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安岳縣2014—2015學(xué)年度第二學(xué)期期末授課質(zhì)量監(jiān)測義務(wù)教育級數(shù)學(xué)試卷答案一、選擇題(共10小題,每題3分)題號12345678910答案CABCCDBACB二、填空題(共6小題,每題3分)11.412.0和113.x(1+40%)×80%=24014.515.6816.13或9三、解答題(共9小題)解:(1)x=10···················································3分x1(2)y2·············································7分z3x4(1)原不等式變?yōu)椤ぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁぁ?分x0所以原不等式組的解為0≤x<4···································5分(2)圖形略················································7分(1)解方程組得a5b3(2)若a=5為腰長,5+5>3滿足,此時三角形周長為:5×2+3=13··········6分若b=3為腰長,3+3>5滿足,此時三角形周長為:3×2+5=11··········8分x2x22kb320.解:(1)當(dāng)3和5時,原方程組變?yōu)閎···············2分yy2k5k2解得:·········································4分b12)由不等式3+2x>m+3x得:x<3-m····························5分又由題可知2<3-m≤3········································7分0≤m1··················································8解:圖略12342··································8解:1△ABC△DEBABDE7,BE=BC4,··································2AE=AB-BE=7-4=3·········································42△ABC△DEB°°·································6A=D=35DBEC=60DFA=A+AEF=A+D+DBE=130°·······················8°°23.解:BECBEC=150EBC+ECB=30············1°°ABCA=50ABC+ACB=180°-50=130°················2∴ABE+ACE=130°30°=100°··································3∵BD、CDABEACE,A2=1ABE,3=1ACE,22∴2+3=1(ABE+ACE)=1×100°=50°.522D∴DBC+DCB=(2+3)+(EBC+ECB)1E4=50°+30°=80°..723BC∴BDC=180°80°=100°..8724.解:1bc-2a0··············································2bc-80a=4·················································32b+c-8=0b=8-c···················································53a+b>c>b-a4+8-c>c>8-c-4··············································86>c>2················································925.解(1)xyxy65··········································26x3y285x30解之得···········································4分352)可設(shè)新同事中有a名男性,則新同事中女性為(3-a)名,由題可列方程為:0.9[30(1+6+a)+35(1+3+3

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