基于51單片機的推箱子游戲

1、推箱子 (以前做的，現(xiàn)在加以整理傳上來給初學(xué)者做個參考，也整點分用用。)演示：/programs/view/tbeezcgrzwy/上電顯示游戲的名字及我的qq開始游戲1. 紅外：不同的遙控器用的芯片不同，發(fā)射出來的數(shù)據(jù)長度都不同。12864：不同的12864的指令可能是不同的，需要根據(jù)具體的模塊來編寫代碼。具體怎么用，去看數(shù)據(jù)手冊吧。我用的是漢升的 12864-15c。2. 游戲?qū)崿F(xiàn)：a、我把屏幕分成了8*8的區(qū)域，箱子，目的地，人墻，都是8*8的。所以這個屏幕是16*8的了b、我的這塊12864，在基本指令集是寫入文字，再在擴展指令集時繪制圖形，文字會

2、反白顯示，我的菜單模塊就是根據(jù)這個特點來實現(xiàn)的。注釋中也叫文本模式，圖形模式。c、數(shù)據(jù)表示：a、在地圖中用0、1、2、3、4分別表示 空地、墻、人、目的地、箱子，他們的點陣數(shù)據(jù)保存在全局變量unsigned char code yuansu_code58中。b、在程序rom中，各關(guān)的地圖保存在全局變量unsigned char code ditu_ju_code3128（我只做了3關(guān)）中。如:第一關(guān)的地圖數(shù)據(jù)： 第一關(guān)游戲畫面：0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,

3、0,1,0,0,0,0,0,0,0,0,0,1,1,4,4,4,0,1,0,0,0,0,0,0,0,1,1,1,3,3,1,0,0,1,0,0,0,0,0,0,0,1,0,4,3,3,0,0,1,1,0,0,0,0,0,0,0,1,0,0,0,0,0,2,1,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,0,0c、一個重要的全局變量unsigned char idata ditu816，游戲開始時，rom中的地圖數(shù)據(jù)會被加載到這個數(shù)組中，之后，所有的游戲操作都會圍繞著這個數(shù)組展開。根據(jù)用戶的操作去修改這個數(shù)組，然后根據(jù)這個數(shù)組刷新屏幕。如，第一關(guān)開始時，將人左移一

4、格，idata ditu816=0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0，0,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0，0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0，0,0,0,0,0,1,1,4,4,4,0,1,0,0,0,0，0,0,0,1,1,1,3,3,1,0,0,1,0,0,0,0，0,0,0,1,0,4,3,3,0,0,1,1,0,0,0,0，0,0,0,1,0,0,0,0,2,0,1,0,0,0,0,0，0,0,0,1,1,1,1,1,1,1,1,0,0,0,0,0電路：推箱子地圖編輯器： (關(guān)閉本word文件再打開，下面

5、的flash可以重新開始。沒寫好，慚愧)(0空地 1墻 2人 3目的地 4箱子)源代碼：#include/*定義引腳連接*/ #define lcd_shuju p0 /12864的引腳#define lcd_en p3_4#define lcd_rs p3_5#define lcd_rw p3_6#define lcd_psb p3_7#define fm p2_3/蜂鳴器引腳/*定義按鍵常數(shù)*/ #definekey_shang 48#definekey_xia 176#definekey_zuo 232#definekey_you 104#definekey_quxiao 40#defi

6、nekey_queding 24#definekey_caidan 136/*紅外用的變量*/char ir_timer=0;/脈沖周期unsigned char ir_datah=0; /存儲8位數(shù)據(jù)碼unsigned char ir_datal=0; /存儲8位數(shù)據(jù)反碼bit ir_ok=0;/接收完bit starflag=0;/等于1時,表示幀已經(jīng)開始/*游戲時用的變量*/unsigned char biaoti0=;unsigned char biaoti1=推箱子;unsigned char biaoti2=;unsigned char shengming=qq:857448526

7、;unsigned int shengyi =0; /當不為0時,就用t1定時器播放聲音unsigned char ren_x,ren_y;/人的座標unsigned char jushu=0;/用來保存玩的是第幾局游戲bit wancheng =0;/是否全部完成char chexiao22=0,0,0,0;/記錄移動箱子時,人的x,y 及運動方向dx,dy 最大撤銷1步unsigned char idata ditu816;/當作內(nèi)存來使用,用來保存游戲的地圖,整個游戲都圍繞著這個數(shù)組展開unsigned char caidan_biaoqian0=打開：; /菜單上的文字unsigned

8、 char caidan_biaoqian1=;unsigned char caidan_biaoqian2=;unsigned char caidan_biaoqian3=;/*游戲元素的點陣數(shù)據(jù)*/unsigned char code yuansu_code58=0,0,0,0,0,0,0,0,/空地 0 255,255,255,255,255,255,255,255,/墻的點陣數(shù)據(jù) 1 0x00,0x18,0x5a,0x7e,0x18,0x24,0x42,0x00,/人的點陣數(shù)據(jù) 20x00,0x42,0x24,0x18,0x18,0x24,0x42,0x00,/目的地的點陣數(shù)據(jù) 30x

9、00,0x7e,0x56,0x6a,0x56,0x6a,0x7e,0x00/箱子的點陣數(shù)據(jù) 4;unsigned char code ditu_ju_code3128=0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,1,0,0,0,0,1,0,0,0,0,0,0,0,0,0,1,1,4,4,4,0,1,0,0,0,0,0,0,0,1,1,1,3,3,1,0,0,1,0,0,0,0,0,0,0,1,0,4,3,3,0,0,1,1,0,0,0,0,0,0,0,1,0,0,0,0,0,2,1,0,

10、0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,0,0,0,0,0,/第 1 局的地圖數(shù)據(jù)0,0,0,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,1,0,2,1,0,0,1,1,0,0,0,0,0,0,0,0,1,0,0,1,0,0,0,1,0,0,0,0,0,0,0,0,1,0,4,0,4,0,4,1,0,0,0,0,0,0,0,0,1,0,0,1,1,4,0,1,0,0,0,0,0,0,0,0,1,1,0,1,0,4,0,1,1,1,0,0,0,0,0,0,0,1,0,0,3,3,3,3,3,1,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1

11、,0,0,0,/第 2 局的地圖數(shù)據(jù)0,0,0,0,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,1,3,3,3,0,1,0,0,0,0,0,0,0,0,0,0,1,3,3,3,3,1,1,1,1,0,0,0,0,0,1,1,1,0,4,1,1,1,0,0,1,0,0,0,0,0,1,0,4,4,0,0,4,0,4,0,1,0,0,0,0,0,1,0,0,0,0,4,0,4,0,0,1,0,0,0,0,0,1,0,0,0,1,1,1,0,0,2,1,0,0,0,0,0,1,1,1,1,1,0,1,1,1,1,1,0,0,0/第 3 局的地圖數(shù)據(jù);/* 延時函數(shù)*/void y

12、anshi(int us) us*=3; for(us;us0;us-);/*與紅外有關(guān)的函數(shù)*/void t0_func() interrupt 1/定時器t0 中斷服務(wù)函數(shù)，有兩個作用ir_timer+;/1、播放聲音。shengyi 是一個全局變量,if(shengyi1)/ 當它等于0時,蜂鳴器連接的引腳輸出低電平,fm=0;/ 當它不等于0時,輸出高電平,使蜂鳴器發(fā)聲shengyi-;/所以呢, shengyi值越大,蜂鳴器響的時間越長if(shengyi=1)/2、測量紅外脈沖的長度，用ir_timer保存。ir_timer=7時，認為該脈沖是1。 fm=1; shengyi=0;

13、void int0_func() interrupt 0 /外部中斷int0中斷服務(wù)函數(shù),用來 解析紅外 /這個只能用來解析幀長度為32個下降沿的紅外幀,/并且不處理長按一個鍵的情況,/在這里,開發(fā)板的硬件上面將紅外接收頭的out腳已經(jīng)經(jīng)過反向后再接單片機/所以剛好這里數(shù)的是下降沿static char i=0;/i用來保存這是第幾個脈沖 if(starflag)/starflag=0，認為這個脈沖是前導(dǎo)碼，下一個脈沖開始依次是/地址碼，地址反碼，數(shù)據(jù)碼，數(shù)據(jù)反碼，這里只處理了數(shù)據(jù)碼和數(shù)據(jù)反碼 if(ir_timer=33&ir_timer=16&i=7)ir_datah|=1;/ir_tim

14、er=7時，向數(shù)據(jù)碼中移入1，否則，移入0.ir_datah=1;elseir_datah=24&i=7時，向數(shù)據(jù)碼反碼中移入1，否則，移入0.if(ir_timer=7)ir_datal|=1; ir_datal=1;elseir_datal=32)/i=32時，標志著一個完整的紅外數(shù)據(jù)幀已經(jīng)接收完，將接收完標志致一ir_ok=1;elsei=0;starflag=1;ir_ok=0;ir_timer=0;/*獲取紅外按鍵值*/unsigned char scanf_hongwai()while(1)if(ir_ok) if(ir_datal | ir_datah) ir_ok=0;star

15、flag=0;shengyi=300; return ir_datah; /* 向 12864 寫指令 */void wzl(unsigned char zl) lcd_en=0; lcd_rs=0; lcd_rw=0; lcd_shuju=zl; lcd_en=1; yanshi(1); lcd_en=0;/*向 12864 寫數(shù)據(jù)*/void wshuju(unsigned char shuju) lcd_en=0; lcd_rs=1; lcd_rw=0; lcd_shuju=shuju; lcd_en=1; yanshi(1); lcd_en=0;/*文本轉(zhuǎn)到圖形模式 并開繪圖顯示*/v

16、oid wenben_to_tuxing()wzl(60); /8位接口、使用擴展指令集wzl(62);/使用擴展指令集,開繪圖顯示 /*繪圖轉(zhuǎn)到文本模式 并關(guān)繪圖顯示*/ void tuxing_to_wenben() wzl(60);/關(guān)繪圖 wzl(56);/轉(zhuǎn)到文本模式 /*圖形模式下的清屏*/void tuxing_qinping()unsigned char x=128;unsigned char y=128;qp0:wzl(y);wzl(x);qp1:wshuju(0);wshuju(0);x+;if(x144)goto qp1;x=0;y+;if(y160)goto qp0;/

17、*圖形模式下 繪制一條 高亮*/void tuxing_gaoliang(unsigned char n)/第幾行 從14 unsigned x=128,y=128,i=0,j=0;if(n=1)x=128;y=128;if(n=2)x=128;y=144;if(n=3)x=136;y=128;if(n=4)x=136;y=144;gl0:wzl(y+j);wzl(x);gl1:wshuju(255);wshuju(255);i+;if(i8)goto gl1;i=0;j+;if(j2) n-; goto cd;goto cd;break;case key_xia: if(n4) n+;got

18、o cd; goto cd;break;case key_quxiao: n=255;break;case key_queding:break;default:goto cd2;break;tuxing_to_wenben();wzl(1);/清屏yanshi(200);wenben_to_tuxing(); return n;/*按頁寫一個高為 8 的行 需要傳入左上角的坐標用戶 兩個 指針*/void tuxing_ye(unsigned char *tx0,unsigned char *tx1,unsigned char ye,unsigned char y)/tx0在左,tx1在右un

19、signed char i=y+8;while(yi)wzl(y);wzl(ye);wshuju(*tx0);tx0+;wshuju(*tx1);tx1+;y+;/*將內(nèi)存中的ditu寫入到屏幕*/void to_lcd()unsigned char i=0;unsigned char j=0; for(i=0;i4;i+) /寫上半屏for(j=0;j=14;j+=2)tuxing_ye(&yuansu_codedituij,&yuansu_codedituij+1,128+j/2,i*8+128); for(i=4;i8;i+)/寫下半屏for(j=0;j=14;j+=2)tuxing_y

20、e(&yuansu_codedituij,&yuansu_codedituij+1,j/2+136,(i-4)*8+128); /*用于檢測人或箱子能否移動 */void chuli(char dx, char dy)/dx,dy要么為0要么為1char x=ren_x+dx;char y=ren_y+dy; if(dituyx=0 | dituyx=3) /空地0 墻1 人2 目的地3 箱子4dituren_yren_x=0;dituyx=2;if(ditu_ju_codejushuren_x+ren_y*16 = 3) dituren_yren_x=3;ren_x=x;ren_y=y;if

21、(dituyx=4 & (dituy+dyx+dx=0 | dituy+dyx+dx=3) )dituren_yren_x=0; chexiao00=ren_x;/將此移動操作記錄到chexiaochexiao10=ren_y;chexiao01=dx;chexiao11=dy;if(ditu_ju_codejushuren_x+ren_y*16 = 3) dituren_yren_x=3;if(ditu_ju_codejushux+y*16 = 3) dituyx=3;dituyx=2;dituy+dyx+dx=4;ren_x=x;ren_y=y;to_lcd();/*測試完成*/bit j

22、iance() unsigned char i=0,j=0;for(i=0;i8;i+)/用來得到人的座標 for(j=0;j16;j+)if(dituij=3)return 0;if( ditu_ju_codejushuren_x+ren_y*16 =3) return 0;return 1;/*游戲完成*/void gaoding()shengyi=3906;/*按取消鍵時的處理函數(shù)*/void quxiao_func() /空地0 墻1 人2 目的地3 箱子4char dx,dy;if(chexiao00!=0)if( ditu_ju_codejushuren_x+ren_y*16=3

23、)/恢復(fù)人現(xiàn)在的這個地方的東西 dituren_yren_x=3;elsedituren_yren_x=0;ren_x= chexiao00;ren_y= chexiao10;ditu ren_y ren_x =2;dx= chexiao01;dy= chexiao11;ditu ren_y+dy ren_x+dx =4;if(ditu_ju_codejushuren_x+dx+dx+(dy+dy+ren_y)*16=3) dituren_y+dy+dyren_x+dx+dx=3;else dituren_y+dy+dyren_x+dx+dx=0; chexiao00=0; chexiao01

24、=0; chexiao10=0; chexiao11=0; /*游戲的正文*/unsigned char youxi()/按菜單鍵時返回0 游戲完成時返回 1unsigned char i=0,j=0; for(i=0;i8;i+)/加載地圖到內(nèi)存for(j=0;j16;j+)dituij=ditu_ju_codejushuj+i*16; to_lcd();for(i=0;i8;i+)/用來得到人的座標 for(j=0;j16;j+)if(dituij=2)ren_x=j;ren_y=i;while(1)i=scanf_hongwai();yanshi(2000);switch(i) case key_shang: chuli(0,-1); break; case key_xia: chuli(0,1); break; case key_zuo: chuli(-1,0); break; case key_you: chu