試驗六繼承與派生

繼承與組合一、實驗目的.了解繼承在面向對象程序設計中的重要作用。.進一步理解繼承與派生的概念。.掌握通過繼承派生出一個新的類的方法。.了解虛基類的作用和用法。.掌握類的組合二、實驗內容1.請先閱讀下面的程序，寫出程序運行的結果，然后再上機運行程序，驗證自己分析的結果是否正確。⑴#include<iostream>usingnamespacestd;classA{public:A(){cout<<"A::A()called.\n";}virtual-A(){cout<<"A::-A()called.\n";}};classB:publicA{public:B(inti){ cout<<"B::B()called.\n";buf=newchar[i];)virtual~B(){delete[]buf;cout<<"B::-B()called.\n";)private:char*buf;);voidfun(A*a){cout<<"Mayyousucceed!"<<endl;deletea;)intmain(){A*a=newB(15);fun(a);return0;)1、(1)程序運行結果：A::A()called.B::B()called.Mayyousucceed!B::~B()called.A::~A()called.h: called.D:：B()called.yousucceed?D：ECcalled.A：:RCcalled.frocessexitedwithr-etu.rnvalue0ressdnykeytogontinu.e...#include<iostream>usingnamespacestd;classA{public:A(inta,intb):x(a),y(b){cout<<"Aconstructor…”<<endl}voidAdd(inta,intb){x+=a;y+=b;}voiddisplay(){cout<<"("<<x<<","<<y<<")";}-A(){cout<<"destructorA..."<<endl;}private:intx,y;);classB:privateA{private:inti,j;AAobj;public:cout<<"BB(inta,intb,intc,intd):A(a,b),i(c),j(d),Aobj(1,1){constructor…”<<endl;}cout<<"BvoidAdd(intx1,inty1,intx2,inty2){A::Add(x1,y1);+=x2;j+=y2;}voiddisplay(){A::display();Aobj.display();cout<<"("<<i<<","<<j<<")"<<endl;}~B(){cout<<"destructorB..."<<endl;}};intmain()Bb(1,2,3,4);b.display();b.Add(1,3,5,7);b.display();return0;)(2)程序運行結果:Aconstructor...Aconstructor...Bconstructor...(1,2)(1,1)(3,4)(2,5)(1,1)(8,11)destructorB...destructorA...destructorA...[BD:\c++\6.2.exeAconstructor...。constPLictor...RconstI'mctor=a=<1,2X1C2,5><ia)<8,ll>destPLictordesti'LictaFlestructurProcea君exitedwithreturnvalue3PressanykeytocontImoe...#include<iostream>usingnamespacestd;classA{public:A(inta):x(a){cout<<"Aconstructor…"<<x<<endl;}intf(){return++x;}-A(){cout<<"destructorA..."<<endl;}private:intx;};classB:publicvirtualA{private:inty;AAobj;public:B(inta,intb,intc):A(a),y(c),Aobj(c){cout<<"Bconstructor..."<<y<<endl;}intf(){A::f();Aobj.f();return++y;}voiddisplay(){cout<<A::f()<<"\t"<<Aobj.f()<<"\t"<<f()<<endl;}~B(){cout<<"destructorB..."<<endl;}};classC:publicB{public:C(inta,intb,intc):B(a,b,c),A(0){cout<<"Cconstructor..."<<endl;}};classD:publicC,publicvirtualA{public:D(inta,intb,intc):C(a,b,c),A(c){cout<<"Dconstructor..."<<endl;}~D(){cout<<"destructorD..."<<endl;}};intmain()Dd(7,8,9);d.f()；d.display();return0;)⑶程序運行結果：Aconstructor...9Aconstructor...9Bconstructor...9Cconstructor...Dconstructor...12 12 11destructorD...destructorB...destructorA...destructorA...(4)#include<iostream>usingnamespacestd;classBase1(public:Base1()(cout<<"classBase1!"<<endl;));classBase2(public:Base2()(cout<<"classBase2!"<<endl;))；classLevel1:publicBase2,virtualpublicBasel(public:Level1()(cout<<"classLevel1!"<<endl;));classLevel2:publicBase2,virtualpublicBase1(public:Level2()(cout<<"classLevel2!"<<endl;);classTopLevel:publicLevel1,virtualpublicLevel2(public:TopLevel()(cout<<"classTopLevel!"<<endl;));intmain()(TopLevelobj;return0;)(4)程序運行結果：classBasel!classBase12classLeve12!classBase2!classLeve11!classTopLevel!

D:\c++\6,4.execlassclassk^lassC1-AGSklagsclassBaselJD:\c++\6,4.execlassclassk^lassC1-AGSklagsclassBase2fLevel2fBase29Lenell*TopLevelTPro(；iESSsxitiedwithrietumvalue0Fressanykeytocontinue檄較抖音半二2.某出版系統(tǒng)發(fā)行圖書和磁帶，利用繼承設計管理出版物的類。要求如下：建立一個基類Publication存儲出版物的標題title、出版物名稱name、單價price及出版日期date。用Book類和Tape類分別管理圖書和磁帶，它們都從Publication類派生。Book類具有保存圖書頁數(shù)的數(shù)據(jù)成員page，Tape類具有保存播放時間的數(shù)據(jù)成員playtime。每個類都有構造函數(shù)、析構函數(shù)，且都有用于從鍵盤獲取數(shù)據(jù)的成員函數(shù)inputData()，用于顯示數(shù)據(jù)的成員函數(shù)display()。#include<iostream>usingnamespacestd;#include<string>classDate{public:Date(){}Date(inty,intm,intd);Date(Date&d);voidSetDate(inty,intm,intd);voidShowDate();private:intyear,month,day;);Date::Date(inty,intm,intd){year=y;month=m;day=d;}Date::Date(Date&d){ year=d.year;month=d.month; day=d.day;}voidDate::SetDate(inty,intm,intd){year=y;month=m;day=d;}voidDate::ShowDate(){ cout<<year<<"年"<<month<<"月"<<day<<"曰"<<endl;}classTime{public:Time(){}Time(inth,intm,ints);Time(Time&t);voidSetTime(inth,intm,ints);voidShowTime();private:inthour,minute,second;);Time::Time(inth,intm,ints){hour=h;minute=m;second=s;}Time::Time(Time&t){hour=t.hour;minute=t.minute;second=t.second;}voidTime::SetTime(inth,intm,ints){hour=h;minute=m;second=s;}voidTime::ShowTime(){cout<<hour<<":"<<minute<<":"<<second<<endl;}classPublication{public:Publication(){}Publication(stringtitle,stringname,floatprice,inty,intm,intd);voidinputData();voiddisplay();private:stringtitle;stringname;floatprice;Datedate;};Publication::Publication(stringtitle,stringname,floatprice,inty,intm,intd):title(title),name(name),price(price),date(y,m,d){}voidPublication::inputData(){cout<<"Pleaseinputtitle,name,price,publicationdateofabook:"<<endl;cin>>title>>name>>price;intyear,month,day;cin>>year>>month>>day;date.SetDate(year,month,day);)voidPublication::display(){cout<<"title="<<title<<endl;cout<<"name="<<name<<endl;cout<<"price="<<price<<endl;cout<<"date=";date.ShowDate();)classBook:publicPublication{public:Book(){}Book(stringtitle,stringname,floatprice,inty,intm,intd,intpage);voidinputData();voiddisplay();private:intpage;};Book::Book(stringtitle,stringname,floatprice,inty,intm,intd,intpage):Publication(title,name,price,y,m,d){this->page=page;}voidBook::inputData(){Publication::inputData();cout<<"Pleasethepagesofthebook:"<<endl;cin>>page;}voidBook::display(){Publication::display();cout<<"page="<<page<<endl;}classTape:publicPublication{public:Tape(){}Tape(stringtitle,stringname,floatprice,inty,intm,intd,Timeplaytime);voidinputData();voiddisplay();private:Timeplaytime;};Tape::Tape(stringtitle,stringname,floatprice,inty,intm,intd,Timeplaytime):Publication(title,name,price,y,m,d),playtime(playtime){}voidTape::inputData(){Publication::inputData();cout<<"Pleasetheplaytimeofthetape:"<<endl;inthour,minute,second;cin>>hour>>minute>>second;playtime.SetTime(hour,minute,second);)voidTape::display(){Publication::display();cout<<"playtime=";playtime.ShowTime();)intmain(){ Bookbook1("教材","C++程序設計",30.00,2009,6,1,300);book1.display();cout<<endl;Timetime1(30,10,20);Tapetape1(M^^","C++程序設計視頻",10.00,2009,8,1,time1);tape1.display();Bookbook2;book2.inputData();book2.display();cout<<endl;Tapetape2;tape2.inputData();tape2.display();return0;)3.分別定義教師類Teacher和干部類Cadre，采用多重繼承的方式由這兩個類派生出新類Teacher_Cadre(教師兼干部類)要求：(1)在兩個基類中都包含姓名、年齡、性別、地址、電話數(shù)據(jù)成員。(2)在Teacher類中還包含數(shù)據(jù)成員職稱title，在Cadre類中還包含數(shù)據(jù)成員職務post,在Teacher_Cadre類中還包含數(shù)據(jù)成員工資wage。(3)對兩個基類中的姓名、年齡、性別、地址、電話數(shù)據(jù)成員用相同的名字，在訪問這類數(shù)據(jù)成員時，指定作用域。(4)在類體中聲明成員函數(shù)，在類外定義成員函數(shù)。(5)在派生類Teacher_Cadre的成員函數(shù)$m亞中調用Teacher類中的display函數(shù)，輸出姓名、年齡、性別、地址、電話，然后再用cout語句輸出職務和工資。#include<string>#include<iostream>usingnamespacestd;classTeacher{public:Teacher(stringnam,inta,chars,stringtit,stringad,stringt);voiddisplay();protected:stringname;intage;charsex;stringtitle;stringaddr;stringtel;);Teacher::Teacher(stringnam,inta,chars,stringtit,stringad,stringt):name(nam),age(a),sex(s),title(tit),addr(ad),tel(t){}voidTeacher::display(){cout<<"name:"<<name<<endl;cout<<"age"<<age<<endl;cout<<"sex:"<<sex<<endl;cout<<"title:"<<title<<endl;cout<<"address:"<<addr<<endl;cout<<"tel:"<<tel<<endl;)classCadre{public:Cadre(stringnam,inta,chars,stringp,stringad,stringt);voiddisplay();protected:stringname;intage;charsex;stringpost;stringaddr;stringtel;);Cadre::Cadre(stringnam,inta,chars,stringp,stringad,stringt):name(nam),age(a),sex(s),post(p),addr(ad),tel(t){}voidCadre::display(){cout<<"name:"<<name<<endl;cout<<"age:"<<age<<endl;cout<<"sex:"<<sex<<endl;cout<<"post:"<<post<<endl;cout<<"address:"<<addr<<endl;cout<<"tel:"<<tel<<endl;}classTeacher_Cadre:publicTeacher,publicCadre{public:Teacher_Cadre(stringnam,inta,chars,stringtit,stringp,stringad,stringt,floatw);voidshow();private:floatwage;};Teacher_Cadre::Teacher_Cadre(stringnam,inta,chars,stringt,stringp,stringad,stringtel,floatw):Teacher(nam,a,s,t,ad,tel),Cadre(nam,a,s,p,ad,tel),wage(w){}voidTeacher_Cadre::show(){Teacher::display();cout<<"post:"<<Cadre::post<<endl;cout<<"wages:"<<wage<<endl;intmain(){Teacher_Cadrete_ca("Wang-li",50,'f',"prof.","president","135BeijingRoad,Shanghai","(021)61234567",1534.5);te_ca.show();return0;)D:\C4-4-\6C3).exename：Wancj-liage50sex：ftitle：praf.address：135BeijingHoadJ.Sharghaitel：<021>61234567post"ppesidsntijages：1534.5Processexiteduithreturnvaluc3PressanyKeytocontinue!...微軟拼音半4.按下列要求編寫程序。(1)定義一個分數(shù)類Sc。re。它有3個數(shù)據(jù)成員：Chinese 〃語文課成績English 〃英語課成績Mathematics//數(shù)學課成績2個構造函數(shù)：無參的和帶參數(shù)的3個成員函數(shù)：是否帶參數(shù)根據(jù)需要自定sum() 〃計算三門課總成績print() 〃輸出三門課成績和總成績modify() 〃修改三門課成績(2)定義一個學生類Student。它有3個數(shù)據(jù)成員：Num 〃學號Name 〃姓名MyScore //成績2個構造函數(shù)：無參的和帶參數(shù)的3個成員函數(shù)：是否帶參數(shù)根據(jù)需要自定sum() 〃計算某學生三門課總成績print() 〃輸出某學生學號、姓名和成績modify() 〃修改某學生學號、姓名和成績(3)在主函數(shù)中，先定義一個學生類對象數(shù)組，再通過for循環(huán)給對象數(shù)組賦上實際值，最后輸出對象數(shù)組個元素的值。#include<iostream>#include<string>usingnamespacestd;classscore(public:score()(chinese=0;english=0;mathematics=0;)score(floatch,floaten,floatma):chinese(ch),english(en),mathematics(ma){}floatsum();voidprint();voidmodify();private:floatchinese;floatenglish;floatmathematics;};classstudent(public:student():myscore(0,0,0)(num="000000000";name="無"；)student(stringn,stringna,floatm,floatc,floate):num(n),name(na),myscore(m,c,e){}floatsum();voidprint();voidmodify();private:stringnum;stringname;scoremyscore;);floatscore::sum()(return(chinese+english+mathematics);)voidscore::print()(cout<<"語文"<<chinese<<endl;cout<<"英語"<<english<<endl;cout<<"數(shù)學"<<mathematics<<endl;cout<<"總成績"<<sum()<<endl;cout<<endl<<endl<<endl;)voidscore::modify()(cout<<"請輸入三門成績"<<endl;cin>>chinese;cin>>english;cin>>mathematics;cout<<endl<<endl<<endl;)floatstudent::sum()(return(myscore.sum());)voidstudent::print()(cout<<"學號:"<<num<<endl;cout<<"姓名:"<<name<<endl;myscore.print();)voidstudent::modify()(cout<<"請輸入學號，姓名和成績:"<<endl;cin>>num;cin>>name;myscore.modify();)intmain()(studentst[3];cout<<"請輸入學生信息:"<<endl;for(inti=0;i<3;i++)(st[i].modify();)for(inti=0;i<3;i++)(st[i].print();)return0;

□D:\c++\8(4).exeD:\c++\6(4)情輸入三門成績清輸入三一成績,抖音半口學姓名;小紅|諳文8?！鮀:\c++\8(4).exeD:\c++\6(4)情輸入三門成績清輸入三一成績,抖音半口學姓名;小紅|諳文8。央治于6忸鵲總成績272姓名詞頻看文77請88段學界4椀學

:l,:d6Bk8B靖抖5.編寫一個程序實現(xiàn)小型公司的人員信息管理系統(tǒng)。該公司雇員(employee)包括經理(manager)，技術人員(technician)、銷售員(salesman)和銷售部經理(salesmanager)。要求存儲這些人員的姓名、編號、級別、當月薪水，計算月薪并顯示全部信息。程序要對所有人員有提升級別的功能。為簡單起見，所有人員的初始級別均為1,然后進行升級，經理升為4級，技術人員和銷售部經理升為3級，銷售員仍為1級。月薪計算辦法是：經理拿固定月薪8000元，技術人員按每小時100元領取月薪，銷售員按該當月銷售額4%提成，銷售經理既拿固定月工資也領取銷售提成，固定月工資為5000元，銷售提成為所管轄部門當月銷售額的5%。。#include<iostream>#include<string>usingnamespacestd;classemployee//虛基類(public:employee()(cout<<"職工編號:"；cin>>ID;cout<<"職工姓名:"；cin>>name;salary=0;//月薪)virtualvoidpay()=0;//月薪計算函數(shù)virtualvoidshow()=0;protected:stringname;//姓名intID;//職工編號doublesalary;//月薪)；classtechnician:virtualpublicemployee(public:technician(){perhour=20;}//每小時附加酬金voidpay(){cout<<"請輸入技術工人本月工作時數(shù)：5";cin>>hours;salary=perhour*hours;}voidshow(){cout<<"技術人員"<<name<<"(編號為"<<ID<<")"<<"本月工資:"<<salary<<endl;}prote