C課程設(shè)計(jì)——日期類設(shè)計(jì)報(bào)告

1、日期類設(shè)計(jì)報(bào)告1. 設(shè)計(jì)題目設(shè)計(jì)一個(gè)日期類，（學(xué)號(hào)尾號(hào)2、5、8完成）要求：2. 設(shè)計(jì)要求l 重載帶參數(shù)構(gòu)造函數(shù)（int year ,int month, int day）和默認(rèn)構(gòu)造函數(shù)，前者要求不合要求的數(shù)據(jù)（年月日超出范圍）拋出異常l 計(jì)算出該日是星期幾，（網(wǎng)上找公式）。l 重載“+”操作，一個(gè)日期對(duì)象和天數(shù)相加（符合交換律）。l 重載“-”操作，兩天日期對(duì)象相減返回相差天數(shù)。 l 重載“+=”操作當(dāng)前日期加天數(shù)l 重載輸入輸出操作。3. 設(shè)計(jì)分析由題中要求可以知道，首先要設(shè)計(jì)一個(gè)日期類（class Cdate），還要有構(gòu)造函數(shù)，明白函數(shù)的帶參與不帶參的區(qū)別；而且在日期類之中需要設(shè)計(jì)正確的

2、日期格式，若不正確則實(shí)現(xiàn)拋出異常，C+中對(duì)異常的處理分為拋出異常、捕獲異常、處理異常；在此處只要求拋出異常即可，接下來(lái)的實(shí)現(xiàn)輸入日期計(jì)算星期幾的代碼，。由題可以進(jìn)行網(wǎng)上的搜索，這個(gè)應(yīng)該行對(duì)簡(jiǎn)單！之后就是重載的操作啦！4. 設(shè)計(jì)主要模塊（代碼實(shí)現(xiàn)）1. 定義一個(gè)日期類class CDatepublic:CDate()CDate(int y,int m,int d);void fun();void display();friend CDate operator + (int d,CDate dt);friend CDate operator - (CDate &dt1,CDate &

3、;dt2);friend CDate &operator += (CDate &a1,int d);friend std:ostream& operator<< ( std:ostream& os, CDate& dt );friend std:istream& operator>> ( std:istream& is, CDate& dt );bool isleapyear();/ 潤(rùn)年的判定bool status;bool check();void gettian();private:int year,

4、month,day,day1;int d,D,D1,D2,D3;CDate:CDate (int y,int m,int d):year(y),month(m),day(d)2. 實(shí)現(xiàn)計(jì)算星期幾：#include <iostream>using namespace std;class Dateint year,month,day;bool isleap(int i) constreturn i%400=0|i%4=0&&i%100!=0;/閏年的判定public:Date(int y, int m, int d): year(y), month(m), day(d)

5、 void print() constchar* s = "星期日,"星期一","星期二","星期三","星期四","星期五","星期六"int d13 = 0,31,28,31,30,31,30,31,31,30,31,30;int sum = 0;int i;if(isleap(year)d2 +;for(i=1;i<year;i+)sum += 365 + isleap(i);for(i=1;i<month;i+)sum += di;sum +=

6、day;cout << ssum%7 << endl;int main()int year,month,day;while(cin >> year >> month >> day && year + month + day)Date d(year,month,day);d.print();3. 重載日期加減的操作：CDate operator - (CDate &dt1,CDate &dt2) /重載-計(jì)算兩日期對(duì)象的天數(shù)差；CDate dt3;if(dt1.year%4=0&&dt1.

7、year%100!=0|dt1.year%400=0)mon_day1=29;if(dt2.year%4=0&&dt2.year%100!=0|dt2.year%400=0)mon_day1=29; dt1.D =(dt1.year-1)*365+(dt1.year-1)/4-(dt1.year-1)/100+(dt1.year-1)/400+dt1.D1 +dt1.day ; for(int i=0;i<=dt1.month -1;i+)dt1.D1 +=mon_dayi;dt2.D2 =(dt2.year -1)*365+(dt2.year-1)/4-(dt2.yea

8、r-1)/100+(dt2.year-1)/400+dt2.D3 +dt2.day ;for(int j=0;j<=dt2.month -1;j+)dt2.D3 +=mon_dayj;dt3.d =dt1.D -dt2.D2 ; return dt3;4. 調(diào)試運(yùn)行圖示1.判斷日期格式是否正確2，輸入日期并且計(jì)算星期幾，返回與系統(tǒng)中初始設(shè)定日期的相差天數(shù)：5. 源代碼附錄：#include <iostream>#include <stdio.h>#include <string.h>using namespace std;class CDate; /聲

9、明類；CDate operator + (int d,CDate dt); /必須在此先聲明重載 CDate operator -(CDate &dt1,CDate &dt2);CDate &operator += (CDate &a1,int d);CDate &operator << (CDate &a1,int d);std:ostream& operator<< ( std:ostream& os, CDate& dt );std:istream& operator>>

10、( std:istream& is, CDate& dt );char *week="星期日","星期一","星期二","星期三","星期四","星期五","星期六" /指針數(shù)組，保存星期；int mon_day=31,28,31,30,31,30,31,31,30,31,30,31; /數(shù)組，保存每月天數(shù)；class CDatepublic:CDate()CDate(int y,int m,int d);void fun();void d

11、isplay();friend CDate operator + (int d,CDate dt);friend CDate operator - (CDate &dt1,CDate &dt2);friend CDate &operator += (CDate &a1,int d);friend std:ostream& operator<< ( std:ostream& os, CDate& dt );friend std:istream& operator>> ( std:istream& is

12、, CDate& dt );bool isleapyear();/ 潤(rùn)年的判定bool status;bool check();void gettian();private:int year,month,day,day1;int d,D,D1,D2,D3;CDate:CDate (int y,int m,int d):year(y),month(m),day(d)void CDate:gettian ()cout<<"兩天日期對(duì)象相減返回相差天數(shù)："<<d<<endl;bool CDate:isleapyear()return (

13、year % 4) = 0) && (year % 100) != 0) | (year % 400) = 0);bool CDate:check()if (year < 0)status = false;return status;if (month < 1) | (month > 12)status = false;return status;switch (month)case 1:case 3:case 5:case 7:case 8:case 10:case 12:if (day < 1) | (day> 31)status = fals

14、e;break;case 2:if (isleapyear()if (day < 1) | (day > 29)status = false;elseif (day < 1) | (day > 28)status = false;break;case 4:case 6:case 9:case 11:if (day < 1) | (day> 30)status = false;break;default:status = false;if (status)cout<<year<<"/"<<month<

15、;<"/"<<day<<endl;cout<<"恭喜日期正確了！"<<endl;return status;void CDate:fun ()int C,W,y;cout<<"請(qǐng)輸入日期!"<<endl;cout<<"年份:"cin>>year;cout<<"月份:"cin>>month;cout<<"日期:"cin>>day;

16、if(year<=0|month<=0|month>12|day<=0|day>31)cout<<"請(qǐng)輸入正確的日期!"<<endl;elseif(month=1|month=2)month+=12;-year;elseC=year/100;y=year%100;W=(C/4)-2*C+y+(y/4)+(13*(month+1)/5)+day-1)+700)%7;cout<<"今天是"<<weekW<<endl;void CDate:display ()if(yea

17、r<=0|month<=0|month>12|day<=0|day>31)cout<<"請(qǐng)輸入正確的日期!"<<endl;else cout<<year<<"/"<<month<<"/"<<day<<endl;CDate operator + (int d,CDate dt)dt.day=dt.day+d;while(dt.day>mon_daydt.month-1)if(dt.year%4=0&

18、&dt.year%100!=0|dt.year%400=0)mon_day1=29;dt.day-=mon_daydt.month-1;if(+dt.month=13)dt.month=1;dt.year+;return dt;CDate operator - (CDate &dt1,CDate &dt2) /重載-計(jì)算兩日期對(duì)象的天數(shù)差；CDate dt3;if(dt1.year%4=0&&dt1.year%100!=0|dt1.year%400=0)mon_day1=29;if(dt2.year%4=0&&dt2.year%100!=

19、0|dt2.year%400=0)mon_day1=29; dt1.D =(dt1.year-1)*365+(dt1.year-1)/4-(dt1.year-1)/100+(dt1.year-1)/400+dt1.D1 +dt1.day ; for(int i=0;i<=dt1.month -1;i+)dt1.D1 +=mon_dayi;dt2.D2 =(dt2.year -1)*365+(dt2.year-1)/4-(dt2.year-1)/100+(dt2.year-1)/400+dt2.D3 +dt2.day ;for(int j=0;j<=dt2.month -1;j+)d

20、t2.D3 +=mon_dayj;dt3.d =dt1.D -dt2.D2 ; return dt3;CDate &operator += (CDate &a1,int d)if(a1.year%4=0&&a1.year%100!=0|a1.year%400=0)mon_day1=29;a1.day+=d;while(a1.day>mon_daya1.month-1)a1.day-=mon_daya1.month-1;if(+a1.month=13)a1.month=1;a1.year+;return a1;std:ostream& operato

21、r<< ( std:ostream& os, CDate& dt ) os << dt.year << '/' << dt.month << '/' << dt.day ; return os;std:istream& operator>> ( std:istream& is, CDate& dt ) is >> dt.year >> dt.month >> dt.day ; return is;int

22、_tmain(int argc, _TCHAR* argv)CDate b2(2021,2,29);b2.check ();CDate b5(2021,6,9);b5.check ();/b2.display (); / CDate b1(-1231,10,17);/b1.display ();/cout<<"*"<<endl;/b1.fun ();/CDate b3(1992,10,17); / CDate b4;/b4=12+b3;/b4.display (); /CDate dt1(2021 ,1,1);/CDate dt2(2021 ,1,1

23、);/CDate dt3;/dt3=dt1-dt2;/dt3.gettian ();/CDate a1(1992,10,17);/a1+=2;/a1.display ();/CDate dt( 1992,10,17); /std:cout << dt<<endl;/cout<<"請(qǐng)輸入日期:"/std:cin>>dt;/cout<<endl;return 0; 公司印章管理制度一、目的 公司印章是公司對(duì)內(nèi)對(duì)外行使權(quán)力的標(biāo)志，也是公司名稱的法律體現(xiàn)， 因此，必須對(duì)印章進(jìn)行規(guī)范化、合理化的嚴(yán)格管理，以保證公司各項(xiàng)業(yè)務(wù)的正常運(yùn)作，由公司指定專人負(fù)責(zé)管理。二、印章的種類1、 公章，是按照政府規(guī)定，由主管部門批準(zhǔn)刻制的代表公