C語言上機(jī)練習(xí)參考答案

1、n 第1章 C語言概述1-1 編寫程序，在屏幕上顯示一個如下輸出： - Programming in C is fun! I love C language.-Program#include <stdio.h>main()printf("-n"); printf("Programming in C is fun!n"); printf("I love C language.n");printf("-n");1-2 編寫程序，在屏幕上顯示一個如下圖案： * * * * * * * * * *Program

2、 (1)#include <stdio.h>main()printf("* * * *n"); printf(" * * *n");printf(" * *n");printf(" *n ");Program (2) #include <stdio.h>main()printf("%c%4c%4c%4cn", '*', '*', '*', '*'); printf("%3c%4c%4cn"

3、, '*', '*', '*');printf("%5c%4cn", '*', '*');printf("%7cn ", '*');1-3 已知某個圓的半徑，編寫一個程序，用來計(jì)算并顯示面積。要求：將定義為符號常量，并假設(shè)一個恰當(dāng)?shù)陌霃街?。Program#include <stdio.h>#define PI 3.14main()float r=5, s;s = PI*r*r; printf("The area of circle is:

4、 %.2fn", s);Output The area of circle is: 78.501-4 已知兩個整數(shù)20和10，編寫程序，自定義函數(shù)add( )將這兩個數(shù)相加，自定義函數(shù)sub( )計(jì)算這兩個數(shù)的差，并按照下面形式顯示計(jì)算結(jié)果：20+10=30 20-10=10Program#include <stdio.h>int add(int a, int b)return (a+b);int sub(int a, int b)return (a-b);main()int a=20, b=10;printf("%d + %d = %dn", a,

5、b, add(a, b);printf("%d - %d = %dn", a, b, sub(a, b);Output 20 + 10 = 3020 10 = 101-5 已知變量a、b和c的值，編寫程序，用來計(jì)算并顯示x的值，其中請分別用以下數(shù)值運(yùn)行該程序（1）a=250，b=85，c=25（2）a=300，b=70，c=80Program (1)#include <stdio.h>main()int a=250, b=85, c=25;float x;x=1.0*a/(b-c);printf("x = %.2fn", x);Output

6、(1)x = 4.17Program (2)#include <stdio.h>main()int a=300, b=70, c=80;float x;x=1.0*a/(b-c); /*試寫成x=a/(b-c); 得到什么運(yùn)行結(jié)果？為什么？*/printf("x = %.2fn", x);Output (2)x = -30.00n 第2章 常量、變量及數(shù)據(jù)類型 & 第3章 運(yùn)算符和表達(dá)式3-1 編寫程序，求華氏溫度100oF對應(yīng)的攝氏溫度。計(jì)算公式如下：式中：c表示攝氏溫度，f表示華氏溫度。（c定義為實(shí)型，f定義為整型）Program #include

7、<stdio.h>main()int f=100;float c;c=5.0*(f-32)/9;/*如果是c=5*(f-32)/9; 會是什么結(jié)果？為什么？*/printf("Celsius degree (corresponding to %d Fahrenheit) is: %.2f.n", f, c);Output Celsius degree (corresponding to 100 Fahrenheit) is: 37.78.3-2 一個物體從100m的高空自由落下，編寫程序，求它在前3s內(nèi)下落的垂直距離。設(shè)重力加速度為10m/s2。要求，將重力加速

8、度定義為符號常量，嘗試將其改為9.8 m/s2，看結(jié)果有何不同？Program #include <stdio.h>#define G 10main()int t=3;float s;s=1.0/2*G*t*t; /*如果是s=1/2*G*t*t; 會是什么結(jié)果？為什么？*/printf("The falling vertical distance (in %d seconds) is: %.2f.n", t, s);Output The falling vertical distance (in 3 seconds) is:45.00.3-3 將球的半徑R定義

9、為符號常量，計(jì)算球的表面積（4R2）和體積（4/3*R3）。Program #include <stdio.h>#define R 5.2#define PI 3.14main()float s, v;s=4*PI*R*R;v=4.0/3*PI*R*R*R;printf("The surface area of the ball (radius is %.2f) is: %.2f, and the volume is: %.2f.n", R, s, v);Output The surface area of the ball (radius is 5.20) i

10、s: 339.62, and the volume 588.68.3-4 給定x、y和z的值，編寫程序，使x等于y的值，y等于z的值，z等于x的值。Program #include <stdio.h>main()int x=1, y=2, z=3, t;printf("Before swap: x=%d, y=%d, z=%d.n", x, y, z);t=x;x=y;y=z;z=t;/*變量t的作用是什么？*/printf("After swap: x=%d, y=%d, z=%d.n", x, y, z);Output Before sw

11、ap: x=1, y=2, z=3.After swap: x=2, y=3, z=1.3-5 編寫一個程序，給定一個浮點(diǎn)數(shù)（例如456.78），顯示該數(shù)的十位數(shù)字與個位數(shù)字之和（例如5+6=11）。Program (1)#include <stdio.h>main()float f=456.78;int n, a, b;n=f;a = n%10;/*賦值后，a是什么值？*/b = n/10%10;/*賦值后，b是什么值？*/printf("The sum of the tens digit and units digit of %.2f is: %d + %d = %d

12、.n", f, b, a, a+b);Program (2)#include <stdio.h>main()float f=456.78;int n, a, b;n=f;a = n%10;b = n%100/10;/*該語句與上面程序不同，看看有何區(qū)別？*/printf("The sum of the tens digit and units digit of %.2f is: %d + %d = %d.n", f, b, a, a+b);Output The sum of the tens digit and units digit of 456.7

13、8 is: 5+ 6 = 11.3-6 某種物品每年折舊費(fèi)的計(jì)算方法如下：編寫一個程序，當(dāng)給定某物品的購買價格、使用年限和每年的折舊費(fèi)時，計(jì)算出其廢品價值。Program #include <stdio.h>main()float price=120.65, year=3, depreciation=10.2, value;value = price - year*depreciation;printf("The scrap value is %.2f.n", value);Output The scrap value is 90.05.3-7 在庫存管理中，某

14、單個物品的經(jīng)濟(jì)定購數(shù)EOQ由下面等式給定：而最優(yōu)的定購時間間隔TBO由下面等式給定：編寫程序，給定需求率（單位時間內(nèi)的物品數(shù)）、生產(chǎn)成本（每個定購）和儲備成本（單位時間內(nèi)每種物品），計(jì)算EOQ和TBO。Program #include <stdio.h>#include <math.h>main()int demand=1000;float product_cost=3.5, storage_cost=0.63, eoq, tbo;eoq=sqrt(2*demand*product_cost/storage_cost);tbo=sqrt(2*product_cost/d

15、emand/storage_cost);printf("EOQ is %.2f, and TBO is %.2f.n", eoq, tbo); Output EOQ is 105.41, and TBO is 0.11.n 第4章 輸入輸出操作管理4-1 輸入兩個數(shù)，將它們交換后輸出。Program #include <stdio.h>main()int x, y, t;printf("Please input 2 numbers: ");scanf("%d%d", &x, &y);printf("

16、;Before swap, the 2 numbers are: %d, %dn", x, y);t=x;x=y;y=t;printf("After swap, the 2 numbers are: %d, %dn", x, y);Output Please input 2 numbers: 3 5¿/* Blue is input */Before swap, the 2 numbers are: 3, 5After swap, the 2 numbers are: 5, 34-2 輸入一個十進(jìn)制數(shù)，輸出對應(yīng)的八進(jìn)制數(shù)和十六進(jìn)制數(shù)。Program #i

17、nclude <stdio.h>main()int n;printf("Please input a decimal number: ");scanf("%d ", &n);printf("The octal is %o, and the hexadecimal is %x.n", n, n);Output Please input a decimal number: 10¿/* Blue is input */The octal is 12, and the hexadecimal is a.考慮：如何

18、得到下面的輸出？Please input a decimal number: 10¿/* Blue is input */The octal is 012, and the hexadecimal is 0xa.4-3 編寫程序，輸入3個整數(shù)，計(jì)算并輸出它們的平均值。Program #include <stdio.h>main()int a, b, c;printf("Please input 3 integers: ");scanf("%d%d%d", &a, &b, &c);printf("Th

19、e average is %.2f.n", (a+b+c)/3.0);Output Please input 3 integers: 4 7 -19¿/* Blue is input */The average is -2.67.4-4 編寫一個程序，讀取x和y的值，顯示下面表達(dá)式的值：（1）（2）（3）Program #include <stdio.h>main()float x, y;printf("Please input x and y: ");scanf("%f%f", &x, &y);print

20、f("(1) (x+y)/(x-y) = %.2fn", (x+y)/(x-y);printf("(2) (x+y)/2 = %.2fn", (x+y)/2);printf("(3) (x+y)(x-y) = %.2fn", (x+y)*(x-y);Output Please input x and y: 3.5 4.1¿/* Blue is input */(1) (x+y)/(x-y) = -12.67(2) (x+y)/2 = 3.80(3) (x+y)(x-y) = -4.564-5 計(jì)算銀行存款的本息。編寫程序，輸

21、入存款金額money、存期year和年利率rate，根據(jù)下列公式計(jì)算存款到期時的本息合計(jì)sum（稅前），輸出時保留兩位小數(shù)。Program #include <stdio.h>#include <math.h>main()float money, rate, sum;int year;printf("Please input the deposit money: ");scanf("%f", &money);printf("Please input the deposit period: ");scan

22、f("%d", &year);printf("Please input the annual interest rate: ");scanf("%f", &rate);sum=money*pow(1+rate, year);printf("The total principal and interest is: %.2fn", sum);Output Please input the deposit money: 2500¿/* Blue is input */Please input t

23、he deposit period: 3¿/* Blue is input */Please input the annual interest rate: 0.023¿/* Blue is input */The total principal and interest is: 2676.504-6 輸入圓柱的高h(yuǎn)和半徑r，求圓柱體積volume=*r2*h。Program #include <stdio.h>#define PI 3.14main()float volume, r, h;printf("Please input the radius

24、 of the cylinder: ");scanf("%f", &r);printf("Please input the height of the cylinder: ");scanf("%f", &h);volume=PI*r*r*h;printf("The volume of the cylinder is: %.2fn", volume);Output Please input the radius of the cylinder: 3.5¿/* Blue is inp

25、ut */Please input the height of the cylinder: 12.7¿/* Blue is input */The volume of the cylinder is: 488.514-7 編寫一個程序，讀取一個實(shí)數(shù)f，將其四舍五入的值賦值給整型變量n，輸出n的值。（嘗試不用if語句完成本程序，并考慮負(fù)數(shù)是否適用）Program (1)#include <stdio.h>main()float f;int n, m;printf("Please input a real number: ");scanf("%f

26、", &f);m=f*10;m=m%10/5;/*m是什么值？*/n=f;n=n+m;/*m有何作用？*/printf("The rounded integer is: %dn", n);Program (2)如果不明白if語句，可以在學(xué)完第5章后再看。#include <stdio.h>main()float f;int n, m;printf("Please input a real number: ");scanf("%f", &f);n=f+0.5;/*是否理解該語句？*/printf(&

27、quot;The rounded integer is: %dn", n);Output (1)Please input a real number: 3.6¿/* Blue is input */The rounded integer is: 4Output (2)Please input a real number: -13.2¿/* Blue is input */The rounded integer is: -134-8 編寫程序，讀入兩個兩位數(shù)字的整數(shù)，并按照如下形式輸出這兩個整數(shù)的乘積。4 5* 3 7 3 1 51 3 5 1 6 6 5提示：注意

28、格式！Program #include <stdio.h>main()int x, y, m, n;printf("Please input 2 integers: ");scanf("%d%d", &x, &y);printf("%5dn *%3dn-n", x, y);m=y%10;n=y/10;printf("%5dn%4dn-n%5dn", x*m, x*n, x*y);n 第5章 判斷與分支5-1 輸入一個字符ch，根據(jù)不同情況進(jìn)行輸出：（1）ch為小寫字母，輸出對應(yīng)的大寫字母

29、；（2）ch為大寫字母，按照原樣輸出；（3）ch為數(shù)字，輸出對應(yīng)的數(shù)字；（4）ch為其他字符，輸出“Other character.”。Program #include <stdio.h>main()char ch;printf("Please input a character: ");ch=getchar();if (ch>='a' && ch<='z')printf("%cn", ch-('a'-'A');elseif (ch>='

30、A' && ch<='Z')printf("%cn", ch);else if (ch>='0' && ch<='9')printf("%dn", ch-'0');elseprintf("Other character.n");Output (1)Please input a character: A¿/* Blue is input */AOutput (2)Please input a charact

31、er: b¿/* Blue is input */BOutput (3)Please input a character: 3¿/* Blue is input */3Output (4)Please input a character: ¿/* Blue is input */Other character.5-2 為鼓勵居民節(jié)約用水，自來水公司采用按月用水量分段計(jì)費(fèi)的辦法，居民應(yīng)交水費(fèi)y元與月用水量x噸的函數(shù)關(guān)系式如下（設(shè)x³0）。編寫程序，輸入用戶的月用水量x噸，計(jì)算并輸出該用戶應(yīng)支付的水費(fèi)y元（保留兩位小數(shù)）。Program #include &

32、lt;stdio.h>main()float x, y;printf("Please input the water consumption: ");scanf("%f", &x);if(x<=15)y=4*x/3;/*是否可以寫成y=4/3*x;？區(qū)別在哪里？*/elsey=2.5*x-10.5;printf("The water price is: %.2f. n", y);Output Please input the water consumption: 27.9¿/* Blue is input

33、 */The water price is: 59.255-3 輸入一個年份year，判斷year是否為閏年。year若為閏年，需要滿足下列條件之一：（1）能被4整除，但不能被100整除（如2004年是閏年，2100年不是閏年）（2）能被400整除（如2000年是閏年）Program #include <stdio.h>main()int year;printf("Please input the year: ");scanf("%d", &year);if (year%4=0&&year%100!=0)|(year%

34、400=0)printf("%d is a leap year!n", year);elseprintf ("%d is not a leap year!n", year);Output Please input the year: 1900¿/* Blue is input */1900 is not a leap year!5-4 輸入3個實(shí)數(shù)，將其按照降序輸出（較大數(shù)在前），保留3位小數(shù)。Program (1)#include <stdio.h>main()float x, y, z;printf("Please i

35、nput 3 real numbers: ");scanf("%f%f%f", &x, &y, &z);if (x>y)if(y>z)printf("%.3f, %.3f, %.3fn", x, y, z);elseif(x>z)printf("%.3f, %.3f, %.3fn", x, z, y);elseprintf("%.3f, %.3f, %.3fn", z, x, y); elseif(x>z)printf("%.3f, %.3f, %

36、.3f", y, x, z);elseif(y>z)printf("%.3f, %.3f, %.3fn", y, z, x);elseprintf("%.3f, %.3f, %.3fn", z, y, x);/*程序結(jié)束時，x, y, z的值是否發(fā)生了變化？*/Program (2)#include <stdio.h>main()float x, y, z,t;printf("Please input 3 real numbers: ");scanf("%f%f%f", &x,

37、&y, &z);if (x>y)t=x; x=y; y=t;if (x>z)t=x; x=z; z=t;if (y>z)t=y; y=z; z=t;/*此程序與上面的程序有何不同？*/printf("%.3f, %.3f, %.3fn", x, y, z); /*程序結(jié)束時，x, y, z的值是否發(fā)生了變化？*/Output Please input 3 real numbers: 7.8 5 10¿/* Blue is input */10.000, 7.800, 5.0005-5 輸入五級制成績（AE），輸出相應(yīng)的百分制成績（

38、0100）區(qū)間。五級制成績對應(yīng)百分制程序區(qū)間為：A（90100）、B（8089）、C（7079）、D（6069）和E（059）。例如：輸入B，輸出（8089）。（1）用switch語句實(shí)現(xiàn)；（2）用if語句實(shí)現(xiàn)。Program (1)#include <stdio.h>main()char grade;printf("Please input the grade: ");scanf("%c", &grade);switch (grade)case 'A': printf("90100n");brea

39、k;case 'B': printf("8089n");break;case 'C': printf("7079n");break;case 'D': printf("6069n");break;case 'E': printf("059n");break;default:printf("Wrong grade! n");Program (2)#include <stdio.h>main()char grade;prin

40、tf("Please input the grade: ");scanf("%c", &grade);if (grade='A')printf("90100n");else if (grade='B')printf("8089n");else if (grade='C')printf("7079n");else if (grade='D')printf("6069n");else if (grade=&#

41、39;E')printf("059n");elseprintf("Wrong grade! n");Output Please input the grade: B¿/* Blue is input */80895-6 用switch語句實(shí)現(xiàn)，輸入數(shù)字17，輸出對應(yīng)的英文單詞Monday, Tuesday, , Sunday。Program #include <stdio.h>main()int day;printf("Please input the day in a week: ");scanf(&q

42、uot;%d", &day);switch(day)case 1: printf("Mondayn"); break;case 2: printf("Tuesdayn");break;case 3: printf("Wednesdayn");break;case 4: printf("Thursdayn"); break;case 5: printf("Fridayn"); break;case 6: printf("Saturdayn");break;ca

43、se 7: printf("Sundayn"); break;default: printf("Wrong day! n");Output Please input the day in a week: 4¿/* Blue is input */Thursday5-7 某高校的某專業(yè)錄取研究生的條件如下：（1）英語成績³55（2）政治成績³60（3）專業(yè)課成績³60（4）以上三科的總數(shù)學(xué)成績³200，或英語和專業(yè)課的總成績³130。編寫程序，讀入一個學(xué)生的成績（英語、政治和專業(yè)課），判斷是否可以

44、被錄取。Program #include <stdio.h>main()float english, politics, professional;printf("Please input score of English: ");scanf("%f", &english);printf("Please input score of Politics: ");scanf("%f", &politics);printf("Please input score of the pro

45、fessional course: ");scanf("%f", &professional);if(english>=55 && politics>=60 && professional>=60 && (english+politics+professional>=200 | english+professional>=130)printf("Congratulations! You have been admitted! n");elseprintf(&q

46、uot;Sorry, you have been rejected! n");Output Please input score of English: 60¿/* Blue is input */Please input score of Politics: 70¿/* Blue is input */Please input score of professional course: 60¿/* Blue is input */Sorry, you have been rejected!5-8 編寫程序，計(jì)算下面二元方程的實(shí)數(shù)根。應(yīng)用如下規(guī)則：（1）

47、如果a和b的值為零，則沒有解；（2）如果a的值為零，則只有一個解（x=-c/b）;（3）如果b2-4ac為負(fù)數(shù)，則沒有實(shí)數(shù)根；（4）否則，有兩個實(shí)數(shù)根：輸入a, b和c的值，輸出求根的情況，如有實(shí)數(shù)根，則輸出實(shí)數(shù)根的值。Program #include <stdio.h>#include <math.h>main ( ) float a, b, c, f;printf ( "Please input the value of a, b and c in the quadratic equation:nax*x + bx + c = 0n" );pri

48、ntf ( "a = " );scanf ( "%f", &a );printf ( "b = " );scanf ( "%f", &b );printf ( "c = " );scanf ( "%f", &c );printf ( "About %.2fx*x + %.2fx + %.2f = 0: ", a, b, c );if ( a = 0 && b = 0 ) printf("There is n

49、o solution!n");elseif ( a = 0 ) printf("There is only one root: %.2f.n",- c/b);elsef = b * b - 4 * a * c;if ( f <0 ) printf("There are no real root!n");elseprintf("There are 2 real roots: %.2f, %.2f.n",(-b + sqrt(f)/2/a, (-b - sqrt(f)/2/a );Output Please input t

50、he value of a, b and c in the quadratic equation:ax*x + bx + c = 0a = -3¿/* Blue is input */b = 4¿/* Blue is input */c = 5¿/* Blue is input */About -3.00x*x + 4.00x+5.00 = 0: There are 2 real roots: -0.79, 2.12.5-9 編寫程序，讀取x的值，求下面函數(shù)的值（1）用else if語句實(shí)現(xiàn)（2）用嵌套if語句實(shí)現(xiàn)（3）用條件運(yùn)算符 ? : 實(shí)現(xiàn)Program (

51、1)#include <stdio.h>main ( )float x;printf ( "Please input the value of x: " );scanf ( "%f", &x );if ( x > 0 )printf ( "y = 1n" );elseif ( x = 0 ) printf ( "y = 0n" );elseprintf ( "y = -1n" );Program (2)#include <stdio.h>main ( )fl

52、oat x;printf ( "Please input the value of x: " );scanf ( "%f", &x );if ( x != 0 )/*寫成if(x)是否正確？*/if ( x > 0 )/*寫成if(x)是否正確？*/printf ( "y = 1n" );elseprintf ( "y = -1n" );elseprintf ( "y = 0n" );Program (3)#include <stdio.h>main ( )float

53、x;printf ( "Please input the value of x: " );scanf ( "%f", &x );printf ( "y = %dn", x > 0 ? 1 : x < 0 ? -1 : 0 );Output Please input the value of x: 9¿/* Blue is input */y = 15-10 某個服裝展示廳宣布以下所賣物品季節(jié)性打折：購買總額折扣機(jī)加工制品手工制品0100無折扣5%1012005%7.5%2013007.5%10.0%大于3

54、0010.0%15.0%編寫程序，計(jì)算某顧客應(yīng)付的款項(xiàng)。要求：同時用switch和if語句實(shí)現(xiàn)。Program #include <stdio.h>main ( )float price, discount;char category;printf ( "Category (m/h): " ); scanf ( "%c", &category );printf ( "Price: " ); scanf ( "%f", &price );if ( category = 'm'

55、; )switch ( (int) (price-1)/100 )case 0:discount = 0;break;case 1:discount = 0.05;break;case 2: discount = 0.075; break;default:discount = 0.1; else switch ( (int) (price-1)/100 )case 0:discount = 0.05; break;case 1:discount = 0.075; break;case 2:discount = 0.1; break;default:discount = 0.15;printf

56、("The net amount to be paid is %.2fn", price*(1-discount);Output Category (m/h): h¿/* Blue is input */Price: 250.60¿/* Blue is input */The net amount to be paid is 225.545-11 編寫程序，輸入x，計(jì)算并輸出下列分段函數(shù)f(x)的值（保留2位小數(shù)）。提示：請調(diào)用sqrt( )函數(shù)求平方根，調(diào)用pow( )函數(shù)求冪。Program #include <stdio.h>#incl

57、ude <math.h>main()float x, y;printf("Please input the value of x: ");scanf("%f", &x);if(x<0)y=pow(x,5)+2*x+1/x;elsey=sqrt(x); printf("The value of y is: %.2f. n", y);Output Please input the value of x: -2¿/* Blue is input */The value of y is: -36.505-1

58、2 編寫程序，輸入一個實(shí)數(shù)（例如456.78），求不小于該數(shù)的最小整數(shù)和不大于該數(shù)的最大整數(shù)。（提示：注意負(fù)數(shù)）。 Program #include <stdio.h>main()float f;int n;printf("Please input a real number: ");scanf("%f", &f);n=f;if(f>=0)printf("The largest integer (not larger than %.2f) is: %dn", f, n);if (f-n>0)printf("The smallest integer (not less than %.2f) is: