案例學(xué)習(xí)性能flexible takeoff

1、FLEXIBLE TAKEOFFObjective: to determine whether a flex Takeoff is possible, to calculate the flexible temperature and the Takeoff speeds for a TakeOff Weight below MTOW.Flex Temperature:when your actual TakeOff Weight is lower than the Maximum TakeOff Weight, you can perform a Takeoff with less than

2、 the max Takeoff thrust,this thrust reduction improves engine life,to manage this thrust reduction, we use an assumed temperature named ”flexible temperature”.Flex TemperatureMax TOWActual TOWAvailablethrustNeededthrustFlat rated thrustTrefWeightThrustEGT limitOATFlex TempT Flex maxOAT25 % reduction

3、 maxExampleWhat is T flex ?JAKARTA ATIS provides the following data:Runway 25LRunway dryWind 10 kt OAT 28 CQNH 1003 hPaTOW = 212 000 kgCONF 1 + FAir conditioning OFFTotal anti-ice OFFTOW = 212 000 kgFLEX temp = 52 CPLUS CORRECTIONS212.4 4/4 154/54/59Conditions: QNH = 1003 hPa Air conditioning OFF An

4、ti-icing OFF DryTFlex Correction - 2 CNo correction on speeds.HEADWIND 10 ktConditions: QNH = 1003 hPaAir conditioning OFFAnti-icing OFFDry -1.7 -2 0/ 0/ 0(+60) -1.7 -2 0/ 0/ 0Compare TFLEX (52 C) with TVMCCheck that: Corrected Temperature CT T flex max (60 C) OAT (28 C) T ref (30 C) 2.02.20 P 7ACTU

5、AL CONDITIONS + CORRECTIONST Flex: 52 - 2 = 50 C Speeds: 154/154/159Example 1JAKARTA ATIS provides the following data:Runway 25LRunway wetWind 080/5 kt OAT 35 CQNH 1005 hPaTOW = 209 000 kgCONF 2Air conditioning ONTotal anti-ice OFFTOW = 209 000 kgCONF 2Air conditioning ONTotal anti-ice OFFAt 209 000

6、 kg Flex = 48 C+ correctionsSpeeds = 153/154/159JAKARTA ATIS provides the following data:RWY 25L Runway wetWind 080/5 ktOAT 35 C QNH 1005CT = 48 C Speeds 150/154/159T flex = 48 C Speeds 153/154/159 0.0 0 -3/ 0/ 0TAILWIND - 5 ktJAKARTA ATIS provides the following data:RWY 25L Runway wetWind 080/5 ktO

7、AT 35 C QNH 1005TOW = 209 000 kgCONF 2Air conditioning ONTotal anti-ice OFFFor each correction,compare TFLEX (48 C) with TVMCJAKARTA ATIS provides the following data:RWY 25L Runway wetWind 080/5 ktOAT 35 C QNH 1005CT = 48 - 2 = 46 C NO CORRECTIONS ON SPEEDS -2.4 -2 0/ 0/ 0TAILWIND - 5 ktTOW = 209 00

8、0 kgCONF 2Air conditioning ONTotal anti-ice OFFTAILWIND - 5 ktTOW = 209 000 kgCONF 2Air conditioning ONTotal anti-ice OFF -2.7 -2 -2/ -2/ -2JAKARTA ATIS provides the following data:RWY 25L Runway wetWind 080/5 ktOAT 35 C QNH 1005CT = 46 - 2 = 44 C NO CORRECTIONS ON SPEEDSV1= 150 VR= 154 V2= 159Check

9、 Corrected Temperature CT TFlex max OAT T RefWhen more than one TO CONFIG chart is availableUse the CONFIG giving the highest FLEX tempIf two CONFIG give the same FLEX tempuse the one giving the lowest speedsand TOW is less than MTOWCONF 1 + FCONF 2CONF 1 + F T flex = 43 C Speeds 150/154/159 CONF 2

10、T flex = 44 C Speeds 150/154/159Example 2JAKARTA ATIS provides the following data:Runway 25LRunway dryWind calmOAT 35 CQNH 1013 hPaTOW = 137 500 kgCONF 1 + FAir conditioning ONTotal anti-ice OFFFLEX TEMP = 60 C= T FLEX MAX197.5 4/4 151/51/55TOW = 137 500 kgCONF 1 + FAir conditioning ONTotal anti-ice

11、 OFFJAKARTA ATIS provides the following data:RWY 25L Runway dryWind calmOAT 35 C QNH 1013197.5 4/4 151/51/55Min V1/VR/V2 = 124/27/32CHECK VMU LIMITATIONCorrect V1/VR/V2 = 0.1 kt/1000 kgTOW = 137 500 kgCONF 1 + FAir conditioning ONTotal anti-ice OFFJAKARTA ATIS provides the following data:RWY 25L Run

12、way dryWind calmOAT 35 C QNH 1013Weight Correction 197 500 kg - 137 500 kg = 60 000 kg Speed Correction - 0.1 kt/1000 kg = - 6 ktV1 = 145 VR = 145 V2 = 149 FOR REFERENCE CONDITIONS197.5 4/4 151/51/55Min V1/VR/V2 = 124/27/32CHECK VMU LIMITATIONCorrect V1/VR/V2 = 0.1 kt/1000 kgTOW = 137 500 kgCONF 1 +

13、 FAir conditioning ONTotal anti-ice OFFJAKARTA ATIS provides the following data:RWY 25L Runway dryWind calmOAT 35 C QNH 1013Check minimum V1/VR/V2TOW = 137 500 kgCONF 1 + FAir conditioning ONTotal anti-ice OFFJAKARTA ATIS provides the following data:RWY 25L Runway dryWind calmOAT 35 C QNH 1013CHECK

14、VMU LIMITATION140128V1 = 145 VR = 145V2 = 149TOW = 137 500 kgCONF 1 + FAir conditioning ONTotal anti-ice OFFJAKARTA ATIS provides the following data:RWY 25L Runway dryWind calmOAT 35 C QNH 1013WIND 0 kt 137.5 t 145/45/49Correction for air conditioningTOW 137 500 kgT FLEX = 60 - 2 = 58 C V1 = 145 VR

15、= 145 V2 = 149NO SPEED CORRECTION -2.9 -2 -2/ -2/ -2Compare TFLEX (60 C) with TVMCExercise 1JAKARTA ATIS provides the following data:Runway 25LRunway wetWind calmCAVOKOAT 35 CQNH 1003TOW = 217 000 kg (= MTOW)Air conditioning ONAnti ice OFFCONF 2WHAT ARE THE CORRECTED TEMPERATURE AND TAKE OFF SPEEDS

16、?Answer:Tflex = 40 C Speeds 155/158/162 TOW = 217 000 kgCONF 2Air conditioning ONJAKARTA ATIS provides the following data:RWY 25L Runway wetWind calmOAT 35 C QNH 1003 219.4 4/4 157/58/62- 216.5 4/4 156/57/61At 217 000 kg Flex = 45 C + correctionsSpeeds = 157/158/162WET RWY corrections: Temp 0 Speeds

17、 -2/ 0 /0 TOW = 217 000 kgCONF 2Air conditioning ONJAKARTA ATIS provides the following data:RWY 25L Runway wetWind calmOAT 35 C QNH 1003 0.0 0 -2/ 0/ 0 WIND 0 ktCompare TFLEX (45 C) with TVMCQNH corrections: Temp -2 Speed corrections irrelevant TOW = 217 000 kgCONF 2Air conditioning ONJAKARTA ATIS p

18、rovides the following data:RWY 25L Runway wetWind calmOAT 35 C QNH 1003 WIND 0 kt -1.9 -2 0/ 0/ 0TOW = 217 000 kgCONF 2Air conditioning ONJAKARTA ATIS provides the following data:RWY 25 l Runway dryWind calmOAT 35C QNH 1003Air conditioning corrections: Temp -3 Speed corrections irrelevant TOW = 217

19、000 kgCONF 2Air conditioning ONJAKARTA ATIS provides the following data:RWY 25L Runway wetWind calmOAT 35 C QNH 1003 WIND 0 kt -3.2 -3 0/ -1/ -1TOW = 217 000 kgCONF 2Air conditioning ONJAKARTA ATIS provides the following data:RWY 25L Runway wetWind calmOAT 35 C QNH 1003TOW = 217 000 kg Tflex 45 Spee

20、ds 157/158/162WET runway corrections:Temp 0 Speeds -2/ 0/ 0QNH corrections:Temp -2 IrrelevantAir conditioning corrections:Temp -3 Irrelevant CT = 40 C V1 = 155 VR = 158 V2 = 162Check that: corrected temperature CT T flex max OAT T refOAT = 35 C T ref = 30 C T flex max = ISA + 45 C Answer:T flex = 40

21、 CSpeeds 155/158/162 Exercise 2MARSEILLE ATIS provides the following data :Runway 32LRunway wetWind -5 ktOAT 20 CQNH 1003TOW = 183 000 kg Air conditioning ONTotal anti ice OFFCONF 2WHAT ARE THE CORRECTED TEMPERATURE AND TAKE OFF SPEEDS ?Answer:Tflex = 32 C Speeds 119/126/134 T FLEX 38 C Speeds 119/2

22、6/34MARSEILLE ATIS provides the following data: take off runway 32L, runway condition WET,wWind - 5 kt OAT 20 C, QNH 1003 hPa.AIRCRAFT STATUS: TOW 183 000 kg CONF 2, air conditioning ON, total anti-ice OFF.183.6 3/9 119/26/34Note gray area indicating VMC limitationT Flex correction = - 2Speed correc

23、tion irrelevant QNH correction:Now apply corrections at bottom of RTOW: runway WET, QNH 1003 hPa, air conditioning ON, OAT 20 C.T FLEX 38 C 119/30/38 -1.9 -1 0/ -1/ -1(+10) -3.4 -2 0/ 0/ 0If TFLEX below or equal to TVMC, use corrections in white box.If TFLEX above TVMC, use corrections in gray box.T

24、VMC Check : for each correction, compare TFLEX with TVMCAir conditioning correction:Now apply corrections at bottom of RTOW: runway WET, QNH 1003 hPa, air conditioning ON, OAT 20 C. -4.0 -2 -1/ -1/ -1(+10) -7.5 -4 0/ 0/ 0T Flex correction = - 4Speed correction irrelevant T FLEX 38 C 119/30/38TVMC Check : for each correction, compare TFLEX with TVMCTotal correctionsTOW = 183 000 kg Tflex 38 Speeds