新高考數(shù)學一輪復習提升訓練4.3 利用導數(shù)求極值最值（精練）（原卷版）

4.3利用導數(shù)求極值最值（精練）（提升版）題組一題組一無參函數(shù)的極值（點）1.（2022·山東·巨野縣實驗中學）已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，導函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)的圖像如圖所示，則函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)的極小值有（

）A．1個 B．2個 C．3個 D．4個2．（2022·天津?qū)嶒炛袑W）下列函數(shù)中存在極值點的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·福建省連城縣第一中學）函數(shù)SKIPIF1<0的極值點的個數(shù)是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．無數(shù)個4．（2022·全國·哈師大附中）已知SKIPIF1<0是函數(shù)SKIPIF1<0的一個極值點，則SKIPIF1<0的值是（

）A．1 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·遼寧·鞍山市華育高級中學）已知函數(shù)SKIPIF1<0的導函數(shù)SKIPIF1<0的圖像如圖所示，則下列判斷正確的是（

）A．在區(qū)間SKIPIF1<0上，SKIPIF1<0是增函數(shù) B．在區(qū)間SKIPIF1<0上，SKIPIF1<0是減函數(shù)C．SKIPIF1<0為SKIPIF1<0的極小值點 D．2為SKIPIF1<0的極大值點6．（2022·湖北·南漳縣第一中學）函數(shù)SKIPIF1<0的極大值為（

）A．-2 B．2 C．SKIPIF1<0 D．不存在7（2022·天津河北）設SKIPIF1<0是函數(shù)f（x）的導函數(shù)，若函數(shù)f（x）的圖象如圖所示，則下列說法錯誤的是（

）A．當SKIPIF1<0時，SKIPIF1<0 B．當SKIPIF1<0或SKIPIF1<0時，SKIPIF1<0C．當SKIPIF1<0或SKIPIF1<0時，SKIPIF1<0 D．函數(shù)f（x）在SKIPIF1<0處取得極小值題組二題組二已知極值（點）求參數(shù)1．（2022·山東濰坊）已知函數(shù)SKIPIF1<0的圖像與直線SKIPIF1<0有3個不同的交點，則實數(shù)m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·重慶·萬州純陽中學校）若函數(shù)SKIPIF1<0在SKIPIF1<0上存在唯一極值點，則實數(shù)a的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·四川省成都市新都一中）已知SKIPIF1<0沒有極值，則實數(shù)SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·湖北）函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)存在極值點，則（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<05．（2022·河南）已知函數(shù)SKIPIF1<0有兩個極值點，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．（2022·安徽·蒙城第一中學）已知SKIPIF1<0為常數(shù)，函數(shù)SKIPIF1<0有兩個極值點，其中一個極值點SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07（2022·陜西·長安一中）已知在SKIPIF1<0中，三個內(nèi)角SKIPIF1<0，SKIPIF1<0，SKIPIF1<0的對邊分別為SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，若函數(shù)SKIPIF1<0無極值點，則角B的最大值是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2022·四川·綿陽中學實驗學校）若函數(shù)SKIPIF1<0在SKIPIF1<0處有極值10，則SKIPIF1<0（

）A．6 B．SKIPIF1<0 C．SKIPIF1<0或15 D．6或SKIPIF1<09．（2022·青?！ご笸ɑ刈逋磷遄灾慰h教學研究室二模（理））設函數(shù)SKIPIF1<0，則下列不是函數(shù)SKIPIF1<0極大值點的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．（2022·全國·高三專題練習）已知t和SKIPIF1<0是函數(shù)SKIPIF1<0的零點，且SKIPIF1<0也是函數(shù)SKIPIF1<0的極小值點，則SKIPIF1<0的極大值為（

）A．1 B．4 C．SKIPIF1<0 D．SKIPIF1<011．（2022·廣西·高三階段練習（理））已知函數(shù)SKIPIF1<0在其定義域的一個子區(qū)間SKIPIF1<0上有極值，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<012．（2022·安徽·合肥市第八中學）已知函數(shù)SKIPIF1<0在SKIPIF1<0處取極小值，且SKIPIF1<0的極大值為4，則SKIPIF1<0（

）A．-1 B．2 C．-3 D．413．（2022·河北承德）已知SKIPIF1<0是函數(shù)SKIPIF1<0的極值點，則SKIPIF1<0的極大值為_____．14．（2022·北京·101中學）設SKIPIF1<0是函數(shù)SKIPIF1<0的兩個極值點，若SKIPIF1<0，則實數(shù)a的取值范圍是______．15．（2022·浙江寧波）已知函數(shù)SKIPIF1<0，若SKIPIF1<0是函數(shù)SKIPIF1<0的唯一極值點，則實數(shù)k的取值范圍是_______．題組三題組三無參函數(shù)的最值1．（2022·海南華僑中學）已知函數(shù)SKIPIF1<0，下列說法正確的是（

）A．函數(shù)在SKIPIF1<0上遞增 B．函數(shù)無極小值C．函數(shù)只有一個極大值SKIPIF1<0 D．函數(shù)在SKIPIF1<0上最大值為32．（2022·湖北·模擬預測）SKIPIF1<0，SKIPIF1<0的最小值為___________．3．（2022·江蘇·南京市江寧高級中學模擬預測）若函數(shù)SKIPIF1<0在SKIPIF1<0內(nèi)有且只有一個零點，則SKIPIF1<0在SKIPIF1<0上的最大值與最小值的和為_______．4．（2022·全國·高三專題練習）若實數(shù)a、b、c、d滿足SKIPIF1<0，則SKIPIF1<0的最小值為______．5．（2022·四川省成都市新都一中）函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最大值為______．6．（2022·天津?qū)嶒炛袑W）函數(shù)SKIPIF1<0在區(qū)間SKIPIF1<0上的最小值為__________．7．（2022·四川·威遠中學校）對任意SKIPIF1<0，存在SKIPIF1<0，使得SKIPIF1<0，則SKIPIF1<0的最小值為_____.8．（2022·河南開封）已知SKIPIF1<0是奇函數(shù)，當SKIPIF1<0時，SKIPIF1<0，則當SKIPIF1<0時，SKIPIF1<0的最小值為________．題組四題組四已知最值求參數(shù)1．（2022·江西萍鄉(xiāng)·三模）已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0，對任意SKIPIF1<0，當SKIPIF1<0時，都有SKIPIF1<0，若存在SKIPIF1<0，使不等式SKIPIF1<0成立，則實數(shù)SKIPIF1<0的最大值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·遼寧·鞍山市華育高級中學）已知SKIPIF1<0，SKIPIF1<0，若SKIPIF1<0，則當SKIPIF1<0取得最小值時，SKIPIF1<0所在區(qū)間是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·河南·模擬預測（理））已知函數(shù)SKIPIF1<0至多有2個不同的零點，則實數(shù)a的最大值為（

）．A．0 B．1 C．2 D．e4．（2022·遼寧·遼師大附中）設函數(shù)SKIPIF1<0(n為正整數(shù))，則SKIPIF1<0在[0，1]上的最大值為（

）A．0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·河南安陽）已知函數(shù)SKIPIF1<0，若SKIPIF1<0時，SKIPIF1<0在SKIPIF1<0處取得最大值，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·江西）設兩個實數(shù)a，b滿足：SKIPIF1<0，則正整數(shù)n的最大值為（

）．（參考數(shù)據(jù)：SKIPIF1<0）A．7 B．8 C．9 D．10題組五題組五最值極值的綜合運用1．（2022·浙江·寧波市李惠利中學）（多選）對于函數(shù)SKIPIF1<0，下列選項正確的是（

）A．函數(shù)SKIPIF1<0極小值為SKIPIF1<0，極大值為SKIPIF1<0B．函數(shù)SKIPIF1<0單調(diào)遞減區(qū)間為SKIPIF1<0，單調(diào)遞增區(qū)為SKIPIF1<0C．函數(shù)SKIPIF1<0最小值為為SKIPIF1<0，最大值SKIPIF1<0D．函數(shù)SKIPIF1<0存在兩個零點1和SKIPIF1<02．（2022·福建泉州）（多選）函數(shù)SKIPIF1<0在SKIPIF1<0處取得極大值，則a的值可以是（

）A．-1 B．0 C．3 D．43．（2022·黑龍江·哈爾濱市第六中學校）（多選）已知函數(shù)SKIPIF1<0，下列命題正確的是（

）A．若SKIPIF1<0是函數(shù)SKIPIF1<0的極值點，則SKIPIF1<0B．若SKIPIF1<0是函數(shù)SKIPIF1<0的極值點，則SKIPIF1<0在SKIPIF1<0上的最小值為SKIPIF1<0C．若SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，則SKIPIF1<0D．若SKIPIF1<0在SKIPIF1<0上恒成立，則SKIPIF1<04．（2022·河南·三模）已知函數(shù)SKIPIF1<0．(1)討論SKIPIF1<0極值點的個數(shù)；(2)證明：SKIPIF1<0．5．（2022·湖南·臨澧縣第一中學二模）已知函數(shù)SKIPIF1<0.(1)當SKIPIF1<0時，若SKIPIF1<0在SKIPIF1<0上存在最大值，求m的取值范圍；(2)討論SKIPIF1<0極值點的個數(shù).6．（2022·江西·上饒市第一中學模擬預測）已知函數(shù)SKIPIF1<0．(1)當SKIPIF1<0時，求函數(shù)SKIPIF1<0的極值；(2)若函數(shù)SKIPIF1<0在SKIPIF1<0無零點，求實數(shù)a的取值范圍．7．（2022·北京市十一學校高三階段練習）已知函數(shù)SKIPIF1<0(1)當SKIPIF1<0