高考物理力學(xué)計(jì)算題(三十三)含答案與解析

1、高考物理力學(xué)計(jì)算題三十三含答案與解析40mF3mmLmBCgRlmgmABABFAFBAgFFBF2m/s7mgFmFLgFABABgABL，傾角BCREmAq8m/sAABBRmTgmmABRBCL3mLAmgBLmFgEB2m+qmERmABmCmABBmgFhmgABABmFgFAmB6m/sABAgABAALAAIABmmRABgBBABCmhDEEmRgEFEFFgF5m/shm4m/sgABBAAFAmAmBFgABFABB1m/sAdbdabbEpdmldLmgb2mbmbABCBCBChAbDEEABmEmBhgBR4mBCmFABFABgBBABCABCABBCABLmq3m

2、/spgBBECF3m/sbmgmABBAhBCABmABdABBCAA5m/sgBCABBABLm2LgABEERABELEABABEmmgABEABABABEEABEmmmmhmm2mmmg求：（mmmBmAlABgB高考物理力學(xué)計(jì)算題三十三含答案與解析參考答案與試題解析40mF+mvF3mmL解：（答：（mBCg4m/smamm答：（4m/sRlmg解：（m/s4m/sFmgmF3mgm+Mm+M+p1m/sEpm+MmABABFAFBAgFFBBB解：（Bmgm+mgma1m/sABCFm+m+mg3maFBCABCm+m+m3ma2m/sm+mgBCmaBCmgBC答：（FFBF2m

3、/s7mgFF解：（7mFFmg+FFFFFmFLgFFF解：（FFF+W+ABgFABBCABL，傾角BCREmAq8m/sAABBAAABB解：（AA6m/sAAhA+mvA+ABggABABBmglBm/sBmgmBCAmglmgRC5m/sCmgmCm/sCCCB答：（ABBRmTgFRmmT解：（5m/s+50+12m+50答：（mmBBm解：（B答：（mABRBCL3mLAmgBABBBB解：（ABB4m/sBmgmBC6m/sB4m/sm/sC6m/sC6m/sCEeqoac(,mg)E答：（B6m/sL解：（LL答：（LmFgFFF解：（FmgmaFFFFmg4mFmm答：（4

4、mFFEB2m+qmE2m解：（3mg2m+ma答：（RmABmCmCmCBmB解：（mBBBmmmBmmBB答：（CmABBmgFmgmagmgmaFABgtA答：（Fhmg2gh解：（mgh2gh答：（ABABABABAFAmAgABBFAFBABmFgFF解：（Fma5m/smm+ma5mma2m/s4m答：（FAmB6m/sABAgABAALAAIBAAAA解：（ABmgAM+mgABAg6m/sL3mAM+mgAABAABAIA3mAAAABmmRABgBBABABBB解：（ABmmBmmBmBm+meqoac(,E)mBm+meqoac(,E)Bm+mm+m+2m+m8m/sBm答

5、：（BBmABCmhDEEmRgEFEEEEF解：（hhm/sDE小球與斜面彈性碰撞后恰好切入圓弧，則小球到達(dá)點(diǎn)的速度為：m/sm/smeqoac(,h)hhEEE4m/sEEEEFF答：（FFgF解：（FmabFFm+t5+8FFFxF答：（F5m/shh解：（hhhhmmh5+a答：（m4m/sgmm1m/sg3m/s1m/s4m）在2meqoac(,mg)1m/s4mABBAAFAmAmBFgABFABB1m/sABBAAFxFABA解：（ABAFAmABmBFxBB1m/sFAAABFFmAmAAFmBmBBA2m/sABFABB1m/sA2m/sdbdabbEpdmld解：（mm+s

6、+sm4mmmm+mE4m/s1m/sm+mm+mm+mm+mRRm+mgm+mm+mm+m+m+mgRR答：（RRRLm解：（FmaF答：（g+ma5mm/sm/sb2mbmbABCBCBChAbDEbb解：（2mgh2m+mv2m2m+gth答：（DEhEABmEmBhgBBB解：（MgBMgCBFMgFBFF1m/sm+m2m/s1m/sE+E答：（B2m/sR4mBCmFABFABgBBABCABBABBC解：（ABmamg6m/sBBBBBmgR+CC8m/smC答：（BBABCABCABBCABLmq3m/spgBBECF3m/sB解：（C1m/sBC2m/sBECFm/smgmaE答：（Bbmgm解：（MgMg+mmMg+M+mM+mM+mghh答：（mABBAhBCABmABdABBCAA5m/sgBCABBAB解：（BkmgmBABBAh1m/sFmaFBRRRBkmgmm/sABmghA答：（ABABLm2LggL解：（LgLmgt答：（gABEERABELEABABEmmgABEABABABEEABEAB解：（mgABFmRABhAImmAIABEABEm/sm/smmmmhmm2mmmg求：（mmmmm解：（mhmmmm