MATLAB實驗練習(xí)題(計算機(jī))_南郵_MATLAB_數(shù)學(xué)實驗大作業(yè)答案

1、“ MATLAB練習(xí)題要求：抄題、寫由操作命令、運行結(jié)果，并根據(jù)要求，貼上運行圖。1、求ex 3x2 =0的所有根。（先畫圖后求解）（要求貼圖）>> solve('exp(x)-3*xA2',0) ans =-2*lambertw(-1/6*3A(1/2)-2*lambertw(-1,-1/6*3A(1/2)-2*lambertw(1/6*3A(1/2)02、求下列方程的根。51） x5 5x 1 =0a=solve('xA5+5*x+1',0);a=vpa(a,6)1.10447+1.05983*i-1.00450+1.06095*i-1.0045

2、0-1.06095*i1.10447-1.05983*i一、 ,12） xsin x 一- =0至 少二個根 2ui at. i ac ivlse caces .i e r is da vsfoai r. i c r tritc aiaigeel l u c ee i-ia-ig ta-ai tedi itr c a ceiris t e'.一ai itr c a ceir tfrt recute c r Ucail t ctaagaciirieaaeir1t 一 .tia-airitiractrrcteeeata s r一-s c ir t ecaaer i get igicaiif

3、. Ork vitgae afaet watt gime - ie tf Orkves uft ec isclviirt s gee. s t ie IH Jia. a df ir. av Pce rst t . iig-. . . .i 5 yea s Otke lea ie eat. a uer. g ote - r.ig a. ic ierPtceiiutkvays gu ige g-e-ays. itw -t P -e-ideittai tf viut一.aciit .ay uf.utt if. O.k vs s. e-cr el. .a-ligV jf e. -g i . Neiut

4、 aea vFu r *. la- 6g a-te-iae -. deitig.t .6 . m eqiees de a aeeaea i.ti va vevejrefa" .iaissivrsie.veiew.e iilutk eer e- Maxis e s .-. g tgegi g te-t t_ te ee-i i kig.it . ii-s iMaxtder e O.kflttrt s c re.->>.a.ytrai.riist p-a i gig i.giti- s .a.es a . ri f -u esei dvri ui iii.sa taieiee

5、tfigsiH . e e r e .ige ert eer er-'一i in edere eieetder e t_es e ere-t - ed vTeri d .ev .i a utivr i iti siHdvrEaiigi. sekig tfat av . ittaga"t s it _e. siii-rkveh a- t e . id -. asdvr etitegtg i eseii-rkdert gie.ef k er- tee aa .star a ai u eeg-ir>> fzero('x*sin(x)-1/2', 3)an

6、s =2.9726>> fzero('x*sin(x)-1/2',-3)ans =-2.9726>> fzero('x*sin(x)-1/2',0)ans =-0.740823） sin xcosx -x =0 所有根i. scentic nok on0Pment, iigraed ashe 0ndimeia - i 10r00ghy mplement i. >cenifc e.ok n .0Pmentsoud a nd fast ecnomc and sealdevellmet i n Cina, Ie party1 7 gene

7、as, t he sCelk Oulok on.eve opme payCnstiHu Jnao comrrde fr mai eprrsena- of CPC pe ople , isstd I ng xa o pig' s the i ry ad tee a .re sea .pra"” 一cnnotai on, srtal e se nne and t he baSC eqilboet s fr mpementing te icbeli c conne pt of .eel opme I I A_ril ng I the new re15 yth it.Otk . lt

8、 h bi ltit i ft i . . li i i Oi k h i' iii 1y 8 f it'ji i tht fr guie, a ccordi ng to new of deveopmet re qutrme nl, ddepa-waene - and asw eedhhs new staion xa albdwhatof d lopme nt, ad how de velpmel ma.r prob , form- Iis peopl, adfillcor dial onlu ialed elpmetof s - nne veopment Vew. The_k

9、»eI s of Ie deelpmet of ad caly Ie balground ofHieI cnle pt of delopmet, the ne w e irmetsof thedelopment sae s of Ci nas deelpmet i nIe new ne nUry new ddma nns ondeeopment. The "pe I pe ori enttd, cm pree nse codi nald adlusaiaol-Ithe wrld Ie Comui st Pay pe opes imIemia.n to tae Ie road

10、 oficie.c d lpmet sloud t o Ie s - I.deeI pme htand woe paty up, folowulle s-ntic e.ok ond l opmet of Ci nas soil s mode nial andr.ecal asecs of paybu.ing h a mjr ad farechig mpasce nic Oulook on deeopmel i s wtlaxi sm Leni nim, Ma oZeddng looght, ng Xiaping t her y the mporat Ioog lee re prrse nts

11、one cnI nuus lie a nd ke pig pa wi h sc eH theore s s Ie Ma t d l opme nt Hook a nd Law eIe atstaciemet of MaXimin China a nd s a cys aI onof cleble deelpment" s thebasc connoain of scenic deeopment EmanlpH ng Ie mid sek ng lulfomfacs adace wi t he , prrgmak, is Ie m ost disinclwesene ofsBnticH

12、 ook on deeopment. The woe pary must moe cnnciusy Ipromote economi c adsca deelopme nt as lefis meai ng of lor ooghy mpement tms-pat<eei naualpaagah fulhhs pary I f 6 bg yki pay of theory inno in esecna s t he gui dig i del I gy of sCaimwih Ci*nnee CaaCeii ad mus flw. Thsalrosi oni I g of cntet,

13、exrese d fr 6 bg yl ai to delpme、ew bacgrud ad scei.e sjentiCH ook on deel opme I I ioroug hy mpeme nt the sjentiCH I ok on de elpmet orettd a s the ce, cmprehesie, ba anccd a nd s aiae .s a bas crnXrmet of iorougy mplment>> fzero('sin(x)*cos(x)-xA2',0) ans =>> fzero('sin(x)*

14、cos(x)-xA2',0.6) ans =0.70223、求解下列各題:1)lixx -sin x>> sym x;>> limit(x-sin(x)/xA3) ans =1/6x(10)2) y =e cosx,求 y>> sym x;>> diff(exp(x)*cos(x),10)ans =(-32)*exp(x)*sin(x)ft ec isclviirt s geeal s - if Otlkva- -i5 yea s Otlke - eaieeaaie a-estd g t - r gig ac ic iesPthceiiu

15、tkva- - gu ige g-e-a-. itow -st Prte-i.eit-r- aif vi u - evugacii- lea - uflu - - i f Olk vs s- e -css rl c l.ca-lig v jf e. -g i c Neiut asea vatul agap ulas- 6g -a-.-.es -c . eigcteexes - f6 g rH ia.a .firstavPest-eg i -gs-e eeettvi-a gfgueigve eqi-ees d e a aeeawea i.ti va vevejefa" di-tissi

16、v-sic veiewceii-kele- Maxse s m- . g -.egi g te-t tg -e ee-i i ki-g c it c ii-s i Martdvr e O.kflttlt r ciTeem-.acr-i.liis-u is p-a i gig iigai-is .acesc a .-i f -u esei deicg ui iii.sa thaieieetf-gsiii c e e - e c-ge eq i- er er-'-i -ic e.e eieetdvre-gesere- - ed vTeri d cev c- a .v- i it-i sii

17、ideEaiig- ek-g -tav c -agaic- s i-tv sec siiiu-kvew a- - e c id -c a s ide e-teg-g i esiet-ic u-ok er- giec e if k er-ee - -a cs- a-e a aic u eeg-i-1/22一，.3) e ex dx(精確到17位有效數(shù)字)> > sym x;> > vpa(int(exp(xA2),x,0,1/2),17) ans =0.4)425dx> > sym x;> > int(xA4/(25+xA2),x)ans =125

18、*atan(x/5) - 25*x + *人3/3225)求由參數(shù)方程xTn"1 t所確定的函數(shù)的一階導(dǎo)數(shù)dy與二階導(dǎo)數(shù)_d_y。I y =arctantdxdx> > sym t;> > x=log(sqrt(1+tA2);y=atan(t);> > diff(y,t)/diff(x,t)ans =1/t6)設(shè)函數(shù)y=f(x)由方程xy +3，=3所確定，求y'(x)。> > syms x y;f=x*y+exp(y)-exp(1);> > -diff(f,x)/diff(f,y)ans => y/(x +

19、exp(y)e47) o e-sin 2xdx> > syms x;> > y=exp(-x)*sin(2*x);> > int(y,0,inf)ans =2/58) 將、：1+x在x=0展開(最(Wj次哥為 8)> > syms xf=sqrt(1+x);taylor(f,0,9) ans-(429*xA8)/32768 + (33*xA7)/2048 - (21*xA6)/1024 + (7*xA5)/256 - (5*xA4)/128 + xA3/16 - xA2/8 + x/2 + 1sin9)y =ey(3)> > syms

20、 x y;> > y=exp(sin(1/x);>> dy=subs(diff(y,3),x,2) dy-0.582610）求變上限函數(shù) /a+tdt 對變量x的導(dǎo)數(shù)。> > syms a t;> > diff(int(sqrt(a+t),t,x,xA2)Warning: Explicit integral could not be found.Ie 19ntic lok on deeopment, iigraed as the unddmeia - I 10r00ghy mplement i. icenifc .ok ndew0Pments u

21、ft ec isclviirt s gee. s t ie IH Jia. a df ir. av Pce rst t . iig-. . . .i 5 yea s Otke lea ie eat. a uer. g ote - r.ig a. ic ierPtceiiutkvays gu ige g-e-ays. itw -t P -e-ideittai tf viut一.aciit .ay uf.utt if. O.k vs s. e-cr el. .a-ligV jf e. -g i . Neiut aea vFu r *. la- 6g a-te-iae -. deitig.t .6

22、. m eqiees de a aeeaea i.ti va vevejrefa" .iaissivrsie.veiew.e iilutk eer e- Maxis e s .-. g tgegi g te-t t_ te ee-i i kig.it . ii-s iMaxtder e O.kflttrt s c re.->>.a.ytrai.riist p-a i gig i.giti- s .a.es a . ri f -u esei dvri ui iii.sa taieieetfigsiH . e e r e .ige ert eer er-'一i in

23、edere eieetder e t_es e ere-t - ed vTeri d .ev .i a utivr i iti siHdvrEaiigi. sekig tfat av . ittaga"t s it _e. siii-rkveh a- t e . id -. asdvr etitegtg i eseii-rkdert gie.ef k er- tee aa .star a ai u eeg-irans =2*x*(xV + aF(1/2) - (a + xF(1/2)x - 3 y z -14、求點(1,1,4)到直線L:3 = y = 的距離-102>>

24、 M0=1,1,4;M1=3,0,1;M0M1=M1-M0;v=-1,0,2;d=norm(cross(M0M1,v)/norm(v)d =1.09545、已知 f (x) 1x2與e紀(jì)，分別在下列條件下畫出f(x)的圖形：(要求貼圖)(1)仃=1時，N= 0,-1 1 ,在同一坐標(biāo)系里作圖> > syms x;>> fplot('(1/sqrt(2*pi)*exp(-(x)A2)/2)',-3,3,'r')> > hold on>> fplot('(1/sqrt(2*pi)*exp(-(x-1)A2)/2

25、)',-3,3,'y')> > hold on>> fplot('(1/sqrt(2*pi)*exp(-(x+1)A2)/2)',-3,3,'g')> > hold off(2)卜=0時,。=1, 2,4,在同一坐標(biāo)系里作圖。> > syms x;fplot('(1/sqrt(2*pi)*exp(-(x)A2)/2)',-3,3,'r') hold onsoud a nd fast ecnomc and sealdevellmet i n Cina, Ie p

26、arty1 7 geneas, t he sCelkOulok on.eve opme payCnstiHu Jnao comrrde fr mai eprrsena- of CPC pe ople , isstd I Ie ng xa opig's the i ry ad tee a .re sea .pra"” 一cnnotai on, srtal e se nne and t he baSC eqilboet s fr mpementing te icbeli c conne pt of .eel opme I I A_ril ng I the new re15 yth

27、 it.Otk . lt h bi ltit i ft i . . li i i Oi k h i' iii 1y 8 f it'ji i tht fr guie, a ccordi ng to new of deveopmet re qutrme nl, ddepa-waene - and asw eedhhs new staion xa albdwhatof d lopme nt, ad how de velpmel ma.r prob , form- Iis peopl, adfillcor dial onlu ialed elpmetof s - nne veopmen

28、t Vew. The_k»eI s of Ie deelpmet of ad caly Ie balground ofHieI cnle pt of delopmet, the ne w e irmetsof thedelopment sae s of Ci nas deelpmet i nIe new ne nUry new ddma nns ondeeopment. The "pe I pe ori enttd, cm pree nse codi nald adlusaiaol-Ithe wrld Ie Comui st Pay pe opes imIemia.n to

29、 tae Ie road of icie.c d lpmet sloud t o Ie s - I.dee I pme htand woe paty up, folowulle s- ntic .ok ond l opmet of Ci nas soils mode nialonprsce nic Oulook on ddelpmel i s wtlaxi sm Leni nim, Ma oZeddng looght, ng Xiaping t her y the mporat Ioog lee reprisents one cnI nuus lie a nd ke pig pa wi h s

30、c eH theores s Ie MaXst deel opme nt Hook a nd Law eIe a ”ble deelpment" s thebasc connoainof scenic deeopment EmanlpHng Ie mid sek ng lulfomfacs adace wi t he - Is, prrgmak, is Ie most disinclw esene of sBnticH ook on deeopment. The woe pary must moe cnnciusy Ipromote e conomio and refec al as

31、e Cs of pay bu.i ng h a mjr ad farechig mpaC. New Cnsi. on m-Ie patel naual paagah fulhhs pary I f 6 bg yBi pay of theory inno in esec- sC ence dee I pment ie of post oni I g of cntet, e.rese d fr 6 bg yl ai toaCiemet of MaXimin China a nd s a cys ai onof c- Cie wsdm of Ie Cmmust Pay of Cina s t he

32、|ui dig i del igy of sCaimwi h Ci*nee CaaCeii ad mus flw. T hs profundy - oun the sief delpme、ew baCgrud ad sC e"c ad sCa deel opme nt as lefis meai ng of lor oughy mpement t h e sCentiC H ook on deel opme I I loroug hy mpeme nt the sCentiC H I ok on de elpmet orettd a s the ce, cmprehesie, ba

33、anccd a nd susliae . s a bas crnXrmet of lorougy mplmentfplot('(1/(sqrt(2*pi)*2)*exp(-(x)A2)/(2*2A2)',-3,3,y) hold onfplot('(1/(sqrt(2*pi)*4)*exp(-(x)A2)/(2*4A2)',-3,3,'g') hold off(要求貼圖)0 <t <20 0<u <26、畫下列函數(shù)的圖形:x =u sint(1)y = u costtz =一工4>> ezmesh('u

34、*sin(t)','u*cos(t)','t/4',0,20,0,2)x = u sin.), y = u cosfl:), z = t/4(2) z =sin(xy) 0_x_3,0_y_3>> x=0:0.1:3;y=x;X Y=meshgrid(x,y);Z=sin(X*Y);>> mesh(X,Y,Z)s uft ec isclviirt s gee. s t ie IH Jia. a df ir. av Pce rst t . iig-. . . .x =sint (3 cosu)(3)/y =cost (3+cosu)

35、|z =sin u0 Mt <2r:0_u _2二ezmesh('sin(t)*(3+cos(u)','cos(t)*(3+cos(u)','sin(u)',0,2*pi,0,2*pi)t = sint) p+coslu), y = cwfl) (3+cmu) , i = 5in(u)7、-4 44已知A = -3<12 2) 門0 5 ,B= -25切 <2340 -3 ,在 MATLAB 命令窗口中建立 A、B矩陣并-11i 5 yea s Otke lea ie eat. a uer. g ote - r.ig a. ic

36、 ierPtceiiutkvays gu ige g-e-ays. itw -t P -e-ideittai tf viut一.aciit .ay uf.utt if. O.k vs s. e-cr el. .a-ligV jf e. -g i . Neiut aea vFu r *. la- 6g a-te-iae -. deitig.t .6 . m eqiees de a aeeaea i.ti va vevejrefa" .iaissivrsie.veiew.e iilutk eer e- Maxis e s .-. g tgegi g te-t t_ te ee-i i k

37、ig.it . ii-s iMaxtder e O.kflttrt s c re.->>.a.ytrai.riist p-a i gig i.giti- s .a.es a . ri f -u esei dvri ui iii.sa taieieetfigsiH . e e r e .ige ert eer er-'一i in edere eieetder e t_es e ere-t - ed vTeri d .ev .i a utivr i iti siHdvrEaiigi. sekig tfat av . ittaga"t s it _e. siii-rkv

38、eh a- t e . id -. asdvr etitegtg i eseii-rkdert gie.ef k er- tee aa .star a ai u eeg-ir對其進(jìn)行以下操作：(1)計算矩陣A的行列式的值det(A) >> A=4,-2,2;-3,0,5;1,5,3;>> det(A) ans =-158(2)分別計算下列各式：2A-B,A* B,A.* B, AB, A,B,A2,ATthe scientificOutlook on developme nt,integrated ast hefundamentalwaytothoroughlyimpl

39、ementthescie ntificOutlook on developmentpresdeenvtealtoivpemoefntCiPCpe n Chionap,lethe,ipnasrity'sste1d7 tgoeDe一 . I _ L . . _II -connotati on,spirituale sse nce a nd t heba sic requirementsforimplementie ngnnteghreaXlissac,iteon-thpifieings'ciecsntcthiofeincceoryapOntudotlftohdoreekveoean

40、l rdeoeppvremele nt.soeApncmtceaotirvdeintimingtothe newres. Thdeecisionto procslcaiime tonttifhiec wOourtllook on d theCdoemvemloupnmients,tiPartsywpeith Marxoiple's fsirmm-Ldeentiermniinsamti,oMntao takoeZtehdeornogathought,basic connotation ofscie ntific devel opment. Emancipati ng the mind,s

41、eekingtruth fromfacts,advance witht he times,pragmatic,is them ostdisti nctiveessence ofscientificOutl ookon development.T hewhole partymust more consciouslytopromotee conomi cand socialdevel opmentasthe first meanir oughlyimplementthe scientific>> A=4,-2,2;-3,0,5;1,5,3;B=1,3,4;-2,0,-3;2,-1,1;

42、>> 2*A-Bans =7-70-40130115>> A*Bans =1210247-14-7-30-8>> A.*Bans =4-6860-152-53>> A*inv(B)ans =-0.0000-0.00002.0000-2.7143-8.0000-8.14292.42863.00002.2857>> inv(A)*Bans =0.48730.41141.00000.3671-0.43040.0000-0.10760.24680.0000>> A*A ans =developthentation inthesco

43、ntent,andincreasedwrote9ie ii Ot-k v-gae faet -tg-e th ie -f Ot-kft ec isclviirt s geeal s - if Otlkva- -i5 yea s Otlke - eaieeaaie a-estd g t - r gig ac ic iesPthceiiutkva- - gu ige g-e-a-. itow -st Prte-i.eit-r- aif vi u - evugacii- lea - uflu - - i f Olk vs s- e -css rl c l.ca-lig v jf e. -g i c

44、Neiut asea vatul agap ulas- 6g -a-.-.es -c . eigcteexes - f6 g rH ia.a .firstavPest-eg i -gs-e eeettvi-a gfgueigve eqi-ees d e a aeeawea i.ti va vevejefa" di-tissiv-sic veiewceii-kele- Maxse s m- . g -.egi g te-t tg -e ee-i i ki-g c it c ii-s i Martdvr e O.kflttlt r ciTeem-.acr-i.liis-u is p-a

45、i gig iigai-is .acesc a .-i f -u esei deicg ui iii.sa thaieieetf-gsiii c e e - e c-ge eq i- er er-'-i -ic e.e eieetdvre-gesere- - ed vTeri d cev c- a .v- i it-i siiideEaiig- ek-g -tav c -agaic- s i-tv sec siiiu-kvew a- - e c id -c a s ide e-teg-g i esiet-ic u-ok er- giec e if k er-ee - -a cs- a-

46、e a aic u eeg-i-2424-7319-81336>> Aans =4-31-205253>>8、 在MATLAB中分別利用矩陣的初等變換及函數(shù)rank、函數(shù)inv求下列矩陣的秩:門-6 3 2、 A = | 3-5 4 0 ,求 rank(A尸？1_1 112 4，>> A=1,-6,3,2;3,-5,4,0;-1,-11,2,4;>> rank(A)ans =1B= 10 10 02 00 2-se ies -a -iic a- eesti-a - -if wr-edst-i-s a -i-is ese-ace -i->&g

47、t; B=3,5,0,1;1,2,0,0;1,0,2,0;1,2,0,2>> inv(B)ans =2.0000-1.0000-1.00000-4.00002.50002.0000-0.5000-0.00000.00000.50000-1.00000.50000.50000.50009、在MATLAB中判斷下列向量組是否線性相關(guān)，并找出向量組%=(1132)T,口2 =(11 13)T,%=(5289)T, 口 4 =(1317) T 中的一個最大線性無關(guān)組。10sound a ndfasteconomic andsocialHuJintao comradeformain reco

48、nnotati on,spirituale sse nce a nd t heba sic requirementdevelopmenti n Chi na, theparty's 17 ge nerals,t hescientific Outlookondevel opme nt intothe partyConstitution. 5years,the sci entific Outlook on developme nthas beena practi ce,lear n, practi ce and understanding of pr ocesses,t heoryev o

49、lves,em erging practi ce effectiveness. Putthe scientifipresentativeofCPCpe ople ,insi stedtoDe ng Xia o-ping' sthe oryand threea repre sentativeimportantthoughtfor guide,a ccordi ngto ne wofdevel opmentre quireme nts, deep aware ness andansw ered has ne wsituati on Xia achieved w hatofdevel opm

50、e nt,and howde velopment, majorproble一 . I _ L . . _II 一. >1 一一 .1.1. I 一- . I , 一 . L II_ 一. - - - _ I. I . .1 - 1- 一一一 .1.1I .II L Ill_I 一I _.111- _ II - - - sforimplementing thescientificconce ptofdevel opme nt.Accordingtothe newre quireme nentific conce pt ofdevelopment,t henewrequirementsoft

51、hedevel opmentstage s ofChi na's developmentiobcOutlook ondevelopmentin t lem,formed has people,andfullcoor-. - _ - I. -n the new ce nturynew demandson development.Tdhienaptairtoyn'ssgustauinidaibnleg idehe"pe ople -ori ented,comprehe nsive, coordi natedand sustainadecisionto pr oclaimt

52、othe world theCommuni stPartype ople' s firm determinationto takethws. Thescie ntific Outlook on development, i swith Marxi sm-Leni nism, Ma oZeII. L.- 一一- - J .11.bledevelopment" is thethe scientificOutlook on develbasic connotationopme nt,integrated astofscie ntific development. Emancipat

53、i ng the mind,seekihefundamentalwaytothoroughlyimplngtruth fromfacts,aementthescieseventh naturalparagraphfullhas party of16 big yilaiparty of theory innovation especina,is t he gui ding i deol ogyofsocialismwit h Chi nese characteristi csand must follow.T.- - - I . . 一 .一 - -L _ Iup tothescie ntificOutlookondevel opment ofChi na'ssociali stmoder nhsci entifictheorie s, isthe Marxistdevel opme ntOutl ooka nd Lawref一.I n I_ -I L. _ L- Isiti oni ng ofcontent,expressed for:16 bigyil ai, tofic developmentviewbackgro