電大經(jīng)濟(jì)數(shù)學(xué)基礎(chǔ)21

經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁(yè)眉頁(yè)腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請(qǐng)聯(lián)系刪除，謝謝！經(jīng)濟(jì)數(shù)學(xué)基礎(chǔ)期末復(fù)習(xí)參考練習(xí)題1(())ffxf(x)（C）x1A1Dx2BCxxx2ysinx1AAyx1By2x1Cyx1y2x1D11(x)edxec()(fxB）fxx1111DABCx2x2xxBC）(AB)AB(AB)(A)BACBD111TTTTT(AB)BA(AB)ABTTTTTTxx112D）xx012AB0解CDx1yD）ln(x1/36、xx且2．x1、x2、xx1f(x)ln(xf(xx2A）．xC、xy2y2、、xy2xy2B）11．ddx()、x2xx3、sinxdxd(cosx)、d(x)23A為35TBCB45545342D．BC11x11D）110x2C0解DDABCD2/36sinx(x)x00在x處連續(xù)，則k（C）fxkxABC1D2C）1、sinxdxd(cosx)lnxdxd()、x11dxx2dxd(2x)、D、xln2BAAABI,則A（A1、、B、(AAB)1bD）AXmnmnr()n、、、r()r()mr()r()r()n、x24yB）x2．[2,)、[2,2)(2,)3/36．(,2)(2,)、(,2)(2,)f(xx)f(x)x（A）f(x)cos,則lim4x02sinsin、0B、、244Dxsinx211cosx22cosx2、2cosx2、cosx、．222A是mB是stACBCDnT．mt、tm、ns、snx2x4x1123xx0C23x23x1x7xx1111．x0、x2、x2、x22222x2x2x2x23333D()x21,g(x)x1、fx(x)(x),g(x)x2、fx14/36．ylnx,g(x)2lnx2f(x)sinxcosx,g(x)1、22xf(x)1()Afxsinxx1、x、x、x0、1、dx（C）x31110、、、22AA1=（C）B、、(IAB)11321426011B）01126022412、1234C）2()(),()2fxxgxxfy(x)x,g(x)xlnx,g(x)3lnxylnx,g(x)2lnx32,C）1x31x2x2x5/36若F(x)f(x)是B）()()()fxFbFa()()()fxFxFabxaa()()()fxfbfa()()fxFxbbaa設(shè)BD）(AB)A(B)(AB)AB111TTTTT(AB)BA(AB)BA111TTTTA）x50exf(x)2）x210x2limxsinx0、xx0f(x)sinxcosxc(AB)A2ABBBn222B1021x2xxA0102則此方程組的一般解為＿＿134x2x0000246/36(x2)x4x5()fxx292fpp7qpq(p)500eE22p．dsinxdxr(,b)r()100100A020A0011200001313x）yxppqpq(p)100eE22px1dx0．x2123aA3a7/361116A0132bt00t10C(q)802q,q50x3232f(x)xx2xx121xx(2、、1111202134xx0120xx0121f(xh)f(x)1,則=f(x)1xhxxh)12xf(x)x1f(x(,)x1x1a()[(()fxx=fx8/361204I(I)=.AT2243中A為0r(A)2x2x6f(x)2f(x)sinx,0)x31dx0x211BBr()r()cos(xy)ex和yxy。y[cos(xy(e)x解ysin(xyy]ey1y[esin(xy)]y1sin(xy)y9/361xy)yeyxy)ycosxedy。x2sinx2x(cos)2xex2解yxe2xsinx2xdy(2xe)dxx2lnsinx,()求yxy211(lnsin)(sin)cos()2xcotx2x2x2解yx2x2sinx2sinx21x)1x求y(0)、y1x)x1xx)x)2yx)2y(0)0ycos2sinx,yx2(cos2sin)2ln2sin22xcos解yx2x2xxx10/36sinxconxy5y(sin)(cos)cos5cossin54yxxxxx2y(x)ey求2xx22()()解2x2xyxexexx22)ex)e2x2xx2x42e2x)2xxx2xy求y2x1xx(2)()解yx1x(cosx)x)cosxx)x)22ln2xcosxx)sinxx)22ln2xlncosx2y()求y412xx)x)2x2xx2解22yx2x211/36()2tan()2y444求1y解y1lnx3212lnx2323(1ln)ln)ln)ln)x32x2x2x233x23xlnx)2lnxdx23x2ye2x求dy2x2x2x2x2)()sin()2exsin2e解ye2x2x2x2222x2(xsin2e)2x2．ycos2x)3(cos23cos2)sin(1222cos2)2)y3x2xxx2xxylnxsin2x、exy12/36(e(ylnx(sin2xxyye(yxy)ylnx2cos2xxyxy(exlnx)y2cos2xeyxyxyx2cos2xeyxyxyexyxlnxx)eexyy求y2[yx(e)(e)解2xyy)()0eyyx1xyx)]y1xyx)yexyxx)xexy]ysinyxe0y求y7(siny)(xe)0解ycosyexey0yyy(cosyxe)yeyy13/36eyycosyxeydyy1xe求ydxx0()xe解yyyexeyyyey1xeyyy1dydxx0e1ey(0)當(dāng)x10e1cos(xy)ex．求y[cos(xy(e)x解yy)sin(xy)ey1y(esin(xy)]y1sin(xy)y1sin(xy)yeysin(xy)14/361sin(xy)dydxeysin(xy)1、16x9x01x9x19161616xx(9)解x9x(x9xx9x)000xsin2x．dx2011解xsin2x[x2x2xdx]dx222224000lnx).eedxxx20ln31563ln30ln3解ex)e2dx)))e2deex30xxx30、xe1112e1e}e2lnxdx{xlnxe解x2=214411lnxdxx15/36lnx1lnxd(lnx)(lnx)2cdxx2(x5x7)cos2xdx、2(x5x7)cos2xdx2(x5x7)sin2x4(2x5)cos2x16sin2xc221ex、2dxx211ex112dx1ed()e11ee11xx1x2x11ex2x2122ex2dx2edxe22()ee解2xx1x111xedx2x01101111101eeee解2x2x2x22x2222040cos2xdxx201111解x222x2x22x222024020016/36xx)dx解xx)dxxx)x)dxxx)x)c3xxx3xx33lnxxc解xxx解4x2x111d(4x)ln(4x)c224x224x22(xlnxdxlnx11(x21x2(x2x)lnxxc(xln(xlnx解2222x2412x1lnx121121dx2dln)21ln2(3xx解1x1lnx1lnx11021124,B2,2IA）BT311317/36解2001111012IA0200210T00224124111311290120033(2IA)B0T24132891001A01,B01,求（B)1T1212解100011213BA01T112121210121001111032011113013211(B)1T102123A,B()1120ABT01218/361010274(AB)2132T12032741010121012101232013201023701327212()1T3272113()求IAA115112100113013解IA010115105001121200131001050101006510501001310001053312000100121100121165(I)5331211151A,B,求(AI)B136119/36151025解AI360137231235(AI)B157157121231A357,B0X5810123100123100357010012310解.5800102550112310010064101231001055200112100112641即A5521264115XAB552031120021210(ABT)1A,B11001120/36200212111解且T1110011101101211011013312[ABI]T0113233013111(AB)T1312010，IA()A1111103110解IA101且10211010011010010002110101001111001011110200101210100101021(I)12110121/3621261102CA,B010,C22120T002422121161606101C0100222022222解BAT002204240424263102A,B12(AB)112041631022112解AB1204141211021102011101212[,I]4101012101210121112()1221231X342231011113401111110430132解3401013222/3623143即34324312X3221121X3520121012300131052解即3501013112152353111121152831X10431203520xx213x2xx01232xxb123a,b1012101210201121解A0111022121ab012401abab23/36當(dāng)ab3當(dāng)a當(dāng)ab3xxx01232xx8x3x012342x3xx0124111011101031A21830123012123003630000x13xx034x2xx0223x13xx34x2xx2342x5xx15x71234bx2xx4x21234x3x2x11xb123424/362511571114212142A1114225115701373解132111321100005bbb12142A0137300000x17x10x434x3x7x32342x5x2x3x01234x2xx3x012342x14x6x12x0123425212131213A121325230949262608121325230000x12xx3x02342x5xx3x0123425/361xxx91344xxx9234x13x2x0232x5x3x0問(wèn)01233x8xx0123132132132101A253011解3801600550x13x2x023xx023xx13xx23xxx2124x2xx4x312342x3xx5x51234110121101211012解A12143011310113123155011310000026/36xxx2124xx3x1234xx2x1134xx3x123xxx21242xx4x3當(dāng)x12342x3xx5x21234110121101211012A111430113101131解23152011320000當(dāng)xx2x1134xxx1234x1x2x134x1x3x234qC(q)1000.25q6q2（qC1000.2510610185227/36C(q)CC18.5q()0.56)0.510611CqqCC(q)）C(q)q6qq令C(q)得q2Cq()qR(q)1002qq（）（）2()()()2)810010q）LqRqCqqq()0Lq令L12L(q)10q)）21010q1002p28/36（C(q)R(q)（C(q)2005q1R(q)pq50qq22L(q)R(q)C(q)45q1q20022()450令Lqq45，q1L(45)454545200812.522Cq()2R(q)120.02q（（()()()120.022100.02LqRqCqqq()得令LqqLq)qq)2550500500()43Cqqq29/36（（(q)C(q)(4q3)2q2qCC(q)C(q)2q3qq()(23)2）Cqqqq2()20得q3令Cqq218C23393qC(q)12qq82q2p（（R2(q)qpq2q)8q2q8q2q2L(q)R(q)C)(q)q2q2qq)6q1q222L(q)66q()660令Lq解q1，q30/361L611322()2.51000()22000RqqqCqq()()()LqRqCq2q2000(2.5q1000)0.5q1000()0令Lq2000得qC1(q)q23q10025qC(q)1qC(q)qq1()0Cqq2q50