人教版八年級上冊數(shù)學(xué)《全等三角形》單元綜合測試卷

1、數(shù)上三元(考試時間90 鐘 試卷滿分: 分)一選題共 小ABCEFD( )AABACEFBCDFCDEBCDFBDFACDEEFDEFDF 1+3( ) 1 A90B120C135DABC 5DEF 332x+1 x ( )A2 B C 3 D 2ABCBAC23 ( )A120BC 4 5 ABC eq oac(,A) eq oac(, )BC ABC eq oac(,A) eq oac(, )B ( )A+90B+2C+D eq oac(,A) eq oac(, )BCA50B ( )ABD ABD A55BC70D75ABC AEDC D ( )A20BC40D50 8 DEF x (

2、A30 B27 C D40DB2 ( )ABCBE B CAD DDEBBE 7 AD ( )A3B5 C4 9 10 11( )A BSAS AAS D ABC C90AD BC DABS ( )A3 B 5 11 二填題(共 4 小 CAB/ B B D ts Q x cmsACP BPQ x ACBD4cm P AB 第 13 題ACEDBFF10 A B AC ; E CE; DE 15 ABC OB ABC ACB D OD ABC 三解題共 小ABCAF8BE2(1):ACDF(2) AB 第 17 題ABCADEDEAB DGB 第 18 題ABCDBE D BC DE ABED

3、BCCDE 第 19 題AEBE D AC 12AE (1) eq oac(,:)BED(2)70AEB 第 20 題: ABC PMAB M N EDBD (1) eq oac(,:)ABD;第 題 ADBC D (2) ACD 第 22題 DB E DBEB M AE DN(1) eq oac(,:)ABEDBC(2) BM BN 第 23 CBCDD+CEAD (1): ;(2) AE 第 24 題一選題共 小ABCEFD( ) AABACEFBCDFCDEBCDF參考答案BDFACDEEFDEFDF :ABCEFDDEDFCFBD 1+3( )A90B120C135DABC DEA 1

4、 4:ABC AB=DEDEABC=AE()143+901+901+90135:CABC 5DEF 332x+1 x ( )A2 B 73C7 33 2D 7 33 2: 32 3x 2 3x2 214 x : DEF 3252+1x73 x73 x+1 x143 5 324 x2 x x+1 x:AABCBAC23 ( )A120B125C127D :B30BAC2323127ACD:CABC eq oac(,A) eq oac(, )BC ABC eq oac(,A) eq oac(, )B ( )A+90B+2C+DCAAACACAAA ;: C eq oac(,A) eq oac(,

5、)B ACCAAC;180 2+180:C eq oac(,A) eq oac(, )BCA50B ( )A55BC70D75CC:A50C60 eq oac(,A) eq oac(, )BCC60:BABC AEDC D ( )A20BC40D50ABC 50 ABC ECA BCE :ABC A30ABCBCDEDCDCEDCEDCB+BCEBCEDCBDCB808020:AABCDEF ( )A30 B27 C D40:ABCDEFEF:ADB2 ( )ABCBE B CAD DDEBABC AB :A BE ;B ACDE ABC;CAD DBE;DACBDEB ASA DBE:B90

6、DACBEAC B EC BE73 AD ( )A3 B 4 ACDACD ADBCBE:90+BCEEBCEACDE BCE DAC=CBE=90ACD=DC=ECACD(AASADBCAC3AC74:C11 ( )A BSAS AAS D: : ABC AD BAC ABDABDABDABDS 15 CD ( )A3 B 5 D DE E DECD : D DE EC90AD DECD 1 1ABDE 1015 2 2 DECD3:A二填題共 小6ACBD /s Q BD B D (s Q / BPQ 2 :ACPBPQ x83 4PA 1.58x3 83ACEDBFF10 CD eq o

7、ac(,:)DBFDA102CD: BC 10 2 2A B AC ; E CE; DE 60 ACB DE :ACB DCE BC=ECDCESASDEDE60 60 :60ABC OB ABC ACB D OD ABC 33 eq oac(, ) OD: OAOBOC ABC ACB OD D ODAB 12:33三解題共 小ABCAF8BE2(1):ACDF(2) AB (1); (2):(1)ABCFEDADF(2)FED22+5ABCADEDEAB DGB ABCADEDAEBAC12EABDFB+BFAB+CABDFB ; DFBDDGB :ABCADEBAC1 1( 2 DFB+

8、CAB+BDGBD902565:65ABCDBE BC DE PABEDBC ABC:162DBCABD+CBE2CPDCDEAEBE D AC AEBD (1) eq oac(,:)BED(2)70AEB (1)C;2 EDBEDAEC:(1)ADE+1CBDEABBED()(2)BEDEDBEDEDCC70BEA2240AEBCP ABC PMAB M N: MAN PDBC D PMPDPD PMPN : PD D ABC PMABPDBCPMPNPDPM PMAC ABC ACB45 A ADBC D E BD (1) eq oac(,:)ABD;(2) ACD (1)ADC AD ;(2)ECD12BAD22.5(1):AD45CDE90 ADCDACD CED AD=CDADB=BD=EDCEDSAS);(2) ECD12(1) eq oac(,:)BAD+4567.5 DB DB ABDBM DN(1) eq oac(,:)ABEDBC(2) BM BN (1) SAS ABE;(2)ABM BMBNABM90 (1):DB ABE90ABE DBC AB=DBABE=BBCBE=BCABE(2)BMBNMBBN:ABEBAMABM AB=DBBDNABM(SAS)BM+DBMABMDBMMB CBCDD+CEAD (1): ;(2) AE C CF F C