電大機(jī)電一體化系統(tǒng)設(shè)計(jì)試題A（小抄參考）

1、專業(yè)好文檔機(jī)電一體化系統(tǒng)設(shè)計(jì)試題a一、單項(xiàng)選擇題(本大題共14小題，每小題1分，共14分)在每小題列出的四個(gè)選項(xiàng)中只有一個(gè)選項(xiàng)是符合題目要求的，請(qǐng)將正確選項(xiàng)前的字母填在題后的括號(hào)內(nèi)。1.受控變量是機(jī)械運(yùn)動(dòng)的一種反饋控制系統(tǒng)稱( )a.順序控制系統(tǒng) b.伺服系統(tǒng) c.數(shù)控機(jī)床 d.工業(yè)機(jī)器人2.齒輪傳動(dòng)的總等效慣量隨傳動(dòng)級(jí)數(shù)( )a.增加而減小 b.增加而增加 c.減小而減小 d.變化而不變3.滾珠絲杠螺母副結(jié)構(gòu)類型有兩類：外循環(huán)插管式和( )a.內(nèi)循環(huán)插管式 b.外循環(huán)反向器式c.內(nèi)、外雙循環(huán) d.內(nèi)循環(huán)反向器式4.某光柵的條紋密度是100條/mm，光柵條紋間的夾角=0.001孤度，則莫爾條紋

2、的寬度是( )a.100mm b.20mm c.10mm d.0.1mm5.直流測(cè)速發(fā)電機(jī)輸出的是與轉(zhuǎn)速( )a.成正比的交流電壓 b.成反比的交流電壓c.成正比的直流電壓 d.成反比的直流電壓6.電壓跟隨器的輸出電壓( )輸入電壓。a.大于 b.大于等于 c.等于 d.小于7.某4極交流感應(yīng)電動(dòng)機(jī)，電源頻率為50hz，當(dāng)轉(zhuǎn)差率為0.02時(shí)，其轉(zhuǎn)速為( )a.1450r/min b.1470r/minc.735r/min d.2940r/min8.右圖稱( )a.直流伺服電動(dòng)機(jī)調(diào)節(jié)特性b.直流伺服電動(dòng)機(jī)機(jī)械特性c.直流伺服電動(dòng)機(jī)動(dòng)態(tài)特性d.直流伺服電動(dòng)機(jī)調(diào)速特性9.計(jì)算步進(jìn)電動(dòng)機(jī)轉(zhuǎn)速的公式為(

3、 )a. b.tsmcos c. d. 180-10.一般說(shuō)來(lái)，如果增大幅值穿越頻率c的數(shù)值，則動(dòng)態(tài)性能指標(biāo)中的調(diào)整時(shí)間ts( )a.增大 b.減小 c.不變 d.不定11.已知f(t)=a+bt，則它的拉氏變換式為( )a.+b b. c. d. 12.連續(xù)路徑控制類中為了控制工具沿任意直線或曲線運(yùn)動(dòng)，必須同時(shí)控制每一個(gè)軸的( )使得它們同步協(xié)調(diào)到達(dá)目標(biāo)點(diǎn)。a.位置和加速度 b.速度和加速度c.位置和速度 d.位置和方向13.圖示利用繼電器觸點(diǎn)實(shí)現(xiàn)的邏輯函數(shù)為( )a.(a+)(+b)b.a+bc.(a+b)(+)d.ab+14.累計(jì)式定時(shí)器工作時(shí)有( )a.1個(gè)條件 b.2個(gè)條件c.3個(gè)條

4、件 d.4個(gè)條件二、名詞解釋題(本大題共5小題，每小題2分，共10分)15.機(jī)電一體化16.軸系的動(dòng)特性17.靈敏度(測(cè)量)18.永磁同步電動(dòng)機(jī)19.復(fù)合控制器三、簡(jiǎn)答題(本大題共4小題，每小題4分，共16分)20.機(jī)電一體化系統(tǒng)設(shè)計(jì)指標(biāo)大體上應(yīng)包括哪些方面?21.步進(jìn)電動(dòng)機(jī)常用的驅(qū)動(dòng)電路有哪幾種類型?其中哪種電路適于永磁式步進(jìn)電動(dòng)機(jī)?22.步進(jìn)電動(dòng)機(jī)數(shù)控系統(tǒng)和參考脈沖伺服系統(tǒng)的輸入信號(hào)是什么?輸出軸的轉(zhuǎn)速、轉(zhuǎn)向、位置各自與哪些因素有關(guān)?23.什么是plc的掃描工作制?四、計(jì)算題(本大題共4小題，每小題5分，共20分)24.已知雙波諧波齒輪的柔輪齒數(shù)z1=200, 剛輪齒數(shù)z2=202，波發(fā)生

5、器的轉(zhuǎn)速nh=600r/min。如圖 試求：(1)剛輪固定時(shí)柔輪的轉(zhuǎn)速n1; (2)柔輪固定時(shí)剛輪的轉(zhuǎn)速n2。25.已知某一線性電位器的測(cè)量位移原理如圖所示。若電位器的總電阻r=2k，電刷位移為x時(shí)的相應(yīng)電阻rx=1k，電位器的工作電壓vi=12v,負(fù)載電阻為rl。(1)已測(cè)得輸出電壓vo=5.8v,求rl。(2)試計(jì)算此時(shí)的測(cè)量誤差。26.某二階系統(tǒng)如圖所示(1)求系統(tǒng)對(duì)r(t)階躍響應(yīng)的最大超調(diào)量%和調(diào)節(jié)時(shí)間ts。(2)求r(t)=1+t,n(t)=0.1共同作用下的穩(wěn)態(tài)誤差ess。27.三相變磁阻式步進(jìn)電動(dòng)機(jī)，轉(zhuǎn)子80個(gè)齒。(1)要求電動(dòng)機(jī)轉(zhuǎn)速為60r/min,單雙拍制通電，輸入脈沖頻率

6、為多少?(2)要求電動(dòng)機(jī)轉(zhuǎn)速為100r/min，單拍制通電，輸入脈沖頻率為多少?五、簡(jiǎn)單應(yīng)用題(本大題共4小題，每小題6分，共24分)28.已知一階低通有源濾波器電路如圖所示。要求：(1)一階低通濾波器現(xiàn)存在什么弱點(diǎn)?(2)將其改進(jìn)為二階低通濾波器，畫出電路圖；(3)畫出二階低通的幅頻特性示意圖。29.三相交流感應(yīng)電動(dòng)機(jī)，電源頻率50hz，空載轉(zhuǎn)速為1450r/min。(1)該電動(dòng)機(jī)為幾極，空載轉(zhuǎn)差率是多少?(2)堵轉(zhuǎn)時(shí)定子、轉(zhuǎn)子繞組電勢(shì)頻率各為多少?(3)空載時(shí)，定子、轉(zhuǎn)子繞組電勢(shì)頻率各為多少?30.二階系統(tǒng)結(jié)構(gòu)圖如圖所示。設(shè)k1=0.1, k2=10,t1=0.5s(1)求系統(tǒng)對(duì)r(t)的

7、階躍響應(yīng)的最大超調(diào)量%及調(diào)節(jié)時(shí)間ts(取=5%);(2)求系統(tǒng)增益ks及伺服剛度kr;(3)求r(t)=1+t及n(t)=0.1共同作用下系統(tǒng)的穩(wěn)態(tài)誤差ess。31.考慮x-y平面上的直線運(yùn)動(dòng)路徑，源點(diǎn)坐標(biāo)(5，-2)，終點(diǎn)坐標(biāo)為(1，-1)。設(shè)兩軸最大加速度限制：xmax=ymax=2。試設(shè)計(jì)三次多項(xiàng)式樣條函數(shù)點(diǎn)位控制指令。六、綜合應(yīng)用題(本大題2小題，每小題8分，共16分)32.某控制系統(tǒng)結(jié)構(gòu)圖如圖所示，圖中g(shù)c(s)=kp(1+tds),gp(s)= =(1) 確定kp和td的值，以使系統(tǒng)性能同時(shí)滿足： 在單位拋物線(恒加速度)函數(shù)作用下的穩(wěn)態(tài)誤差essa0.2，幅值穿越(截止)頻率c=

8、5(2) 計(jì)算系統(tǒng)在上述取值條件下的相位裕量m。33.采用plc設(shè)計(jì)二臺(tái)電動(dòng)機(jī)a、b工作的系統(tǒng)。（1） 按鈕x1為a電動(dòng)機(jī)起動(dòng)，按鈕x2為a電動(dòng)機(jī)停止（輸出y1）；（2） 按鈕x3為b電動(dòng)機(jī)起動(dòng)，按鈕x4為b電動(dòng)機(jī)停止（輸出y2）；（3） 只有a電動(dòng)機(jī)在工作中，b電動(dòng)機(jī)才能工作。 要求：畫出梯形圖，寫出助記符指令程序。機(jī)電一體化系統(tǒng)設(shè)計(jì)試題參考答案一、單項(xiàng)選擇題(本大題共14小題，每小題1分，共14分) 1.b 2.a 3.d 4.c 5.c 6.c 7.b 8.b 9.c 10.b 11.b 12.c 13.a 14.b 二、名詞解釋題(本大題共5小題，每小題2分，共10分)15.機(jī)械與電子

9、的集成技術(shù)。16.指軸系抵抗沖擊、振動(dòng)、噪聲的特性。17.輸出變化量與對(duì)應(yīng)的輸入(被測(cè)量)變化量的比值。有時(shí)稱為增量增益或標(biāo)度因子。18.以電子換向取代了傳統(tǒng)直流電動(dòng)機(jī)的電刷換向，又稱無(wú)刷電動(dòng)機(jī)。19.在反饋控制器的基礎(chǔ)上附加一個(gè)前饋控制器，二者的組合稱為復(fù)合控制器。它的作用是使系統(tǒng)能以零穩(wěn)定誤差跟蹤已知的輸入信號(hào)。三、簡(jiǎn)答題(本大題共4小題，每小題4分，共16分)20.應(yīng)包括系統(tǒng)功能、性能指標(biāo)、使用條件、經(jīng)濟(jì)效益。21.主要有：?jiǎn)螛O性驅(qū)動(dòng)電路、雙極性驅(qū)動(dòng)電路、高低壓驅(qū)動(dòng)電路、斬波驅(qū)動(dòng)電路、細(xì)分電路。其中雙極性驅(qū)動(dòng)電路適于永磁式步進(jìn)電動(dòng)機(jī)。22.(1)參考脈沖序列。轉(zhuǎn)速與參考脈沖頻率成正比。

10、(2)輸出軸 轉(zhuǎn)向由轉(zhuǎn)向電平?jīng)Q定。 位置由參考脈沖數(shù)決定。23.plc的掃描工作制，即檢測(cè)輸入變量、求解當(dāng)前控制邏輯以及修正輸出指令。重復(fù)進(jìn)行。四、計(jì)算題(本大題共4小題，每小題5分，共20分)24.（1）剛輪固定時(shí)： n1=- （2）柔輪固定時(shí) 25.v0=(1) 當(dāng)v01=5.8時(shí)，5.8= 5.8= ()空載時(shí)設(shè)測(cè)量出5.8輸出電壓時(shí)的測(cè)量誤差則26.(1)求閉環(huán)傳函及誤差表達(dá)式 c(s)=cr(s)+cn(s)= e(s)=r(s)-c(s)=1-r(s)- (2)求 ts= (3)求ess 二階系統(tǒng)ai0閉環(huán)穩(wěn)定 r(s)= ess=27.(1) 即 （2） 單拍制 即： f= 五、

11、簡(jiǎn)單應(yīng)用題（本大題共4小題，每小題6分，共24分）28（1）一階低通濾波器存在過(guò)渡區(qū)域衰減緩慢的弱點(diǎn)。 2）二階低通有源濾波器電路圖(3)低通濾波幅頻率特性示意圖。29（1） 即該電動(dòng)機(jī)為四級(jí) 空載時(shí)轉(zhuǎn)差率為：s= （2）堵轉(zhuǎn)時(shí)：s定子繞組電勢(shì)頻率f1=50hz,轉(zhuǎn)子繞組電勢(shì)頻率f2=sf1=50hz(3) 空載時(shí)：定子繞阻電勢(shì)頻率f150hz,轉(zhuǎn)子繞組電勢(shì)頻率：f2=30.(1)g(s)=1型v=p= (2)性能指標(biāo) ts=(3)系統(tǒng)增益與伺服剛度 ks=kv=k1k2=1， kr=k1=0.1 （4） essr= essn=-31. 所以協(xié)調(diào)運(yùn)動(dòng)先設(shè)計(jì)x軸，再利用下列直線方程變換成y軸控制

12、指令 y(t)=- x(t)=5+3(1-5)()2-2(1-5)( )3=5-t2+ y(t)=-2+六、綜合應(yīng)用題（本大題共小題，每小題分，共分）32.(1)開(kāi)環(huán)傳函g(s)=gc(s)gp(s)= (2)確定kp和td 由essa= 取kp=2.5 在 1+25t (3)相應(yīng)的33.(1)梯形圖：（）助記符指令程序： str x1 or y1 and not x2 out y1 str x3 or y2 and not x4 and y1 out y2if we dont do that it will go on and go on. we have to stop it; we ne

13、ed the courage to do it.his comments came hours after fifa vice-president jeffrey webb - also in london for the fas celebrations - said he wanted to meet ivory coast international toure to discuss his complaint.cska general director roman babaev says the matter has been exaggerated by the ivorian an

14、d the british media.blatter, 77, said: it has been decided by the fifa congress that it is a nonsense for racism to be dealt with with fines. you can always find money from somebody to pay them.it is a nonsense to have matches played without spectators because it is against the spirit of football an

15、d against the visiting team. it is all nonsense.we can do something better to fight racism and discrimination.this is one of the villains we have today in our game. but it is only with harsh sanctions that racism and discrimination can be washed out of football.the (lack of) air up there watch mcaym

16、an islands-based webb, the head of fifas anti-racism taskforce, is in london for the football associations 150th anniversary celebrations and will attend citys premier league match at chelsea on sunday.i am going to be at the match tomorrow and i have asked to meet yaya toure, he told bbc sport.for

17、me its about how he felt and i would like to speak to him first to find out what his experience was.uefa hasopened disciplinary proceedings against cskafor the racist behaviour of their fans duringcitys 2-1 win.michel platini, president of european footballs governing body, has also ordered an immed

18、iate investigation into the referees actions.cska said they were surprised and disappointed by toures complaint. in a statement the russian side added: we found no racist insults from fans of cska.baumgartner the disappointing news: mission aborted.the supersonic descent could happen as early as sun

19、da.the weather plays an important role in this mission. starting at the ground, conditions have to be very calm - winds less than 2 mph, with no precipitation or humidity and limited cloud cover. the balloon, with capsule attached, will move through the lower level of the atmosphere (the troposphere

20、) where our day-to-day weather lives. it will climb higher than the tip of mount everest (5.5 miles/8.85 kilometers), drifting even higher than the cruising altitude of commercial airliners (5.6 miles/9.17 kilometers) and into the stratosphere. as he crosses the boundary layer (called the tropopause

21、),e can expect a lot of turbulence.the balloon will slowly drift to the edge of space at 120,000 feet ( then, i would assume, he will slowly step out onto something resembling an olympic diving platform.below, the earth becomes the concrete bottom of a swimming pool that he wants to land on, but not

22、 too hard. still, hell be traveling fast, so despite the distance, it will not be like diving into the deep end of a pool. it will be like he is diving into the shallow end.skydiver preps for the big jumpwhen he jumps, he is expected to reach the speed of sound - 690 mph (1,110 kph) - in less than 40 seconds. like hitting the top of the water, he will begin to slow as he approaches the more dense air closer t