設有定義語句"struct int x;int y;d2=1,3,2,7;",則printf("%dn",d0.y/d0.x*d1.x;的輸出結果是A 0 B 1C 3 D 6D10、若有如下定義union long x2;int y4;char z8;them;則printf("%dn",sizeof(them;的輸出是A 32 B 16C 8 D 24C11、若有如下定義,則對data中的a成員的正確引用是B12、

6、若有以下說明和定義語句,則變量w在內(nèi)存中所占的字節(jié)數(shù)是union aa float x;float y;char c6;struct st union aa v;float w5;double ave;w;A 42 B 34C 30 D 26B13、若有變量定義語句union long x2;short y45;char10;u1;則表達式sizeof(u1的值是A 8 B 10C 40 D 58C14、下列程序的輸出結果是:struct abcint a,b,c;main(struct abc s2=1,2,3,4,5,6;int t;t=s0.a+s1.b;printf("%dn

7、",t;A 5 B 6C 7 D 8B15、變量a所占的內(nèi)存字節(jié)數(shù)是union Uchar st4;int i;long l;struct Aint c;union U u;a;A 4 B 5C 6 D 8C16、執(zhí)行下面的程序后,輸出的結果是struct abcint a,b,c;main(struct abc s2=1,2,3,4,5,6;int t;t=s0.a+s1.b;printf("%dn",t; A 5 B 6C 7 D 8C B17、下列程序的輸出結果是#indlude "stdio.h"main(struct dateint

8、year ,month,day;today;union long i;int k;char c; mix;printf("%dn",sizeof(struct date; printf("%dn",sizeof(mix;A 6 B 62 4C 8 D 84 6 B18、下面程序的輸出結果是typedef unionlong x2;int y4;char z8;MYTYPE;MYTYPE them;main(printf("%dn",sizeof(them; A 32 B 16 C 8 D 24 C19、若有以下的說明:struct personchar name20;int age;char sex;a="li ning",20,'