新高考數(shù)學(xué)一輪復(fù)習(xí)第2章 第01講 函數(shù)的概念及其表示 精講+精練（學(xué)生版）

第01講函數(shù)的概念及其表示(精講+精練）目錄第一部分：知識點精準(zhǔn)記憶第二部分：課前自我評估測試第三部分：典型例題剖析高頻考點一：函數(shù)的概念高頻考點二：函數(shù)定義域①具體函數(shù)的定義域；②抽象函數(shù)定義域高頻考點三：函數(shù)解析式①湊配法求解析式（注意定義域）②換元法求解析式（換元必?fù)Q范圍）③待定系數(shù)法；④方程組消去法高頻考點四：分段函數(shù)①分段函數(shù)求值②已知分段函數(shù)的值求參數(shù)③分段函數(shù)求值域（最值）高頻考點五：函數(shù)的值域①二次函數(shù)求值域；②分式型函數(shù)求值域③根式型函數(shù)求值域；④根據(jù)值域求參數(shù)⑤根據(jù)函數(shù)值域求定義域第四部分：高考真題感悟第五部分：第01講函數(shù)的概念及其表示（精練）第一部分：知識點精準(zhǔn)記憶第一部分：知識點精準(zhǔn)記憶1、函數(shù)的概念設(shè)SKIPIF1<0、SKIPIF1<0是兩個非空數(shù)集，如果按照某種確定的對應(yīng)關(guān)系SKIPIF1<0，使對于集合SKIPIF1<0中的任意一個數(shù)SKIPIF1<0，在集合SKIPIF1<0中都有唯一確定的數(shù)SKIPIF1<0和它對應(yīng)，那么稱SKIPIF1<0為從集合SKIPIF1<0到集合SKIPIF1<0的一個函數(shù)，記作SKIPIF1<0，SKIPIF1<0.其中：SKIPIF1<0叫做自變量，SKIPIF1<0的取值范圍SKIPIF1<0叫做函數(shù)的定義域與SKIPIF1<0的值相對應(yīng)的SKIPIF1<0值叫做函數(shù)值，函數(shù)值的集合SKIPIF1<0叫做函數(shù)的值域．2、同一（相等）函數(shù)函數(shù)的三要素：定義域、值域和對應(yīng)關(guān)系．同一（相等）函數(shù)：如果兩個函數(shù)的定義和對應(yīng)關(guān)系完全一致，則這兩個函數(shù)相等，這是判斷兩函數(shù)相等的依據(jù)．3、函數(shù)的表示函數(shù)的三種表示法解析法（最常用）圖象法（解題助手）列表法就是把變量SKIPIF1<0，SKIPIF1<0之間的關(guān)系用一個關(guān)系式SKIPIF1<0來表示，通過關(guān)系式可以由SKIPIF1<0的值求出SKIPIF1<0的值.就是把SKIPIF1<0，SKIPIF1<0之間的關(guān)系繪制成圖象，圖象上每個點的坐標(biāo)就是相應(yīng)的變量SKIPIF1<0，SKIPIF1<0的值.就是將變量SKIPIF1<0，SKIPIF1<0的取值列成表格，由表格直接反映出兩者的關(guān)系.4、分段函數(shù)若函數(shù)在其定義域內(nèi)，對于定義域內(nèi)的不同取值區(qū)間，有著不同的對應(yīng)關(guān)系，這樣的函數(shù)通常叫做分段函數(shù)．5、高頻考點結(jié)論5.1函數(shù)的定義域是使函數(shù)解析式有意義的自變量的取值范圍，常見基本初等函數(shù)定義域的要求為：(1)分式型函數(shù)：分母不等于零.(2)偶次根型函數(shù)：被開方數(shù)大于或等于0.(3)一次函數(shù)、二次函數(shù)的定義域均為SKIPIF1<0(4)SKIPIF1<0的定義域是SKIPIF1<0.(5)SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)，SKIPIF1<0，SKIPIF1<0的定義域均為SKIPIF1<0.(6)SKIPIF1<0(SKIPIF1<0且SKIPIF1<0)的定義域為SKIPIF1<0.(7)SKIPIF1<0的定義域為SKIPIF1<0.5.2函數(shù)求值域（1）分離常數(shù)法：將形如SKIPIF1<0(SKIPIF1<0)的函數(shù)分離常數(shù)，變形過程為：SKIPIF1<0，再結(jié)合SKIPIF1<0的取值范圍確定SKIPIF1<0的取值范圍，從而確定函數(shù)的值域.（2）換元法：如：函數(shù)SKIPIF1<0，可以令SKIPIF1<0，得到SKIPIF1<0，函數(shù)SKIPIF1<0SKIPIF1<0可以化為SKIPIF1<0(SKIPIF1<0)，接下來求解關(guān)于t的二次函數(shù)的值域問題，求解過程中要注意t的取值范圍的限制．（3）基本不等式法和對勾函數(shù)（4）單調(diào)性法（5）求導(dǎo)法第二部分：課前自我評估測試第二部分：課前自我評估測試一、判斷題1．（2021·江西·貴溪市實驗中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0和SKIPIF1<0是相同的函數(shù)()2．（2021·江西·貴溪市實驗中學(xué)高二階段練習(xí)）函數(shù)SKIPIF1<0的定義域是SKIPIF1<0

()3．（2021·江西·貴溪市實驗中學(xué)高三階段練習(xí)）已知SKIPIF1<0則SKIPIF1<0.()4．（2021·江西·貴溪市實驗中學(xué)高三階段練習(xí)）函數(shù)SKIPIF1<0的定義域為SKIPIF1<0.()二、單選題1．（2022·寧夏·青銅峽市高級中學(xué)高二學(xué)業(yè)考試）如圖，可以表示函數(shù)SKIPIF1<0的圖象的是（

）A． B．C． D．2．（2022·全國·高一階段練習(xí)）函數(shù)SKIPIF1<0的定義域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·黑龍江·鐵人中學(xué)高一開學(xué)考試）以下各組函數(shù)中，表示同一函數(shù)的是（

）A．SKIPIF1<0，SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0C．SKIPIF1<0，SKIPIF1<0 D．SKIPIF1<0，SKIPIF1<04．（2022·安徽·北大培文蚌埠實驗學(xué)校高三開學(xué)考試（文））設(shè)函數(shù)SKIPIF1<0，若SKIPIF1<0（

）A．1 B．2 C．3 D．4第三部分：典型例題剖析第三部分：典型例題剖析高頻考點一：函數(shù)的概念1．（2022·全國·高三專題練習(xí)）函數(shù)y=f(x)的圖象與直線SKIPIF1<0的交點個數(shù)（

）A．至少1個 B．至多1個 C．僅有1個 D．有0個、1個或多個2．（2022·湖南·高一課時練習(xí)）設(shè)集合SKIPIF1<0，SKIPIF1<0，那么下列四個圖形中，能表示集合SKIPIF1<0到集合SKIPIF1<0的函數(shù)關(guān)系的有（

）A．①②③④ B．①②③ C．②③ D．②3．（2022·江西贛州·高一期末）如圖所示某加油站地下圓柱體儲油罐示意圖，已知儲油罐長度為SKIPIF1<0，截面半徑為SKIPIF1<0（SKIPIF1<0，SKIPIF1<0為常量），油面高度為SKIPIF1<0，油面寬度為SKIPIF1<0，油量為SKIPIF1<0（SKIPIF1<0，SKIPIF1<0，SKIPIF1<0為變量），則下列說法錯誤的（

）A．SKIPIF1<0是SKIPIF1<0的函數(shù) B．SKIPIF1<0是SKIPIF1<0的函數(shù)C．SKIPIF1<0是SKIPIF1<0的函數(shù) D．SKIPIF1<0是SKIPIF1<0的函數(shù)4．（2022·江蘇泰州·高一期末）若函數(shù)SKIPIF1<0和SKIPIF1<0．分別由下表給出：SKIPIF1<0SKIPIF1<001SKIPIF1<010SKIPIF1<0SKIPIF1<0123SKIPIF1<001SKIPIF1<0則不等式SKIPIF1<0的解集為（

）．A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0高頻考點二：函數(shù)定義域①具體函數(shù)的定義域1．（2022·廣東汕尾·高一期末）函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·湖北省廣水市實驗高級中學(xué)高一階段練習(xí)）函數(shù)SKIPIF1<0的定義域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·廣東潮州·高一期末）函數(shù)SKIPIF1<0的定義域為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0②抽象函數(shù)定義域1．（2022·廣東·化州市第三中學(xué)高一階段練習(xí)）已知函數(shù)y＝f（x＋1）定義域是[－2，3]，則y＝f（x－2）的定義域是（）A．[1，6] B．[－1，4] C．[－3，2] D．[－2，3]2．（2022·重慶巴蜀中學(xué)高一期末）已知函數(shù)SKIPIF1<0的定義域為[1，10]，則SKIPIF1<0的定義域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高一）已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，則函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點三：函數(shù)解析式①湊配法求解析式（注意定義域）1．（2022·全國·高一）已知函數(shù)SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國·高三專題練習(xí)）已知SKIPIF1<0=SKIPIF1<0，則SKIPIF1<0的表達(dá)式是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0②換元法求解析式（換元必?fù)Q范圍）1．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，則SKIPIF1<0的解析式為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·浙江·高三專題練習(xí)）已知SKIPIF1<0，則（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）若SKIPIF1<0，那么SKIPIF1<0等于（

）A．8 B．3 C．1 D．30③待定系數(shù)法1．（2022·全國·高三專題練習(xí)）已知SKIPIF1<0是一次函數(shù)，且SKIPIF1<0，則SKIPIF1<0的解析式為A．SKIPIF1<0或SKIPIF1<0 B．SKIPIF1<0或SKIPIF1<0C．SKIPIF1<0或SKIPIF1<0 D．SKIPIF1<0或SKIPIF1<02．（2022·湖南·高一課時練習(xí)）已知二次函數(shù)f（x）的圖象經(jīng)過點（-3，2），頂點是（-2，3），則函數(shù)f（x）的解析式為___________.④方程組消去法1．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0（

）A．0 B．2 C．3 D．SKIPIF1<02．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）已知SKIPIF1<0滿足SKIPIF1<0，則SKIPIF1<0等于（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0高頻考點四：分段函數(shù)①分段函數(shù)求值1．（2022·甘肅張掖·高一期末）已知SKIPIF1<0，則SKIPIF1<0為（

）A．SKIPIF1<0 B．2 C．3 D．SKIPIF1<0或32．（2022·安徽阜陽·高一期中）函數(shù)SKIPIF1<0則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·河南·高一階段練習(xí)）若SKIPIF1<0是奇函數(shù)，則SKIPIF1<0（

）A．2 B．SKIPIF1<0 C．3 D．54．（2022·黑龍江·牡丹江市第三高級中學(xué)高一開學(xué)考試）設(shè)SKIPIF1<0，則SKIPIF1<0的值為（

）A．0 B．1 C．2 D．3②已知分段函數(shù)的值求參數(shù)1．（2022·遼寧朝陽·高一開學(xué)考試）函數(shù)SKIPIF1<0，若SKIPIF1<0，則實數(shù)a的值為（

）A．±1 B．-2或±1 C．-1 D．-2或-12．（2022·新疆烏魯木齊·二模（理））已知函數(shù)SKIPIF1<0，若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．2或SKIPIF1<0 C．SKIPIF1<0或2 D．SKIPIF1<0或SKIPIF1<03．（2022·江西南昌·一模（理））已知SKIPIF1<0若SKIPIF1<0，則SKIPIF1<0（

）A．2 B．SKIPIF1<0 C．1 D．04．（2022·河南洛陽·二模（文））已知函數(shù)SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0（

）A．26 B．16 C．－16 D．－26③分段函數(shù)求值域（最值）1．（2022·全國·高三專題練習(xí)）SKIPIF1<0，若SKIPIF1<0是SKIPIF1<0的最小值，則SKIPIF1<0的取值范圍為（

）.A．[SKIPIF1<01，2] B．[SKIPIF1<01，0] C．[1，2] D．SKIPIF1<02．（2022·江西·景德鎮(zhèn)一中高一期末）已知函數(shù)SKIPIF1<0的值域為SKIPIF1<0，那么實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的值域為R，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·北京平谷·高一期末）已知函數(shù)SKIPIF1<0(1)求SKIPIF1<0，SKIPIF1<0的值；(2)作出函數(shù)的簡圖；(3)由簡圖指出函數(shù)的值域；5．（2022·湖南·高一課時練習(xí)）已知函數(shù)f(x)＝SKIPIF1<0求f(x)的最大值、最小值．高頻考點五：函數(shù)的值域①二次函數(shù)求值域1．（2022·黑龍江·哈爾濱市第三十二中學(xué)校高三期末（理））函數(shù)y＝x2－2x＋2在區(qū)間[－2，3]上的最大值、最小值分別是（

）A．10，5 B．10，1C．5，1 D．以上都不對2．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，值域為SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0的定義域和值域都是SKIPIF1<0，則SKIPIF1<0（

）A．1 B．3 C．SKIPIF1<0 D．1或3②分式型函數(shù)求值域1．（2022·全國·江西科技學(xué)院附屬中學(xué)模擬預(yù)測（文））函數(shù)SKIPIF1<0的值域（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域為A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域為________________．③根式型函數(shù)求值域1．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國·高二）函數(shù)SKIPIF1<0的值域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0④根據(jù)值域求參數(shù)1．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的值域為SKIPIF1<0，求a的取值范圍為A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<02．（2022·全國·高三專題練習(xí)）若函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，值域為SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0的值域為SKIPIF1<0，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0在SKIPIF1<0上的值域為SKIPIF1<0，則實數(shù)m的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<05．（2022·全國·高三專題練習(xí)）已知二次函數(shù)SKIPIF1<0的值域為SKIPIF1<0，則SKIPIF1<0的最小值為（

）A．3 B．6 C．9 D．126．（2022·全國·高三專題練習(xí)）已知函數(shù)SKIPIF1<0，SKIPIF1<0，若對任意SKIPIF1<0，總存在SKIPIF1<0，使得SKIPIF1<0，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0⑤根據(jù)函數(shù)值域求定義域1．（2021·山西·懷仁市第一中學(xué)校高一階段練習(xí)）已知函數(shù)f（x）=x2-2x-3的定義域為[a，b]，值域為[-4，5]，則實數(shù)對（a，b）的不可能值為（

）A．（-2，4） B．（-2，1） C．（1，4） D．（-1，1）2．（2021·江蘇·高一專題練習(xí)）若一系列函數(shù)的解析式相同，值域相同，但其定義域不同，則稱這些函數(shù)為“同族函數(shù)”.那么函數(shù)解析式為f(x)＝x2，值域為{1,4}的“同族函數(shù)”共有（

）A．7個 B．8個 C．9個 D．無數(shù)個3．（2021·江西省泰和中學(xué)高二開學(xué)考試（理））定義區(qū)間SKIPIF1<0的長度為SKIPIF1<0，已知函數(shù)SKIPIF1<0的定義域為SKIPIF1<0，值域為SKIPIF1<0，則區(qū)間SKIPIF1<0的長度的最大值與最小值的差為（

）A．1 B．2 C．3 D．SKIPIF1<04．（2021·全國·高一課時練習(xí)）已知函數(shù)SKIPIF1<0的值域為SKIPIF1<0，則函數(shù)SKIPIF1<0的定義域為______.第四部分：高考真題感悟第四部分：高考真題感悟1．（2021·山東·高考真題）函數(shù)SKIPIF1<0的定義域為（

）A．SKIPIF1<0且SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0且SKIPIF1<0 D．SKIPIF1<02．（2020·山東·高考真題）函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．（2021·浙江·高考真題）已知SKIPIF1<0，函數(shù)SKIPIF1<0若SKIPIF1<0，則SKIPIF1<0___________.4．（2021·湖南·高考真題）已知函數(shù)SKIPIF1<0（1）畫出函數(shù)SKIPIF1<0的圖象；（2）若SKIPIF1<0，求SKIPIF1<0的取值范圍.5．（2020·山東·高考真題）已知函數(shù)SKIPIF1<0.（1）求SKIPIF1<0的值；（2）求SKIPIF1<0，求實數(shù)SKIPIF1<0的取值范圍.第五部分：第五部分：第01講函數(shù)的概念及其表示（精練）一、單選題1．（2022·全國·高一）已知SKIPIF1<0，SKIPIF1<0，下列圖形能表示以A為定義域，B為值域的函數(shù)的是（

）A． B．C． D．2．（2022·內(nèi)蒙古·赤峰紅旗中學(xué)松山分校高一期末（文））下列各組函數(shù)表示同一函數(shù)的是（

）A．SKIPIF1<0，SKIPIF1<0 B．SKIPIF1<0，SKIPIF1<0C．SKIPIF1<0，SKIPIF1<0 D．SKIPIF1<0，SKIPIF1<03．（2022·吉林·農(nóng)安縣教師進(jìn)修學(xué)校高一期末）函數(shù)SKIPIF1<0的定義域是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．（2022·全國·高三專題練習(xí)（理））若SKIPIF1<0，則SKIPIF1<0的解析式為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．（2022·四川成都·二模（文））已知函數(shù)SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<06．（2022·遼寧朝陽·高一開學(xué)考試）若函數(shù)SKIPIF1<0在SKIPIF1<0上單調(diào)遞減，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．（2022·全國·高一期末）某校要召開學(xué)生代表大會，規(guī)定各班每SKIPIF1<0人推選一名代表，當(dāng)班人數(shù)除以SKIPIF1<0的余數(shù)大于SKIPIF1<0時，再增選一名代表，則各班推選代表人數(shù)SKIPIF1<0與該班人數(shù)SKIPIF1<0之間的函數(shù)關(guān)系用取整函數(shù)SKIPIF1<0（SKIPIF1<0表示不大于SKIPIF1<0的最大整數(shù)，如SKIPIF1<0，SKIPIF1<0）可表示為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<08．（2022·內(nèi)蒙古·赤峰二中高一期末（理））設(shè)集合SKIPIF1<0，函數(shù)SKIPIF1<0，若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0