電壓損失計算表

,電壓,35,10,0.38,單相0.38,0.22,0.036,0.024,0.012,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,線纜,銅芯線纜,銅包鋁線纜,鋼芯鋁絞線,銅導(dǎo)體插接母線槽,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,截面,1.5mm2,2.5mm2,4mm2,6mm2,10mm2,16mm2,25mm2,35mm2,50mm2,70mm2,95mm2,120mm2,150mm2,185mm2,240mm2,300mm2,400mm2,100A,200A,250A,400A,600A,800A,1000A,1250A,1600A,2000A,2500A,3150A,4000A,5000A,6400,,,,,,,,

銅芯線纜,電阻R,13.739,8.234,5.152,4.435,2.061,1.288,0.824,0.589,0.412,0.294,0.217,0.172,0.137,0.111,0.086,,,,,,,,,,,,,,,,,,,,,,,,,

,電抗X,0.109,0.102,0.095,0.09,0.073,0.068,0.066,0.064,0.063,0.061,0.06,0.062,0.06,0.059,0.058,,,,,,,,,,,,,,,,,,,,,,,,,

銅包鋁線纜,電阻R,,7.41,4.61,3.08,1.83,1.15,0.727,0.524,0.387,0.268,0.193,0.153,0.124,0.0991,0.0754,0.0601,0.047,,,,,,,,,,,,,,,,,,,,,,,

,電抗X,0.109,0.102,0.095,0.09,0.073,0.068,0.066,0.064,0.063,0.061,0.06,0.062,0.06,0.059,0.058,,,,,,,,,,,,,,,,,,,,,,,,,

合金鋁線纜,電阻R,,,,,,2.19,1.402,1.001,0.701,0.501,0.37,0.293,0.235,0.191,0.148,0.12,0.092,,,,,,,,,,,,,,,,,,,,,,,

,電抗X,,,,,,0.08,0.08,0.078,0.075,0.074,0.072,0.071,0.071,0.071,0.071,0.07,0.07,,,,,,,,,,,,,,,,,,,,,,,

鋼芯鋁絞線,電阻R,,,,,,,,0.823,0.5946,0.4217,0.3058,0.2496,0.1339,,,,,,,,,,,,,,,,,,,,,,,,,,,

,電抗X,,,,,,,,0.38,0.38,0.38,0.38,0.38,0.38,,,,,,,,,,,,,,,,,,,,,,,,,,,

銅導(dǎo)體插接母線槽,電阻R,,,,,,,,,,,,,,,,,,0.85,0.39,0.13,0.105,0.1335,0.0862,0.063,0.0429,0.0289,0.0225,0.0189,0.0144,0.0113,0.0095,0.0077,,,,,,,,

,電抗X,,,,,,,,,,,,,,,,,,0.19,0.2,0.064,0.062,0.0833,0.0521,0.0383,0.0321,0.0232,0.0183,0.0146,0.0116,0.0091,0.0073,0.0058,,,,,,,,

起重量,0.5(電動葫蘆),1(電動葫蘆),2(電動葫蘆),3(電動葫蘆),4(電動葫蘆),0.5(梁式),1(梁式),2(梁式),3(梁式),5(梁式),1+1(梁式),2+1(梁式),2+2(梁式),3+1(梁式),3+2(梁式),3+3(梁式),5+1(梁式),5+2(梁式),5+3(梁式),5+5(梁式),5,10,15/3,20/5,30/5,50/10,5+5,10+5,10+10,10/3+5,15/3+10,15/3+15/3,20/5+5,20/5+10,20/5+15/3,20/5+20/5,30/5+5,30/5+10,30/5+15/3,30/5+20/5,30/5+30/5

尖峰電流,17,27,36,61,90,19,29,38,62,90,30,45,47,70.5,72,74,102,103,105,108,94,142,253,253,360,376,127,177,190,296,310,344,296,310,344,344,418,421,454,454,483

滑觸線電流,60,100,125,160,250,400,630,800,1000,1250,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

滑觸線阻抗(Ω/m),0.003604,0.002891,0.001968,0.000364,0.0003,0.000221,0.000137,0.000117,0.000102,0.000086,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

線纜電壓損失計算表,,,,,,,,,,,,,,,天車滑觸線壓降計算,,,,,,,,,,,,,,,,,,,,,,,,,,

序號,起點,回路號,終點,額定電壓,導(dǎo)體,導(dǎo)體,距離,功率,功率,單位電阻,單位電抗,電壓損失,,,序號,廠房名稱,供電距離(m),起重量(t),滑觸線額定電流,尖峰電流(A),滑觸線阻抗(Ω/m),壓降,,,,,,,,,,,,,,,,,,,

,,,,kV,類型,規(guī)格,m,kw,因數(shù),Ω/km,Ω/km,,,,1,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

1,,,,0.22,銅芯線纜,2.5mm2,20,1,0.8,8.234,0.102,1.1896,%,,2,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

2,0,,,0.38,銅芯線纜,2.5mm2,20,1,0.8,8.234,0.102,0.1151,%,,3,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

3,0,,,10,鋼芯鋁絞線,50mm2,1000,1000,0.8,0.5946,0.38,0.8796,%,,4,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

4,0,,,,,,,,,,,,%,,5,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

5,0,,,,,,,,,,,,%,,6,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

6,0,,,,,,,,,,,,%,,7,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

7,0,,,,,,,,,,,,%,,8,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

8,0,,,,,,,,,,,,%,,9,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

9,0,,,,,,,,,,,,%,,10,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

10,0,,,,,,,,,,,,%,,11,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

11,0,,,,,,,,,,,,%,,12,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

12,0,,,,,,,,,,,,%,,13,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

13,0,,,,,,,,,,,,%,,14,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

14,0,,,,,,,,,,,,%,,15,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

15,0,,,,,,,,,,,,%,,16,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

16,0,,,,,,,,,,,,%,,17,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

17,0,,,,,,,,,,,,%,,18,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

18,0,,,,,,,,,,,,%,,19,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,合計,,,,,,1040,1002,,,,2.1843,%,,20,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,結(jié)論,,,最不利處電壓損失小于5%，滿足要求。,,,,,,,,,,,21,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,計算公式,,,單相相電壓,電壓損失＝(2×31/2÷10÷額定相電壓2)×(單位電阻+單位電抗×tg(arccos功率因數(shù)))×功率×(距離÷1000),,,,,,,,,,22,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,,,,單相線電壓,電壓損失＝(2÷10÷額定相電壓2)×(單位電阻+單位電抗×tg(arccos功率因數(shù)))×功率×(距離÷1000),,,,,,,,,,23,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,,,,三相,電壓損失＝(1÷10÷額定線電壓2)×(單位電阻+單位電抗×tg(arccos功率因數(shù)))×功率×(距離÷1000),,,,,,,,,,24,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,,,,等距等負荷線路末端電壓損失簡易算法：,,,L＝起點至第一個設(shè)備的距離＋第一個設(shè)備至最后一個設(shè)備的距離的一半,,,,,,,,25,,,,,0,0,0.00%,,,,,,,,,,,,,,,,,,,

,,,,,,,Pj＝全部設(shè)備容量總和,,,,,,,,,計算公式,電壓降＝31/2×尖峰電流×滑觸線阻抗×供電距離÷額定電壓×100,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

,,,,,,,,,,,,,,,,,,,,,,,,