7.微積分基本定理練習(xí)題(最新整理)

1、7、微積分基本定理一、選擇題11. (x22x)dx 等 于()0124a.b.c1d.3332. 2(sinxcosx)dx 等于()a3b2c1d0 3自由落體的速率 vgt，則落體從 t0 到 tt0 所走的路程為()1a. gt203b. gt201c. gt20231d. gt0264. 曲線 ycosx (0 x 2 )與坐標(biāo)軸所圍圖形的面積是()5a4b2c.d3 25. 如圖，陰影部分的面積是()333235a2b2c.d.3336. |x24|dx()021222325a.b.c.d.3333417dx 等于()x2a2ln2b2ln2cln2dln2a118若 (2xx)d

2、x3ln2，則 a 等于()a6b4c3d29(2010ft東理，7)由曲線 yx2，yx3 圍成的封閉圖形面積為()1117a.b.c.d.124312210. 設(shè) f(x)error!，則 f(x)dx 等于()0345a.b.c.d不存在456212解析f(x)dxx2dx(2x)dx，001二、填空題11. 從如圖所示的長方形區(qū)域內(nèi)任取一個點(diǎn) m(x，y)，則點(diǎn) m 取自陰影部分的概率為1t12. 一物體沿直線以 vm/s 的速度運(yùn)動， 該物體運(yùn)動開始后 10s 內(nèi)所經(jīng)過的路程是 513. 求曲線 ysinx 與直線 x，x ，y0 所圍圖形的面積為2422214. 若 ax2dx，b

3、x3dx，csinxdx，則 a、b、c 大小關(guān)系是 000三、解答題15. 求下列定積分：2x (3x24x3)dx；sin2 dx.2017求直線 y2x3 與拋物線 yx2 所圍成的圖形的面積118(1)已知 f(a) (2ax2a2x)dx，求 f(a)的最大值；01(2)已知 f(x)ax2bxc(a0)，且 f(1)2，f(0)0， f(x)dx2，求 a，b，c 的0值1232dbcdccddac11.12.(11 1)13.4 解析所求面積為33222212(1 2 )4 2 .14.答案 cab三、解答題2x15 (3x24x3)dx；sin2 dx.20222解析(3x24

4、x3)dx3x2dx4x3dxx3error!x4error!24.000112 ( 0) (10).222417求直線 y2x3 與拋物線 yx2 所圍成的圖形的面積解析由方程組error! 得 x11，x23，則所求圖形的面積為132(x23x)error! x3error!.33211a2x)dx21322121144212218.(1)因 為 ( ax3 a2x2) 2ax2 a2x， 所 以 (2ax2( ax3 a2x2)error! a a2.所以 f(a) a a20 (a2 a) (a)2 .所以當(dāng) a323222322399239時，f(a)有最大值.3911(2)f(1)

5、2，f(0)0，error!而 f(x)dx(ax2bxc)dx，0011111取 f(x) ax3 bx2cx，則 f(x)ax2bxc.f(x)dxf(1)f(0) a bc323202解得 a6，b0，c4.“”“”at the end, xiao bian gives you a passage. minand once said, people who learn to learn are very happy people. in every wonderful life, learning is an eternal theme. as a professional cleric

6、al and teaching position, i understand the importance of continuous learning, life is diligent, nothing can be gained, only continuous learning can achieve better self. only by constantly learning and mastering the latest relevant knowledge, can employees from all walks of life keep up with the pace of enterprise development and innovate to meet the needs of the market. this document is also edited by my studio